Help pls
Find f '(a).
f(t) = [tex]\frac{2t+4}{t+9}[/tex]

Find f '(a).
f(x) = [tex]\frac{1}{\sqrt{x+1} }[/tex]

Answer:

This shows the step by step process of rhetorical reduction of the question given

Answer:

1

Step-by-step explanation:

1.  One way to do this is converting both into improper fractions.  To do this, multiply the whole number by the denominator and add that to the numerator.

2 3/5 --> 2*5 is 10 --> 10+3 is 13.  --> 13/5

2.  This leaves us with 13/5 - 8/5

3.  Subtract the numerators

13/5 - 8/5 = 5/5

4.  Simplify.  If the numerator is the same number as the denominator, it's a whole number.

5/5 = 1

Answer:

y = -5x + 31

Step-by-step explanation:

To find the equation of a line parallel to the line 5x + y = 5, we first need to rearrange it in slope-intercept form, which is

y = -5x + 5. (We see that the slope of this line is -5)

A line parallel to this line will have the same slope of -5. Now, we need to find the equation of a line that passes through the point (8,-9) with slope -5.

We can use the point-slope form of the line to find the equation. The point-slope form of a line is given by y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope of the line.

Substituting the values we have, we get:

y - (-9) = -5(x - 8)

Simplifying this equation, we get:

y + 9 = -5x + 40

y = -5x + 31

Therefore, the equation of the line parallel to 5x + y = 5 that passes through the point (8, -9) is y = -5x + 31.

Emilio can find that the critical value t* for a 90% confidence level and 11 degrees of freedom is approximately 1.796.

To construct a t interval for the mean lifespan with 90% confidence, Emilio needs to use a t-distribution with n-1 degrees of freedom. The confidence interval for the population is given by:

confidence interval = x ± t × (s·x/√n)

Where x is the sample mean, s·x is the sample standard deviation, n is the sample size, and t is the critical value of the t-distribution.

Since the sample size is n=12, the degrees of freedom for the t-distribution will be (n-1) = 11. To find the critical value t* for a 90% confidence level and 11 degrees of freedom, Emilio can use a t-distribution table or a statistical software.

Using a t-distribution table or calculator, Emilio can find that the critical value t* for a 90% confidence level and 11 degrees of freedom is approximately 1.796.

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The sales tax on 250 dollars purchase is: $3865

We are told that sales tax is directly proportional to retail price. Thus:

S ∝ p

Any item that sells for 158 dollars has a sales tax of 10.22 dollars. Thus:

158 = 10.22k

where k is constant of proportionality

Thus:

k = 158/10.22

k = 15.46

Thus, the equation is:

S = 15.46p

Sales tax on 250 dollars purchase is:

S = 15.46 * 250

S = $3865

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Betty consumed a total of 148.294 milliliters of liquid with her breakfast.

We can change the volumes of the coffee and orange juice to milliliters so that all of the measurements are in the same unit:

4 ounces =  4 * 29.5735, = 118.294 ml.

8 ounces = 8 x 29.5735, = 236.588 ml.

Half of Betty's 4-ounce glass of orange juice, or:

1/2 * 118.294 mls = 59.147 mls

She consumed 25% of her 8-ounce coffee, which is :

0.25 * 236.588 mls = 59.147 mls.

So, in total, Betty consumed:

30 mls of cough medicine + 59.147 mls of orange juice + 59.147 mls of coffee = 148.294 mls

Therefore, Betty consumed a total of 148.294 milliliters of liquid with her breakfast.

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Answer: No.

Step-by-step explanation:

The graph doesn't represent a linear, exponential, or quadratic function.

An example of a linear function is a straight line.

An example of a quadratic function is like a smile.

An example of an exponential function is a curved line.

So hence, this doesn't represent a function.

Reply below if you have any questions of concerns.

You're welcome!

- Nerdworm

The scatter plot that has a pattern that is best fit by y = x^2 has a property that displays a nonlinear pattern

From the question, we have the following parameters that can be used in our computation:

Equation of the best fit of the scatter plot: y = x^2

As a general rule

Any equation that has a degree other than 1 is a non linear equation

This means that the property it displays is a nonlinear pattern

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The 95% confidence interval of the mean pulse rate for adult females is 68.2 bpm < μ < 76.4 bpm

For a 95% confidence interval, the Z-score is 1.96. Plugging in the values we have for the sample mean, sample standard deviation, and sample size, we get:

Confidence interval = 75.8 ± (1.96 × (3.7 / √50))

Simplifying the expression, we get:

Confidence interval = 71.5 bpm < μ < 80.2 bpm

This means that we can be 95% confident that the true population mean pulse rate for adult females falls within this range.

Now let's construct a confidence interval for adult males. We are given that the sample mean pulse rate for adult males is 72.3 bpm, and the sample standard deviation is 4.0 bpm. Using the same formula and Z-score as before, we can calculate the confidence interval as follows:

Confidence interval = 72.3 ± (1.96 × (4.0 / √50))

Simplifying the expression, we get:

Confidence interval = 68.2 bpm < μ < 76.4 bpm

This means that we can be 95% confident that the true population mean pulse rate for adult males falls within this range.

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Only 17 is a solution of the equation 3q = 51 among the values in the set {15, 16, 17}.

To check if a value is a solution of the equation 3q = 51, we substitute the value for q and check if the equation is true.

Let's check each value in the set {15, 16, 17}:

For q = 15, 3q = 3(15) = 45, which is not equal to 51. Therefore, 15 is not a solution of the equation 3q = 51.

For q = 16, 3q = 3(16) = 48, which is not equal to 51. Therefore, 16 is not a solution of the equation 3q = 51.

For q = 17, 3q = 3(17) = 51, which is equal to 51. Therefore, 17 is a solution of the equation 3q = 51.

Therefore, only 17 is a solution of the equation 3q = 51 among the values in the set {15, 16, 17}.

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It can be seen that if the circumference were smaller, the area would decrease, as it is proportional to the square of the radius.

Given the circumference (C) of the hub cap as 83.90 cm, we can find the radius (r) using the formula C = 2 * π * r,

where π = 3.14.

Thus, r ≈ 13.363 cm.

To find the area (A), use the formula A = π * r^2, yielding A ≈ 560.509 cm². Rounded, the area is about 561 cm².

Therefore, it can be seen that if the circumference were smaller, the area would decrease, as it is proportional to the square of the radius.

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The value of t= -1.946; p = 0.029; Reject the null hypothesis; there is strong evidence to suggest that the highlighters last less than 14 hours.

To test the hypothesis that the highlighters last less than 14 hours, we will use a one-sample t-test. The null hypothesis for this test is that the mean continuous writing time for the highlighters is equal to or greater than 14 hours. The alternative hypothesis is that the mean continuous writing time for the highlighters is less than 14 hours.

In this problem, we are given that x = 13.6 hours and s = 1.3 hours. The sample size is n = 40. Substituting these values into the formula for the test statistic, we get:

t = (13.6 - 14) / (1.3 / √(40)) = -1.946

The p-value for the test can be found using a t-distribution table or a statistical software program. The p-value is the probability of observing a t-value as extreme as the one we calculated, assuming the null hypothesis is true. In this problem, the p-value is 0.029.

To make a decision about the null hypothesis, we compare the p-value to the significance level, which is typically set at 0.05. If the p-value is less than the significance level, we reject the null hypothesis. If the p-value is greater than the significance level, we fail to reject the null hypothesis.

In this problem, the p-value is less than 0.05, so we reject the null hypothesis. This means there is strong evidence to suggest that the highlighters last less than 14 hours. We can conclude that the manufacturer's claim that their highlighters can write continuously for 14 hours is not supported by the sample data.

Hence the correct option is (c).

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Complete Question:

Solve the problem. Suppose a consumer product researcher wanted to find out whether a highlighter lasted less than the manufacturer's claim that their highlighters could write continuously for 14 hours. The researcher tested 40 highlighters and recorded the number of continuous hours each highlighter wrote before drying up. Test the hypothesis that the highlighters wrote for less than 14 continuous hours. Following are the summary statistics:

x =13.6 hours,

s =1.3 hours

Report the test statistic, p-value, your decision regarding the null hypothesis, and your conclusion about the original claim. Round all values to the nearest thousandth.

a)  z = 1.946; p = 0.029; Reject the null hypothesis; there is strong evidence to suggest that the highlighters last less than 14 hours.

b) t = -1.946; p = 0.029; Fail to reject the null hypothesis; there is not strong evidence to suggest that the highlighters last less than 14 hours. o

c)  t= -1.946; p = 0.029; Reject the null hypothesis; there is strong evidence to suggest that the highlighters last less than 14 hours.

d) z = 1.946; p = 0.974; Fail to reject the null hypothesis; there is not “strong evidence to suggest that the highlighters last less than 14 hours.

Answer:

196

Step-by-step explanation:

There are 7 choices for the first spot.

4 choices for the second spot. And 7 choices for the third spot, which cannot be 6,7,8--so it can be 0,1,2,3,4,5 or 9 (7choices)

7 × 4 × 7 is 196

There are 196 possibilities for the three digit area code with this plan.

Answer:

Step-by-step explanation:

To find the number of seconds it will take for the planes to be at the same altitude, we need to set the altitude equations for both planes equal to each other and solve for time:

2639 + 35.25t = h    (altitude equation for Plane A)

0 + 80.75t = h       (altitude equation for Plane B)

where h is the altitude of both planes when they are at the same altitude, and t is the number of seconds that have passed.

Setting the two equations equal to each other and solving for t, we get:

2639 + 35.25t = 80.75t

45.5t = 2639

t = 58

Therefore, it will take 58 seconds for the planes to be at the same altitude.

To find their altitude at that time, we can substitute t = 58 into either of the altitude equations and solve for h:

2639 + 35.25t = h

2639 + 35.25(58) = h

h = 4818.5

Therefore, when the planes are at the same altitude, their altitude will be approximately 4818.5 feet.

Answer:

----------------------

If the system of linear equations has infinitely many solutions, it means the two lines overlap.

In other words, each point of one of the lines also belongs to the second line.

Choices a, b, c  give us one or no solutions and therefore not the answer.

Choice d is reflecting the infinitely many solutions and hence is the correct one.

The equation represents the line of best fit is y = -2x + 22.

A mathematical statement that represents a relationship between two or more quantities is typically expressed using symbols, numbers, and mathematical operations. Equations are used to express mathematical relationships, make predictions, and solve problems. An equation typically consists of an expression on each side of an equal sign (=), indicating that the values on both sides are equivalent.

According to the given information:

To determine the equation of the line of best fit in the scatter plot, we can use the slope-intercept form of a linear equation, which is given by:

y = mx + b

where m is the slope and b is the y-intercept.

Given that the line of best fit goes through points (5, 12) and (9, 4), we can calculate the slope (m) using the formula:

m = [tex]\frac{(y_{2}-y_{1})}{(x_{2}-x_{1} ) }[/tex]

Plugging in the values from the given points, we get:

m = [tex]\frac{(4-12)}{(9-5)}[/tex]

m = -8 / 4

m = -2

So, the slope of the line of best fit is -2.

Next, we can substitute the slope and one of the given points (5, 12) into the slope-intercept form to solve for the y-intercept (b):

12 = -2(5) + b

12 = -10 + b

b = 12 + 10

b = 22

So, the y-intercept of the line of best fit is 22.

Thus, the equation of the line of best fit is:

y = -2x + 22.

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Answer:

Step-by-step explanation:

You want the lists of ordered pairs that represent a functional relation.

A function maps an input value to exactly one output value. A set of ordered pairs will represent a function if no input (x-value) is repeated.

We only need to look at the first values of the ordered pairs.

  (a) 2 is repeated

  (b) -4 is repeated

  (c) a function

  (d) 7 is repeated

  (e) a function

Answer:

Step-by-step explanation:

You want the lists of ordered pairs that represent a functional relation.

A function maps an input value to exactly one output value. A set of ordered pairs will represent a function if no input (x-value) is repeated.

We only need to look at the first values of the ordered pairs.

  (a) 2 is repeated

  (b) -4 is repeated

  (c) a function

  (d) 7 is repeated

  (e) a function

The total area of the given figure is 525 cm² respectively.

The area is the entire amount of space occupied by a flat (2-D) surface or an object's shape.

The area of a plane figure is the area that its perimeter encloses.

The quantity of unit squares that cover a closed figure's surface is its area.

So, first, we will divide the figure into 2 parts which will be the triangle and the rectangle, and then add their area to get the total area as follows:

Triangle:

1/2 * b * h

1/2 * 15 * 20

15 * 10

150 cm²

Rectangle:

l*b

15*25

375 cm²

The total area of the figure: 375 + 150 = 525 cm²

Therefore, the total area of the given figure is 525 cm² respectively.

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The actual speed (along the road) of the red car is 8.37 feet per second

Let's call the distance between the police car and the red car "x" at time t. Then, we know that:

x^2 = 40^2 + (140 - vt)^2

Where

We are given that dx/dt (the rate at which x is decreasing) is -85 ft/s, so:

d/dt [x^2] = d/dt [40^2 + (140 - vt)^2]

2x(dx/dt) = 0 - 2v(140 - vt)

Substituting dx/dt = -85 and solving for v, we get:

2x(−85) = −2v(140−vt)

−170x = −280v + 2v^2t

v^2t = 140v - (85/2)x

Now, we can differentiate the equation x^2 = 40^2 + (140 - vt)^2 with respect to time to get:

2x(dx/dt) = 2(140 - vt)(-v)

Substituting dx/dt = -85 and solving for x, we get:

-170x = -2v(140 - vt)

x = (140v - vt^2)/85

Substituting this expression for x into the equation we derived earlier, we get:

v^2t = 140v - (85/2)((140v - vt^2)/85)

v^2t = 140v - 70(2v - t^2)

v^2t = 140v - 140v + 70t^2

v^2t = 70t^2

v = sqrt(70t^2)/t = sqrt(70) = 8.37 ft/s (rounded to two decimal places)

Therefore, the actual speed (along the road) of the red car is 8.37 feet per second

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The length of the shadow would be approximately 41.7 feet if the angle of elevation from the horizontal to the sun is 38° at this time.

If the angle of elevation from the horizontal to the sun is 38°, then the tangent of that angle is equal to the opposite side (the height of the tree) divided by the adjacent side (the length of the shadow).

Therefore, we can set up the equation using trigonometric function tangent as,
tan(38°) = height of tree / length of shadow

Solving for the length of the shadow, we get:
length of shadow = height of tree / tan(38°)

Plugging in the given height of the tree (32 feet) and using a calculator to find the tangent of 38°, we get:
length of shadow = 32 / tan(38°) = 41.7 feet (rounded to one decimal place)

Therefore, the length of the shadow would be approximately 41.7 feet at this time.

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The solution equates to f(x) = 6x + 8.

Reiterating the same statement without reiteration, it is observed that f'(x) equals ƒ""(x), ultimately resulting in a value of 6. Subsequently, we can derive a complete expression for f(x) where C represents an integration constant.

It should be noted that to find this constant, since f(-1) = 2, plugging in x as -1 and f(x) as 2 into the above equation results in:

2 = 6(-1) + C

C = 8

As such, we can confirm that the entire expression of f(x) is simply 6 times x added to 8. Validating this answer, when assessing f(0) or f(1) , either result should match the given values from our initial problem which they do. Hence, the solution equates to:

f(x) = 6x + 8.

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The intercepts of the equation are: D. D. x-intercept (-7/4, 0), y-intercept (0,7).

The x-intercept of an equation is simply the value of x when the corresponding value of y equals zero. Also, this is where the line of the equation cuts across the x-axis on a graph.

The y-intercept of an equation, on the other hand, is the value of y when the corresponding value of x equals zero. It is the point where the line of the equation cuts across the y-axis on a graph.

Thus, given the equation y = 4x + 7, the y-intercept is:

y = 4(0) + 7

y = 7

The x-intercept is:

0 = 4x + 7

-4x = 7

x = 7/-4

x = -7/4

The correct option is: D. x-intercept (-7/4, 0), y-intercept (0,7).

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The value of x is 18.4 and the value of y is 22.5 in the cube

From the question, we have the following parameters that can be used in our computation:

The diagram of a cube.

Each edge of the cube = 13 units.

The diagonal of each face is x units long

So, we have

x^2 = 13^2 + 13^2

Evaluate

x = 18.4

The diagonal of the cube is y units long.

So, we have

y^2 = 13^2 + 13^2 + 13^2

Evaluate

y = 22.5

Hence, the value of x is 18.4 and the value of y is 22.5

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Answer:

To convert kilometers per hour to miles per hour, we need to multiply by 0.62. Therefore, to find the maximum speed that Hannah can drive without exceeding the speed limit of 130 kilometers per hour, we can multiply 130 by 0.62:

130 km/h * 0.62 = 80.6 mph

Since Hannah needs to stay within the speed limit, the maximum whole-number speed she can drive is 80 mph, which is option D.

Step-by-step explanation:

Upper Critical Value; 1.645

p-Value; 0.0814

Reject the null hypothesis

a).

claim: A. The mean breaking distance is different for the two makes of automobiles

H0 and Ha.: E

[tex]\ H_0: \mu_1 = \mu_2 \ \ \ H_a: \mu_1 \neq \mu_2[/tex]

b).

critical values are (-1.645, 1.645)

Rejection region: E. z < -1.645 , z >1.645

c)

test statistic z= -1.743

d).

C. Reject H0. The stat statistic falls in the rejection region.

e).

At the 10% significance level, there is sufficient evidence to support the claim that means breaking distance of make A is different from mean breaking distance of making B.

m 2

M1

7t

Z Test for Differences in Two Means

Data

Hypothesized Difference

0

Level of Significance

0.1

Population 1 Sample

Sample Size

35

Sample Mean

42

Population Standard Deviation

4.9

Population 2 Sample

Sample Size

35

Sample Mean

44

Population Standard Deviation

4.7

Intermediate Calculations

Difference in Sample Means

-2

Standard Error of the Difference in Means

1.1477

Z Test Statistic

-1.7427

Two-Tail Test

Lower Critical Value

-1.645

Upper Critical Value

1.645

p-Value

0.0814

Reject the null hypothesis

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the probability that Juan will catch at least 10 passes out of 15 is approximately 0.987.

The binomial distribution, which models the number of successful trials (catches) in a certain number of independent trials (passes thrown), can be used to solve this problem.

The likelihood of not catching a pass is 0.2, but the likelihood of catching one is 0.8. The likelihood of catching at least 10 passes out of 15 can be calculated as follows:

P(X >= 10) equals P(X = 10) plus P(X = 11). + ... + P(X = 15)

where X is how many of the 15 passes were intercepted.

The probability of catching precisely k passes out of n can be calculated using the binomial distribution formula:

P(X = k) = (n choose k) × p²k × (1 - p)²(n-k)

where (n choose k) is the binomial coefficient, which represents the number of ways to choose k items from a set of n distinct items.

Plugging in the values for n = 15, p = 0.8, and k = 10, 11, 12, 13, 14, and 15, we get:

P(X >= 10) = P(X = 10) + P(X = 11) + ... + P(X = 15)

= (15 choose 10) × 0.8²10 × 0.2²5 + (15 choose 11) × 0.8²11 × 0.2²4 + ... + (15 choose 15) × 0.8²15 × 0.2²0

≈ 0.987

Therefore, the probability that Juan will catch at least 10 passes out of 15 is approximately 0.987.

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Answer: 9.32 inches.

Step-by-step explanation: