I am trying to find the answer to (in photo). But my calculator wont give me the answer. Does anyone know the answer to it? Or know how to calculate it without a calculator?

Answer:

[tex]\sqrt{13}[/tex] = 3.605551275......

Step-by-step explanation:

[tex]\sqrt{13}[/tex]

       3.6

3 [tex]\sqrt{13}[/tex]

     -9

36[tex]\sqrt{4}[/tex]00

do you need to know more... ??

9514 1404 393

Answer:

  √13 ≈ 3.60555127546

  "by hand": 3 4/7 or 398143/110425 or 3.6055 or 3 23/38

Step-by-step explanation:

Most on-line calculators, calculator apps for phone or tablet, and any spreadsheet can calculate this for you. The first attachment shows the result from the Go.ogle calculator.

Here, we describe 4 methods of approximating the root "by hand." That is, the calculations can be done with pencil and paper. They are easily within the capability of a 4-function calculator.

__

Method 1 -- Linear approximation

You can approximate it by hand in the following way.

√13 is between √9 = 3 and √16 = 4. As a first approximation, it is ...

  3 + (13 -9)/(16 -9) = 3 4/7 ≈ 3.57 ≈ 3.6

This is a linear interpolation between √9 and √16.

_____

Method 2 -- Babylonian method

The "Babylonian method" can be used to refine this approximation. For the next guess, average this number and the quotient 13 divided by this number.

  x = (3 4/7 + (13/(3 4/7))/2 = (25/7 + 13·7/25)/2 = (625 +637)/350 = 631/175

  x = 3 106/175 ≈ 3.6057 . . . . . . good to 3 decimal places

One more iteration will double the number of correct decimal digits.

  x = (3 106/175 + 13/(3 106/175))/2 = 398143/110425 ≈ 3.60555127915

(correct digits are highlighted)

_____

Method 3 -- "long division"

There is also a "long-division" method that develops the root one digit at a time. This is described in the second attachment, an extract from the NIST web site. For a number like 13, you would use 13.00 00 00 00 as the initial "dividend" to get a 4-digit root.

_____

Method 4 -- continued fraction

Once you realize that the root is between 3 and 4, you can write a "continued fraction" for the fractional part:

  3 +x = √13 . . . . . . where x is the fractional part of the root

  (3 +x)² = 13 . . . . . . square both sides

  x² +6x +9 = 13 . . . expand the square

  x(x +6) = 4 . . . . . . . subtract 9 and factor

  x = 4/(6 +x) . . . . . . write as an iterator (continued fraction)

At this point, we can say x = p/q for some integers p and q. Then the next iteration is ...

  p/q = 4/(6 +p/q) = 4q/(6q +p)

That is, successive approximations of x can be had by the transformation ...

  (p, q) ⇒ (4q, 6q+p)

Starting with the linear interpolation fraction x=4/7, the next refinements using this method are ...

  (p, q) = (4, 7) ⇒ (28, 46) = (14, 23)* ⇒ (92, 152) = (23, 38)

At this point, you have approximated the root as 3 23/38 ≈ 3.6053, accurate in the third decimal place. Convergence is clearly much slower than using the Babylonian method.

__

* We have reduced the fraction p/q = 28/46 to 14/23 in order to keep the numbers as small as possible. Similarly, 92/152 is reduced to 23/38.

3a^2+6b^3 a=3 and b=2

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