Help please Its about functions

Finding the value of x,

→ 3x - 9 = 3

→ 3x = 3 + 9

→ x = 12/3

→ [ x = 4 ]

Thus, the value of x is 4.

Answer:

no he doesnt brush his teeth

Step-by-step explanation:

Answer:

the answer to your questions is 90%

this is best solved using algebra

let the width be 4x (since it is 4 times more the length)

let the length be x

the formula for perimeter is (l+b)2 let us sub these variables in our formula

(x + 4x)2 = 64

expand brackets

2x + 8x = 64

combine like terms

10x = 64

make x the subject

x = 64/10 = 6.4

the length is 6.4 m

now let's find the width, the width is 4 times more the length so we simply substitute our value we found for x in 4x

we get:

4(6.4) = 25.6

the length is 25.6m

let's check our answers to see if its correct

25.6 + 6.4 = 32

32 × 2 = 64

the answer is correct

Answer:

Step-by-step explanation:

The area A of a rectangle is given by the formula, A=lw , where l is the length and w is the width.

so

8 * 15 = 120sq. units

The two positive numbers whose product is 300 and such that the sum of the first and four times the second is a minimum are 7.66 and 39.16

Let the two variables be x and y

If the product of the numbers is 300, hence

xy = 300

x = 300/y ........ 1

If the sum of the first and four times the second is a minimum, then;

P(x, y) = x + 4y .................. 2

Substitute equation 1 into equation 2:

P(x, y) = x + 4y

P(y) = 300/y + 4y

If this function is at mimimum, hence dP/dy = 0

dP/dy = -300/y² + 4 = 0

-300/y² + 4 = 0

-300 + 4y² = 0

4y² = 300

y² = 300/4

y²=   75

y = 7.66

Since xy = 300

x = 300/7.66

x = 39.16

Hence the two positive numbers whose product is 300 and such that the sum of the first and four times the second is a minimum are 7.66 and 39.16

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Answer:

Option D

Step-by-step explanation:

It is a right triangle because AB ⊥ BC

Answer:

ABC

Step-by-step explanation:

Answer:

Print it

Step-by-step explanation:

Answer:

The answer to " How much is a pen or pencil at the school store?" is $0.5

Step-by-step explanation:

3+5=8

-1.00 for erasers

total cost now =4

4/8= $0.5

total cost of everthing =5

Answer:

61 + 8 is 69 and that is a funny number

Answer: if i get this correct mark me the brainlist promise

Step-by-step explanation:6+x=12To evaluate an algebraic expression, you have to substitute a number for each variable and perform the arithmetic operations. In the example above, the variable x is equal to 6 since 6 + 6 = 12.

Example

Calculate the following expression for x=3 and z=2

6z+4x=?

Solution: Replace x with 3 and z with 2 to evaluate the expression.

6z+4x=?

6⋅2+4⋅3=?

12+12=24

Answer:

Step-by-step explanation:

(a+ b) ² = a² + b² + 2ab

Answer:

x<3

Step-by-step explanation:

22-6x > 4

solve like a regular equation for x

subtract 22 on both sides

-6x>-18

divide -6

x>3

and since 6 is negative you switch the sign

so

x<3

Answer:

-14k+17

Step-by-step explanation:

Answer:

[tex]\frac{3}{8}[/tex] ( d + 2)

Step-by-step explanation:

[tex]\frac{3}{8}[/tex] d + [tex]\frac{3}{4}[/tex]

= [tex]\frac{3}{8}[/tex] d + [tex]\frac{6}{8}[/tex] ← factor out [tex]\frac{3}{8}[/tex] from each term

= [tex]\frac{3}{8}[/tex] (d + 2) ← in factored form

The number of unique ways is given by the number of possible

combination having distinct members.

The number of unique ways there are to arrange 4 of the 6 swimmers are 15 ways.

Reasons:

The given parameters are;

The number of swimmers available = 6 swimmers

The number of swimmers the coach must select = 4 swimmers

Required:

The number of unique ways to arrange 4 of the 6 swimmers.

Solution:

The number of possible combination of swimmers is given as follows;

[tex]_4C_6 = \dfrac{6!}{4! \times (6 - 4)!} = 15[/tex]

Therefore, the coach can select 4 of the 6 available swimmers in 15 unique ways

Learn more here:

https://brainly.com/question/23589217

Answer:

360

Step-by-step explanation:

6!/(6-4)!

Answer:

m-4

Step-by-step explanation:

4 marbles taken away = -4 marbles

Answer:

-8

Step-by-step explanation:

u just do the 2x8 first

Hi! So in equations similar to this, you will need to use PEMDAS.

P - Parenthesis

E - Exponents

M - Multiplication

D - Division

A - Addition

S - Subtraction

Now that you know this, reevaluate your equation.

7-2x8+1

Firstly, you must multiply -2 and 8. Leaving you with -16.

7-16+1

Next, subtract 16 from 7.

-9 + 1

Finally, add -9 and 1.

-8

Your final answer is -8.

Answer: -4, -3, 0, 2

Step-by-step explanation:

Answer:

-4,-3,0,2

Step-by-step explanation:

Decimals that are higher is the less than the smallest

Answer:  35 miles, but this is not an answer option.

Step-by-step explanation:

A   X   B       C

AC = 41 miles

BC = 2AB + 2  

AX = 6

AX + XC = 41        [This is the key equation.  We want XC and AX is given as 6]

6 + XC = 41          

XC = 35 miles

None of the answer options show this value.

I don't know why, since:

a.  "the distance from A to C is 41 miles." means AC = 41, and

b.  "Town X is between A and B, 6 miles from A" means AX = 6

If we say that AX + XC = 41, then 6 + XC = 41 and XC = 35

I don't know why this would be incorrect, so I'll leave it to someone else to spot the problem.

Step-by-step explanation:

the radius is diameter divided by 2

7/2/2 =1 .75

circumference of a circle is 2πr

2*22/7*1.75=11

3.14*11 =34.54

Answer:

i think 36???

Step-by-step explanation:

3 x 2 is 6 and 6 x 6 is 36

Im going to be honest, I don't know what I'm doing

Check the picture below.

[tex]\\\text{Given that,}\\\\(x_1 , y_1) = (5,6) ,~~ (x_2, y_2) = (-5,-4)\\\\\text{Slope},~m = \dfrac{y_2 - y_1}{x_2 - x_1} = \dfrac{-4-6}{-5-5} = \dfrac{-10}{-10} = 1[/tex]

REFER THE PICTURE FOR YOUR ANSWER !!

Whats 1/2 + 8/11

___________________

= 1/2 + 8/11

= (1 × 11)/(2 × 11) + (8 × 2)/(11 × 2)

= 11/22 + (8 × 2)/(11 × 2)

= 11/22 + 16/22

= (11 + 16)/22

= 27/22

= 1 5/22 ☑️

Answer:

∠AFB is adjacent

Answer:

[tex] \large\color{red}{ \tt{36n⁸}}[/tex]

Step-by-step explanation:

[tex] \large\color{lime}{ \tt{(3n×2n³)²}}[/tex]

[tex] \large\color{lime}{ \tt{(3n⁴ × 2)²}}[/tex]

[tex] \large\color{lime}{ \tt{(6n⁴)²}}[/tex]

[tex] \large\color{lime}{ \tt{6²(n⁴)²}}[/tex]

[tex] \large\color{lime}{ \tt{6²n⁸}}[/tex]

[tex] \large\color{lime}{ \tt{36n⁸}}[/tex]

Hope It's Help