Which would result in an increase in the magnetic field strength produced by an electromagnet? A) increasing the space between the turns in the coil B) increasing the number of turns in the coil C) decreasing the current in the coil D) decreasing the voltage in the coil
Answer:
B) increasing the number of turns in the
Explanation:
A) Increasing the space between the turns in the coil will decrease the number of coils. It will result in a decrease in the strength of the magnetic field because the strength of the magnetic field of an electromagnet is directly proportional to the number of coils.
B) Increasing the no. of turns in the coil will result in an increase in the strength of the magnetic field.
C) Strength of magnetic field is directly proportional to the magnitude of current passing through the electromagnet. Therefore, decreasing the current will decrease the strength of the magnetic field.
D) Decreasing the voltage will decrease the current and as a result, the strength of the magnetic field will also be decreased.
Hence, the correct option is:
B) increasing the number of turns in the
Reo performed an experiment to investigate the strength of an electromagnet and the amount of force that would be affected by the size of the current flowing through its coils. Which of the following changes would increase the current flow the most?
a. Decreasing the number of paper clips being picked up
b. Decreasing the number of coils of wire wrapped around the nail
c. Increasing the voltage power supply
d. Increasing the number of nails
(WILL GIVE BRAINLIEST)
Answer:
b. Decreasing the number of coils of wire wrapped around the nail
it can cause an electrical current running through it creates a magnetic field.
A negative charge of - 0.0005 C exerts an attractive force of 7.0 N on a second charge that is 10 m away. What is the magnitude of the second charge?
Answer:
the magnitude of the second charge is 0.000156 C.
Explanation:
Given;
mangitude of the first charge, q₁ = 0.0005 C
attractive force between the two charges, F = 7.0 N
distance between the two charges, r = 10 m
let the magnitude of the second charge = q₂
The magnitude of the second charge is calculated by applying Coulomb's law;
[tex]F = \frac{kq_1q_2}{r^2}[/tex]
Where;
K is Coulomb's constant = 9 x 10⁹ Nm²/C²
[tex]q_2 = \frac{Fr^2}{kq_1} \\\\q_2 = \frac{7 \times \ 10^2}{(9\times 10^9)(0.0005)} \\\\q_2 = 0.000156 \ C[/tex]
Therefore, the magnitude of the second charge is 0.000156 C.
How are frequency, wavelength, and energy related? Choose all that apply.
Explanation:
The energy of a wave is given by :
[tex]E=\dfrac{hc}{\lambda}[/tex]
Where
h is Planck's constant
c is the speed of light
[tex]\lambda[/tex] is wavelength
Energy is inversely proportional to wavelength. Also, the relation between frequency and wavelength is inverse.
If the frequency is high, the wavelength will be shorter.
Hence, the correct options are :
Higher frequencies have shorter wavelengths.
Shorter wavelengths have lower energy.
Lower frequencies have lower energy.
How has modern safety equipment found in automobiles helped to counteract Newton’s First Law of Motion?
Answer:
Well. the law says "an object in motion stays in motion" So seatbelts could be one. they stop us humans from continuing to move when the car stops.
List and discuss 5 importances
of land-
Select the correct answer?
Answer:
The answer is d i think so yea
Explanation:
hope u hae a really good day
7. A train 100 m long is moving with the velocity of 72 km/h. Find the time it takes to cross the bridge which is 2 km long?
a) 1050 S
b) 10500 s
c) 10.5 s
d) 105 s
Answer:
d) 105 s
Explanation:
Given the following data;
Distance A (length of train) = 100 m
Velocity = 72 km/h to meters per seconds = 72 * 1000)/3600 = 72000/3600 = 20 m/s
To find the time;
Time = distance/speed
Time = 100/20
Time = 5 seconds.
II. When the distance (bridge) is 2km;
Distance B = 2km = 2*1000 = 2000 meters
Time = distance/speed
Time = 2000/20
Time = 100 seconds
Therefore, total time = 5 + 100 = 105 seconds
What mistake did Kamala make? Gamma rays should have a very high frequency, not a very low frequency. Visible light should have a low frequency and a long wavelength. Infrared light should have a short wavelength, not a long wavelength. Microwaves should have a high frequency and a short wavelength.
Answer:
The answer is "Option A".
Explanation:
Please find the complete question in the attached file.
Kamala uses Gamma radiation inside this question should be very high, not very low. Electromagnetic radiation is a penetrating type resulting from radioactive nuclear decline. Its radiation is a very high-frequency, radioactive waveform to frequencies greater than [tex]10^{19} \ Hz[/tex] usually emitted from the radioactive decline.
Answer:
A
Explanation:
edge 2022
What are the four major tasks of the digestive system?
Ingestion, Digestion, Absorption, Elimination.
Ingestion, Procrastination, Absorption, Face the Nation.
Congestion, Progestion, Ingestion, Elimination
Answer:
Option A
The four major tasks of the digestive system are - Ingestion, Digestion, Absorption, Elimination
Explanation:
A digestive system has primarily four main functions
a) Motility - In this the food is ingested through opening in the form of mouth and then it starts moving from the mouth via esophagus to the stomach
b) Digestion - In the stomach, the food gets digestion and then it is passed on to the intestine
c) Absorption - In the small intestine essential nutrients and water is absorbed
b) Secretion - The waste remaining after intestine digestion is passed on to the rectum for secretion
Hence, option A is correct
How many pieces of thin, light glass will have the same effect as one thick, dark glass?
Answer:
Explanation:
i would 3 thin light glass would have the same effect as one thick dark glass
Four pieces of thin, light glass will have the same effect as one thick, dark glass.
What is Glass ?Glass is an inorganic solid substance that is generally transparent or translucent, as well as hard, brittle, and resistant to the elements. From ancient times, glass has been used to make utilitarian and aesthetic products, and it is now highly significant in uses as diverse as building construction, kitchenware, and telecommunications. It is created by rapidly chilling molten components such as silica sand to prevent the creation of visible crystals.
A quick discussion on glass follows. A lot of articles go into great length on glass. Stained glass and glassware explain stained glass and the aesthetic qualities of glass design. Industrial glass discusses the composition, characteristics, and industrial manufacture of glass. The physical and atomic properties of glass are discussed in amorphous solid.
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Two ice skaters on ice push away from each other. The friend on the left is 45 kg and the friend on the right is
40 kg. The right skater gets pushed and moves with an acceleration 2 m/s". Based on this scenario what will
happen to the left skater?
8. What is the frequency heard by a person driving at 15.0 m/s toward a blowing factory whistle (800. Hz) if the speed of sound is 340.6 m/s? (837 Hz) F= (340.6×800)÷(340.6-15)= 836.9 Hz F=836.9 9. From the previous problem, what frequency would he hear after passing the factory if he continues at the same speed? (766 Hz)
Answer:
A) f_o ≈ 836.9 Hz
B) f ≈ 765 Hz
Explanation:
A) To solve this, we will use the formula;
f_o = (v•f_s)/(v - v_p)
Where;
v is speed of sound in air
f_s is frequency of source
v_p is the speed of the person moving towards the whistle.
We are given;
v = 340.6 m/s
v_p = 15 m/s
f_s = 800 Hz
Thus;
f_o = (340.6 × 800)/(340.6 - 15)
f_o ≈ 836.9 Hz
B) to solve this, let's first calculate the wavelength from the formula;
λ = v/f_s
λ = 340.6/800
λ = 0.42575 m
To get the frequency he will hear after passing the factory, we will use the formula;
f = (v - v_p)/λ
f = (340.6 - 15)/0.42575
f ≈ 765 Hz
A 1200 kg car accelerats from reat to 10.0 m/s in a time of 4.50 seconds. Calculate the force that thr car's tires exerted on the road.
Answer:
2667 N
Explanation:
Method 1: ImpulseWe can solve this problem by using the impulse formula.
FΔt = mΔv Δt = time interval, m = mass of the car (kg), Δv = change in velocityWe have three known variables, so we can solve for the fourth: F.
Divide Δt from both sides to isolate F.
F = (mΔv)/ΔtSubstitute known values into the equation.
F = [(1200 kg)(10 m/s - 0 m/s)] / 4.5 s F = [(1200)(10)]/4.5 F = 12000/4.5 F = 2666.666667 NThe force that the car's tires exert on the road is 2667 N.
Method 2: Newton's Second LawThe force that the car's tires exert on the road is equivalent to the force that the road exerts on the car due to Newton's Third Law of Motion.
We can calculate the force that the car's tires exert on the road by using the formula F = ma, which was derived from Newton's Second Law of Motion.
F = ma F = force exerted on the car, m = mass of the car (kg), a = acceleration of the car (m/s²)We are given the mass of the car, velocity of the car, and the time in which it accelerated.
We can use this equation for acceleration:
a = Δv/Δt Δv = final velocity - initial velocity (change in velocity), Δt = time intervalThe car started from rest, meaning it had an initial velocity of 0 m/s. Its final velocity was 10 m/s. The time that it took for the car to go from 0 m/s to 10 m/s was 4.5 seconds.
a = (10 m/s - 0 m/s) / 4.50 s a = 10/4.5 a = 2.222... m/s²Now we have two known variables, mass and acceleration. We can solve for the force exerted on the car (and thus, the force the car exerts on the road) using the formula F = ma.
F = ma F = (1200 kg)(2.222... m/s²) F = 1200 · 2.222...F = 2666.666667 NThe force that the car's tires exert on the road is 2667 N.
Calculate the pressure exerted on the floor by the boy standing on both feet if the weight of the boy is 40kg. Assume that the area of each of his shoes is 6cm x 25cm.
(Take 1kg of weight = 10N)
Answer:
P = 1333.33 N
Explanation:
The pressure exerted by the boy on the floor can be calculated by the following equation:
[tex]P = \frac{F}{A}[/tex]
where,
P = Pressure exerted by the boy = ?
F = Force Applied = Weight of Boy = 40 kg = 40 N (since 1 kg = 1N)
A = Area of application of force = 2(Area of one show) = 2(6 cm x 25 cm)
A = 2(0.06 m x 0.25 m) = 0.03 m²
Therefore,
[tex]P = \frac{40\ N}{0.03\ m^2}\\\\[/tex]
P = 1333.33 N
In a perfectly inelastic collision between two balls:
a) No changes happen to the internal structure of the balls
b) The total kinetic energy of the balls is conserved
c) The balls have the same velocity after the collision
d) The balls temperature does not change.
Answer:
c) The balls have the same velocity after the collision
Explanation:
In a perfectly inelastic collision between two balls, there is a loss in the maximum kinetic energy of the system and the two ball stick together, and thereby have the same velocity after the collision and also the coefficient of restitution of the two balls is also zero accompanied by a loss in the kinetic energy of the system
Therefore, the correct option is that both balls will have the same (equal) velocity after the collision.
Can anyone help me!!!
I need this really soon!!!!
Q. Rama's weight is 40kg . She is carrying a load of 20 kg up to a height of 20 metres. What work does she do? Also mention the type of work
No links!!!!
No spams!!!!
Answer:
3920 N.
Explanation:
that's what the answer is..
Which one of the following is an example of an acid-base reaction?
A. 2HCl + Mg(OH)2 + 2H2O + MgCl2
B. Fe + CuSO4 → FeSO4 + Cu
C. 2Li + ZnSO4 → Li2SO4 + Zn
O D. C5H12 + 802 - 5CO2 + 6H20
No links please
Answer:
A. 2HCl + Mg(OH)2 + 2H2O + MgCl2
hope it helps
Simple harmonic motion occurs when an object is displaced from its stable equilibrium position and the force or torque pushing it back toward equilibrium is ______ in displacement. Group of answer choices exponential sinusoidal quadratic linear
Answer:
force is of the LINEAR type
Explanation:
In simple harmonic movements the restoring force is of the Hooke e-force type, which has the form
F = - k (x-x₀)
where x₀ is the initial length of the spring.
Therefore we can see this force is of the LINEAR type
A book that weighs 20 N sits on a table. How big and in what direction does the force of gravity from the Earth act on the book?
A. 20 N down
B. 10 N down
C. 20 N up
D. 10 N up
Answer:
A. 20 N down
Explanation:
It's asking how much force of gravity is acting on it. The book weighs 20 Newtons so that's how much gravity is being applied. Hope this helps
When a book that weighs 20 N sits on a table. then the force of gravity from the Earth acts on the book would be 20 N down, therefore the correct option is A.
What is gravity?It can be defined as the force by which a body attracts another body towards its center as the result of the gravitational pull of one body and another, The gravity varies according to the mass and size of the body for example the force of gravity on the moon is the 1/6th times of the force of gravity on the earth.
When an object is thrown straight up in the absence of air resistance there is no external force acting on it except the gravitational force of the earth which very much reflects the fact that the acceleration due to gravity is constant and is the result of the gravitational pull of the earth which act on the downward direction.
A book that weighs 20 N sits on a table and faces a downward force of 20N acts on the book because the force of gravity from the Earth acts on the book.
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An object's velocity increases, multiplied by a factor of 9. What factor would its Kinetic Energy increase by?
Answer:
by 81
Explanation:
KE = (1/2)mv^2. If v2 ---> 9v then
KE2 = (1/2)m(9v)^2 = 81[(1/2)mv^2]
= 81 KE
Answer:
by a factor of 4
Explanation:
The kinetic energy is proportional to the square of the speed so doubling the speed increases.
What conditions would probably exist the dew point and dry bulb temperatures to be the same at the ground ?
Answer: The conditions would probably exist the drew point and dry bulb temperatures to be the same at the ground because When the dew point temperature and air temperature are equal, the air is said to be saturated. Dew point temperature is NEVER GREATER than the air temperature. Therefore, if the air cools, moisture must be removed from the air and this is accomplished through condensation.
Explanation:
Since the air is said to be saturated when the dew point temperature and air temperatures are equal, the circumstances are likely present for the dew point and dry bulb temperatures to be equal at the ground. NEVER is the dew point temperature higher than that of the air temperature. As a result, condensation is used to remove moisture from the air when it cools.
What is dew point temperature?The dew point, under the assumption of constant air pressure and water content, is the temperature at which air must be chilled to become water vapor condenses. Airborne vapor will condense to create liquid water, known as dew, when it is cooled below the dew point, thereby moisture capacity. If this occurs via coming into contact with a cooler surface, dew will grow there.
Humidity influences the dew point. The dew point rises as the amount of moisture in the atmosphere increases.
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Which is NOT something that all green plants have in common?
1.They make their own food.
2. They reproduce.
3 .They grow.
4 .They produce flowers.
Answer:
4
Explanation:
Not all plants can grow flowers. Only the ones thay have buds can.
Not all plants produce flowers. Hence, this is the characteristic which is not common in all plants.Therefore, the correct option is 4.
What are flowers?Flowers are the structures of plants. They are responsible for producing seeds that will grow into new plants. Flowers typically consist of a colorful or ornamental part called the corolla, which attracts pollinators such as bees and butterflies, and a reproductive part called the stamen and pistil, which contain the plant's male and female organs.
Not all green plants produce flowers. Flowering plants are a type of plant that belong to the group Angiosperms, but there are also non-flowering plants like ferns and mosses that do not produce flowers. Therefore, the correct option is 4.
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How is energy transferred during the water cycle? Question 1 options: Water gains energy during evaporation and releases it during condensation in the atmosphere Water gains energy during evaporation and condensation in the lithosphere. Water gains energy in condensation and releases it in evaporation. Water releases energy during evaporation and condensation.
Answer:
Water gains energy during evaporation and releases it during condensation in the atmosphere
Explanation:
In the water cycle, heat energy is gained or lost by water as it undergoes various processes in the cycle.
In evaporation, water molecules gains energy because the molecules of water vibrate faster and become more energetic. Hence they are able to escape into the atmosphere from the surface of the liquid.
In condensation, the molecules of gaseous water looses energy and becomes liquid.
Hence, water gains energy during evaporation and releases it during condensation in the atmosphere.
Answer:
K12 HE HE
Explanation:
The lens of a telescope has a diameter of 25 cm. You are using it to look at two stars that are 2 × 1017 m away from you and 6 × 109 m from each other. You are measuring light with a wavelength of 700 nm. As the light goes through the lens, it diffracts. a. Is it possible, using this telescope, to see the two stars as separate stars? b. What is the minimum possible lens diameter you would need in order to resolve these two stars?
Answer:
a)It is NOT possible using this telescope, to see the two stars as separate stars
b)[tex]d_{min} =28.466m[/tex]
Explanation:
From the question we are told that:
Diameter of lens,[tex]d = 25 cm \approx 0.25 m[/tex]
Distance from both star [tex]D_f= 2*10^{17} m[/tex]
Distance between both stars [tex]D_b= 6*10^9 m[/tex]
Wavelength of light [tex]\lambda =700 nm \approx 700*10^-9 m[/tex]
Generally the equation for angle subtended by the two stars at the lens is mathematically given by
[tex]\theta=\frac{D_f}{D_b}[/tex]
[tex]\theta=\frac{6*10^9}{2*10^{17}}[/tex]
[tex]\theta=3.0*10^{-8} rad[/tex]
Generally the equation for minimum angular separation of two object is mathematically given by
[tex]\theta_{min} = 1.22*\lambda/d[/tex]
[tex]\theta_{min}= \frac{1.22*700*10^-9}{0.25}[/tex]
[tex]\theta_{min}= 3.416*10^-^6 rad[/tex]
Therefore
[tex]\theta < \theta_{min}[/tex]
[tex]3.0*10^{-8} rad< 3.416*10^-^6 rad[/tex]
It is NOT possible using this telescope, to see the two stars as separate stars
b)
Generally the equation for minimum diameter of the lens is mathematically given by
[tex]d_{min} =\frac{ 1.22*\lambda}{\theta}[/tex]
[tex]d_{min} =\frac{ 1.22*700*10^{-9}}{3*10^{-8}}[/tex]
[tex]d_{min} =28.466m[/tex]
Which statement can be made about waves A and B? Wave A has a lower amplitude than Wave B. Wave A has a higher amplitude than Wave B. Wave A has a lower frequency than Wave B. Wave A has a higher frequency than Wave B.
Answer:
Wave A has a higher amplitude than Wave B.
Explanation:
please check the attached image for the waves
Answer:
b
Explanation:
got it right on edge
pls help with science!!!!!
Answer:
Your answer is C~
Explanation:
Which product forms from the synthesis reaction between calcium (Ca) and
chlorine (CI)?
A. CaCl2
B. CaCl
C. Ca2Cl2
O D. Caci
SUBMIT
Answer:
CaCl2
Explanation:
Answer:
its a! the answer is a
Explanation:
the distance between the sun and moon is 480 light second. convert the distance into meter
Answer:
1.439 × 10¹¹ m is the answer.
Explanation:
1 light-second = 2.998 × 10⁸m
480 light-seconds = 480 × 2.998 × 10⁸
= 1439.04 × 10⁸
= 1.439 × 10¹¹
∴ 1.439 × 10¹¹ m is the answer.
The distance converted into the meter will be 1.439×10¹¹ m.In one light second, there are 2.998 ×10⁸ m.
What is the distance?Distance is a numerical representation of the distance between two objects or locations.
The distance can refer to a physical length or an estimate based on other factors in physics or common use. |AB| is a symbol for the distance between two points A and B.
The given data in the problem is;
The distance between the sun and moon is,d= 480 light second
[tex]\rm d_m[/tex] is the distance in meter
As we know,
[tex]\rm 1\ light\ second = 2.998 \times 10^8m \\\\ 480\ light\ seconds = 480 \times 2.998 \times 10^8\ m \\\\ d_m= 1439.04 \times 10^8 \\\\ d_m = 1.439 \times 10^{11}[/tex]
Hence the distance converted into the meter will be 1.439×10¹¹ m.
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What type of specialized cell in the eye is used for detecting low levels of light?
Answer:
There are about six to seven million cones in a human eye and are most concentrated towards the macula. Cones are less sensitive to light than the rod cells in the retina (which support vision at low light levels), but allow the perception of color.
Answer:
Rods
Explanation:
There are about six to seven million cones in a human eye and are most concentrated towards the macula. Cones are less sensitive to light than the rod cells in the retina (which support vision at low light levels), but allow the perception of color.