How many moles are present in 5.67x10^25 atoms of Carbon (C)?
Answers
Answer:
94.155 Moles
Explanation:
Since you are given atoms, to get to moles you need to use the formula I used below. Pretty simple, just plug and chug. Work can be found below.
Hope this helps! :^)
94. 125 moles are present in 5.67x10^25 atoms of Carbon (C).
What is mole?
The mole is a unit of measurement that is comparable to well-known units like pair, dozen, bulk, etc. It offers a precise count of atoms or molecules in a large sample of materials.
The amount of substance that has the same number of discrete entities (atoms, molecules, ions, etc.) as the number of atoms in a sample of pure 12C weighing exactly 12 g is known as a mole.
The word "mole" has a "big mass" or "bulk" sense in Latin, which is congruent with its use as the name for this unit. The mole establishes a connection between bulk mass, which is a simple macroscopic attribute to measure, and the number of atoms, molecules, and other fundamental units, which is a crucial fundamental property.
Therefore, 94. 125 moles are present in 5.67x10^25 atoms of Carbon
(C).
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A student wants to perform an experiment to study the relationship between the temperature and pressure of an enclosed gas. In one or two sentences, describe two assumptions that must be made in performing this experiment.(2 points)
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An assumption that must be made when studying the relationship between pressure and temperature is that the gases do not interact with each other.
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What's the Matter?
Which statements correctly describe matter? Select all that apply.
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Answer:
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What mass of KBr (in grams) do you need to make 250. 0 mL of a 1. 50 MKBr solution?.
Answers
Answer:
KBr final solution:
V = 250mL --> 0.25L
Concentration/Molarity = 1.5 mol/L
To find the amount of moles of KBr here, just multiply the volume by the concentration (0.25 x 1.5 = 0.375 mol)
So the amount of moles for KBr is 0.375 mol. Now we know that the mass divided by the molar mass (the atomic mass values of K and Br in the periodic table added together) would give us the amount of moles aswell.
n = moles
m = mass
M = molar mass
n = m/M
so if we rearrange this equation to find mass, we would get:
m = n x M
Molar mass for KBr: (39.09) of K + (79.90) of Br = 118.99
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m = 44.62g
Therefore 44.62g of KBr is needed to make 250mL of a 1.5 M KBr solution.
omg y'all pls so much help me!!!
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98amu
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86amu
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Answer:
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Answer:
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