How to find the equation of OB?

Answer:

C) 86

Step-by-step explanation:

To find the mean you first add all of the numbers together. So you would add 75+90+84+95=344. Then you would divide the sum by the amount if numbers there are. So it would be 344÷4 =86

Hope this helped :)

Answer:

x = 75, 90 , 84, 95

[tex]Mean = \frac{ \sum x}{n}= \frac{75+90+84+95}{4} = 86[/tex]

Answer:

0.1357 = 13.57% of bolts will have a diameter greater than 1.211 inches

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 1.20 inches and a standard deviation of 0.01 inches.

This means that [tex]\mu = 1.20, \sigma = 0.01[/tex]

What proportion of bolts will have a diameter greater than 1.211 inches?

This is 1 subtracted by the p-value of Z when X = 1.211. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{1.211 - 1.20}{0.01}[/tex]

[tex]Z = 1.1[/tex]

[tex]Z = 1.1[/tex] has a p-value of 0.8643.

1 - 0.8643 = 0.1357

0.1357 = 13.57% of bolts will have a diameter greater than 1.211 inches

Answer:

The arm routine lasts 10 minutes, and the abs routine lasts 15 minutes.

Step-by-step explanation:

Since Oscar is trying to incorporate more exercise into his busy schedule, and he has several short exercise routines he can complete at home, and last week, he worked out for a total of 35 minutes by doing 2 arm routines and 1 abdominal routine while That this week, he has completed 4 arm routines and 1 abdominal routine and spent a total of 55 minutes exercising, to determine how long does each routine last the following calculation must be performed:

2ARM + 1ABS = 35

4ARM + 1ABS = 55

4ARM + 1ABS - 2ARM - 1ABS = 55 - 35

2ARM = 20

ARM = 20/2

ARM = 10

2 x 10 + ABS = 35

ABS = 15

Therefore, the arm routine lasts 10 minutes, and the abs routine lasts 15 minutes.

x^2 + 21^2 = 29^2

x^2 + 441 = 841

x^2 = 841 - 441

x^2 = 400

x = √400

x = 20

Answer:

There is one solution

(2, 2)

Step-by-step explanation:

The solutions are where the line and curve intersect.

The isone point of intersection and therefor one solution (2, 2)

Answer:

answer is b.) one

Step-by-step explanation:

edge 2021

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

A graphing calculator is useful for this.

The region of interest is below the parabola and above the line.

Answer:

Easton entered in 25 shows last year.

Step-by-step explanation:

Given that Easton won best in show in 60% of the shows I have entered, to determine how many show was Easton entered if he won best in show 15 times last year, the following calculation must be performed:

60 = 15

100 = X

(100 x 15) / 60 = X

1,500 / 60 = X

25 = X

Therefore, Easton entered in 25 shows last year.

Answer:

(x+1)(x+3)(x+5)

Step-by-step explanation:

==========================================================

Explanation:

a = 8, b = 13, and c = 15 are the sides of the triangle

s = (a+b+c)/2 = (8+13+15)/2 = 18 is the semi-perimeter, aka half the perimeter.

Those values are then plugged into Heron's Formula below

[tex]A = \sqrt{s*(s-a)*(s-b)*(s-c)}\\\\A = \sqrt{18*(18-8)*(18-13)*(18-15)}\\\\A = \sqrt{18*(10)*(5)*(3)}\\\\A = \sqrt{2700}\\\\A = \sqrt{900*3}\\\\A = \sqrt{900}*\sqrt{3}\\\\A = 30\sqrt{3}\\\\A \approx 51.9615\\\\A \approx 52\\\\[/tex]

The triangular plaque has an area of approximately 52 square inches.

Answer:

Step-by-step explanation:

1 m =0.001 km

15m=15*0.001

=0.015 km

Answer:

20 lawyers

Step-by-step explanation:

48 ÷ 12 = 4

which means every year 4 lawyers are hired

5 × 4 = 20

so this means the law firm has hired 20 lawyers in the last 5 years

9514 1404 393

Answer:

  32%

Step-by-step explanation:

The man invested a total of ...

  3600 +150 = 3750

in the house. He sold it for a profit of ...

  4950 -3750 = 1200

The percentage profit on his investment is ...

  (1200/3750) × 100% = 32%

Answer:

a) This is the p-value of Z when X = A subtracted by the p-value of Z when X = B.

b) P-value of Z when X = 76 subtracted by the p-value of X = 68.

c) Because the underlying distribution(pulse rates of females) is normal.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

Mean [tex]\mu[/tex], standard deviation [tex]\sigma[/tex].

standard deviation of beats per minute.

a. If 1 adult female is randomly​ selected, find the probability that her pulse rate is between A beats per minute and B beats per minute.

This is the p-value of Z when X = A subtracted by the p-value of Z when X = B.

b. If 4 adult females are selected, find the probability that they have pulse rates with a mean between 68 beats per minute and 76 beats per minute.

Sample of 4 means that we have [tex]n = 4, s = \frac{\sigma}{\sqrt{4}} = 0.5\sigma[/tex]

The formula for the z-score is:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{X - \mu}{0.5\sigma}[/tex]

[tex]Z = 2\frac{X - \mu}{\sigma}[/tex]

This probability is the p-value of Z when X = 76 subtracted by the p-value of X = 68.

c. Why can the normal distribution be used in heartbeat even the sample side does not exceed 30?

Because the underlying distribution(pulse rates of females) is normal.

Answer:

2.9

hope this helps

have a good day :)

Step-by-step explanation:

Answer:

Step-by-step explanation:

area of circle=π*r^2

=3.14*2.5^2

=3.14*6.25

=19.625

=19.63

Answer:

1/5

Step-by-step explanation:

Answer:

as given 20%,

so 20% into fraction

20

100

=>1

5 is the answer

Answer:

The area is 36 inches

Step-by-step explanation: 18 * 2 = 36

Answer:

[tex]\boxed {\boxed {\sf 18 \ inches^2}}[/tex]

Step-by-step explanation:

The area is the amount of space inside the shape. The area of a triangle is half the product of the base and height.

[tex]a= \frac{1}{2} bh[/tex]

The base of the triangle is 18 inches and the height is 2 inches.

Substitute the values into the formula.

[tex]a= \frac{1}{2} (18 \ in)(2 \ in)[/tex]

Multiply the numbers in parentheses.

[tex]a= \frac{1}{2}(36 \ in^2)[/tex]

Multiply by 1/2 or divide by 2.

[tex]a= 18 \ in^2[/tex]

The area of the triangle is 18 square inches.

Answer:

y=-2/3x

Step-by-step explanation:

Perpendicular gradients(slopes) are negative reciprocals so first rearrange the given equation to find the gradient. y=3/2x-7/2

the gradient of the new line will be m=-2/3 then use the point (-3,-2) to find the equation of the line

y=mx+b

-2=(-2/3)(-3)+b

-2=2+b

b=0

y=-2/3x

Answer:

252

Step-by-step explanation:

To answer the equation, you first need to note that it asks for surface area.

To find surface area, you use an input formula, known as SA=2lw+2lh+2hw. 'H' stands for height, 'L' stands for length, and 'W' stands for width.

Since the current height is 12, the current length is 6, and the width is 3, you need to plug them into the equation.

SA=2(6)(3)+2(6)(12)+2(12)(3)

SA=252

Quick tip! It's tempting to just multiply them all at once, but using the power of distribution is vital to solving these equations.

Answer:

(D)

Step-by-step explanation:

The slope of the given line is (2/3) which means that a line perpendicular to it must have a slope of (-3/2).

Answer:

Step-by-step explanation:

x+2x+27=90

3x=90-27

3x=63

x=63/3

x=21

Answer:

x = 21

Step-by-step explanation:

Since ∠ PQR = 90° , then the sum of the 3 angles = 90° , that is

x + 2x + 27 = 90

3x + 27 = 90 ( subtract 27 from both sides )

3x = 63 ( divide both sides by 3 )

x = 21

Answer: B

Step-by-step explanation: An Isosceles triangle has two equal sides. A equallateral triangle has all the sides equal

Answer:

Complementary Angles - 3rd one (at the bottom)

Supplementary Angles - 2nd one (at the top-right)

Vertical Angles - 1st one (at the top-left)

Feel free to mark it as brainliest :D

Answer:

[tex]a:b = 8:3[/tex]

Step-by-step explanation:

To find the ration, we want to get in equation in the form [tex]\frac{a}{b} =\frac{x}{y}[/tex].

We can start by dividing by b on both sides:

3a = 8b

÷b     ÷b

[tex]\frac{3a}{b} = 8[/tex]

Now, we can divide by 3 on both sides to get:

[tex]\frac{a}{b} = \frac{8}{3}[/tex]

We can change the format into a ratio:

[tex]a:b = 8:3[/tex]

Answer:

C

Step-by-step explanation:

The answer is c because the point where they meet is -6 so it has to be all real number greater than.

Answer:

339.4cm³

Step-by-step explanation:

V

=

π

r

2

h

3

22/7×6²×9/3= 339.42

Answer:

[tex]I = \frac{1}{6}\cdot \sin^{2} 3x + C[/tex]

Where [tex]C[/tex] is the integration constant.

Step-by-step explanation:

We use integration by substitution to obtain the integral, where:

[tex]u = \sin 3x[/tex], [tex]du = 3\cdot \cos 3x\,dx[/tex]

[tex]I = \int {\sin 3x\cdot \cos 3x} \, dx[/tex]

[tex]I = \frac{1}{3} \int {u} \, du[/tex]

[tex]I = \frac{1}{6}\cdot u^{2} + C[/tex]

[tex]I = \frac{1}{6}\cdot \sin^{2} 3x + C[/tex]

Where [tex]C[/tex] is the integration constant.

Answer:

60 cm³

Step-by-step explanation:

Applying,

Volume (V) = Area of the base(A)×Height(h)

V = Ah................ Equation 1

From the diagram,

A =  Area of Trapezium

A = 1/2(a+b)c............. Equation 2

Substitute equation 2 into equation 1

V = [1/2(a+b)c]h........... Equation 3

Given: a = 3 cm, b = 7 cm, c = 3 cm, h = 4 cm

Substitute these values into equation 3

V = [3(3+7)/2]4

V = (3×10/2)4

V = (3×5)4

V = 15×4

V = 60 cm³

Answer:

a) 0.2981 = 29.81% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

b) 0.999 = 99.9% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes

c) 0.2971 = 29.71% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 8.9 minutes and a standard deviation of 2.9 minutes.

This means that [tex]\mu = 8.9, \sigma = 2.9[/tex]

Sample of 37:

This means that [tex]n = 37, s = \frac{2.9}{\sqrt{37}}[/tex]

(a) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes?

320/37 = 8.64865

Sample mean below 8.64865, which is the p-value of Z when X = 8.64865. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{8.64865 - 8.9}{\frac{2.9}{\sqrt{37}}}[/tex]

[tex]Z = -0.53[/tex]

[tex]Z = -0.53[/tex] has a p-value of 0.2981

0.2981 = 29.81% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

(b) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes?

275/37 = 7.4324

Sample mean above 7.4324, which is 1 subtracted by the p-value of Z when X = 7.4324. So

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{7.4324 - 8.9}{\frac{2.9}{\sqrt{37}}}[/tex]

[tex]Z = -3.08[/tex]

[tex]Z = -3.08[/tex] has a p-value of 0.001

1 - 0.001 = 0.999

0.999 = 99.9% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes.

(c) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes?

Sample mean between 7.4324 minutes and 8.64865 minutes, which is the p-value of Z when X = 8.64865 subtracted by the p-value of Z when X = 7.4324. So

0.2981 - 0.0010 = 0.2971

0.2971 = 29.71% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes