I understand how a change in the size of the moon jellies' resource population can change the number of births in the moon jelly population.
Responses

Explain your answer choice.

Answers

Answer 1

A change in the size of the moon jellies' resource population can change the number of births in the moon jelly population because the big size of the resources can produce more births.

How do moon jellies reproduce?

When there is more energy storage molecules present in the moon jellies, they can reproduce more, in more births. Fewer deaths would also lead to the jelly population increasing. The sea turtle population, and the moon jellies consumer population is also decreased.

There must be a change to the birth rate or the death rate in the moon jelly population. Within a population, organisms are born and dying continuously. If the number of births and deaths in a given time interval are equal, then the population size will remain stable.

So we can conclude that a large population of resources will lead to more births.

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Related Questions

Which statement is true about the potential energy diagram for an endothermic reaction? (5 points)
The potential energy of the products is equal to the potential energy of the reactants.
It starts at a higher energy value and ends at a lower energy value.
The energy value remains the same throughout the diagram.
Products have more potential energy than reactants.

Answers

Answer:

Products have more potential energy than reactants.

As shown in the image.

Which of these is an example of a physical property?

A. Potassium ignites when placed in water.

B. Iron melts at 1,535 °C.

C. Hydrogen combines with oxygen to form water.

D. Chlorine oxidizes bacterial cells.​

Answers

Answer: B is correct.

Explanation:

Answer A is a chemical change because of intense changes of color and expansion.

Answer C is a chemical change, as hydrogen and water are chemically bonding together.

Answer D is a chemical change because oxidation involves loss of electrons during a chemical reaction.

On the other hand, melting is a physical change. Therefore, answer B is the correct answer.

Antigens are substances that may induce immune response as they are recognised and bound by antibodies or cells of the immune system.
Based on your knowledge of the structures of bacteria and viruses, can you suggest some examples of molecules that are antigenic?

Answers

Some examples of molecules that are antigenic may be proteins and or polysaccharides in the cell wall of pathogenic bacteria which may be targeted by the immune system during the production of antibodies.

What is the relationship between antigens in pathogenic bacteria and antibodies of the immune system?

The relationship between antigens in pathogenic bacteria and antibodies of the immune system is based on the fact that antigens are biomolecules in the pathogens that can be targeted to bond antibodies that are produced by the organism in immune responses against bacteria, viruses, and allergens in the air and foods, etc.

Therefore, with this data, we can see that antigen molecules be any type of biomolecule present in the pathogen and the relationship between antigens in pathogenic bacteria and antibodies of the immune system is based on the binding between them (antigens and antibodies) which is fundamental during certain specific immune responses.

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If hydrogen diffuses at the rate of 10 cm³ per second from a given apparatus under given conditions of temperature and pressure, calculate under same conditions: a) the volume of oxygen (O₂) which diffuses in 20 seconds ​

Answers

Answer:

Volume of O₂ = 200cm³

Explanation:

Rate of diffusion of gas is directly and inversely proportional to the volume and time taken for the gas to diffuse completely.

Volume

R = -----------

time

let R₁ represent the rate at which the given volume of hydrogen gases diffuses and R₂ represent the rate at which the the volume of the oxygen gas diffused.

V₁, V₂, T₁ and T₂ follows the same process

If the two gases diffuses at the same rate, then;-

R₁ = R₂

V₁ V₂

---------- = ------------

T₁ T₂

V₂

10 = ----------------

20

V₂ = 20•10

V₂ = 200cm³

Therefore, the volume of oxygen that could diffuse in 20 seconds is 200cm³

If 160 grams of a 200-gram sample of gold-198 decay in 6.25 days, what is the half-life of gold-198?

Answers

The half-life of gold-198 is 2.77 days

What is half-life of gold-198?Gold-198 decays with a half-life of 2.7 days to stable mercury-198 by emission of ß particles of maximum energy 0.960 Mev and Y -rays of energies 0.412, 0.68 and 1.09 Mev as shown schematically in  In a gold grain, the thickness of the enveloping sheath of platinum is such that the ß particles: The amount of time it takes to disintegrate by half an initial amount. For a given reaction, a reactant's half-life t1/2 is the time it takes for its concentration to reach a value which is the arithmetic mean of its initial and final (equilibrium) value.Since Au-198 is 200 g originally and it decays to 160 g, so 40g leftthe fraction decay is 40/200 = 0.2the time base is 6.25 daysln0.2/6.25 = -0.25k=ln2/half life therefore half-life = ln2/k = ln2/0.25half life = 2.77 daysSo, half life of gold is 2.77 days

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order these elements by decreasing electron affinity:
Na, Al, S, K, F

Answers

Answer:

increasing to decreasing:

F--- S--- Al--- Na--- K

not sure...

how do you test the methods of cleaning an oil spill while not risking the lives of the organisms

Answers

Answer:

Get a controlled environment, such as a pool or even a bowl. Pour some oil in it then you can test your solutions without causing any damage.

Explanation:

I need help in this please

Answers

it reflects back into the glass with a 45 degree angle of reflection.

What is refraction?

The direction of the light changes as it passes through the air-water barrier. Refraction is the name for this phenomenon. Filling a glass with water and inserting a straw will make it simple to see. It will seem as though the straw is shattered.

Because light travels at a different speed in air and water, refraction takes place. The electromagnetic properties of a specific medium, which differ for air and water, determine the speed at which a light wave propagates in that medium. The speed of light in the air is very near to the vacuum's speed of light, which is 3*108 m/s. The speed of light is slower underwater. Consequently, The direction of the light changes as it passes through the air-water barrier. Refraction is the name for this phenomenon. Filling a glass with water and inserting a straw will make it simple to see. It will seem as though the straw is shattered.

A form of break occurs in the wavefront of propagating light when it encounters the air-water barrier, causing the ray of light to diverge from its original path. (Please go to the reference link for a more thorough explanation and instructions on how to calculate the light's refraction angle.)

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What is the mass of a 8.45 m3 piece of copper?

Answers

The mass of a 8.45 m3 piece of copper is 7537.4 grams.

What is mass?

Mass is described as a dimensionless quantity representing the amount of matter in a particle or object.

density of copper =8.92g/cm^3

volume = 8.45 x 100 cm^3

mass =  (8.45 x 100) x 8.92

mass = 7537.4 grams.

The relationship between mass, density and volume is that density offers a convenient means of obtaining the mass of a body from its volume or vice versa.

This means that the mass is equal to the volume multiplied by the density (M = Vd), while the volume is equal to the mass divided by the density (V = M/d).

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PROBLEM 1.22 Give the hybridization state of each carbon in the following

compounds:

(a) Carbon dioxide (0 = C = O)

(d) Propene (C*H_{3}*CH = C*H_{2})

(b) Formaldehyde (H_{2}*C = O)

(e) Acetone [(CH 3 ) 2 C = OI

(c) Ketene (H_{2}*C = C = O)

(f) Acrylonitrile ( C*H_{2} =CHC equiv N)

SAMPLE SOLUTION

(a) Carbon in C*O_{2} is directly bonded to two other atoms. It

is sp-hybridized.

Answers

To solve this we must be knowing each and every concept related to hybridisation. Therefore, the hybridisation of the given molecule can be given as below.

What is hybridisation?

Only during bond formation does hybridization occur, not in an individual gaseous atom. If the bonding of a molecule is known, the geometry of the molecule may be predicted.

compound                                                              hybridisation

Carbon dioxide (0 = C = O)                                       sp

Propene (CH[tex]_3[/tex]CH = CH[tex]_2[/tex])                                            sp³, sp²,sp²

Formaldehyde (H[tex]_2[/tex]C = O)                                             sp²

Acetone [(CH[tex]_3[/tex] )[tex]_2[/tex] C = O                                                 sp³, sp²,      sp³

Ketene (H[tex]_2[/tex]C = C = O)                                                  sp²,    sp

Therefore, the hybridisation of the given molecule can be given as above.

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Combustion of 1.125 of an unknown compound containing carbon, hydrogen, and oxygen resulted in 1.649g of CO2 and 0.675g of H2O. If the molar mass is 180g/mol What is the molecular formula?
CxHyOz + O2 → CO2 + H2O

Answers

The molecular formula of the unknown compound, given that it contains carbon, hydrogen, and oxygen is C₆H₁₂O₆

How do I determine the molecular formula?

First, we'll begin by obtaining the mass of carbon, hydrogen and oxygen. Details below:

For Carbon

Mass of CO₂ = 1.649 gMolar mass of CO₂ = 44 g/mol Molar of C = 12 g/mol Mass of C =?

Mass of C = (12 / 44) × 1.649

Mass of C = 0.45 g

For Hydrogen

Mass of H₂O = 0.675 gMolar mass of H₂O = 18 g/mol Molar of H = 2 × 1 = 2 g/mol Mass of H =?

Mass of H = (2 / 18) × 0.675

Mass of H = 0.075 g

For Oxygen

Mass of compound = 1.125 gMass of C = 0.45 gMass of H = 0.075 gMass of O =?

Mass of O = (mass of compound) - (mass of C + mass of H)

Mass of O = 1.125 - (0.45 + 0.075)

Mass of O = 0.6 g

Next, we shall determine the empirical formula. details below:

C = 0.45 gH = 0.075 gO = 0.6 gEmpirical formula =?

Divide by their molar mass

C = 0.45 / 12 = 0.0375

H = 0.075 / 1 = 0.075

O = 0.6 / 16 = 0.0375

Divide by the smallest

C = 0.0375 / 0.0375 = 1

H = 0.075 / 0.0375 = 2

O = 0.0375 / 0.0375 = 1

Thus, the empirical formula of the compound is CH₂O

Finally, we shall determine the molecular formula. Details below:

Molar mass of compound = 180 g/molEmpirical formula = CH₂OMolecular formula =?

Molecular formula = empirical × n = mass number

[CH₂O]n = 180

[12 + (2×1) + 16]n = 180

30n = 180

Divide both sides by 30

n = 180 / 30

n = 6

Molecular formula = [CH₂O]n

Molecular formula = [CH₂O]₆

Molecular formula = C₆H₁₂O₆

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2. The nonmetals in the Groups 16 and 17________.
a) lose electrons when they form ions
b) gain electrons making them an anion
c) all have ions with a -1 charge
d) end in -ate

Answers

The nonmetals in the Groups 16 and 17 gain electrons making them an anion.

Why gaining electrons is a significant characteristic of nonmetals in Groups 16 and 17?

The nonmetals of group 16 are made up of Oxygen, Sulfur, and Selenium whereas group 17, also called the halogen group is made up of Fluorine, Chlorine, etc.

The further right we go in the periodic table, the atomic size decreases. Due to the increase in the number of protons, the electrons are more tightly bound and the atom shows strong attraction to electrons.  

The gain of additional electrons helps in the completion of octets for the atoms further making their configuration stable, and more alike to that of the noble gases.

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What is a flame test used for?
A. To identify an unknown sample by its emission spectrum
B. To determine the ionization energies of electrons
C. To remove impurities from a sample through burning
D. To identify an unknown sample by its melting point

Answers

The flame test used for to identify an unknown sample by its emission spectrum

What is the purpose of a flame test?A metal or metalloid ion discovered in an ionic compound can be identified, or at least its potential identification, using the flame test, a qualitative chemical test. It's possible for the compound to emit a distinctive colour that may be seen with the unaided eye if it's placed in a gas burner's flame. To determine whether metal and metalloid ions are present in the sample, chemists employ a qualitative examination known as a flame test. The metal ions heated in the gas burner don't all produce colour. The quickest and most straightforward method for determining whether group 1 metal ions are present in the chemical is a flame test. A wire or wooden splint is dipped into a sample solution or coated with the substance to be tested.

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Answer: to identify an unknown sample by its emission spectrum

Explanation:

Explain how an incorrect of dietary information on high blood sugar could potentially affect the patient’s

Answers

Long-term (months or years) high blood sugar levels can cause irreversible harm to organs such the kidneys, blood vessels, eyes, nerves, and nervous system. Speak with your doctor or the diabetes care team if you frequently have hyperglycemia.

What effects could an extremely high blood sugar level have on us?

If left untreated, having excessive blood sugar levels for an extended length of time might lead to major health issues. In addition to raising the risk of heart disease, stroke, kidney illness, vision issues, and nerve issues, hyperglycemia can harm the blood arteries that provide blood to essential organs.

What dietary requirements are impacted by diabetes?

A high-fat, high-calorie, and high-cholesterol diet

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Which of these is an example of a physical property?

A. Iron combines with oxygen to rust.

B. Potassium reacts in water to form a base.

C. Sodium metal is soft and malleable.

D. Sodium ignites when placed in water.​

Answers

The answer is C. This is because it’s soft and malleable.

A sample of helium was compressed at 35 °C from a volume of 0.5 L to 0.25 L where the pressure is 500 mmHg. What was the original pressure?

Answers

Answer:

The ideal gas law is a formula that relates the pressure, volume, temperature, and number of moles of a gas. It can be expressed as:

PV = nRT

where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of the gas, R is the gas constant, and T is the temperature in Kelvin.

Since the number of moles and the temperature are constant in this problem, we can rearrange the formula to solve for the pressure:

P = (nRT) / V

Plugging in the known values, we get:

P = (nRT) / V

= (n * R * (35 + 273)) / 0.25 L

= (n * R * 308 K) / 0.25 L

We are given that the pressure is 500 mmHg and the volume is 0.25 L at this pressure, so we can set these equal:

500 mmHg = (n * R * 308 K) / 0.25 L

Solving for n, we get:

n = (500 mmHg * 0.25 L) / (R * 308 K)

We know that the pressure and volume of the gas at its original state are what we are trying to solve for. Let's call the original pressure P_0 and the original volume V_0. We can then express the relationship between the original and final state of the gas as:

P_0 * V_0 = n * R * T

Substituting the expression we found for n and the known values, we get:

P_0 * V_0 = ((500 mmHg * 0.25 L) / (R * 308 K)) * R * 308 K

Solving for P_0, we get:

P_0 = (500 mmHg * 0.25 L) / (R * 308 K) * (R * 308 K) / V_0

= (500 mmHg * 0.25 L) / (V_0)

Since V_0 = 0.5 L, we can substitute this value to get:

P_0 = (500 mmHg * 0.25 L) / (0.5 L)

= 500 mmHg / 2

= 250 mmHg

Therefore, the original pressure of the gas was 250 mmHg.

Why don’t different varieties of corn plants grow to the same size under similar growing conditions?

Answers

Because they were planted at different times in different conditions

An experiment requires 65.00 g of sodium chloride. Sodium chloride is available at a price of $179.0 per 5.000 kg sodium chloride. What is the cost of the sodium chloride in the experiment (reported to the hundredths place because we're working with dollars)?

Answers

Answer: on

Explanation:5

The price of sodium chloride per 5 kg is 179 dollars. The experiment requires 65 g of NaCl. The price of65 g or 0.065 kg is 2.3 dollars.

What is sodium chloride?

Sodium chloride is an ionic compound formed by the combination of sodium metal and chlorine atom. Sodium metal has extra one electron in its valance shell and chlorine needs one more electron into its valence shell. Hence sodium donates its valence electron to chlorine forming NaCl.

NaCl is used as the table salt in food. It is a very important compound in our daily diet. Similarly NaCl is industrially important for many reaction especially in electrochemical processes.

It is given that, the price of 5 kg of NaCl = $179

required mass of NaCl = 65 g = 0.065 Kg

then , price of 0.065 kg = (0.065 × 179 /5) =  $2.31

Therefore, the cost of NaCl in the experiment is 2.31 dollars.

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When the conductivity is at a minimum, what must be true about the amount of Ba(OH)2?

Answers

When the conductivity is at a minimum, the true thing about the amount of Ba(OH)₂ is that the amount of the two reactants are the same when conductivity is low.

What is conductivity?

The ability of an aqueous solution to carry an electric current is measured by its conductivity. Ionic strength is measured by conductivity monitors. In automated chromatography systems, conductivity is the main input control parameter used to enable the generation of salt gradients or to control buffer dilution or in-line buffer preparation.

Conductivity monitors can be used to automate and monitor cleaning and equilibration procedures. It's important to remember that temperature affects measurements of conductivity and pH.

When conductivity is low, the amounts of the two reactants are equal. Between the reactants, there are no excesses. The aqueous solution cannot dissolve the precipitate BaSO₄. Since there are no ions, the conductivity is at its lowest.

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Complete question

The Ba(OH)₂ dissociates as Ba+2 + 2 OH-. H₂SO₄ dissociates as 2 H+ + SO₄-2. When the conductivity is at a minimum, what must be true about the amount of Ba(OH)₂ compared to H₂SO₄

What is the hybridization of all the atoms (other than hydrogen) in each of the following species?
Drag the appropriate items to their respective bins.

Answers

The hybridization of C in HCN is sp because, carbon is triple bonded to the nitrogen. Hybridization of N in HCN is also sp. Hybridization of nitrogen in NH₄ is sp³.

What is hybridization?

When tow atoms combines to form a molecules, the energy of individual atomic orbitals redistribute to form  hybrid orbitals of  equivalent energy. The type of hybridization s based on the on the involvement of s, p or d orbitals of the atom.

In HCN, carbon is triple bonded to nitrogen. Here, both s and p orbital contribution is 50%. Hence, both C and N in HCN in sp hybridized.

In NH₄, the nitrogen is sigma bonded to each hydrogen and the hybridization of N is sp³ here since, 3 p orbitals of nitrogen and one s orbital are involved.

In CH₃-,  C is sp² hybridized and in CH₃⁺ , C is sp³ hybridized. The C in C(CH₃)₄ is also sp³ hybridized where carbon involves sigma bonds with the methyl groups.

N in NH₃ is sp³ hybridized. Oxygen in water is sp² hybridized. When water abstracts one more proton forming H₃O⁺ , oxygen forms sp³ hybridized orbitals.

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A dairy is mainly involved in the operations of bottling of milk, making ice-cream and limited production of cheese. Calculate the BOD produced per 1000kg of milk processed and its population equivalent from the following data;
Quantity of milk processed daily=150000kg Waste water produced daily =240m3 BOO of waste water =1400mg/I Population equivalent per capita per day of 5-days BOD at 20C°=75g

Answers

Answer:

BOD produced per 1000kg of milk processed = (1400mg/I x 240m3) / 150000kg = 0.192mg/I

Population equivalent = (0.192mg/I x 75g) / 5 = 0.576g

Explanation:

Which fuels are non-renewable

Answers

Answer:

fossil fuels

Explanation:

Well I had some topics on this stuff last quarter in science and from what I can remember it should be fossil fuels I think that fossil fuels are technically renewable but they are considered non-renewable since they are either in small supplies, are hard to obtain or take a long time to form.

I need help please in this:(

Answers

Answer:

That would be A sir or Miss

Explanation: Tell me if I am wrong, Also hope this helped you!

For the reaction H2(g) +O2(g) — H2O (g) how many liters of water can be made from 5 L of oxygen gas at 37.0 Celsius, 1.76atm and an excess of hydrogen?

Answers

Answer:

12.5 L

Explanation:

Part 1 - Finding Number of moles

First thing we need to find out is number of moles of oxygen gas. We can achieve this using the formula: PV=nRT

Pressure (Pa) x Volume (cubic meters) = no. moles x gas constant (8.31 J/K*mol) x Temperature (K)

We can rearrange this formula to solve for no. moles:[tex]n=\frac{PV}{RT}[/tex] and plug in the values to solve.

1 atm = 1.01325 x 10^5 Pa, therefore 1.76atm = [tex]1.76*1.01325*10^{5} =178332Pa[/tex]

1 L = 1 x 10^-3 m^3, therefore 5L = [tex]5*1*10^{-3}=5*10^{-3}m^{3}[/tex]

Finally Kelvin = Celsius + 273.15, therefore 37.0C = [tex]37.0+273.15=310.15K[/tex]

Substituting this all back into the formula we get:

[tex]n=\frac{(178332)(5*10^{-3})}{(8.31)(310.15)}[/tex]

[tex]n=\frac{891.66}{2577.3465}[/tex]

[tex]n=0.346[/tex] moles (3.s.f)

Part 2 - Balancing Equation

The equation given is not balanced so we need to balance it to find the correct molar ratio. We can start by balancing the oxygens as there are less of them. We can see that there are 2 oxygen atoms on the left as denoted by 'O2' but only one on the right in 'H2O', therefore we can add a two in front of the H2O on the right side to balance the oxygen atoms:

[tex]H_{2(g)} +O_{2(g)} - > 2H_{2} O_{(g)}[/tex]

Now we have four hydrogens on the right side so we have a 2 in front of H2 on the left hand side to balance the hydrogens:

[tex]2H_{2(g)} +O_{2(g)} - > 2H_{2} O_{(g)}[/tex]

And voila! The equation is balanced and shows the correct molar ratio.

Part 3 - Calculating moles of water

As we can see from the molar ratio in the balanced equation, every mole of O2 will produce two moles of H2O- the ratio is 1:2. As we have an excess of hydrogen, we only need to worry about the amount of oxygen we have. Therefore to calculate the number of moles of water that can be made we simply need to multiple by the ratio:

[tex]0.346*2=0.692[/tex] moles of water

Part 4 - Converting to Liters

Finally, to convert our amount of moles into volume, we can use water's molecular mass to find the mass and then its density to find its volume. Water's molecular mass is 18.02gmol^-1 (2x1.01+16.00) and its density is 997kg/m^3.

m=nM (mass = no. moles x molecular mass): m=[tex]0.692*18.02=12.46984g[/tex]

rho = m/v (density = mass/volume): [tex]997=12.46984/v[/tex], therefore [tex]v=0.0125m^{3}[/tex]

Finally as mentioned above, 1 L = 1 x 10^-3 m^3, therefore the volume of water that can be made is 12.5 Liters.

A fluid flowing in a pipe has 1.05 in diameter. If the fluid has density, viscosity and
volumetric flow rate are 62.3 , 1.2 cP and 35 gpm respectively. Calculate: 3
a) The velocity.
b) Reynolds number ()

[2]- Find the following
a) Drive an expression to find a pressure of methane gas at point B b) If the temperature of methane is 100 F, Calculate pressure of
methane gas at point B.
c) Calculate pressure of oil at point C.
PA = 1, 000 psig
[3]- If the water is pumped down one well and the displaced oil which flows up through well exit (see the fig below), drive an expression to find a pressure of inlet water Pw needed to displace oil when the water/oil interfacial tension σ is applied.

Answers

Velocity is a vector quantity that describes the rate and direction of an object's motion.

a) The velocity of the fluid:

V = 35 gpm / (π * (1.05 in)^2 / 4) = 7.09 ft/s

b) Reynolds number:

Re = (62.3 lbm/ft^3 * 7.09 ft/s * 1.05 in) / (1.2 cP) = 4,211.9

[2]- a) Expression to find pressure of methane gas at point B:

PB = PA + rgh

b) Pressure of methane gas at point B:

PB = 1,000 psig + (0.072 lbm/ft^3 * 32.2 ft * 0.0689 psia/ft) = 1,233.5 psig

c) Pressure of oil at point C:

PC = PB - 0.433 psia/ft * 32.2 ft = 1,093.3 psig

[3]- Expression to find pressure of inlet water Pw needed to displace oil:

Pw = PC + (σ / r) * (h2 - h1)

Pw = 1,093.3 psig + (σ / 0.072 lbm/ft^3) * (32.2 ft - 0 ft) = 1,093.3 psig + (σ / 0.072 lbm/ft^3) * 32.2 ft.

What is velocity?

Velocity is a vector quantity that describes the rate and direction of an object's motion. It is commonly represented by the symbol 'v' and is measured in meters per second (m/s). Velocity includes both the speed and the direction of the object. For example, if an object is moving north at 10 m/s, its velocity would be 10 m/s north. Velocity can also be determined by taking the derivative of the position function with respect to time.

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What is the number of moles of K+ ions are present in 250 mL of a 0.4M KCl solution?

a. 0.1 mol c. 0.62 mol
b. 0.16 mol d. 1.6 mol

Answers

The concentration terms are molality, normality and mole fraction. Molarity can be used to find out the ionic strength of any solution. Therefore, 0.025  is the number of moles of K+ ions are present in 250 mL of a 0.4M KCl solution.

What is molarity?

Molarity can be calculated by dividing number of moles of solute by volume of solution in litre. Molarity is affected by temperature. Its unit is mole/liter. It measure the concentration of any solute in a solution.

Mathematically,

Molarity= number of moles of solute/volume of solution in litre

Substituting values in equation 1

0.4M=number of moles of solute/0.25

number of moles of solute=0.025moles

Therefore, 0.025  is the number of moles of K+ ions are present in 250 mL of a 0.4M KCl solution.

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Help me please please i is in middle school need help ple

Answers

the answer is that it is a

18-38 Name the following ketones and aldehydes. When possible, give both a common name and an IUPAC name.
(a) CH₃CO(CH₂) ₄CH₃
(b) CH₃(CH₂)₂CO(CH₂)₂CH₃
(c) CH₃(CH₂)CHO₅
(d) PhCOPh
(e) CH₃CH₂CH₂O
(f) CH₃COCH₃
(g) CH₃CH₂CHBrCH₂CH(CH₃)CHO
(h) Ph --- CH = CH ----CHO
(i) CH₃CH= CH---CH = CH --CHO

Answers

The IUPAC name of the following organic compounds are,a) hept-2-one b) hept-4-one c) heptanal d) diphenylmethanone e) propan-1-one f) acetone g) 3-bromo-1-hexanal h) 3-phenylprop-2-enal i) 2,4-hexdiene-1-al.

What is a compound?

Compound is defined as a chemical substance made up of identical molecules containing atoms from more than one type of chemical element.

Molecule consisting atoms of only one element is not called compound.It is transformed into new substances during chemical reactions. There are four major types of compounds depending on chemical bonding present in them.

They have a unique chemical structure held together by chemical bonds Compounds have different properties as those of elements because when a compound is formed the properties of the substance are totally altered.

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Question (1 point)
Given the model, answer the following questions regarding effusion. The orange spheres have a greater root-mean-square speed than the blue spheres. Assume the balloon has a tiny opening for gas molecules to escape.
1st attempt
Part 1 ( 0.5 point)
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Which balloon, A or B, most accurately illustrates the effusion of a gas from the central balloon?
Calculate the relative rate of effusion for the orange to blue spheres. The root-mean-square speed for the orange spheres is 495.0m/s. The root-meah-5quare speed for the blue spheres is 380.0m/ s.

Answers

According to the claim, Balloon A, which has more blue and less orange, exhibits accurate effusion at a relative effusion rate of 1.303. (orange is 1.303 times more effused than blue).Relative rate of effusion for the orange to blue spheres = 1.531.

What is effusion ?

The process of effusion is when a gas escapes from a container through a hole that is significantly smaller in diameter than the molecules' mean free path.

Gas molecules flow through a small opening in one container and into another by effusion. Graham's law allows rates of effusion to be compared at the same temperature. Diffusion is the random molecular motion-based movement of gas molecules through one or more other types of gas.

Rate of effusion of Orange / Rate of effusion of blue

= [Mblue / Morange]^1/2

Vrms = sqrt [(3RT/M)]

Vorange / Vblue = [ Mblue / Morange]^1/2

Rate of effusion of Orange / Rate of effusion of blue

= 565/ 369

= 1.531

Thus,  Balloon A, which has more blue and less orange, exhibits accurate effusion at a relative effusion rate of 1.303.

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what is van't hoff factor?
state the formulas to calculate " i " during association or dissociation.

tysm! :)​

Answers

The relationship between the calculated concentration of a material and the actual concentration of particles is known as the Van't Hoff factor.

I is the difference between a typical or theoretical colligative quality and an observable one.

What does the connection van t Hoff factor mean?

The van 't Hoff factor is the difference between the concentration of a material determined by its mass and the concentration of particles actually formed when the substance is dissolved. The van 't Hoff factor is virtually 1 for the majority of non-electrolytes dissolved in water.

What does Van t Hoff factor mean in terms of connection and dissociation?

For dissociation, association, and the non-electrolyte solute, the Van't Hoff factor value is more than one, less than one, and equal to one respectively.

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