how to calculate tax rebate​

Answer:

The equality is only true for [tex]a = 0\ and\ 1[/tex], not for all values

Step-by-step explanation:

Given

[tex](\sqrt a)^4 = a[/tex]

Required

Determine if it is valid

[tex](\sqrt a)^4 = a[/tex]

Evaluate the exponent

[tex](a^\frac{1}{2})^4 = a[/tex]

[tex]a^\frac{1*4}{2} = a[/tex]

[tex]a^2 = a[/tex]

Rewrite as:

[tex]a^2 - a = 0[/tex]

Factorize

[tex]a(a- 1) = 0[/tex]

[tex]a =0\ or\ a - 1 = 0[/tex]

[tex]a =0\ or\ a = 1[/tex]

The equality is only true for [tex]a = 0\ and\ 1[/tex], not for all values

Answer:

1. x = 2, y = -2 prod: -4 / 2 = -2

2. x = 6, y = -6 prod: -36 / 2 = -13

3. x = -1, y = -1 prod: 1 / 2 = 0.5

4. x = -4, y = -1 prod: 4 / 2 = 2

5. x = 10, y = -1 prod: -10 / 2 = -5

Answer:

we need the answer for median

Step-by-step explanation:

Answer:

its C

Step-by-step explanation:

Answer:

Domain: {2, 3, 4 }

Range: {3, 5, 7, 8}

Step-by-step explanation:

hope this helps and is right. p.s. i really need brainliest :)

Answer:

Step-by-step explanation:

Full circle is:

Arc length of LM is:

Correct choice is C

Length

Answer: the shark is at sea level

Step-by-step explanation: is you are 300 beneath the sea level that's -300 and if you go up 300 ft that +300. So 300+(-300) gives you 0 making the shark at sea level.

Answer:

30

Step-by-step explanation:

Answer:

3 times 10 + 5 times 1

Step-by-step explanation:

Answer:

Hi how are you doing today Jasmine

Answer:

i need help on this question

Step-by-step explanation:

Answer:

9

Step-by-step explanation:

To solve this question you need the formula of hypothenuse theorem, I personally use [tex]a^{2} + b^{2} = c^{2}[/tex].

Since [tex]c^{2}[/tex] is the hypothenuse, and the hypothenuse in this case is 15, the equation will be [tex]12^{2}+ b^{2} = 15^{2}[/tex].

144+[tex]b^{2}[/tex]=225

subtract 144 from both sides

[tex]b^{2}[/tex]= 81

[tex]\sqrt{b^{} } = \sqrt{81}[/tex]

b=9

Answer:

a) lilla has 1/5 of the book left to read

b) lilla has 15 pages left to read

Step-by-step explanation:

a) 1/5 + 3/5 = 4/5

b) 75÷ 5= 15

15× 4= 60

75-60= 15

Answer:

Adult =$7------x

Child=$4-------y

Total Tickets= 565= $2920

7x+4y = 2920

x+y= 565

x=565-y

7(565-y) + 4y= 2920

3955 - 7y +4y= 2920

-3y=2920-3955

y=1035/3= 345

x= 565-345= 220

child= 345

Answer:

Explore is Answer

Step-by-step explanation:

Answer:

the number of downloads of the standard version is 260

Step-by-step explanation:

Let us assume the downloads of the standard version be x

And, the download of the high-quality version be y

Now as per the question

2.5x + 4.4y = 4522 .........(1)

x + y = 1140

y = 1140 - x .......................(2)

Now put the value of equation 2 in the equation 1

So,

2.5x + 4.4 (1140 - x) = 4522

2.5x + 5016 - 4.4x = 4522

-1.9x = -494

x = 260

Hence, the number of downloads of the standard version is 260

Answer:

No they do not.

5/18 ≠ 1/2

If it did, it would be 9/18

Hope that helps!

Step-by-step explanation:

Answer:

200 ft squared of   W I N E

Step-by-step explanation:

W I N E

Answer:

498,000

Step-by-step explanation:

Step-by-step explanation:

[tex]( {m}^{15} )( {m}^{3} ) ^ {- 4} \\ = ( {m}^{15} )( {m}^{3 \times - 4} ) \\ = ( {m}^{15} )( {m}^{ - 12} ) \\ = {m}^{15 + ( - 12)} \\ = {m}^{15 - 12} \\ = {m}^{3} \\ {m}^{x} = {m}^{3} \\ x = 3[/tex]

Answer:

23

Step-by-step explanation:

1357/59

23

1357/59=23

:)

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Answer:

his salary per game is  669,643

Step-by-step explanation:

The computation of the salary per game in the year 2009 is shown below

Given that

His salary  in the year 2009 is 18,750,000

And, he pitched 28 games in the year 2009

Based on the above information

His salary per game is

= 18,750,000 ÷ 28 games

= 669,643

hence, his salary per game is  669,643

The same is relevant

Answer:

Step-by-step explanation:

20 dude hahah

Answer:

Your answer would be A and B

Step-by-step explanation:

Simply look for the coordinates on the graph and look for the name of the lines that intersect there.

Step-by-step explanation:

[tex]\\\\\\[/tex]

The equation of [tex]$\frac{45}{3}\left[\frac{90}{45}+3\left(19-16\right)\right][/tex] is 165.

PEMDAS exists as an acronym for the terms parenthesis, exponents, multiplication, division, addition, and subtraction.

Given:

[tex]$\frac{45}{3}\left[\frac{90}{45}+3\left(19-16\right)\right][/tex]

45/3 = 15

Simplifying the given equation, we get

[tex]$\frac{45}{3}\left[\frac{90}{45}+3\left(19-16\right)\right]=15\left[\frac{90}{45}+3(19-16)\right][/tex]

90 / 45 = 2

By simplifying the above equation, then we get

= 15[2 + 3(19 -16)]

By using the PEMDAS rule

15[2 + 3(19 -16)] = 11

[tex]$\frac{45}{3}\left[\frac{90}{45}+3\left(19-16\right)\right]= 15*11[/tex]

= 165

Therefore, the equation of [tex]$\frac{45}{3}\left[\frac{90}{45}+3\left(19-16\right)\right][/tex] is 165.

To learn more about PEMDAS rule refer to:

https://brainly.com/question/17297306

#SPJ2

9514 1404 393

Answer:

  19/21 hours, about 54 minutes 17 seconds

Step-by-step explanation:

The time is found from ...

  time = distance/speed

  time = (95 mi)/(105 mi/h) = 95/105 h = 19/21 h

The trains will meet after 19/21 hours, about 54 minutes, 17 seconds.

Answer:

19

Step-by-step explanation:

Answer:

Total # of students = 12 + 13 = 25

%-Boys = (12 / 25) x 100% = 48%

Step-by-step explanation:

Hello!

This is a problem about the general solution of a differential equation.

What we can first do here is separate the variables so that we have the same variable for each side (ex. [tex]dy[/tex] with the [tex]y[/tex] term and [tex]dx[/tex] with the [tex]x[/tex] term).

[tex]\frac{dy}{dx}=\frac{x-1}{3y^2}[/tex]

[tex]3y^2dy=x-1dx[/tex]

Then, we can integrate using the power rule to get rid of the differentiating terms, remember to add the constant of integration, C, to at least one side of the resulting equation.

[tex]y^3=\frac{1}{2}x^2-x+C[/tex]

Then here, we just solve for [tex]y[/tex] and we have our general solution.

[tex]y=\sqrt[3]{\frac{1}{2}x^2-x+C}[/tex]

We can see that answer choice D has an equivalent equation, so answer choice D is the correct answer.

Hope this helps!