How do you find range and domain

Answer:

6 y^5 - 8 y^4 - 10 y^3 + 36 y^2 - 28 y

Step-by-step explanation:

Expand the following:

(3 y^3 + 2 y^2 - 7 y) (2 y^2 - 4 y + 4)

| | | | 3 y^3 | + | 2 y^2 | - | 7 y | + | 0

| | | | | | 2 y^2 | - | 4 y | + | 4

| | | | 12 y^3 | + | 8 y^2 | - | 28 y | + | 0

| | -12 y^4 | - | 8 y^3 | + | 28 y^2 | + | 0 | + | 0

6 y^5 | + | 4 y^4 | - | 14 y^3 | + | 0 | + | 0 | + | 0

6 y^5 | - | 8 y^4 | - | 10 y^3 | + | 36 y^2 | - | 28 y | + | 0:

Answer: 6 y^5 - 8 y^4 - 10 y^3 + 36 y^2 - 28 y

Answer:

x=2

Step-by-step explanation:

-14x+28+6x=-44

-8x+28=-44

-8x= -16

x=2

combine like terms

-8x+28 = -44

subtract 28 from both sides

-8x = -72

divide both sides by -8

x = 9

Answer:

d) 1/2 ÷ 4 = 1/2 • 4/1

Step-by-step explanation:

when dividing fractions use keep change flip (keep the first fraction, change the sign to multiplication, flip the second fraction)

when multiplying just multiply straight across

SP of a machine = Rs. 990

Profit% = 10 %

SP of other machine = Rs. 1960

loss% = 2 %

his gain or loss percentage​

We know that,

CP * (100 + profit%)/100 = SP

So,

First machine :

CP * (100 + 10)/100 = 990

⟹ CP = 990 * 100/110

⟹ CP = Rs. 900

Second machine :

We know that,

CP * (100 - loss%)/100 = SP

⟹ CP * (100 - 2)/100 = 1960

⟹ CP = 1960 * 100/98

⟹ CP = Rs. 2000

Now,

We have to find the total loss or profit percentage.

We observe that,

SP > CP.

so, a gain is occured.

gain % = gain/CP * 100

gain = SP - CP

So,

gain% = (2950 - 2900)/2900 * 100

⟹ gain% = 50/29

⟹ gain% = 1.72 %

∴ A gain of 1.72% is occured in the whole transaction.

I hope it will help you.

Regards.

Answer:

HELLO SISO❤

IT'S ME YIREN

Step-by-step explanation:

→ CP of machine = (SP * 100) / (100 + Profit%) = (990 * 100) / (100 + 10) = (990 * 100) / 110 = Rs. 900 . Case 2) :- shopkeeper sells another machine for Rs. 1960 at a loss of 2%

Florence should buy 6 gallons of sealant for 1200 ft² of decking.

A ratio indicates the number of times one number contains another.

Given that, 400 ft² of decking requires 2 gallons of sealant.

400 ft² = 2 gallons

400 ×3 ft² = 2 × 3 gallons

1200 ft² = 6 gallons

Hence, Florence should buy 6 gallons of sealant for 1200 ft² of decking.

To learn more about ratios, click here:

https://brainly.com/question/13419413

#SPJ2

Answer:

If you are multiplying (-45)(158)(73)(-1) your answer is 519,030.

Step-by-step explanation:

9514 1404 393

Answer:

  16 inches

Step-by-step explanation:

The sum of length and width is half the perimeter, so is 36 inches.

The width is 4/(4+5) = 4/9 of the total of length and width, so is ...

  (4/9)(36 inches) = 16 inches

The width of the rectangle is 16 inches.

Answer:

358

Step-by-step explanation:

Answer:

50%

Step-by-step explanation:

Answer:

this isn't a social studies stream

ask the question again but in a social studies thingy

Answer:

Positive discriminant = 2 real solution

x= -5,-40

Step-by-step explanation:

The discriminant is used to see how many solutions an equation has. If it is negative, the equation has no real solutions, if =0 the equation has 1, and if it is positive, the equation has two real solutions.

The discriminant is the part of the quadratic formula inside the square root:

[tex]b^{2}-4ac[/tex]

Every quadratic formula has the structure:

[tex]ax^{2} +bx+c=0[/tex]

So first, in order to meet this structure we need to add 200 to both sides so the equation is equal to 0. This gives us:

[tex]x^{2} +45x+200=0[/tex]

Our a=1, b=45 and c=200

Now we can substitute these values into the discriminant:

[tex](45)^{2} -4(1)(200)[/tex]

Solve:

[tex]2025-800=1225[/tex]

The discriminant is a positive number which means this equation will have 2 real solution. Now we just need to plug in our values into the quadratic formula to solve this equation. Quadratic formula:

[tex]x=\frac{-+/-\sqrt{b^{2}-4ac} }{2a} \\x=\frac{-45+/-\sqrt{1225} }{2}[/tex]

(Same discriminant value)

[tex]x=\frac{-45+/-35}{2}[/tex]

Now to find the two solutions, we use both signs in the equation. Solution 1:

[tex]x=\frac{-45+35}{2}[/tex]

[tex]x=\frac{-10}{2}=-5[/tex]

Our first solution is -5, now for the second:

[tex]x=\frac{-45-35}{2}\\\\ x=\frac{-80}{2}=-40[/tex]

The two solution to this equation are -5 and -40.

Hope this helped!

Answer:

(2x-6)+4(x-3)

2x-6+4x-12

6x-18

6(x-3)

Answer:

yes they are equivalent

Answer:

The bakery sold 340 that day

Step-by-step explanation:

119 is 35 percent of 340

Answer:

2,1

Step-by-step explanation:

Answer: 50%

Step-by-step explanation: math

Answer: x=-3, y=2

Step-by-step explanation: -2x+y=8 + -3x-y=7 and you get x=-3 then you put that in to x and pick one of the beginning equations i chose to put -3 in to -2(-3)+y=8 and got 6+y=8 then you subtract the 6 on both sides and should get y=2

Answer:

(-3,2)

Step-by-step explanation:

You can solve it by various methods. These two equations can be solved simultaneously or by matrix method, or even by graphing

Simultaneous is easier so lets get started.

1st equation  : [tex]-2x+y=8[/tex]

2nd equation: [tex]-3x-y=7[/tex]

We solve it by using the substitution method which means there are two variables x and y and we substitute one variable in form of another variable.

Like, take the 1st equation

[tex]-2x+y=8\\y=8+2x[/tex]

the equation is arranged in a different manner but its the same thing.

This new equation becomes our new third equation and now we simply put our third equation in our 2nd equation. Like this, take the 2nd equation and substitute it with our 3rd third equation

[tex]-3x-y=7\\-3x-7=y\\-3x-7=8+2x\\-3x-2x=8+7\\-5x=15\\x=-3[/tex]

we get x=-3 and then we put the value of x and in our third equation to get the value of y or we can simply put it in any equation 1st , 2nd , 3rd it will give the same answer. I chose third.

[tex]y=8+2x\\y=8+2(-3)\\y=8-6\\y=2[/tex]

The solution set of our system of linear equations is

(-3,2)

Answer:

x=130, x=-77.5, x=1/3

Step-by-step explanation:

1st equation:

1/5x + 24 = 50

1/5x = 26

x = 26(5)

x = 130

2nd equation:

0.4x + 18=-13

0.4x = -31

x=-77.5

3rd equation:

3x - 5/6 = 1/6

3x = 1

x=1/3

Answer:

€20,000

Step-by-step explanation:

% decrease = (original price of the car - new price) ÷ original price × 100

Let "x' represents the original price before the decrease.

New price = €13,000

% decrease = 35%

Plug in the values into the equation

[tex] 35 = \frac{x - 13,000}{x}*100 [/tex]

[tex] 35 = \frac{100x - 1,300,000}{x} [/tex]

Multiply both sides by x

[tex] 35*x = \frac{100x - 1,300,000}{x}*x [/tex]

[tex] 35x = 100x - 1,300,000 [/tex]

Subtract 100x from both sides

[tex] 35x - 100x = 100x - 1,300,000 - 100x [/tex]

[tex] -65x = -1,300,000 [/tex]

Divide both sides by -65

[tex] \frac{-65x}{65} = \frac{-1,300,000}{65} [/tex]

[tex] x = 20,000 [/tex]

The car was worth €20,000 before the decrease.

Answer:

17

Step-by-step explanation:

the answer would have been 16.75 but you cant divide a class, so you round up.

Answer:

Wonka bars=3 and  Everlasting Gobstoppers=24

Step-by-step explanation:

let the wonka bars be X

and everlasting gobstoppers be Y

the objective is to

maximize 1.3x+3.2y=P

subject to constraints

natural sugar

4x+2y=60------1

sucrose

x+3y=75---------2

x>0, y>0

solving 1 and 2 simultaneously we have

4x+2y=60----1

x+3y=75------2

multiply equation 2 by 4 and equation 1 by 1 to eliminate x we have

 4x+2y=60

 4x+12y=300

-0-10y=-240

10y=240

y=240/10

y=24

put y=24 in equation 2 we have'

x+3y=75

x+3(24)=75

x+72=75

x=75-72

x=3

put x=3 and y=24 in the objective function we have

maximize 1.3x+3.2y=P

1.3(3)+3.2(24)=P

3.9+76.8=P

80.7=P

P=$80.9

Answer:

wonka bars=3 and  Everlasting Gobstoppers=24

Step-by-step explanation:

Answer:

125,000

Step-by-step explanation:

Answer:

the answer is 40

Step-by-step explanation:

its simple try and do the link that I put you'll understand how to do this better

Answer:

The rate of the second car is 30 miles/hour

Step-by-step explanation:

The Given formula is:

4(r + 15) + 4r = 300, where r is the rate for the second car

Let us solve the equation to find r

→ Multiply 4 by (r + 15) first

∵ 4(r + 15) = 4(r) + 4(15) = 4r + 60

→ Substitute it in the equation above

∴ 4r + 60 + 4r = 300

→ Add the like terms in the left side

∵ (4r + 4r) + 60 = 300

∴ 8r + 60 = 300

→ Subtract 60 from both sides

∴ 8r + 60 - 60 = 300 - 60

∴ 8r = 240

→ Divide both sides by 8

∴ [tex]\frac{8r}{8}=\frac{240}{8}[/tex]

∴ r = 30

∴ The rate of the second car is 30 miles/hour

Answer:

85% of 19 = 16.15

Step-by-step explanation: