How do you find the endpoint?

Given:

Total number of marbles = 15

Probability of randomly selecting a green marble = [tex]\dfrac{1}{5}[/tex].

Probability of randomly selecting a green marble, replacing it, and then randomly selecting a blue marble = [tex]\dfrac{2}{25}[/tex].

To find:

The number of blue marbles.

Solution:

Let the number of blue marbles be x.

[tex]\text{Probability}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}[/tex]

[tex]P(Blue)=\dfrac{x}{15}[/tex]

It is given that,

[tex]P(Green)=\dfrac{1}{5}[/tex]

Probability of randomly selecting a green marble, replacing it, and then randomly selecting a blue marble is [tex]\dfrac{2}{25}[/tex]. So,

[tex]P(Green)\times P(Blue)=\dfrac{2}{25}[/tex]

[tex]\dfrac{1}{5}\times \dfrac{x}{15}=\dfrac{2}{25}[/tex]

[tex]\dfrac{x}{75}=\dfrac{2}{25}[/tex]

Multiply both sides by 75.

[tex]\dfrac{x}{75}\times 75=\dfrac{2}{25}\times 75[/tex]

[tex]x=2\times 3[/tex]

[tex]x=6[/tex]

Therefore, the number of blue marbles in the bag is 6.

Answer:

Atomic mass unit-

It is represented by ‘amu’. It is equal to the quantity 1/12th mass of an atom of C-12.

Actual mass of one atom of C-12 = 1.9924 x 10-23 gm. = 1.9924 x 10-26 Kg.

1 amu = 1.9924 x 10 -23/12 = 1.66 x 10 -24 gm. = 1.66 x 10 -27 Kg.

Atomic mass of an element = mass of one atom of the element / 1 amu

Actual mass of an element = atomic mass of an element in amu x 1.66 x 10 -24 gm.

For ex-

Actual mass of hydrogen atom = 1.008 x 1.66 x 10 -24 gm. = 1.6736 x 10-24 gm.

Actual mass of oxygen atom = 16.00 x 1.66 x 10 -24 gm. = 2.656 x 10-23 gm.

Average Atomic weight (Mass)-

“The Average Atomic Masses of many elements are determined by multiplying the atomic mass of each isotope by its fractional abundance and adding these values and then dividing it by 100.”

Ex.- Naturally occurring carbon contains three isotopes – C12 (98.892 % abundance), C13 (1.108 % abundance), C14 (2 x 10-10 % abundance).The relative atomic masses of these isotopes are 12.000, 13.00335 and 14.00317 amu respectively.

Average atomic mass = % of I isotope x its atomic mass + % of II isotope x its atomic mass +% of III isotope x its atomic mass/100

= 12 x 98.892 + 13.00335 x 1.108 + 14.00317 x 2 x10-10 /100

Average atomic mass= 12.011 amu

Molar volume –

Molar volume of a substance is volume occupied by 1 mole of that substance .

Molar volume of solid or liquid = molar mass / density

Molar volume of ideal gas at 00C or 273 K and 1 atmosphere pressure is 22.4 litre.

Gram atomic mass(weight) or gram atom –

“Gram atomic mass(weight) of an element is the mass of Avogadro number ( 6.023 x 1023 ) of atoms of that elements in grams.”

Ex –

mass of 1 atom of oxygen = 16 amu = 16 x 1.66 x 10-24 gm

Mass of 6.023 x 1023 atoms of oxygen= 16 x 6.023 x 1023 x 1.66 x 10-24 = 16 gm.

Hence, Gram atomic weight of oxygen = 16 gm.

No. of gram atoms = mass of element in gm / atomic mass of element in gm.

Answer:

C,B,D,A,D

Step-by-step explanation:

Answer:

It was 3

Step-by-step explanation:

This is because its the one clóset to 0

I hope this help you out

Answer:

1. 3 hours

2. i cant figure this one out

Step-by-step explanation:

Answer:

Haha

Step-by-step explanation:

ghgewucjbauierfyucierh kjaluchliaucwa bb

wrgwrgweg

ttrtrtttgb

trbtgrbgttr

bheetbg

etbnhtehg

bertertgetfhjgeyfguiwrehodvqeiir

rgeyshudfvr8ov

Answer:

(3a +6b) (9a² - 18ab + 36b²)

Step-by-step explanation:

27 = 3 * 3 * 3 = 3³

216 = 6 * 6 * 6 = 6³

a³ + b³ = (a + b)(a² - ab + b²)

27a³ + 216b³ = (3a)³ + (6b)³

                      = (3a + 6b)( (3a)² - 3a*6b + (6b)² )

                      = (3a +6b) (9a² - 18ab + 36b²)

Answer:

A) likely

Step-by-step explanation:

It is likely that the toast will land with the honey side facing down. This is because if we find the percentage of chance/probability of the honey side facing down using the data provided it would be the following...

8 / 40 = 0.20 .... times 100 to find percentage value

0.20 * 100 = 20%

We see that there is a 20% that the honey side will land facing down every time that you drop the piece of toast. This means that there is an 80% chance that the honey side will land facing down which is ultimately a high probability and a very likely chance of it happening.

Answer:

It is likely, I got it right on the test.

Step-by-step explanation:

Answer:

67

Step-by-step explanation:

Answer:

3x² - 8x - 3y

Let the smallest angle in a triangle be = x

Largest angle in a triangle = 55 + x

The middle angle in a triangle = 3x ( triple the measure of the smallest angle )

Their sum = 180° ( according to the angle sum property all the angles of a triangle sum up to 180° )

This can be written as :

= x + 55 + × + 3x = 180

Let us find each angle by solving the equation .

= x + 55 + x + 3x = 180°

= x + x + 3x + 55 = 180°

= 5x + 55 = 180°

= 5x = 180 - 55 ( transposing +55 from LHS to RHS changes +55 to -55 )

= 5x = 125

= x = 125 ÷ 5 (transposing ×5 from LHS to RHS changes ×5 to ÷5 )

= x = 25

Using this let us find the measure of each angle .

Smallest angle = x = 25

Smallest angle = 25°

Middle angle = 3x = 3 × 25 = 75

Middle angle = 75°

The largest angle = x + 55 = 25 + 55 = 80

Largest angle = 80°

Therefore , the measure of the smallest angle = 25° , the measure of the middle angle = 75° and the measure of the largest angle = 80° .

We have that the measures of the  angles are as follows

[tex]\theta_1=80 \textdegree[/tex]

[tex]\theta_2=75 \textdegree[/tex]

[tex]\theta_3=25 \textdegree[/tex]

From the question we are told that:

The measure of the middle angle  is triple the measure of the smallest angle

The measure of the largest angle is 55° greater  than the measure of the smallest angle

Let

[tex]\theta_1=Largest\ angle[/tex]

[tex]\theta_2=Middle\ angle[/tex]

[tex]\theta_3=Smallest\ angle[/tex]

Therefore

[tex]\theta_1=55 \textdegree+\theta_3\\\\\theta_2=3*\theta_3[/tex]

Generally, the equation for the angle of a triangle is mathematically given by

[tex]\theta_1+\theta_2+\theta_3=180[/tex]

Therefore

[tex]55 \textdegree+\theta_3+3*\theta_3+\theta_3=180[/tex]

[tex]\theta_3=25 \textdegree[/tex]

Therefore

Substitute [tex]\theta_3[/tex] into equations of [tex]\theta_1[/tex] and [tex]\theta_2[/tex]

For [tex]\theta_1[/tex]

[tex]\theta_1=55 \textdegree+25 \textdegree\\\\\theta_1=80 \textdegree[/tex]

For [tex]\theta_2[/tex]

[tex]\theta_2=3*\theta_3[/tex]

[tex]\theta_2=3*25 \textdegree[/tex]

[tex]\theta_2=75 \textdegree[/tex]

in conclusion

The measures of the  angles are as follows

[tex]\theta_1=80 \textdegree[/tex]

[tex]\theta_2=75 \textdegree[/tex]

[tex]\theta_3=25 \textdegree[/tex]

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Given:

[tex]\left(12x^5+Rx^4+Px^2-5\right)+\left(-6x^5-4x^4+13x+Q\right)=6x^5+3x^4+9x^2+13x+7[/tex]

To find:

The values of R, P and Q.

Solution:

We have,

[tex]\left(12x^5+Rx^4+Px^2-5\right)+\left(-6x^5-4x^4+13x+Q\right)=6x^5+3x^4+9x^2+13x+7[/tex]

On combining like terms, we get

[tex](12x^5-6x^5)+(Rx^4-4x^4)+Px^2+13x+(Q-5)=6x^5+3x^4+9x^2+13x+7 [/tex]

[tex]6x^5+(R-4)x^4+Px^2+13x+(Q-5)=6x^5+3x^4+9x^2+13x+7 [/tex]

On comparing the coefficients of [tex]x^4[/tex], we get

[tex]R-4=3[/tex]

[tex]R=3+4[/tex]

[tex]R=7[/tex]

On comparing the coefficients of [tex]x^2[/tex], we get

[tex]P=9[/tex]

on comparing the constants, we get

[tex]Q-5=7[/tex]

[tex]Q=7+5[/tex]

[tex]Q=12[/tex]

Therefore, [tex]R=7,P=9[/tex] and [tex]Q=12[/tex].

Answer:

Step-by-step explanation:

Since the expression for the amount of gas in the tank is given as

g = 5t + 4

we already know that g=14 which is the capacity of the tank

so let us put g=14 we have

14=5t+4

solving for t, which is the time taken to fill up the tank that already has 4 gal already we have

14=5t+4

14-4=5t

10=5t

t=10/5

t=2min

Therefore the time taken to fill the tank is 2minutes

Answer:

c. 5 units left and 3 units up

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation is translation, rotation, reflection and rotation.

If a point A(x, y) is translated a units right and b units up, the new location is at A'(x+a, y+b), while if a point A(x, y) is translated a units left and b units down, the new location is at A'(x-a, y-b)

The vertices of triangle FGH are F(4, 1), G(0, 3), and H(2, -1). A translation of 6 units left and 2 units down, triangle FGH becomes triangle F'(-2, -1) G'(-6, 1) H'(-4, -3). A translation of 1 unit right and 5 units up, triangle F'G'H' becomes triangle F"(-1, 4) G"(-5, 6) H"(-3, 2)

The translation of FGH to F"G"H" is a translation of (x -5, y + 3), that is 5 units left and 3 units up

Answer:

0.07–

Step-by-step explanation:

The answer is above :)

Answer:

to express in decimal form , we have to join convert the mixed fraction into a improper fraction.

8 7/90 = d * w + n

          =  90 * 8 + 7

        =    720 + 7

          = 727 / 90

 now you have to make the denominator into a mutiple of 10

         = 727 / 90  divided by 9

        =  80 / 10

       = 0.80

Step-by-step explanation:

hope it helps .

Answer:

$45

Step-by-step explanation:

ratio is 3:5

David gets 3x, Jack gets 5x

So, 3x+5x=120

8x=120

x=15

David got 3x = 3*15 = $45

Answer:

45$

Step-by-step explanation:

120/8=15

15*3=45

because it is 3:5 ratio

Answer:

Option 1

Step-by-step explanation:

First inequality:

-x/3>=-3 => x<9

Second inequality:

x>=17

Answer:

x > 83 / 3

Step-by-step explanation:

Let's solve your inequality step-by-step.

3x+5>88

Step 1: Subtract 5 from both sides.

3x+5−5>88−5

3x>83

Step 2: Divide both sides by 3.

3x/3 > 83/3

x > 83/3

Answer:

Step-by-step explanation:

The distance between two points can be found by using the formula

[tex]d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\[/tex]

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

P(7,,1) and Q(5,7)

We have

[tex] |PQ| = \sqrt{ ({7 - 5})^{2} + ({1 - 7})^{2} } \\ = \sqrt{ {2}^{2} + ({ - 6})^{2} } \\ = \sqrt{4 + 36 } \: \: \: \: \: \: \: \: \: \\ = \sqrt{40} \: \: \\ = 2 \sqrt{10} \\ = 6.32455532...[/tex]

We have the final answer as

Hope this helps you

Answer:

PQ=1.4 I think

Step-by-step explanation:

Answer: 48

Step 1: Find how much 12 is of 48.

12 = 1/4 of 48

Step 2: Multiply 12 by 3 for 3/4.

12 x 3 = 36.

Step 3: Add the numbers.

12 + 36 = 48

Answer = 48

Approximately, 48 hot dogs did he eat during the 12-minute contest.

One strategy to promote uniformity in work efforts, costs, and time is to simplify procedures. It lessens diversity and variation that is damaging, unnecessary, or meaningless. PEMDAS stands for parenthesis, exponents, multiplication, division, addition, and subtraction. Given two or more operations in a single statement, the order of the letters in PEMDAS tells you what to compute first, second, third, and so on, until the computation is complete.

As a result, Takeru Kobayashi broke the record for eating the hottest dogs in a 12-minute period.

Since,

In the first three minutes, he consumed 12 hot dogs.

in three minutes, he ate = 12 hot dogs

in 1 minute, he ate = 12/3

in 1 minute, he ate = 4

So,

in 12 minutes, the total number of hot dogs he ate = 4*12

in 12 minutes, the total number of hot dogs he ate = was 48

therefore, Approximately, 48 hot dogs did he eat during the 12-minute contest.

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Answer:

should be 1

Step-by-step explanation:

its constant meaning its an exact slope

and it runs through intersections every 1-1

so the answer is 1 because 1 over 1 in a fraction is still 1

the slope is positive because as you move to the right, the graph goes up

the slope is rise/run = 3/3 = 1

the slope of the line is 1

hope this helps!

Answer:

$0.05 per day

Step-by-step explanation:

So we know that the initial late fee would be $0.50. For every additional day, the fee increases by $0.05. The rate of change would be the rate at which the cost of the fee changes.

Note, the initial value does not affect the rate of change.

The initial late fee of $0.50 would not affect the rate of change, so we can ignore that piece of information.

Since the fee increases by $0.05 daily, $0.05 per day would be the rate of change.

I hope this helps.

Answer:

The expression of the perimeter of the triangle is 0.1x - 16 ⇒ C

Step-by-step explanation:

The perimeter of a triangle is the sum of the lengths of its sides

Let us solve the problem

∵ The lengths of the sides of a triangle are:

∵ The perimeter of the triangle = sum of lengths of its sides

∴ The perimeter = (0.5x + 9) + (3x) + (-3.4x - 25)

→ Add the like terms

∵ The perimeter = (0.5x + 3x - 3.4x) + (9 + -25)

→ Remember (+)(-) = (-)

∴ The perimeter = (3.5x - 3.4x) + (9 - 25)

∴ The perimeter = 0.1x + -16

∴ The perimeter = 0.1x - 16

The expression of the perimeter of the triangle is 0.1x - 16

Answer:

C.

Step-by-step explanation:

0.1x − 16

Answer:

Twice something means multiply by 2 , you have 80 feet of fencing all together so half of 80 is 40 . Then take 40 and times it by 2 . which comes out to 80 .

(Just copy and Paste)

Step-by-step explanation:

Answer:

y=2x-15

Step-by-step explanation:

In parallel lines the gradient is always the same. then we sub the coordinates in to find c.

so

1=2(8)+c

c equals to -15 t

then

y=2x-15

Answer:

X= 13/6

and in decimal form:  x=2.16repeated

Answer:

I like yo cut gggggggggggg

Answer:

24

Step-by-step explanation:

set them up as a fraction.

21/49=x/56

cross multiply: 21*56=49x

1176=49x

divide both sides by 49

x=24

Answer:

28

Step-by-step explanation:

notice that when x=21 thats 3x7=21  

then when y=49  thats 7x7  

so when y=56  that's 8x7

notice there is a patter of 7 being used?   there are probably a lot of other patterns that would also work.. but.  if your class is working on multiplying by 7 , then this is probably the right pattern.  

from the above pattern, then,

x=4x7 when y=56

x=28

Answer:

∠6, ∠13, ∠2, ∠9, ∠4, ∠11, ∠8, ∠15 are corresponding angles

∠6, ∠9, ∠2, ∠13, ∠4, ∠15, ∠8, ∠11 are alternate interior angles

∠1, ∠14, ∠5, ∠10, ∠3, ∠16, ∠7, ∠12 are alternate exterior angles

∠6, ∠13, ∠2, ∠9, ∠4, ∠11, ∠8, ∠15 are consecutive interior angles

sry i dont  know which are the consecutive exterior angles

but i hope you understood

<2 and <13 are alternate interior angles

Reason: At the opposite sides of the transversal and fall between

<4 and < 11 are co-interior angles

Reason: Same side of the transversal and fall between the two parallel lines

<1 and <16 do not have any direct relationship

<3 and <12 are co-exterior angles

Reason: Same side of the transversal but each of them are outside the  parallel lines

<3 and <5 are co-interior angles

Reason: Same side of the transversal and fall between the two parallel lines

<14 and 16 are corresponding angles

Reason: They are at corresponding sides of the parallel lines to the transversal

<1 and <3 are corresponding angles

Reason: They are at corresponding sides of the parallel lines to the transversal

<5 and <10 are alternating exterior angles

Reason: Alternate side of the transversal but each of them are outside the  parallel lines

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