I will give you more points!!! :)

But first, answer the question below!!!

Answer:

False

Explanation:

The mass of something does not depend on gravity. A planet has a constant gravitational force. Earth's is 9,80 N/kg. The moon, on the other hand, is 1,6 N/kg. the number of kilograms of something doesn't change if you go from one planet to another and since mass is measured in kilograms, mass doesn't change, therefore it does not refer to gravity. Mass refers to the quantity of matter in an object. It is weight that refers to the gravitational force on an object, since it is measured in newtons, and the amount of newtons per kilogram changes from planet to planet due to different gravity constants

Answer:

The acceleration of the smaller cart is 50 m/s²

Explanation:

The given masses of the carts are 0.1 kg and 0.2 kg

The direction in which the small cart bounces = In the revers to its initial direction

The force exerted by the larger cart on the small cart = 5 N

Therefore, we have;

Force acting on smaller cart = Mass of smaller cart  × Acceleration of the smaller cart

∴ The acceleration of the smaller cart = Force acting on smaller cart/(Mass of smaller cart)

The acceleration of the smaller cart = 5 N/(0.1 kg) = 50 m/s²

The acceleration of the smaller cart = 50 m/s².

Answer:

9V

Explanation:

V=IR

V=2.5*3.6

V=9

Answer:

9V

Explanation:

V =IR

V =2.5 * 3.6

V = 9V

Answer:

ans: Electromagnetic

Answer:

B on edg.

Explanation:

Answer:

it's C! electromagnetic

Explanation:

Answer:

Static stretching.

Explanation:

It is static stretching because it is a form of stretching which u can do actively for a period of time and you hold position for about 30 to 60 seconds which allow the muscles and connective tissues to lengthen. It is done after work out with out movement in order to loosen up muscles so as to gain flexibility.

Answer:

The pulling force that acts along a stretched flexible connector, such as a rope or cable, is called tension, T. When a rope supports the weight of an object that is at rest, the tension in the rope is equal to the weight of the object: T = mg.

Explanation:

Answer:

hope it helps ....

Explanation:

The inside air that has been heated rises due to the difference of density between the hot and cold air particles. The heated air, the air that is inside the balloon, is less dense than the cool air, the air outside of the balloon. ... You can see that the bigger the volume gets, the smaller the density is.

Answer:

mass!!

Explanation:

Answer:

B

Explanation:

Answer:

answer is B

Explanation:

took the test

Answer:

The correct answer is 'A'

Explanation:

I guessed and was correct.

Freud backed Bernheim's efforts to establish hypnosis and suggestion as acceptable fields of study for science and to advance them as therapeutic tools. Thus, option A is correct.

Both neurologists and psychiatrists treat illnesses and ailments that affect the brain and the psyche. However, while psychiatrists focus on psychological issues, neurologists are experts in physiological illnesses.

According to medical terminology, neurological disorders are conditions that impact the spinal cord, brain, and body's nerves.

A variety of symptoms can be caused by structural, metabolic, or electrical abnormalities in the brain, spinal cord, or other nerves.

Therefore, whether hypnosis was a neurological or psychological phenomenon.

Learn more about neurological or psychological here:

https://brainly.com/question/28702031

#SPJ2

Answer:

A

Explanation:

We know the force is (16N-12), which is 4N, and we know the acceleration is 2 m/s^2. Meaning, we can solve the formula m = F / a (mass equals force divided by acceleration), and we get 2kg.

Answer:

Pushing force

Explanation:

You technically push a ball when kicking it.

Answer:

I'm pretty sure that the answer is A

-- The train starts at 23 m/s and slows down by 0.25 m/s every second.

So it'll take (23/0.25) = 92 seconds to stop.

-- Its average speed during that time will be (1/2)(23+0) = 11.5 m/s

-- Moving at an average speed of 11.5 m/s for 92 sec, the train will cover

(11.5 m/s) x (92 sec)  =  1,058 meters .

The distance required for the train to travel before stopping is 1,058 m.

The given parameters;

initial velocity of the train, u = 23 m/s

deceleration of the train, a = 0.25 m/s

The distance traveled by the train is calculated as follows;

[tex]v^2 = u^2 -2as[/tex]

where;

v is the final velocity of the train

The final velocity of the train is zero when the train stops

[tex]v^2 = u^2 -2as\\\\0 = 23^2 - 2(0.25)s\\\\0.5s = 529\\\\s = \frac{529}{0.5} \\\\s = 1,058 \ m[/tex]

Thus, the distance required for the train to travel before stopping is 1,058 m.

Learn more here: https://brainly.com/question/23852683

Answer:

The wrong items are;

1) The normal for FN equals the weight Fmg

2) The force of friction, Ff, equals the applied force Fpull

The corrected statements are;

1) The normal force is weight less the vertical component of the applied force Fpull

FN = Fmg - Fpull × sin(θ)

2) The force of friction equals the horizontal component of the applied force Fpull

Ff = Fpull × cos(θ)

Explanation:

The given statement was;

The velocity of the block is constant, so the net force exerted on the block must be zero. Thus, the normal force FN equals the weight Fmg, and the force of friction Ff equals the applied force Fpull

By the equilibrium of forces actin on the system, given that the applied force acts at an angle, θ, with the horizontal, we have;

The normal force is equal to the weight less the vertical component of the applied force;

That is we have, FN = Fmg - Fpull × sin(θ)

The friction force similarly, is equal to the horizontal component of the applied force;

Ff = Fpull × cos(θ)

The wrong items are therefore as follows;

1) The normal for FN equals the weight Fmg

1 i) The normal force is weight less the vertical component of the applied force Fpull

FN = Fmg - Fpull × sin(θ)

2) The force of friction, Ff, equals the applied force Fpull

2 i) The force of friction equals the horizontal component of the applied force Fpull

Ff = Fpull × cos(θ).

When a lower tank is damaged, the incoming sea water pushes the oil in the damaged tank up into the ballast tank. Because of the hydrostatic pressure, there is an automatic transfer out of the damaged tank. The double-hull design is aimed at the probability of zero outflow.

Answer:

Which has more inertia - a car with a mass of 900kg or a car with a mass of 1500kg - explain. The bigger the mass - the larger the inertia but you need to exert more force to start the movement.

Explanation:

Answer:

Thermosphere A,B

Mesosphere B,C,D

Stratosphere D,E,F

Troposphere G

Hope this helps please give me brainliest!

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Answer:

Isopropyl is an element compound.

Explanation:

Answer:

   h = 2,9002 10⁴ ft

Explanation:

Scientific notation is a method to write very large and small numbers clearly, the figure is written with an integer and the other figures in decimals, with an exponent so that the number does not change.

If it is necessary to approximate a figure, the criterion is if the next figure is greater than or equal to five, the figure rises by one unit.

Mount Everest height

    h = 29002 ft

    h = 2,9002 10⁴ ft

if we approximate three significant figures that

     h = 2.90 10⁴ ft

Answer:

[tex]2.9002 \cdot 10^{4} ft[/tex]

Explanation:

To express the height 29,002 in scientific notation we need to move the decimal point four places to the left and express the answer into a base-ten power, as follows:

[tex]29,002 = 2.9002 \cdot 10^{4}[/tex]

The answer expressed in scientific notation results in 2.9002 times a ten to the fourth power, as a result of the four movements of the decimal point.  

I hope it helps you!                

Answer:

3m/s^2

Explanation:

Acceleration is change in velocity / time = 45/15 = 3m/s^2

Answer:

a) El punto de colisión de los dos automóviles desde donde parte el conductor del automóvil A es de aproximadamente 293,14 metros.

b) La velocidad del automóvil A, en relación con la velocidad del automóvil B, es de 15 m / s

Explanation:

Los parámetros del movimiento son;

La distancia entre ambos coches = 500 m

La aceleración de ambos coches = 15 m / s²

La dirección de movimiento de ambos coches = uno hacia el otro

La hora de inicio del conductor A = Un segundo antes de la hora de inicio del conductor B

Por lo tanto, de la ecuación de movimiento, tenemos;

s = u · t + 1/2 · a · t²

v² = u² + 2 · a · s

Dónde;

u = La velocidad inicial de los autos = 0 (los autos parten del reposo)

t = El tiempo de movimiento de una aceleración dada

a = La aceleración = 15 m / s²

s = La distancia recorrida en el tiempo t

Por lo tanto, para el controlador A, tenemos;

s₁ = 0 × (t + 1) + 1/2 × 15 × (t + 1) ² = 7.5 × (t + 1) ²

s₁ = 7.5 × (t + 1) ²

Para el conductor B, tenemos;

s₂ = 0 × t + 1/2 × 15 × t² = 7.5 × t²

s₂ = 7,5 × t²

Dado que ambos chocan a lo largo del camino de 500 m, tenemos;

s₁ + s₂ = 500 metros

∴ 7.5 × (t + 1) ² + 7.5 × t² = 500

∵ s₁ + s₂ = 7.5 × (t + 1) ² + 7.5 × t²

Lo que da;

15 · t² + 15 · t + 7.5 = 500

15 · t² + 15 · t - 492,5 = 0

Resolver usando la aplicación en línea da; t = -6,25181 o t = 5,25181

Dado que t es un número natural, tenemos el valor correcto para t = 5.25181 segundos

a) Por tanto, el punto de colisión de los dos coches desde donde parte el conductor del coche A es;

s₁ = 7.5 × (t + 1) ² = 7.5 × (5.25181 + 1) ² ≈ 293.14 metros

El punto de colisión de los dos automóviles desde donde parte el conductor del automóvil A ≈ 293,14 metros

b) La semilla de A en el punto de colisión se da de la siguiente manera

Velocidad, v₁ = u + a × (t + 1) = 0 + 15 × (5.25181 + 1) ≈ 93.78

v₁ ≈ 93,78 m / s

La semilla de B en el punto de colisión también se da de la siguiente manera

Velocidad, v = u + a × (t) = 0 + 15 × 5.25181 ≈ 78.78

v₁ ≈ 78,78 m / s

Por lo tanto, la velocidad del automóvil A, en relación con la velocidad del automóvil B, [tex]v_{relative}[/tex] se da como sigue;

 = v₁ - v₂ = 93,78 m / s - 78,78 m / s = 15 m / s

la velocidad del automóvil A, relativa a la velocidad del automóvil B = 15 m/s.

Answer;  Ultrasonic waves (sounds having frequency greater than 20,000 Hz) are used in sonar because: ... Ultrasonic waves can penetrate water to long distances (because of their high frequency and very short wavelength), but ordinary sound waves or infrasonic waves cannot penetrate water to such long distances.

Answer:

Ultrasonic waves (sounds having frequency greater than 20,000 Hz) are used in sonar because: ... Ultrasonic waves can penetrate water to long distances (because of their high frequency and very short wavelength), but ordinary sound waves or infrasonic waves cannot penetrate water to such long distances

Explanation:

Answer:

-142m

Explanation:

To find the initial position of the car, we can add the displacement.

-245 + 103 = -142

Best of Luck!