i need the answer now plz

Answer:

1) 135 y 137, 2) 13 y 15, 3) El lado del cuadrado es de 14 unidades, 4) Se necesita 350 metros de valla, 5) El niño tiene 6 años de edad.

Step-by-step explanation:

1) El conjunto de los números naturales comprende al subconjunto de los números reales que son enteros y positivos. El enunciado se puede traducir con la siguiente expresión numérica:

[tex]x + (x+n) = 272[/tex]

Donde [tex]x[/tex] y [tex]n[/tex] son números naturales. Se despeja [tex]x[/tex]:

i) [tex]2\cdot x + n = 272[/tex] Propiedad asociativa/Definición de adición

ii) [tex]2\cdot x = 272-n[/tex] Compatibilidad con la adición/Existencia del inverso aditivo/Propiedad modulativa/Definición de sustracción

iii) [tex]x = \frac{272-n}{2}[/tex] Compatibilidad con la multiplicación/Existencia del inverso multiplicativo/Propiedad modulativa/Definición de división

iv) [tex]x = \frac{272}{2}-\frac{n}{2}[/tex]  [tex]\frac{x+y}{z} = \frac{x}{z} + \frac{y}{z}[/tex]

v) [tex]x = 136 - \frac{n}{2}[/tex] Definición de división/Resultado

Puesto que [tex]x[/tex] y [tex]n[/tex] son números naturales, [tex]\frac{n}{2}[/tex] también debe ser entero y para garantizar la consecución entre los números, [tex]n[/tex] debe ser el elemento natural más pequeño posible. El número natural más pequeño es 1, por tanto, el valor mínimo de [tex]n[/tex] es 2. En consecuencia, el valor de [tex]x[/tex] es:

[tex]x = 136-\frac{2}{2}[/tex]

[tex]x = 136-1[/tex]

[tex]x = 135[/tex]

Los dos números naturales consecutivos son 135 y 137.

2) El enunciado se puede traducir en las siguientes dos ecuaciones matemáticas:

[tex]x+y = 28[/tex]

[tex]x^{2}-y^{2} = 56[/tex]

Se despeja una de las variables de la primera ecuación y se elimina la variable correspondiente en la segunda ecuación:

[tex]x = 28-y[/tex]

[tex](28-y)^{2}-y^{2} = 56[/tex]

Se expande la ecuación resultante por álgebra de reales:

[tex]784-56\cdot y +y^{2}-y^{2} = 56[/tex]

[tex]784-56\cdot y = 56[/tex]

[tex]56\cdot y = 784-56[/tex]

[tex]56\cdot y = 728[/tex]

[tex]y = 13[/tex]

Finalmente, se halla el valor de la variable restante:

[tex]x = 28-13[/tex]

[tex]x = 15[/tex]

Los dos números naturales son 13 y 15.

3) Las fórmulas para el área ([tex]A[/tex]) y el perímetro del cuadrado ([tex]p[/tex]) son, respectivamente:

[tex]A = l^{2}[/tex]

[tex]p = 4\cdot l[/tex]

Donde [tex]l[/tex] es la longitud del lado del cuadrado.

De acuerdo con el enunciado, existe la siguiente condición:

[tex]A + p = 252[/tex]

[tex]l^{2}+4\cdot l = 252[/tex]

[tex]l^{2}+4\cdot l -252 = 0[/tex]

La ecuación resultante es un polinomio de segundo orden, cuyas raíces se obtienen por la Fórmula Cuadrática:

[tex]l_{1} = 14[/tex] y [tex]l_{2} = -18[/tex]

La primera raíz es la única solución razonable para la condición dada.

El lado del cuadrado es de 14 unidades.

4) Dado que la finca tiene una área rectangular y que se conoce la medida de la diagonal así como la diferencia entre el largo y el ancho, se puede determinar las variables restantes a partir del Teorema de Pitágoras:

[tex]d^{2} = l^{2}+w^{2}[/tex]

Donde:

[tex]d[/tex] - Diagonal, medida en metros.

[tex]l[/tex] - Largo, medido en metros.

[tex]w[/tex] - Ancho, medido en metros.

Además, las relaciones son las siguientes:

[tex]l = w + 25\,m[/tex]

[tex]d = 125\,m[/tex]

Se desarrolla y simplifica la identidad pitagórica hasta obtenerse un polinomio de segundo orden:

[tex]125^{2} = (w+25)^{2}+w^{2}[/tex]

[tex]2\cdot w^{2}+50\cdot w -15000 = 0[/tex]

Las raíces del polinomio se hallan con ayuda de la Fórmula Cuadrática:

[tex]w_{1} = 75[/tex] y [tex]w_{2} = -100[/tex]

Solo la primera raíz ofrece una solución razonable, el ancho del rectángulo es de 75 metros. Por último, se halla el largo de la figura:

[tex]l = 75\,m+25\,m[/tex]

[tex]l = 100\,m[/tex]

El largo del rectángulo es de 100 metros.

El perímetro del rectángulo ([tex]p[/tex]), medido en metros, es calculado por la siguiente fórmula:

[tex]p = 2\cdot (w+l)[/tex]

[tex]p = 2\cdot (75\,m+100\,m)[/tex]

[tex]p = 350\,m[/tex]

Se necesita 350 metros de valla.

5) Sea [tex]x[/tex] la edad actual del niño y [tex]l[/tex] el lado del cuadrado. Entonces:

[tex]x + 3 = l^{2}[/tex]

[tex]x -3 = l[/tex]

Se reemplaza el lado del cuadrado en la primera ecuación con ayuda de la segunda ecuación:

[tex]x+3 = (x-3)^{2}[/tex]

[tex]x +3 = x^{2}-6\cdot x + 9[/tex]

[tex]x^{2}-7\cdot x+6 = 0[/tex]

Las raíces se obtienen por factorización:

[tex](x-6)\cdot (x-1) = 0[/tex]

[tex]x = 6 \,\wedge \,x = 1[/tex]

Ambas raíces son parecen razonables, se comprueba cada una para ver si satisfacen las condiciones del enunciado:

x = 1

[tex]1+3 = l^{2}[/tex]

[tex]4 = l^{2}[/tex]

[tex]1-3 = l[/tex]

[tex]-2 = l[/tex]

Si bien está matemáticamente bien, no lo es en lo que respecta a edad.

x = 6

[tex]6+3 = l^{2}[/tex]

[tex]9 = l^{2}[/tex]

[tex]6-3 = l[/tex]

[tex]3 = l[/tex]

Esta solución es correcto en cuanto a matemática y edad.

El niño tiene 6 años de edad.

Step-by-step explanation:

I would say a speed/time line graph because those types of graphs are usually used for these scenarios in Physics problems.

Hope this helped!

Answer:

Hope this is helpful for you

Answer:

95°

Step-by-step explanation:

Here we have angles of 30° and 55°, so the remaining angle is:

Answer:

x=4

Step-by-step explanation:

move the variable to the left side and change its sign

20x-5x=65-5

collect like terms

15x=65-5

15x=60 divide both side by 15

x=4

Answer:

6)44

7)64

8)121

9)23

Step-by-step explanation:

6)5z-16=3z+8

z=12

7)4w+4=2w+22

w=9

8)9x-5=10x-19

x=14

9)3y-1=y+15

y=8

Answer:

w = -6/7

Step-by-step explanation:

Step 1:

-5/10w - 6/10 = 2/10w

Step 2:

-6/10 = 7/10w

Step 3:

-6/10 × 10/7w

Answer:

w = -6/7

Hope This Helps :)

Answer:

2376

Step-by-step explanation:

given 135MPH

convert it inches per second

as 1MPH=7.6 inches per second

so

135×7.6

2376 inches per second

Answer:

LOL, its Shuhuai from Accelerated Science. I just finished the question and copy and pasted it to check it. I'm like, nobody is going to answer this because my teacher just made it up. And I see the top result is your comment,  but hey at least I got the question correct. But yeah, i just thought it was a bit coincidental lol.

Step-by-step explanation:

Answer:

y=3/4x+45

Step-by-step explanation:

Answer:

the equation is 1/3x + 2

Answer : The price per ounce of funyuns is $0.356.

Step-by-step explanation :

As we are given that the price of 7 ounce bag of funyuns is $2.49.

Now we have to determine the price per ounce.

According to the question,

As, 7 ounce bag of funyuns = $2.49

So, 1 ounce bag of funyuns = [tex]\frac{1\text{ ounce}}{7\text{ ounce}}\times \$ 2.49[/tex]

                                             = $0.356

Therefore, the price per ounce of funyuns is $0.356.

Answer: 37/40

Step-by-step explanation:

divide 185 by 5 and same with 200 so your answer is 37/40

please mark me brainliest :)

Answer: Yes they are like terms

They both have the same variable so that is why they are like terms.

We can think of 'd' representing something like "dogs" maybe

d = 1 dog

2d = 2 dogs

3d = 3 dogs

4d = 4 dogs

and so on

Adding 2d with 4d gets us 2d+4d = 6d meaning we have 6 dogs overall if we started with 2 and added on 4 more. This is one way to help see why we can combine like terms.

In contrast, something like 2c+4d cannot be combined since having 2 cats and 4 dogs doesn't result in 6 cats or 6 dogs. We just simply leave it as 2c+4d.

Answer:

I believe it's positive 2

Answer:

where is the rest of the context?

Answer:

Walter earns $1,517 more than Stevens in one year.

Step-by-step explanation:

Giving the following information:

Two brothers Steven and Walter each inherit $41,000

Steven:

Annual return= 2.7%

Walter:

Annual return= 6.4%

To determine the future value for the brothers, we need to use the following formula:

FV= PV*(1+i)^n

Steven:

FV= 41,000*1.027= $42,107

Walter:

FV= 41,000*1.064= $43,624

Difference= 43,624 - 42,107= $1,517

Walter earns $1,517 more than Stevens in one year.

Length of rectangle = x - 7

Width of rectangle = x + 12

We have to find area of rectangle[tex].[/tex]

_________________________________

[tex]:\implies\sf\:Area=Length\times Width[/tex]

[tex]:\implies\sf\:Area=(x-7)(x+12)[/tex]

[tex]:\implies\sf\:Area=x^2+12x-7x-84[/tex]

[tex]:\implies\bf\:Area=x^2+5x-84[/tex]

Answer:

15 DEGREES

Step-by-step explanation:

OK SO BASICALLY,  USING THE EXTERIOR ANGLES THEOREM, YOU FIND THAT 9x = 5x + something. That something is 4x so:

9x = 5x + 4x

THEN YOU FIND THAT 8x = 5x + something. That something is 3x so:

8x = 5x + 3x

4x and 3x and 5x are the interior angles of the triangle (ABC)

Then you use triangle theorem and get 4x + 3x + 5x = 180

Then: 12x = 180 and so you get x = 15

Answer:

The number of times it would take more than 27 minutes to manufacture a pair of running shoes is 2.275 times or approximately 2 times per every 100 shoes

Step-by-step explanation:

The average time it takes to manufacture a pair of shoes = 21 minutes;

The standard deviation = 3 minutes

To find how often it takes more than 27 minutes to manufacture a pair of running shoes, we have;

Standard score, given as follows;

[tex]Z=\dfrac{x-\mu }{\sigma }[/tex]

Where;

x = The raw score = 27 minutes

μ = The average score = 21 minutes

σ = The standard deviation = 3 minutes

From which we have;

[tex]Z=\dfrac{27-21 }{3 } = 2[/tex]

Therefore, it is borderline unusual with a p value of P(z>2) = 1 - 0.97725 = 0.02275

Therefore, the number of times out of 100 that it would take more than 27 minutes to manufacture a pair of running shoes = 100 × 0.02275 = 2.275 times which is approximately 2 times in every 100 shoes.

Answer: The answer should be

C) f(t)=1.5t+5

Answer: The next two terms are 33 and 39

Step-by-step explanation:

9,15,21,27    

First determine how you get from one value to the other.

To get from 9 to 15 you add 6.

To get from 15 to 21 you add 6 to 15.

And to get from 21 to 27 you add 6 to 21  

So to get to the next term add 6 and another 6 to the value you get.

27 + 6 = 33

33 + 6 = 39

Answer:

c represents the number of classes

6 + 5c = 6c

Can you solve for c and answer?

Answer:

[tex]g(x) = -(x - 2)^2[/tex]

[tex]k(x) = -\frac{x}{2} - 1[/tex]

[tex]h(x) = 2^x - 7[/tex]

[tex]f(x) =\sqrt{x}[/tex]

Step-by-step explanation:

Given

Input = 6

Expected Output = 11

Process:

[tex]f(x) =\sqrt{x}[/tex]

[tex]g(x) = -(x - 2)^2[/tex]

[tex]h(x) = 2^x - 7[/tex]

[tex]k(x) = -\frac{x}{2} - 1[/tex]

Required

Arrange the processes to give an output of 11

To answer this question, I'll make use of trial by error methods.

After some attempts, the following is the order of the processes;

Set x = 6

Substitute 6 for x in g(x)

[tex]g(x) = -(x - 2)^2[/tex]

[tex]g(6) = -(6 - 2)^2[/tex]

[tex]g(6) = -(4)^2[/tex]

[tex]g(6) = -16[/tex]

Substitute -16 for x in k(x)

[tex]k(-16) = -\frac{-16}{2} - 1[/tex]

[tex]k(-16) = -(-8) - 1[/tex]

[tex]k(-16) = 8 - 1[/tex]

[tex]k(-16) = 7[/tex]

Substitute 7 for x in h(x)

[tex]h(x) = 2^x - 7[/tex]

[tex]h(7) = 2^7 - 7[/tex]

[tex]h(7) = 128 - 7[/tex]

[tex]h(7) = 121[/tex]

Substitute 121 for x in f(x)

[tex]f(x) =\sqrt{x}[/tex]

[tex]f(121) = \sqrt{121}[/tex]

[tex]f(121) = 11[/tex]

Hence, the processes is:

[tex]g(x) = -(x - 2)^2[/tex]

[tex]k(x) = -\frac{x}{2} - 1[/tex]

[tex]h(x) = 2^x - 7[/tex]

[tex]f(x) =\sqrt{x}[/tex]

Answer:

XZ=19

Step-by-step explanation:

the total length of the segment is 37, and half of the segment is 18, so to find the other half of the segment, you would subtract the half from the total amount: 37-18=19

hope this helps

Answer:

33/25 should be the answer

Step-by-step explanation:

Answer:

-2 is the answer

Step-by-step explanation:

mark as me brainlist

Answer:

C.

Step-by-step explanation:

Answer:

n=9

Step-by-step explanation:

LCM(n,15)=45

LCM(9,15)=45

Answer:

4

Step-by-step explanation:

Answer:

7/4 or 1.75 or 1 3/4

Step-by-step explanation:

try to use a scientific calculator and then that will be your answer that I came up with.