Answer:
1.55 × 10²⁴ atoms Xe
General Formulas and Concepts:
Atomic Structure
Reading a Periodic TableMolesSTP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Stoichiometry
Using Dimensional AnalysisExplanation:
Step 1: Define
[Given] 57.5 L Xe at STP
[Solve] atoms Xe
Step 2: Identify Conversions
[STP] 22.4 L = 1 mol
Avogadro's Number
Step 3: Convert
[DA] Set up: [tex]\displaystyle 57.5 \ L \ Xe(\frac{1 \ mol \ Xe}{22.4 \ L \ Xe})(\frac{6.022 \cdot 10^{23} \ atoms \ Xe}{1 \ mol \ Xe})[/tex][DA] Divide/Multiply [Cancel out units]: [tex]\displaystyle 1.54583 \cdot 10^{24} \ atoms \ Xe[/tex]Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
1.54583 × 10²⁴ atoms Xe ≈ 1.55 × 10²⁴ atoms Xe
I will mark brainliest
What kind of weather forms with an occluded front?
Answer:Occluded fronts usually form around areas of low atmospheric pressure. There is often precipitation along an occluded front from cumulonimbus or nimbostratus clouds. Wind changes direction as the front passes and the temperature either warms or cools.
Explanation:
18. A 35.0 G piece of metal wire is heated and the temperature changes from 21°C to 52°C the specific heat of the metal is 0.900 J/G degrees Celsius how much energy was required to heat the metal please show work
Answer:
[tex]\boxed {\boxed {\sf 976.5 \ Joules}}[/tex]
Explanation:
We are asked to find the heat energy. Since we are given the mass, specific heat, and change in temperature, we should use this formula for heat:
[tex]q=mc\Delta T[/tex]
Where m is the mass, c is the specific heat, and ΔT is the change in temperature.
We know this is a 35.0 gram piece of wire, the temperature changes from 21 °C to 52°C and the specific heat is 0.900 J/ g °C.
Therefore,
m= 35.0 gc= 0.900 J/g °CΔT= 52 °C - 21°C= 31°CSubstitute these values into the formula.
[tex]q= (35.0 \ g)(0.900 \ J/g \ \textdegree C)(31 \textdegree C)[/tex]
Multiply the first two values. The grams will cancel each other out.
[tex]q=31.5 \ J/ \textdegree C (31 \textdegree C)[/tex]
Multiply again. This time, the degrees Celsius cancel each other out, so the final units are Joules.
[tex]q=976.5 \ J[/tex]
976.5 Joules of energy were required to heat the piece of metal.
Last time I'm asking this, answer, this time, 50 points.
Think about a single cell and its parts; for example, think about a cell inside the human body. Now, select an everyday object that could be used as a model for a cell and its parts. In words and/or pictures, describe your model and how it is like the cell.
Explanation:
Well i mean clothes so cells make tissues which help organs clothes can technically help you if you fall it has layers so it woulf be as a cell?
A motorcycle that travels north 201m in 7s. What is it's velocity?
7. D=
8. TE
9. V=
Which of the following is NOT a benefit of strength training? WILL GIVE BRAINLIEST! :)
A. Better control of muscle
B. More efficient movement
C. Decreased force variance
D. Increased flexibility
I think it's D
Explanation:
if you think abt it strength training means weights and stuff so I dont think it increases flexibility. it's that or letter C
Try moving an electron from the metal to the non metal.What happens?
Answer:
Sodium becomes a positive ion and chlorine becomes a negative ion. ... Each atom is neutrally charged, which means that each atom has the same number of protons and electrons.
Explanation:
Use the following chemical equation, how many moles of ammonia (NH 3 ) produced when 3.15 moles of nitrogen (N 2 ) reacts with hydrogen (H 2 ) ? N 2(g) + 3H 2(g) 2NH 3(g)
Answer:
[tex]n_{NH_3}^{produced}=6.3molNH_3[/tex]
Explanation:
Hello there!
In this case, according to the given chemical reaction, it is possible for us to use the 1:2 mole ratio of nitrogen to ammonia to calculate the moles of the latter that are produced when reacting 3.15 moles of the former with hydrogen as shown below:
[tex]n_{NH_3}^{produced}=3.15molN_2*\frac{2molNH_3}{1molN_2}[/tex]
Thus, by solving the equation we obtain:
[tex]n_{NH_3}^{produced}=6.3molNH_3[/tex]
Best regards!
Your teacher gives you 0.09 L of a 0.850 M solution of NaCl dissolved in water. What will the new volume be if you dilute it down to 0.500 M?
Answer:
[tex]V_2=0.153L[/tex]
Explanation:
Hey there!
In this case, according to the equation for dilution process, in which the moles of the solute remain the same after the addition of additional solvent:
[tex]M_1V_1=M_2V_2[/tex]
Thus, by solving for the new volume, V2, of the base, NaOH, we can obtain:
[tex]V_2=\frac{M_1V_1}{M_2}=\frac{0.09L*0.850M}{0.500M}\\\\V_2=0.153L[/tex]
Best regards!
Which is a reason to use rate laws?
A. to investigate how the pressure of liquids affects reaction rates
B. to find the new rate when the concentration of reactants changes
C. to calculate the molecular weight of compounds in a reaction
D. to find the number of moles of solute that are dissolved in 1 L of solution
Answer:
B
Explanation:
to find the new rate when the concentration of reactants changes
Silver sulfate dissociates into silver ions and sulfate ions:
Ag2SO4(s) = 2Ag+ (aq) + SO42- (aq)
Which of the following equations is the equilibrium constant expression for
this reaction?
A. Kot
[Ag+][80.21
[Ag 2504)
O B. Ko = [Ag+ 12 [5042")
[A92504)
O C. KE =
[Ag+1?[s042-7
O D. KG
[A92504
[Ag+ ][5042-)
Answer:
A its a step by step equation the answer is A
Which of the following is a metal?
a.
silicon, Si, Z = 14
b.
phosphorus, P, Z = 15
c.
thallium, Tl, Z = 81
d.
arsenic, Z = 33
e.
nitrogen, N, Z = 7
Answer:
A.................. I think the answer
When i make an account for different college can I use the same email username for each one or do I have make a different username email
Answer:
No you have to use a new email unless you delete the other accaount
Explanation:
hope that helps
According to the reaction, below, how many grams of aluminum are needed to react fully with 100 grams of sulfur? 2AL + 3s - Al2S3
Answer: 56.2 g of Aluminium is needed to react fully with 100 grams of sulphur.
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} S=\frac{100g}{32g/mol}=3.125moles[/tex]
The balanced chemical equation is:
[tex]2Al+3S\rightarrow Al_2S_3[/tex]
According to stoichiometry :
3 moles of [tex]S[/tex] require = 2 moles of [tex]Al[/tex]
Thus 3.125 moles of [tex]S[/tex] will require=[tex]\frac{2}{3}\times 3.125=2.08moles[/tex] of [tex]Al[/tex]
Mass of [tex]Al=moles\times {\text {Molar mass}}=2.08moles\times 27g/mol=56.2g[/tex]
Thus 56.2 g of Aluminium is needed to react fully with 100 grams of sulphur.
How many moles of argon gas would be present in a 37.0 liter vessel at 45.00 °C at a pressure of 2.50 atm?
Answer:
3.54 mol
Explanation:
Step 1: Given data
Volume (V): 37.0 LTemperature (T): 45.00 °CPressure (P): 2.50 atmStep 2: Convert "T" to Kelvin
We will use the following expression.
K = °C + 273.15
K = 45.00°C + 273.15 = 318.15 K
Step 3: Calculate the number of moles (n) of argon gas
We will use the ideal gas equation.
P × V = n × R × T
n = P × V/R × T
n = 2.50 atm × 37.0 L/(0.0821 atm.L/mol.K) × 318.15 K = 3.54 mol
i need help help me please
Answer:
C is the correct answer.
Explanation:
We can eliminate some answers immediately:
A is incorrect because nitrogen and hydrogen do not change their identity, they just combine into a new molecule that contains them. Notice how there are 2 nitrogen atoms and 6 hydrogen atoms on both sides of the equation.
B is incorrect because the first law of thermodynamics tells us that matter and energy will always be conserved, so the mass of the products must be equal to the mass of the reactants, not less than the mass of the reactants.
C is correct because balanced chemical equations help chemists predict how much product will form from certain amounts of reactants.
D is incorrect because this equation is showing the exact opposite. Molecular hydrogen and nitrogen can combine stoichiometrically to form ammonia.
solution with low concentration of hydrogen ions have a __________ ph .
Answer:
6.37
Explanation:
Answer:
high ph
Explanation:
if you have high conc of H+ ph is low therefore acidic but if vice versa basic
high ph
What is the frequency of a light source that has a wavelength of 430 NM? What is the energy of this wave?
Answer:
Explanation:
[tex]c = f \lambda[/tex]
where c = speed of light (3x10^8m/s)
f = frequency
[tex]\lambda[/tex] = wavelength.
We can solve that the frequency is (3x10^8)/(420 x 10^-9) = 7.14x10^14 Hz
Also, E = hf where h = 6.62x10^-34.
So the energy is (6.62x10^-34) x (7.14x10^14) = 4.73x10^-19 J.
Hope this helps and tell me if I made any mistakes.
Why are diamonds unevenly distributed on Earth?
Soil forms only in places where rock particles are deposited.
Soil forms only in places where larger rocks are broken into smaller rocks.
Soil forms only within the Earth under heavy pressure.
Soil forms in the air and is then deposited mainly in places that get a lot of rain.
Answer:
Why aren't diamonds found evenly distributed on Earth? Diamonds are only formed under specific conditions that involve geological processes, such as volcanic activities and plate movements. Since these conditions and processes only take place in certain areas, you can only find diamonds in these special places.
Explanation:
In alpha decay, the parent nucleus loses an alpha particle, which is two protons and two neutrons.
a. True
b. False
Answer:
True
Explanation:
In an alpha decay, the isotope of an element releases two protons and two neutrons. An alpha particle or helium has two protons and two neutrons and hence, in an alpha decay an alpha particle is released.
Hence, the given statement is true
PLEASE HURRY IM TIMED I WILL GIVE BRAINYEST
What is another name for the sunlit zone of the ocean?
A twilight zone
B abyssal zone
C photic zone
D benthic zone
Answer:
The answer is the C. Photic zone.
Explanation:
I wish you good luck! :>
Answer: C photic zone
Explanation:
What volume will 1.27 moles of helium gas occupy at 80.00 °C and 1.00 atm?
Pls and thank you :) !
Answer:
36.8 L
Explanation:
We'll begin by converting 80 °C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
T(°C) = 80 °C
T(K) = 80 + 273
T(K) = 353 K
Finally, we shall determine the volume occupied by the helium gas. This can be obtained as follow:
Number of mole (n) = 1.27 moles
Temperature (T) = 353 K
Pressure (P) = 1 atm
Gas constant (R) = 0.0821 atm.L/Kmol
Volume (V) =?
PV = nRT
1 × V = 1.27 × 0.0821 × 353
V = 36.8 L
Thus, the volume occupied by the helium gas is 36.8 L
What is the vapor pressure of an aqueous solution that has a solute mole fraction of 0.1000? The vapor pressure of water is 25.756 mmHg at 25 °C.
Answer:
χsolvent = 1.0000 - 0.1000 = 0.9000
Use Raoult's Law:
Psolution = (χsolvent) (P°solvent)
x = (0.900) (25.756)
x = 23.18 mmHg (to four sig figs)
The vapor pressure of an aqueous solution is x = 23.18 mmHg (to four sig figs)
χsolvent = 1.0000 - 0.1000 = 0.9000
Use Raoult's Law:
P solution = (χsolvent) (P°solvent)
x = (0.900) (25.756)
x = 23.18 mmHg (to four sig figs)
What is an aqueous solution?An aqueous answer is one in which the solvent is liquid water. that is, solute (dissolved) ions and molecules are surrounded by water molecules and integrated into the network of bonds within the water. The dissolved species then spread in the course of the water.
A solution wherein water is the solvent is called an aqueous solution. although water is an exceptional solvent, now not the whole thing dissolves comfortably in the water.
Aqueous' in a chemical equation suggests that the cloth dispersed in water (an answer in water). As an example, when we pour sodium hydroxide answer into dilute hydrochloric acid, we get an aqueous solution of sodium chloride. The liquid is used to signify the formation of liquid materials in response.
Learn more about the aqueous solution here: https://brainly.com/question/19587902
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36. Write a balanced chemical equation for each chemical reaction. (a) Solid copper reacts with solid sulfur to form solid copper(I) sulfide. (b) Sulfur dioxide gas reacts with oxygen gas to form sulfur trioxide gas. (c) Aqueous hydrochloric acid reacts with solid manganese(IV) oxide to form aqueous manganese(II) chloride, liquid water, and chlorine gas. (d) Liquid benzene (C6H6) reacts with gaseous oxygen to form carbon dioxide and liquid water.
Answer:
a) 2Cu(s) + S(s) → Cu₂S(s)
b) 2SO₂(g) + O₂(g) → 2SO₃(g)
c) 4HCl(aq) + MnO₂(s) → MnCl₂(aq) + 2H₂O(l) + Cl₂(g)
d) C₆H₆(l) + 15/2 O₂(g) → 6CO₂(g) + 3H₂O(l)
Explanation:
First, we have to write the chemical formulas for reactants and products. Then, to identify which is the state of matter of each compound (liquid: l, solid: s, aqueous: aq, gas: g). Finally, we write the equation and balance the atoms.
a) Solid copper reacts with solid sulfur to form solid copper(I) sulfide.
Reactants: solid copper (Cu(s)) and solid sulfur (S(s)). Product: copper(I) sulfide (Cu₂S) because sulfur anion has two negative charges (S⁻²) and we need two copper ions with one positive charge (Cu⁺) to obtain the neutral compound.
The balanced requires a coefficient of 2 for Cu(s) to balance the 2 Cu atoms on the products side:
2Cu(s) + S(s) → Cu₂S(s)
(b) Sulfur dioxide gas reacts with oxygen gas to form sulfur trioxide gas.
Reactants: sulfur dioxide (SO₂) and oxygen gas (which is a diatomic molecule: O₂). Products: sulfur trioxide gas (SO₃(s)).
The balanced equation is:
2SO₂(g) + O₂(g) → 2SO₃(g)
We need a coefficient of 2 for SO₂ and SO₃ to balance O and S atoms.
(c) Aqueous hydrochloric acid reacts with solid manganese(IV) oxide to form aqueous manganese(II) chloride, liquid water, and chlorine gas.
Reactants: aqueous hydrochloric acid (HCl(aq)) and solid manganese (IV) oxide (MnO₂(s), because we need two oxygen anions O²⁻ to neutralize 4 positive charges in Mn IV). Products: aqueous manganese(II) chloride (MnCl₂, because we need two chloride ions Cl⁻ to neutralize two positive charges in Mn(II)), liquid water (H₂O), and chlorine gas (Cl₂, because it is a diatomic molecule).
The balanced chemical equation is:
4HCl(aq) + MnO₂(s) → MnCl₂(aq) + 2H₂O(l) + Cl₂(g)
(d) Liquid benzene (C₆H₆) reacts with gaseous oxygen to form carbon dioxide and liquid water.
Reactants: benzene (C₆H₆) and gaseous oxygen (O₂). Products: carbon dioxide (CO₂, because C has valence IV) and liquid water (H₂O).
The balanced chemical equation is:
C₆H₆(l) + 15/2 O₂(g) → 6CO₂(g) + 3H₂O(l)
In this case, we need a coefficient of 15/2 for O₂ because on the product side there are 15 atoms of O (12 in CO₂ and 3 in H₂O).
How many grams of water can be heated from 15.0°C to 75°C using 12,500 Joules?
Answer:
m = 49.8 g
Explanation:
Hello there!
In this case, for this calorimetry processes we can define the involved heat in terms of mass, specific heat and temperature as shown below:
[tex]Q=mC\Delta T[/tex]
Thus, given the heat, final and initial temperature and specific heat of water (4.184), the mass of water can be computed as shown below:
[tex]m=\frac{Q}{C\Delta T}\\\\m=\frac{12500J}{4.184\frac{J}{g\°C}(75\°C-15.0\°C)} \\\\m=49.8g[/tex]
Best regards!
1 Write the chemical symbols for following elements: Nitrogen-
Phosphorus- bromine- Zinc-Potassium-Magnesium.
Answer:
I think
Explanation:
N for nitrogen
P for phosphorus
Br for bromine
K for potassium
Mg for magnesium
what is the electrolysis of water
If 2.00 moles of H2 and 1.55 moles of Oz react how many moles of H20
can be produced in the reaction below?
2 H2(g) + O2(g) → 2 H2O(g)
What is the molarity of a 9.79 L solution that contains 0.400 mol HCI
Answer:
0.041 MExplanation:
The molarity of a solution when given the number of moles the substance and it's volume can be found by using the formula
[tex]c = \frac{n}{v} \\ [/tex]
n is the number of moles
v is the volume in L
We have
[tex]c = \frac{0.4}{9.79} \\ = 0.04058...[/tex]
We have the final answer as
0.041 MHope this helps you
Part A
How many moles of chlorine gas are needed to make 0.6 moles of sodium chloride?
Given the reaction: 2Na + Cl2 + 2NaCl
O 1.2
O 0.6
0 3.6
O 0.3
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Answer:
[tex]n_{Cl_2}=0.3molCl_2[/tex]
Explanation:
Hello there!
In this case, according to the given chemical reaction whereas the sodium chloride is in a 2:1 mole ratio with chlorine, the required moles of the later are computed as shown below:
[tex]n_{Cl_2}=0.6molNaCl*\frac{1molCl_2}{2molNaCl}[/tex]
So we cancel out the moles of NaCl to obtain:
[tex]n_{Cl_2}=0.3molCl_2[/tex]
Best regards!
the desity of gold is 19.3 g/cm3. what is the volume of a 13 g gold nugget .
Answer:
0.67 cm³
Explanation:
We can solve this problem by using the definition of density:
Density = Mass / VolumeWe can rearrange the equation and isolate volume:
Volume = Mass / DensityAs we are given both the mass and the density, we can now calculate the volume:
Volume = 13 g ÷ 19.3 g/cm³Volume = 0.67 cm³