Help me with this pls

Answer:

Alright but first

How is this 7th grade stuff?

I thoguh yall were doing algebra. But it kinda looks like it but here’s a brief explanation anyway.

If you dont know a vualure, use other surrounding it to help you sovle this final thingy. Like if its division, multiply. addditon, subtract. multiply, Davison. Just tdo inver properties on both sides and isolate the number that x in it Either be dividing or multiplying. When your left with a final value just solve, whatever thing that lies next to that equal sign is your answer.

2) 6

3) -36

4) 40

5) 9

6) -4

7) 63

8) -48

9) -5

10) -7

Answer:

1014 in

Step-by-step explanation:

(13 x 13) x 6 = 1014 in^3

Answer:

The answer should be A (676)

Step-by-step explanation:

Answer:

a) P(X < 99) = 0.2033.

b) P(98 < X < 100) = 0.4525

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 100 and variance of 36.

This means that [tex]\mu = 100, \sigma = \sqrt{36} = 6[/tex]

Sample of 25:

This means that [tex]n = 25, s = \frac{6}{\sqrt{25}} = 1.2[/tex]

(a) P(X<99)

This is the pvalue of Z when X = 99. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{99 - 100}{1.2}[/tex]

[tex]Z = -0.83[/tex]

[tex]Z = -0.83[/tex] has a pvalue of 0.2033. So

P(X < 99) = 0.2033.

b) P(98 < X < 100)

This is the pvalue of Z when X = 100 subtracted by the pvalue of Z when X = 98. So

X = 100

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{100 - 100}{1.2}[/tex]

[tex]Z = 0[/tex]

[tex]Z = 0[/tex] has a pvalue of 0.5

X = 98

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{98 - 100}{1.2}[/tex]

[tex]Z = -1.67[/tex]

[tex]Z = -1.67[/tex] has a pvalue of 0.0475

0.5 - 0.0475 = 0.4525

So

P(98 < X < 100) = 0.4525

Answer:

119

Step-by-step explanation:

A=w 1=7x17=119

Answer: AA

Step-by-step explanation:

You can do vertical angles or alternate interior angles. Hope this helps :)

Answer:

28.27

Step-by-step explanation:

3.14 x 9

is how to do this problem

Answer:

8 5 7 1 3 2 4 6

Step-by-step explanation:

my Cashsap kinqcollin

Answer:

F

(

−

2

x

+

12

)

=

−

8

x

3

+

144

x

2

−

864

x

+

1731

Step-by-step explanation:

Answer:

....

Step-by-step explanation:

mean: 16

median: 16

there is no mode

range: 8

Answer:

[tex]3\frac{7}{8}[/tex]

Step-by-step explanation:

Equation: 4 1/7 + 2 1/8 + x= 10 1/7

Convert into improper fractions:

29/7 + 17/8= 71/7

Add fractions

351/56+x= 71/7

Subtract on both sides

X= 31/8 or 3 7/8

[tex]6^{2}+8^{2}=x^{2} \\36+64=x^{2} \\100=x^{2} \\x=10[/tex]

Answer:

The wingspan of a pelican is 1 8/15 feet longer than the wingspan of an eagle.

(1 whole 8/15 feet)

Step-by-step explanation:

We'll need to find a common denominator for the fractions. 15 is the lowest number divisible by both 5 and 3, so we'll use 15. For this problem, it's also easier to convert to improper fractions, in my opinion.

Pelican:

8 1/5 = 41/5

41/5 x 3/3 = 123/15

Eagle:

6 2/3 = 20/3

(20/3) x (5/5) = 100/15

Find the difference:

123/15 - 100/15 = 23/15 = 1 8/15

Please let me know if you have questions.

Answer:

4/7

Step-by-step explanation:

The probability that a student does not play an instrument given that they play a sport is 4/23.

It is the chance of an event to occur from a total number of outcomes.

The formula for probability is given as:

Probability = Number of required events / Total number of outcomes.

We have,

Total number of students = 23

From the Venn diagram,

Number of students who play sport but not an instrument = 4

The probability that a student does not play an instrument given that they play a sport.

= 4/23

Thus,

The probability is 4/23.

Learn more about probability here:

https://brainly.com/question/14099682

#SPJ2

Answer:

3x+18+4x+15=180

7x+33=180

7x=147

x=21

Answer:

54ft

Step-by-step explanation:

9ft x 6ft

Answer:

I want her mollah

Step-by-step explanation:

Ewan HH

Step-by-step explanation:

Ewanjajsbehudbeiisiejebejehehehheehhehehe

Answer:

???

Step-by-step explanation:

Answers:

d = v(initial)t + 1/2(at^2)

v(final) = √(v(initial)^2 + 2ad)

a = 2(d-v(initial)t) / t^2

t = -v(initial)±√(v(initial)^2 + 2ad) / a

Answer:

1. vt-d=1/2at^2

2. d-vt=1/2at^2

3. a=2(d-vt)/t^2

Step-by-step explanation:

Answer:

A) The parameter of interest is the average filling weight of all cereal packages. ;

Point estimate = 1.22

Margin of Error = 0.0196

Confidence interval = (1.2004, 1.2396)

C) No, since the confidence interval contains the target filling weight of 1.20.

Step-by-step explanation:

A) The parameter of interest is the average filling weight of all cereal packages.

The point estimate = sample mean = 1.22

The margin of error with 95% confidence :

Zcritical * σ/sqrt(n)

Zcritical at 95% confidence = 1.96

Margin of Error = 1.96 * 0.06/sqrt(36)

Margin of Error : 1.96 * 0.01

Margin of Error = 0.0196

Confidence interval :

xbar ± margin of error

1.22 ± 0.0196

Lower boundary = 1.22 - 0.0196 = 1.2004

Upper boundary = 1.22 + 0.0196 = 1.2396

(1.2004, 1.2396)

C) No, since the confidence interval contains the target filling weight of 1.20.

Since, the internal contains 1.20, then we can conclude that it is filling properly.

Answer:

3x+5-7

Step-by-step explanation:

Answer:

If im not mistaken it should be answer 3. Because you would have to divide amongst groups.

Answer:

Cylinder

Step-by-step explanation:

A cone is a 3D triangle with a circular base, and a sphere is a 3D circle

Answer:

CYLIDER

Step-by-step explanation:

The total animals = 139, and we can substitute this value into equation (3) to obtain:x = 2(139) - 279 => x = -1This doesn't make sense since we can't have negative chickens.

Let the number of chickens be x and the number of cows be y in the backyard. We can create two equations based on the given information:The total number of animals is x + y = total animals ...

(1)The total number of eyes and legs can also be expressed as 2x + 2y = 366 (since each animal has two eyes) and 2x + 4y = 558 (since each chicken has 2 legs and each cow has 4 legs).

Simplifying the equations, we get:x + y = total animals ... (1)x + 2y = 279 ... (2)From equation (1),

we can substitute y = total animals - x in equation (2) to obtain:x + 2(total animals - x) = 279 => 2total animals - x = 279 => x = 2total animals - 279 ... (3)We also know that x + y = total animals, so y = total animals - x.

Substituting equation (3) into this expression, we get:y = total animals - (2total animals - 279) => y = 279 - total animals ... (4)

To find the value of x, we need to know the value of total animals. We can obtain this value by adding equations (1) and (4):x + y + (279 - total animals) = total animals => x + y = 279/2 => x + y = 139.5

Since x and y are both whole numbers, they must add up to an even number. The only possible value is 70 + 69 = 139.  Therefore, there must be a mistake in the problem statement or calculations.

To learn more about : value

https://brainly.com/question/843074

#SPJ8

Answer:

LDM

MDL

Step-by-step explanation:

The names of a figure are gotten from the points on the figure. The names of the figure are LDM  and MDL.

There are three points on the given figure, and these points are: point L, point D and point M, where Point D is between L and M.

This means that, when naming the figure, alphabet D must be at the middle while alphabets M and L can be at either sides of D.

So, the possible names of the figure are: LDM  and MDL.

Read more about naming figures at:

https://brainly.com/question/1514423

Answer:

third option

Step-by-step explanation:

subtract 125/4 from each side to get:

x² + 11x -1

use quadratic formula to get:

-11 ± √121 - 4(-1)/2

= -11 ± ([tex]\sqrt{125}[/tex]) / 2

* [tex]\sqrt{125}[/tex] = [tex]\sqrt{25}[/tex] · [tex]\sqrt{5}[/tex] = 5[tex]\sqrt{5}[/tex]

= -11 ± (5[tex]\sqrt{5}[/tex]) / 2

Answer:

The average function [tex]f_{avg}[/tex] value = 4

Step-by-step explanation:

Given that:

[tex]f(x,y,z) = 3x^2z+3y^2z[/tex]

The enclosed region [tex]z = 4 -x^2 -y^2[/tex] and the plane z = 0.

Over an area E, the average value of a function f(x,y,z) is:

[tex]f_{avg} = \dfrac{1}{V_{E}} \iiint_E f(x,y,z) dV ------ (1)[/tex]

where;

[tex]V_E[/tex] = volume of region E

To find the volume use cylindrical coordinates;

[tex]x=rcos \theta; \ \ \ y = rsin \theta; \ \ \ z = z[/tex]

Then;

E = 0 ≤ r ≤2, 0 ≤ θ ≤ 2π, 0 ≤ z ≤ 4 - r²

[tex]V_E = \int^{2 \pi}_{0} \int^{2}_{0} \int^{4-r^2}_{0} \ rdzdrd \theta[/tex]

[tex]V_E = \int^{2 \pi}_{0} \int^{2}_{0} r(4-r^2) \ drd \theta[/tex]

[tex]V_E = \int^{2 \pi}_{0} \int^{2}_{0} (4r-r^3) \ drd \theta[/tex]

[tex]V_E = \int^{2 \pi}_{0} \Big(2r^2- \dfrac{r^4}{4} \Big)^2_0 \ d \theta[/tex]

[tex]V_E = 4(2 \pi)\\\\ V_E = 8 \pi[/tex]

However, from equation (1):

[tex]f_{avg} = \dfrac{1}{V_E} \iiint_E f(x,y,z) \ dV \\ \\ = \dfrac{1}{8 \pi} \iiint_E (3x^2z + 3y^2 z) dV \\ \\ = \dfrac{1}{8 \pi } \int^{2 \pi}_{0} \int^{2 }_{0} \int^{4 - r^2}_{0} \ \ 3zr^2 \ rdzdrd\theta \\ \\ = \dfrac{3}{8 \pi} \int^{2 \pi}_{0} \int^{2 }_{0} \Big(\dfrac{z^2}{2}\Big)^{4-r^2}_{0} \ r^3 drd\theta \\ \\ = \dfrac{3}{16 \pi} \int^{2 \pi}_{0} \int^{2 }_{0} (4-r^2)^2 \ r^3 \ dr d\theta[/tex]

[tex]= \dfrac{3}{16 \pi} \int^{2 \pi}_{0} \int^{2 }_{0} (16-8r^2 + r^4)r^3 \ dr d\theta \\ \\ = \dfrac{3}{16 \pi} \int^{2 \pi}_{0} \int^{2 }_{0} (16r^3 -8r^5 + r^7) \ dr d \theta \\ \\ = = \dfrac{3}{16 \pi} \int^{2 \pi}_{0} \Big (4r^4 - \dfrac{8}{6}r^6 + \dfrac{r^8}{8} \Big)^2_0 \ d \theta \\ \\ = \dfrac{3}{16 \pi } (2 \pi) \Big (64 - \dfrac{8}{6} \times 64 \times \dfrac{256}{8} \Big) \\ \\ = \dfrac{3}{16 \pi} (2 \pi) (\dfrac{32}{3}) \\ \\ = 4[/tex]

Answer:

hope this helps :D

Step-by-step explanation:

Perfect cube factors:

If a number is a perfect cube, then the power of the prime factors should be divisible by 3.

Example 1:Find the number of factors of293655118 that are perfect cube?

Solution: If a number is a perfect cube, then the power of the prime factors should be divisible by 3. Hence perfect cube factors must have

2(0 or 3 or 6or 9)—– 4 factors

3(0 or 3 or 6)  —–  3  factors

5(0 or 3)——- 2 factors

11(0 or 3 or 6 )— 3 factors

Hence, the total number of factors which are perfect cube 4x3x2x3=72

Perfect square and perfect cube

If a number is both perfect square and perfect cube then the powers of prime factors must be divisible by 6.

Example 2: How many factors of 293655118 are both perfect square and perfect cube?

Solution: If a number is both perfect square and perfect cube then the powers of prime factors must be divisible by 6.Hence both perfect square and perfect cube must have

2(0 or 6)—– 2 factors

3(0 or 6) —– 2 factors

5(0)——- 1 factor

11(0 or 6)— 2 factors

Hence total number of such factors are 2x2x1x2=8

Example 3: How many factors of293655118are either perfect squares or perfect cubes but not both?

Solution:

Let A denotes set of numbers, which are perfect squares.

If a number is a perfect square, then the power of the prime factors should be divisible by 2. Hence perfect square factors must have

2(0 or 2 or 4 or 6 or 8)—– 5 factors

3(0 or 2 or 4 or 6)  —– 4 factors

5(0 or 2or 4 )——- 3 factors

11(0 or 2or 4 or6 or 8 )— 5 factors

Hence, the total number of factors which are perfect square i.e. n(A)=5x4x3x5=300

Let B denotes set of numbers, which are perfect cubes

If a number is a perfect cube, then the power of the prime factors should be divisible by 3. Hence perfect cube factors must have

2(0 or 3 or 6or 9)—– 4 factors

3(0 or 3 or 6)  —–  3  factors

5(0 or 3)——- 2 factors

11(0 or 3 or 6 )— 3 factors

Hence, the total number of factors which are perfect cube i.e. n(B)=4x3x2x3=72

If a number is both perfect square and perfect cube then the powers of prime factors must be divisible by 6.Hence both perfect square and perfect cube must have

2(0 or 6)—– 2 factors

3(0 or 6) —– 2 factors

5(0)——- 1 factor

11(0 or 6)— 2 factors

Hence total number of such factors are i.e.n(A∩B)=2x2x1x2=8

We are asked to calculate which are either perfect square or perfect cubes i.e.

n(A U B )= n(A) + n(B) – n(A∩B)

=300+72 – 8

=364

Hence required number of factors is 364.