Help pleaseeeee thanks

Answer:

emm who exactly is chipo bcause i literally have no idea

Answer:

Yeah its B or 99

Step-by-step explanation:

This problem is easy to solve even without a calculator. Simply 10 times 10 would be 100 (since its asking for square root) and the closest number to 100 would be 99 and the square root of 99 is around 9.94.

Answer:

105.6

hope this helps

have a good day :)

Step-by-step explanation:

Step-by-step explanation:

angle ABE=angle EBC

Answer:

[tex]x=73[/tex]

Answer:

You need to show the statements or I can't help.

Answer:

(17/12)π radians

Step-by-step explanation:

π radians = 180º

255 * (π/180) = (17/12)π

Answer:

1.(a) 25.3

(b) 3.49

(c) 14.44

2.(a) 86.64

(b) 59.85

(c) 27.92

3. 5.92

4.(a) 13.96

(b) 43.32

(c) 101.12

5.(a) 59.85

(b) 10.47

(c) 50.6

6. 5.56

Answer:

m=4

2y/2=y

8x/2=4x

4/2=2

so

y=4x+4

Answer: 3 pounds

Step-by-step explanation: 12 - 4.50 = 7.50 7.50/2.50=3

Answer:

N=115

Step-by-step explanation:

n=.25(2.5715/.12)^2 =114.8 so round up to 115. Hope that help you

m<1=130°[alternate angle are equal again]

m<1+m<2180°[linear pair]

m<2=180°-130°

====================================

If you have any questions feel free to ask me^^

Have a nice and great day!

#PilipinasAngBayanKo

Answer:

hello there! I am mizuki, and I'll be helping you with this problem.

Mean is the average in numbers by the way!

Anyways, the answer is about 14.3

or...

14 1/3

Step-by-step explanation:

14 + 12 + 17 = 43

43 ÷ 3 = 14.333333...

Answer:

C = 19.9 ft

Step-by-step explanation:

Your question isn't properly constructed. However, I'll attempt in providing a possible way of finding one of the sides of a given triangle.

Generally, the Pythagorean theorem is used to find the side of a triangle when two of its sides are known or provided.

Assuming the following data;

Let the length of sides of the triangle be;

Opposite side = a = 15 ft

Adjacent side = b = 13 ft

Hypotenuse side = c

From Pythagorean theorem;

Mathematically, Pythagorean theorem is given by the formula;

C² = a² + b²

C² = 15² + 13²

C² = 225 + 169

C² = 394

Taking the square root of both sides, we have;

C = √394

C = 19.9 ft

Answer:

B

Step-by-step explanation:

that's how exponential functions are shaped

Answer:

180

Step-by-step explanation:

volume= (6*5)/2*12 =180 in

Answer:

A) John

Answer:

john

Step-by-step explanation:

Answer:

[tex]P(81)=56.16[/tex]

Step-by-step explanation:

From the question we are told that:

Mean [tex]\mu=50[/tex]

Standard Deviation [tex]\sigma=7[/tex]

Percentile 81st

Generally Probability of 81st Percentile

 [tex]P(Z<x)=81\%[/tex]

Using Standard normal Table

 [tex]P(Z<0.88)=81\%[/tex]

Therefore the 81st percentile is given as

 [tex]P(81)=z*\sigma *\mu[/tex]

 [tex]P(81)=0.88*7*50[/tex]

 [tex]P(81)=56.16[/tex]

Answer:

The 85% confidence interval for the mean number of toys purchased each year is (6.7, 6.9).

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.85}{2} = 0.075[/tex]

Now, we have to find z in the Ztable as such z has a pvalue of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.075 = 0.925[/tex], so Z = 1.44.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

[tex]M = 1.44\frac{2.1}{\sqrt{686}} = 0.1[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is 6.8 - 0.1 = 6.7

The upper end of the interval is the sample mean added to M. So it is 6.8 + 0.1 = 6.9

The 85% confidence interval for the mean number of toys purchased each year is (6.7, 6.9).

Answer:

7.3

Step-by-step explanation:

Biggest value = 8.9

smallest value = 1.6

range = 8.9-1.6 = 7.3

Step-by-step explanation:

range=highest number - lowest number

= 8.9 - 1.6

=7.3

Answer:

17

Step-by-step explanation:

Use the distance formula to determine the distance between the two points.

[tex]d = \sqrt{(x_{2} -x_{1})^{2} + (y_{2} - x_{1})^{2} }[/tex]

d = distance

[tex](x_{1}, y_{1})[/tex] = coordinates of the first point

[tex](x_{2}, y_{2})[/tex] = coordinates of the second point

Answer: The distance between the points (6,-7)(-2,8) is 17.

Step-by-step explanation:

To calculate the distance between two points, we apply the following formula:

[tex]\boldsymbol{\sf{d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2 } }}[/tex]

The points are:

We substitute in the formula and solve:

[tex]\boldsymbol{\sf{d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2 } }}\\ \\ \boldsymbol{\sf{d=\sqrt{(-2-6)^2+(8-(-7))^2 } }}\\ \\ \boldsymbol{\sf{d=\sqrt{(-8)^2+15^2}=\sqrt{64+225 } }}\\ \\ \boldsymbol{\sf{d=\sqrt{289}=17 }}[/tex]

The distance between the points (6,-7)(-2,8) is 17.

Answer:

Root of 65

Step-by-step explanation:

8^2 is equal to 64, so the sqrt of 64 would equal 8 exactly. The question is asking for which of the sqrts would be closest to 8, so sqrt of 65 is the number that is closest to 64, so it is the answer.

Answer:

[tex] \sqrt{65} [/tex]

as

[tex] \sqrt{64} = 8[/tex]

so it's the closest value to 8

and also

[tex] \sqrt{65} = 8.06[/tex]

via calculator

Step-by-step explanation:

DAG = DG

120=120°

DHG + DG =360°

DHG +120° =360°

DHG+120°-120°=360°-120°

DHG°=240°

Answer:

[tex]x=19.67[/tex]cm

Step-by-step explanation:

Por Pitágoras,

[tex]x^{2} = 26^{2} - 17^{2} \\\\x^{2} = 676 - 289\\\\x^{2} =387\\\\x=\sqrt{387} \\\\x=19.67[/tex]

Answer:

[tex]area = \frac{1}{2} \times 11 \times 18 \\ = 99 \: {ft}^{2} [/tex]

Answer:

Rhoda, whose ACT has a z-score of 1, scored in the 84th percentile in the ACT, compared to Bill, whose SAT has a z-score of -2, who scored in the 2nd percentile on the SAT. Due to the higher percentile(higher z-score)  on her test, Rhoda did better on her respective test than Bill, and thus, his logic is wrong.

Step-by-step explanation:

Z-score:

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Bill:

Scored 300, so [tex]X = 300[/tex]

SAT has a μ of 500 and a σ of 100.

His z-score is:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{300 - 500}{100}[/tex]

[tex]Z = -2[/tex]

[tex]Z = -2[/tex] has a p-value of 0.02.

This means that Bill, whose SAT score has Z = -2, scored in the 2nd percentile.

Rhoda

Scored 25, so [tex]X = 25[/tex].

ACT has a μ of 20 and a σ of 5

Her z-score:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{25 - 20}{5}[/tex]

[tex]Z = 1[/tex]

[tex]Z = 1[/tex] has a p-value of 0.84

This means that Rhoda, whose ACT score has Z = 1, scored in the 84th percentile.

What is wrong with Bill’s logic ?

Rhoda, whose ACT has a z-score of 1, scored in the 84th percentile in the ACT, compared to Bill, whose SAT has a z-score of -2, who scored in the 2nd percentile on the SAT. Due to the higher percentile(higher z-score)  on her test, Rhoda did better on her respective test than Bill, and thus, his logic is wrong.

Answer:

a = 32,37

b=99

Step-by-step explanation:

a = 32,369

The third decimal place is greater (or equal) than 5, so we need to add one unit to the second place.

= 32,37

b = 99,004

The third decimal place is lesser than 5, so we can simply delete it.

= 99,00

Since only zero in every decimal places are not relevant, we can remove them:

= 99

Answer:

[tex]A + B + E = 32[/tex]

Step-by-step explanation:

Given

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{1}{64}e^{-4x}[Ax^2 + Bx + E]C[/tex]

Required

Find [tex]A +B + E[/tex]

We have:

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{1}{64}e^{-4x}[Ax^2 + Bx + E]C[/tex]

Using integration by parts

[tex]\int {u} \, dv = uv - \int vdu[/tex]

Where

[tex]u = x^2[/tex] and [tex]dv = e^{-4x}dx[/tex]

Solve for du (differentiate u)

[tex]du = 2x\ dx[/tex]

Solve for v (integrate dv)

[tex]v = -\frac{1}{4}e^{-4x}[/tex]

So, we have:

[tex]\int {u} \, dv = uv - \int vdu[/tex]

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = x^2 *-\frac{1}{4}e^{-4x} - \int -\frac{1}{4}e^{-4x} 2xdx[/tex]

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} - \int -\frac{1}{2}e^{-4x} xdx[/tex]

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} +\frac{1}{2} \int xe^{-4x} dx[/tex]

-----------------------------------------------------------------------

Solving

[tex]\int xe^{-4x} dx[/tex]

Integration by parts

[tex]u = x[/tex] ---- [tex]du = dx[/tex]

[tex]dv = e^{-4x}dx[/tex] ---------- [tex]v = -\frac{1}{4}e^{-4x}[/tex]

So:

[tex]\int xe^{-4x} dx = -\frac{x}{4}e^{-4x} - \int -\frac{1}{4}e^{-4x}\ dx[/tex]

[tex]\int xe^{-4x} dx = -\frac{x}{4}e^{-4x} + \int e^{-4x}\ dx[/tex]

[tex]\int xe^{-4x} dx = -\frac{x}{4}e^{-4x} -\frac{1}{4}e^{-4x}[/tex]

So, we have:

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} +\frac{1}{2} \int xe^{-4x} dx[/tex]

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} +\frac{1}{2} [ -\frac{x}{4}e^{-4x} -\frac{1}{4}e^{-4x}][/tex]

Open bracket

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} -\frac{x}{8}e^{-4x} -\frac{1}{8}e^{-4x}[/tex]

Factor out [tex]e^{-4x}[/tex]

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = [-\frac{x^2}{4} -\frac{x}{8} -\frac{1}{8}]e^{-4x}[/tex]

Rewrite as:

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = [-\frac{1}{4}x^2 -\frac{1}{8}x -\frac{1}{8}]e^{-4x}[/tex]

Recall that:

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{1}{64}e^{-4x}[Ax^2 + Bx + E]C[/tex]

[tex]\int\limits {x^2\cdot e^{-4x}} \, dx = [-\frac{1}{64}Ax^2 -\frac{1}{64} Bx -\frac{1}{64} E]Ce^{-4x}[/tex]

By comparison:

[tex]-\frac{1}{4}x^2 = -\frac{1}{64}Ax^2[/tex]

[tex]-\frac{1}{8}x = -\frac{1}{64}Bx[/tex]

[tex]-\frac{1}{8} = -\frac{1}{64}E[/tex]

Solve A, B and C

[tex]-\frac{1}{4}x^2 = -\frac{1}{64}Ax^2[/tex]

Divide by [tex]-x^2[/tex]

[tex]\frac{1}{4} = \frac{1}{64}A[/tex]

Multiply by 64

[tex]64 * \frac{1}{4} = A[/tex]

[tex]A =16[/tex]

[tex]-\frac{1}{8}x = -\frac{1}{64}Bx[/tex]

Divide by [tex]-x[/tex]

[tex]\frac{1}{8} = \frac{1}{64}B[/tex]

Multiply by 64

[tex]64 * \frac{1}{8} = \frac{1}{64}B*64[/tex]

[tex]B = 8[/tex]

[tex]-\frac{1}{8} = -\frac{1}{64}E[/tex]

Multiply by -64

[tex]-64 * -\frac{1}{8} = -\frac{1}{64}E * -64[/tex]

[tex]E = 8[/tex]

So:

[tex]A + B + E = 16 +8+8[/tex]

[tex]A + B + E = 32[/tex]

Answer:

340

Step-by-step explanation:

2(10*8)=160

2(8*5)=80

2(5*10)=100

160+80+100=340