Answer:
2.35mL
Explanation:
The amount of space a substance holds is its volume.
Density = mass (g) /volume (L)
Where;
mole = mass/molar mass
Since 1 mol of Cu contains 6.022 × 10^22 atoms.
There are 2 x 10^22/6.022 × 10^22 moles in 2 x 10^22 atoms of copper
2 x 10^22/6.022 × 10^22
2/6.022 × 10^(22-22)
0.332 × 10^0
0.332mol
Mole = mass/molar mass
0.332 = mass/63.5
mass = 63.5 × 0.332
mass = 21.08g
Density = mass/volume
Density of copper (Cu) is 8.96 g/cm³
8.96 = 21.08/v
V = 21.08/8.96
V = 2.35mL or cm³
What solution turns litmus paper red?
A. acidic
B. neutral
C. none
D. basic
Answer:
The answer is A please mark brainliest
Explanation:
6. A sheet of metal is 2 cm wide, 10 cm tall, and 15 cm long. It was 4 grams. What is the
density?
Answer:
0.013g/cm^3
Explanation:
density= mass÷volume
Answer:
0.01(3) g/cm3 (cm3 means centimeter cubed, (3) means the 3 goes on forever)
Explanation:
The volume of the sheet is 300 cm3, and dividing 4 grams by 300 cm3 gets you 0.01(3) g/cm3. Hope it helps!
If an animal is placed into a sealed container for a short time, the oxygen level will
A. decrease and the carbon dioxide level will increase.
B. decrease and the carbon dioxide level will decrease,
C, increase and the carbon dioxide level will increase.
D. decrease and the carbon dioxide level will stay the same.
E increase and the carbon dioxide level will decrease.
Answer:
A
Explanation:
Animals take in oxygen and convert it into carbon dioxide therefore the oxygen levels will decrease and the carbon dioxide levels will increase
If an animal is placed into a sealed container for a short time, the oxygen level will: decrease and the carbon dioxide level will increase.
What happens to oxygen level inside a container:The oxygen held inside the space is quickly being consumed by the freight or because of rusting inside a space, and that encased spaces must consistently be treated as perilous. And the carbon dioxide levels on the other hand will increase.
It will not take a long time for an animal to survive under these conditions.
Thus. option A is correct.
Find more information about Oxygen here:
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How many moles are in a sample of 2.39 x 10^23 atoms of sodium (Na)
Answer:
The answer is 0.4 molesExplanation:
To find the number of moles in a substance given it's number of entities we use the formula
[tex]n = \frac{N}{L} \\ [/tex]
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
[tex]n = \frac{2.39 \times {10}^{23} }{6.02 \times {10}^{23} } \\ = 0.39700996...[/tex]
We have the final answer as
0.4 molesHope this helps you
what is the name of CCI3
carbon trichlorine????
Carbon tetrachloride, also known by many other names (such as tetrachloromethane, also recognised by the IUPAC, carbon tet in the cleaning industry, Halon-104 in firefighting, and Refrigerant-10 in HVACR) is an organic compound with the chemical formula CCl4.
How does pentane and butane differ from each other
Answer:
Butane has only two isomers and pentane has just three, but some hydrocarbons have many more isomers than these. As you increase the number of carbon atoms in a hydrocarbon, the number of isomers quickly increases.
*
new
The process of wave erosion is a relatively
phenomenon on Earth.
10 points
о
True
о
False
The answer fam is......... False
Which of the following statements is true?
a) Carbon dioxide is easier to compress than water.
b) Plasma is made of free electrons, ions, and neutral atoms.
c) Bose-Einstein condensates form at very cold temperatures.
d) All of the above.
Answer:
All of the above
Explanation:
I know about the first two choices but not so much about the last one
The Following do not need sun's energy EXCEPT
a. rotating clock
b. evening torch
c. plowing man
d. winding stairways
Compounds have different properties than the elements they are made from because
A . They are produced from a chemical change . B. They are produced by a physical change. C. A new substance is not made . D. Smoke , change or color, production of gas does not occur during the process.
Answer:
D
Explanation:
In preschool, students have the current exchange system for toys: 4 orange blocks = 5 stickers
7 stickers = 2 toy soldiers
3 toy soldiers = 6 dinosaurs
How many dinosaurs (dino) will a student get if they have 16 orange blocks?
Answer:
11
Explanation:
16 orange blocks = 4*5stickers
20 stickers=20*2/7 toy soldiers =40/7 toy soldiers
40/7 toy soldiers=40/7*6/3 dinosaurs =40*2/7=80/7 =11.43 ~~ 11 dinosaurs
Question: Give the name for
the following compounds
1. MgF2
2. C2H6
3. Fe203
A piece of metal that has a density of 5.2 g/cm3 and a mass of 100 g was placed in a full jar of water. How many mL of water was spilled out of the jar? Note: one cm^3 = one mL
Answer:
100g / (5.2g/cm3)
= 100g / (5.2g / 1cm3)
= 100g x 1cm3 / 5.2 g
= 19.2 cm3
Since 1 cm3 = 1 ml, your answer is 19.2 ml.
The given density and mass of the metallic piece can be used to estimate the volume of the substance. The metal with a mass of 100 gm and a density of 5.2 g/cm³ has a volume of 19.23 ml.
What is the relation between density and volume?The density of the substance has been given by the ratio of mass to the volume of the substance in g/cm³ or g/mL. It shows the packaging of the molecules in the substances and has been in inverse relation to the volume.
The mass being constant and an increase in volume decreases the density of the substance and vice versa. The volume can be calculated as:
Volume = mass ÷ density
Given,
Density of the metal (ρ) = 5.2g/cm³
Mass of the metal piece (m) = 100g
Volume = V
Substituting the values above as:
ρ = m ÷ V
V = m ÷ ρ
V = 100 ÷ 5.2
= 19.23 mL
Therefore, 19.23 mL is the volume of water that spilled out of the jar.
Learn more about volume and density, here:
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What is the charge on an electron? -1 0 +1 +2
Answer:
to be honest I don't know
Explanation:
my brain won't work with this
Volcanic belts form along
a.
islands in the Pacific Ocean.
b.
North American mountain ranges.
c.
the boundaries of Earth’s plates.
d.
the coast of Antarctica.
Please select the best answer from the choices provided
An object with a mass of 1.2 g takes up a space of 2.4 mL. What is it's density?
Answer:
The answer is 0.5 g/mLExplanation:
The density of a substance can be found by using the formula
[tex]density = \frac{mass}{volume} \\ [/tex]
From the question we have
[tex]density = \frac{1.2}{2.4} \\ [/tex]
We have the final answer as
0.5 g/mL.Hope this helps you
the number of moles in 4.5 x 10^24 atoms of oxegen is
Answer:
The answer is 7.48 molesExplanation:
To find the number of moles in a substance given it's number of entities we use the formula
[tex]n = \frac{N}{L} \\ [/tex]
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
[tex]n = \frac{4.5 \times {10}^{24} }{6.02 \times {10}^{23} } \\ = 7.47508...[/tex]
We have the final answer as
7.48 molesHope this helps you
what is 1.23 x 10^-3 in standard notation
Answer:
=0.00123
Explanation:
Look at the attachments below
Hope this helps (:
Answer:
0.00123
Explanation:
Standard notation is the normal way of writing numbers. Examples include 1, 2, and 10. The number 1.23 x 10^-3 is written in scientific notation. The decimal goes after the first nonzero integer and it is multiplied by a power of 10. The power or exponent attached to the 10 tells you how many places over you need to move the decimal to get back into scientific notation. Examples include 1.00 x 10^2 (representing 100 in standard form because you would move the decimal two places to the right.), 2.0 x 10^1 (representing 20 in standard form because you would move the decimal one place to the right), and 3.0 x 10^-4 (representing 0.0003 in standard form because you would move the decimal four places to the left since it is a negative exponent).
The negative (-3) exponent in 1.23 x 10^-3 indicated to move the decimal three places to the left. If it was positive, you would move it three places to the right.
In 1.23 x 10^-3 move the decimal to the left 1 place to get:
0.123
two places to get:
0.0123
and a third place to get:
0.00123
The final answer is 0.00123
what is the mass of 10 moles of helium
Answer:
The mass of 10 moles of helium is: 2.5
How many moles of Al are there in 20g of Al2(C2O4)3?
Determine the number of moles of 725.0 g of BaSO4
Answer:
It would be 3.1063937724731447 moles.
Hope this helps :)
can you help me with percent abundance??
Percent abundance is the percentage of all the different isotopes of an element and is used to calculate the average atomic mass. For example 99.98% of all Hydrogen in the universe is [tex]^1H[/tex] meaning hydrogen with 1 proton and 0 neutrons while the remaining 0.02% is [tex]^2H[/tex] meaning that [tex]^1H[/tex] is the most abundant by percent.
why people on earth cannot see the entire shape of the milky way
Answer:
Explanation:
That is because the Milkyway is full of dust and gas, you cannot really see something if it has dust and gas
Answer:
Its too far away to see
Explanation:
You would probably have to be in space
The graph above compares three states of a substance.
Which of the following choices would NOT be an appropriate label for the y-axis?
A. motion of particles.
B. density of particles.
C. randomness of particles.
D. kinetic energy of particles.
Answer: is C
Explanation:
Identify the mineral that can have the composition of KMg3AlSi3O10(OH)2
Answer:
Phlogopite
Explanation:
It is a member of mica group family of phyllosilicates mineral. It is the magnesium endmember of the biotite stable - the chemical formulation KMg3AlSi3O10 (F, OH) 2.
What is the ratio of aluminum atoms to oxygen atoms in aluminum oxide?
Answer:
Al2 O3 or 2:3
Explanation:
The aluminum oxide consists of two elements, which are oxygen atoms and aluminum atoms, and there are 2 aluminum atoms and 3 oxygen atoms in aluminum oxide. The ratio from aluminum atoms to oxygen atoms is 2:3.
There are two types of chemical compound one is covalent compound and other is ionic compound, covalent compound formed by sharing of electron and ionic compound formed by complete transfer of electron. Therefore, the ratio of aluminum atoms to oxygen atoms in aluminum oxide is 2:3.
What is chemical Compound?Chemical Compound is a combination of molecule, Molecule forms by combination of element and element forms by combination of atoms in fixed proportion.
An ionic compound is a metal and nonmetal combined compound. Ionic compound are very hard. They have high melting and boiling point because of strong ion bond. The ratio of aluminum atoms to oxygen atoms in aluminum oxide is 2:3. Aluminium oxide is an ionic compound.
Therefore, the ratio of aluminum atoms to oxygen atoms in aluminum oxide is 2:3.
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Why are the coefficients before a chemical symbol important?F. They show the number of elements in each molecule.G. They indicate the number of molecules of each substance.H. They describe the number of times each molecule reacts.J. They explain the order in which the reaction takes place
Answer:They indicate the number of molecules of each substance
Explanation:
When we write chemical reaction equations, we usually put a number before the symbol of each reactant.
These coefficient shows the number of molecules of that specie that is involved in the balanced reaction equation for the reaction.
These coefficients are important because they are used in carrying out stoichiometric calculations.
What is the specific location water is in during each state of matter
2. When one plate is thrust under another plate it will create what landform?
a. Rift valley
b. Mountain range
C. Subduction zone-trench
d. Crater
Answer:
a
Explanation:
NEED HELP ASAP WITH THESE QUESTIONS GIVING FAIR AMOUNT OF POINTS IF HELPED WITH ALL QUESTIONS Violet light has a wavelength of 4.20 x 10-12 m. What is the frequency?
3. A photon has a frequency (n) of 3.468 x 106 Hz. Calculate its energy
Calculate the energy (E) and wavelength (l) of a photon of light with a frequency of 4.215 x 1014 Hz.
Calculate the frequency and the energy of blue light that has a wavelength of 400 nm
(h = 6.62 x 10-34 J-s).
Calculate the wavelength and energy of light that has a frequency of 9.5 x 1015 Hz.
A photon of light has a wavelength of 0.090 cm. Calculate its energy.
Calculate the energy and frequency of red light having a wavelength of 2.80 x 10-5 cm.
Calculate the energy (E) and wavelength (l) of a photon of light with a frequency of 5.165 x 1014 Hz.
The wavelength of green light from a traffic signal is centered at 7.20 x 10-5 cm. Calculate the frequency.
If it takes 1.56 seconds for radio waves (which travel at the speed of light) to reach the moon from Earth, how far away is the moon?
Calculate the frequency of light that has a wavelength of 4.20 x 10-9m. Identify the type of electromagnetic radiation.
Answer:
a) 7.14e19 Hz
b) 2.298e-27 J
c) 2.793e-19 J; 7.117e9 nm
d) 7.5e14 Hz; 4.96e-19 J
e) 6.2947e-18 J; 31.6 nm
f) 2.21e-22 J
g) 7.1e-19 J; 1.1e15 Hz
h) 3.422e-19 J; 581 nm
i) 4.2e14 Hz
j) 1.92e8 m
k) 7.14e16 Hz; Ultraviolet
Explanation:
Frequency: ν Wavelength: λ Energy: E Speed of light: C (3.00e8) Planck's Constant: h (6.626e-34)
ν -> λ λ = C/ν
λ -> ν ν = C/λ
For either of these equations, wavelength must be converted to meters or nanometers, depending on the equation.
For ν -> λ, after doing the equation, convert the wavelength into nanometers by dividing by 1e-9.
For converting λ -> ν, convert the wavelength into meters by multiplying by 1e-9.
For energy: E = hν = hc/λ
Now that the setup is out of the way:
a) Violet light has a wavelength of 4.20 x 10-12 m. What is the frequency?
λ -> ν ν = C/λ
[tex]\frac{3.00e8}{4.20e-12}[/tex] = 7.14e19 Hz
b) A photon has a frequency (n) of 3.468 x 106 Hz. Calculate its energy
E = hν = hc/λ
(6.626e-34) (3.468e6) = 2.298e-27 J
c) Calculate the energy (E) and wavelength (l) of a photon of light with a frequency of 4.215 x 1014 Hz.
E = hν = hc/λ
(6.626e-34) (4.215e14) = 2.793e-19 J
ν -> λ λ = C/ν
[tex]\frac{3.00e8}{4.215e14}[/tex] = 7.117 m
[tex]\frac{7.117m}{1}*\frac{1nm}{1e-9m}[/tex] = 7.117e9 nm
d) Calculate the frequency and the energy of blue light that has a wavelength of 400 nm (h = 6.62 x 10-34 J-s).
λ -> ν ν = C/λ
[tex]\frac{400 nm}{1} *\frac{1e-9m}{1nm}[/tex] = 4e-7 m
[tex]\frac{3.00e8}{4e-7}[/tex] = 7.5e14 Hz
E = hν = hc/λ
(6.626e-34) (7.5e14) = 4.96e-19 J
e) Calculate the wavelength and energy of light that has a frequency of 9.5 x 1015 Hz.
ν -> λ λ = C/ν
[tex]\frac{3.00e8}{9.5e15}[/tex] = 3.16e-8 m
[tex]\frac{3.16e-8m}{1}*\frac{1nm}{1e-9m}[/tex] = 31.6 nm
E = hν = hc/λ
(6.626e-34) (9.5e15) = 6.2947e-18 J
f) A photon of light has a wavelength of 0.090 cm. Calculate its energy.
E = hν = hc/λ
Convert the wavelength from cm to meters:
[tex]\frac{0.090cm}{1} *\frac{1m}{100cm}[/tex] = 9e-4 m
[tex]\frac{(6.626e-34)(3.00e8)}{9e-4}[/tex] = 2.21e-22 J
g) Calculate the energy and frequency of red light having a wavelength of 2.80 x 10-5 cm.
E = hν = hc/λ
Convert the wavelength from cm to meters:
[tex]\frac{2.80e-5cm}{1} *\frac{1m}{100cm}[/tex] = 2.8e-7 m
[tex]\frac{(6.626e-34)(3.00e8)}{2.8e-7}[/tex] = 7.1e-19 J
λ -> ν ν = C/λ
Convert the wavelength from cm to meters:
[tex]\frac{2.80e-5cm}{1} *\frac{1m}{100cm}[/tex] = 2.8e-7 m
[tex]\frac{3.00e8}{2.8e-7}[/tex] = 1.1e15 Hz
h) Calculate the energy (E) and wavelength (l) of a photon of light with a frequency of 5.165 x 1014 Hz.
E = hν = hc/λ
(6.626e-34) (5.165e14) = 3.422e-19 J
ν -> λ λ = C/ν
[tex]\frac{3.00e8}{5.165e14}[/tex] = 5.81e-7 m
[tex]\frac{5.81e-7m}{1}*\frac{1nm}{1e-9m}[/tex] = 581 nm
i) The wavelength of green light from a traffic signal is centered at 7.20 x 10-5 cm. Calculate the frequency.
λ -> ν ν = C/λ
Convert the wavelength from cm to meters:
[tex]\frac{7.20e-5 cm}{1} *\frac{1m}{100cm}[/tex] = 7.2e-7 m
[tex]\frac{3.00e8}{7.2e-7}[/tex] = 4.2e14 Hz
j) If it takes 1.56 seconds for radio waves (which travel at the speed of light) to reach the moon from Earth, how far away is the moon?
All we want to do here is to convert frequency (speed) to wavelength (distance). This problem requires a bit of thought, but it isn't bad once you realize that frquency is speed and wavelength is distance. It becomes just like the other problems after that. Also, I'll leave this distance in meters, but I think you can figure out how to convert it if it wants it in another unit.
One second is equal to 1 Hertz, so our frequency is 1.56 Hz.
ν -> λ λ = C/ν
[tex]\frac{3.00e8}{1.56}[/tex] = 1.92e8 m
The actual distance from the earth to the moon via google is 3.84e7, but sometimes problems like this will mess with the numbers to make sure that you didn't just look up the answer. I'm still pretty sure that this is right, however.
k) Calculate the frequency of light that has a wavelength of 4.20 x 10-9m. Identify the type of electromagnetic radiation.
First, we convert wavelength to frequency, as normal:
λ -> ν ν = C/λ
[tex]\frac{3.00e8}{4.20e-9}[/tex] = 7.14e16 Hz
Then we identify the electromagnetic wave type. You can look up a conversion chart for these on google, but since our frequency is in the e15 - e17 range, this light is considered ultraviolet.