I dropped the ball from the roof of a building the speed when I hit the ground is 52 m/s how tall is the building

[tex]{\tt{\red{\underline{\underline{\huge{Answer:}}}}}}[/tex]

[tex]\longrightarrow[/tex] The rate of change of velocity per unit time is called acceleration.

[tex]\longrightarrow[/tex] Its SI unit is m/s².

[tex]\huge\boxed{\fcolorbox{blue}{red}{Thank you}} [/tex]

Answer:

harder daddy

Explanation:

Answer:

UV rays aid in the production of Vitamin D. But it can also give you cancer.

Explanation:

i am a scientist

Answer: heretidey and stress

Explanation:

Answer:

As the earth travels around the sun during the year it maintains this tilt. Because of this tilt, in the summer we (north of the equator) are slanted more directly towards the sun so it's hotter. In the winter, we're slanted away so the sun's rays are less direct, making it colder.

Answer:7800

work=force x distance

Force in Newtons

Distance in Meters

Work in Joules

Answer: the body is trained to wake up when the sun rises and get the energy from the sun and sleep and it is night on when the sun is not there. So when a watchman works at night there is no sun first of all to give him any kind of energy and secondly the body clock resists him waking up thus making him tired.

Explanation:

Explanation:

If we assume negligible air resistance and heat loss, we can assume that all of the Gravitational potential energy of the ball will turn into Kinetic energy as it falls toward the ground.

Therefore our Kinetic energy = mgh = (10kg)(9.81N/kg)(100m) = 9,810J.

Answer:

yeet yeet yeet yeet

Explanation:

Kinetic energy (K.E):-

So, the Mass of the Squirrel is 0.51 Kg (or) 510 grams.

A squirrel runs at a speed of 9.9 m/s with 25 J of kinetic energy.

What is the squirrel’s mass?

Answer: 0.51 kg

Explanation:

Kinetic Energy

= 0.5mv²

= 0.5(900kg)(25m/s)²

= 281,250J.

Answer: at the same time

Explanation: in a vacuum, there isnt air, right? so there isnt gravity pushing down on the heavier object, so they will both land at the same time.

good? :)

Answer: holding the ball in the air without moving it

Explanation:

When the ball goes up it’s potential energy

Throwing a ball high into the air is an example of kinetic energy being transformed into potential energy.

"Kinetic energy is a form of energy that an object or a particle has by reason of its motion. If work, which transfers energy, is done on an object by applying a net force, the object speeds up and thereby gains kinetic energy."

"Potential energy is the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors."

Know more about potential energy here

https://brainly.com/question/24284560

#SPJ2

Answer:

I think it is D

Explanation:

Answer:

D :D lol

Explanation:

Answer:

True

Explanation:

The object is at rest, which means it's not moving, so there is no net force on it, according to Newton's First Law.

Answer:

What is the meaning of the kinetic I think the answer is both the ball has both Kinetic and potential energy so I think is the answer is true

Answer:

It depends upon what you have given in the question but according to Ohm's law,

[tex]\boxed{V\:= I × R}[/tex]

where, V = voltage (v)

I = current (amperes)

R = resistance (Ω)

Other formulas are:

Hope it helps!<3

The question is not complete. The complete question is :

During a certain period of time, the angular position of a rotating object is given by [tex]$\theta =2t^2 +10t+5$[/tex], where θ is in radians and t is in seconds.  Determine the angular position, angular speed, and angular acceleration of the door (a) at t = 0.00 seconds, (b) at t = 3.00 seconds.

Solution :

Given :

Displacement or angular position of the object, [tex]$\theta =2t^2 +10t+5$[/tex]

∴ Angular speed is   [tex]$\omega = \frac{d \theta}{dt}$[/tex]

                                 ω = 10 + 4t

And angular acceleration is [tex]$\alpha = \frac{d \omega}{dt}$[/tex]

                                              α = 4

a). At time, t = 0.00 seconds :

   Angular displacement is [tex]$\theta =2t^2 +10t+5$[/tex]

                                            [tex]$\theta =2(0)^2 +10(0)+5$[/tex]

                                               = 5 rad

  Angular speed is  ω = 10 + 4t

                                 ω = 10 + 4(0)

                                     = 10 rad/s

Angular acceleration is α = 4 [tex]$rad/s^2$[/tex]

b). At time, t = 3.00 seconds :

   Angular displacement is [tex]$\theta =2t^2 +10t+5$[/tex]

                                            [tex]$\theta =2(3)^2 +10(3)+5$[/tex]

                                               = 53 rad

  Angular speed is  ω = 10 + 4t

                                 ω = 10 + 4(3)

                                     = 22 rad/s

Angular acceleration is α = 4 [tex]$rad/s^2$[/tex]

Answer:

Explanation:

Synthetic fabrics, such as nylon and polyester, are produced entirely from chemicals. Natural fabrics, such as cotton, silk, and wool are made of fibres from plants and animals. Synthetic fabrics are useful because they have very different or enhanced (improved) properties in comparison to natural materials.

Answer:

161.28m

Explanation:

The resultant is calculated using the formula

R² = dx²+dy²

R = √dx²+dy²

From the diagram. dx = 101cos60°+85

dx = 101(0.5) + 65

dx = 50.5 + 85

dx = 135.5m

For the vertical component dy

dy = dsin theta

dy = 101 sin 60

dy = 101(0.8660)

dy = 87.47

R = √135.5²+87.47²

R = √18,360.25+7,651.0009

R = √26,011.2509

R = 161.28m

Hence the magnitude of the sum of the vectors is 161.28m

Answer:

The sum of the two vectors is 161.278 m.

Explanation:

Given;

vector, B = 101 m inclined at angle 60⁰

vector, A = 85 m inclined at angle 0⁰

Y-component of the vectors;

[tex]R_y = 101(sin \ 60^0) + 85(sin \ 0^0) =87.466 \ m[/tex]

X-component of the vectors;

[tex]R_x = 101(cos \ 60^0) + 85(cos \ 0^0)\\\\R_x = 50.5 + 85 = 135.5 \ m[/tex]

Sum of the two vectors;

[tex]R = A+ B\\\\R = \sqrt{R_y^2 + R_x^2} \\\\R = \sqrt{87.466^2 \ + \ 135.5^2} \\\\R = \sqrt{26010.55} \\\\R = 161.278 \ m[/tex]

Therefore, the sum of the two vectors is 161.278 m.

Answer:

The escape velocity on the planet is approximately 178.976 km/s

Explanation:

The escape velocity for Earth is therefore given as follows

The formula for escape velocity, [tex]v_e[/tex], for the planet is [tex]v_e = \sqrt{\dfrac{2 \cdot G \cdot m}{r} }[/tex]

Where;

[tex]v_e[/tex] = The escape velocity on the planet

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

m = The mass of the planet = 12 × The mass of Earth, [tex]M_E[/tex]

r = The radius of the planet = 3 × The radius of Earth, [tex]R_E[/tex]

The escape velocity for Earth, [tex]v_e_E[/tex], is therefore given as follows;

[tex]v_e_E = \sqrt{\dfrac{2 \cdot G \cdot M_E}{R_E} }[/tex]

[tex]\therefore v_e = \sqrt{\dfrac{2 \times G \times 12 \times M}{3 \times R} } = \sqrt{\dfrac{2 \times G \times 4 \times M}{R} } = 16 \times \sqrt{\dfrac{2 \times G \times M}{R} } = 16 \times v_e_E[/tex]

[tex]v_e[/tex] = 16 × [tex]v_e_E[/tex]

Given that the escape velocity for Earth, [tex]v_e_E[/tex] ≈ 11,186 m/s, we have;

The escape velocity on the planet = [tex]v_e[/tex] ≈ 16 × 11,186 ≈ 178976 m/s ≈ 178.976 km/s.

Answer:

3 hours 71 minutes

Explanation:

As because Speed= distance/time taken

so time taken= 3.71

Answer:

The magnitude and direction of the centripetal acceleration will be:

[tex]a_c=5[/tex] m/s²   (towards the center of the circle).

Explanation:

Given

Using the formula to determine the centripetal acceleration

[tex]a_c=\frac{v^2}{r}[/tex]

[tex]a_c=\frac{\left(10\right)^2}{20}[/tex]

[tex]\:a_c=\frac{100}{20}[/tex]

[tex]a_c=5[/tex] m/s²

As the truck is moving in a circle, therefore the direction is towards the center of the circle.

Hence, the magnitude and direction of the centripetal acceleration will be:

[tex]a_c=5[/tex] m/s²   (towards the center of the circle).

F = ma

= 10kg × 2m/s

= 20N

Answer : 20N

Explanation :

F = Force (N)

m = mass (kg)

a = acceleration (m/s)

Answer:

4.81 L

Explanation:

From the question given above, we obtained the following information:

Initial temperature (T₁) = 298 K

Initial Volume (V₁) = 6 L

Final Temperature (T₂) = – 34 °C

Final Volume (V₂) =?

Next, we shall convert – 34 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

T(°C) = – 34 °C

T(K) = – 34 + 273

T(K) = 239 K

Thus, –34 °C is equivalent to 239 K

Finally, we shall determine the final volume of the balloon as follow:

Initial temperature (T₁) = 298 K

Initial Volume (V₁) = 6 L

Final Temperature (T₂) = 239 K

Final Volume (V₂) =?

V₁ / T₁ = V₂ / T₂

6 / 298 = V₂ / 239

Cross multiply

298 × V₂ = 6 × 239

298 × V₂ = 1434

Divide both side by 298

V₂ = 1434 / 298

V₂ = 4.81 L

Thus, the volume of the balloon when it was brought outside the store was 4.81 L.

Answer:

I think it's C I'm so sorry if I'm wrong.

Explanation:

Answer:

Explanation:

__________________________________________________________

Here's why this is the answer,

__________________________________________________________

Alex's Range = 3.20 - 0.90 = 2.30

Sanni's Range = 1.35 - 1.30 = 0.05

Chai's Range = 2.10 - 1.05 = 1.05

Jimmy's Range = 2.20 - 1.55 = 0.65

__________________________________________________________

Greatest to Least

Alex > Chai > Jimmy > Sanni

Here's why this is correct.

Alex = 2.30

Chai = 1.05

Jimmy = 0.65

Sanni = 0.05

I do not see the answer I have on this question so I think it is A.

__________________________________________________________

Hope this helps! <3

__________________________________________________________

Answer:

uniform an uniform

please fill it like yhis

Answer:

Its the third quarter or waning quarter

  Hope this helps :3

Answer:

21.67 m/s²

Explanation:

From the question given above, the following data were obtained:

Velocity (v) = 49.7 m/s

Radius (r) = 114 m

Centripetal acceleration (a) =?

The centripetal acceleration can be obtained by using the following formula:

a = v²/r

a = 49.7² / 114

a = 2470.09 / 114

a = 21.67 m/s²

Therefore, the centripetal acceleration of the car is 21.67 m/s²