Identify the gas law that applies to the following scenario: A 36.5 liter balloon holding 2.9 moles of carbon dioxide leaks. If we are able to determine that 1.2
moles of carbon dioxide escaped before the container could be sealed, what is the new volume of the container?
O Boyle's Law
O Charles' Law
O Gay-Lussac's Law
Avogadro's Law

Answer:

The heat contained is 1236 Joules

Explanation:

As we know

[tex]Q = mc\Delta[/tex]T

Where

[tex]\Delta[/tex]T is the change in temperature

m is the mass in grams

c is the specific heat of water (ice) = 2.06 joules/gram

Substituting the given values, we get -

[tex]Q = 20 * (-15+45)*2.06\\Q = 20*2.06*30\\Q = 1236[/tex]Joules

Answer:

The pressure of the gas is 224839.8 atm

Explanation:

As we know

PV = nRT

Substituting the given values, we get -

P * 1 L = 90.1 moles * 8.314 4621(75). J K−1 mol−1 * 300

P = 224839.8 atm

The pressure of the gas is 224839.8 atm

Explanation:

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Answer:

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A sample of aluminum has a density of 2.7g/cm³. The mass of the aluminum is 11g. What would be the volume of the aluminum sample ?

Density of a sample of aluminium is 2.7g/cm³.

The mass of the aluminium is 11g.

The volume of the aluminium sample.

We know,

[tex] { \boxed{\bf{\rm \red {Volume \: = \frac{Mass}{Density}}}}} [/tex]

So, [tex] \bf Volume \: = \frac{11}{2.7} [/tex]

Sublimation. Sublimation is the change of a solid direct to gas or vapour without becoming liquid

Answer:

Sistema Nervioso Autónomo

Explanation:

El Sistema Nervioso es el encargado de enviar señales (impulsos nerviosos en su mayoría) a órganos y partes del cuerpo, para que ejerzan su función. En general, se compone de 3 divisiones o subsistemas:

De éstos, el encargado de acciones y procesos involuntarios es el Sistema Nervioso Autónomo (SNA), que a su vez se divide en simpático y parasimpático. El SNA se encarga de los movimientos involuntarios de órganos, como el corazón, el sistema digestivo, etc., y de regular procesos como la secreción de hormonas y la regulación de la temperatura corporal.

Answer: 18

Explanation:hope this help

Answer:

No, although the bean crop can grow perfectly in full sun or a little shade in very warm places. It does not mean that they will adopt the growth patterns of the cactus, especially because this plant needs constant watering (in small quantities), very constant. Beans require good drainage for their growth.

Each vegetation have its own characteristics and the power of adaptation. A green bean cannot survive in a desert like a cactus in desert without water. It can only grow thick in soil with proper water content and nutrients.

Cactus is a type of plant grow in dry regions such as deserts. It can adapt in deserts without water for long time because, the plant have enough water storage in its stem.

Domestic vegetation such as bean, pea, nuts etc ill not grow in dry regions because they cannot adapt in deserts without water. The soil in deserts is dry and have no nutrients.

These conditions prevent the growth of vegetables in desert areas. Moreover, desert have summer season only. The extreme temperature over there will cause the normal plants to diminish.

Therefore, planting green bean in deserts will not make it grow thick like a cactus plant.

To refer more about cactus, refer the link below:

https://brainly.com/question/16636755

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Answer:

The answer is "Option B"

Explanation:

Formula:

Na atoms= Na atoms moles \times  NA

               [tex]= \frac{mass}{Na \ Molar\ mass} \times 6.022 \times 10^{23}\\\\= \frac{9.2}{23} \times 6.022 \times 10^{23}\\\\=0.2875 \times 6.022 \times 10^{23}\\\\=2.4 \times 10^{23}\ atoms \\\\[/tex]

Answer:

hydrogen bonding

Explanation:

Dipole-Dipole, Dispersion, hydrogen bonding and ion bond

Lets take an example to explain this

Sodium(Na) has 1 electron in its outer or valence shell hence it will lose it and become a cation say to Chlorine(Cl)

To form Sodium Chloride.

Since it is capable of losing electrons, Sodium becoems a metal and has properties of metal

Whereas Chlorine which has 7 electrons in its valence shell gains an electrons to become an anion

Hence it is a non metal

And has the properties of an anion

Answer:

4.58g of CO₂ could be produced

Explanation:

Based on the reaction:

C₂H₄(g) + 3O₂(g) → 2CO₂(g) + 2H₂O(g)

1 mole of C₂H₄ reacts with 3 moles of oxygen to produce 2 moles of CO₂

To solve this question we must find the moles of each reactant in order to find limiting reactant. With limiting reactant we can find the moles -And the mass- of CO₂ produced:

Moles C₂H₄ -Molar mass: 28.05g/mol-

2.0g * (1mol / 28.05g) = 0.0713moles

Moles O₂ -Molar mass: 32g/mol-

5.0g * (1mol / 32g) = 0.156moles

For a complete reaction of 0.0713 moles of C2H4 are required:

0.0713 moles C₂H₄ * (3 moles O₂ / 1 mol C₂H₄) = 0.214 moles of O₂

As there are just 0.156 moles, O₂ is limiting reactant.

The moles of CO₂ produced are:

0.156 moles O₂ * (2mol CO₂ / 3mol O₂) = 0.104 moles CO₂

The mass is -Molar mass CO₂: 44.01g/mol-

0.104 moles CO₂ * (44.01g / mol) =

Answer:

P = 9800 Pa

Explanation:

Given that,

The mass of a box, m = 30 kg

Length of the box, l = 0.2 m

The width of a box, b = 0.15 m

We need to find the pressure it exerted on the floor. Pressure is equal to force acting per unit area. So,

[tex]P=\dfrac{F}{A}\\\\=\dfrac{mg}{lb}\\\\=\dfrac{30\times 9.8}{0.2\times 0.15}\\\\P=9800\ Pa[/tex]

So, 9800 Pa of pressure is exerted on the floor.

Answer:

A, D, E

Explanation:

Answer:

Period 4

Explanation:

Given the electronic configuration of the element;

= Is²  2s²  2p⁶  3s²  3p⁶  3d¹⁰   4s²    4p¹

The period of the element is determined by the highest coefficient in the electronic configuration.

For this given configuration (Is²  2s²  2p⁶  3s²  3p⁶  3d¹⁰   4s²    4p¹), "4" is the highest coefficient and the element will certainly belong to period 4 in the periodic table.

To test if the prediction is correct:

Total number of electrons in the given element = 2+2+6+2+6+10+2+1 = 31

The element with atomic number of 31 = Gallium (Ga). (This element belong to period 4).

Answer:matter

Explanation:

matter

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Answer:

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Explanation:

Answer:

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Explanation:

single forever

Answer:

1. Moles of oxygen required to react with 5 moles of C₈H₁₈ = = 62.5 moles of oxygen

2. Mass of oxygen required = 2000 g of oxygen

3. Moles of CO₂ that will be produced = 40 moles of CO₂

4. Mass of CO₂ that will be produced = 1760 g of CO₂

5. Moles of H₂O that will be produced = 45 moles of H₂O

Explanation:

Balanced equation of the reaction : 2 C₈H₁₈ + 25 O₂ ---> 16 CO₂ + 18 H₂O

1. Mole ratio of Oxygen and C₈H₁₈ = 25 : 2

Moles of oxygen required to react with 5 moles of C₈H₁₈ = 5 × 25/2 moles

Moles of oxygen required to react with 5 moles of C₈H₁₈ = = 62.5 moles of oxygen

2. Mass of oxygen required = number of moles of oxygen × molar mass of oxygen

Molar mass of oxygen = 32.0 g/mol

Mass of oxygen required = 62.5 moles × 32.0 g/mol

Mass of oxygen required = 2000 g of oxygen

3. Mole ratio of CO₂ and C₈H₁₈ = 16 : 2

Moles of CO₂ that will be produced = 5 × 16/2 moles

Moles of CO₂ that will be produced = 40 moles of CO₂

4. Mass of CO₂ that will be produced = number of moles of CO₂ × molar mass of CO₂

Molar mass of CO₂ = 44.0 g/mol

Mass of CO₂ that will be produced = 40 moles × 44 g/mol

Mass of CO₂ that will be produced = 1760 g of CO₂

5. Mole ratio of H₂O and C₈H₁₈ = 18 : 2

Moles of H₂O that will be produced = 5 × 18/2 moles of H₂O

Moles of H₂O that will be produced = 45 moles of H₂O

Answer:

two atoms

Explanation:

In its stable molecular form, oxygen exists as two atoms and is written O2. to distinguish it from an atom of oxygen O, or ozone, a molecule of three oxygen atoms, O3. Even though each of these is all oxygen, combining atoms of the same element may give very different properties to the molecule.

Answer:

D. Electrical energy is changed into mechanical energy

Explanation:

When you turn on the fan, the electricity that is given through the power outlet allows the fan to have the available energy to spins the fan blades. By the fan's blades spinning, this is a movement that can be described as mechanical energy.

Answer:

A gas occupies a volume of 250 mL at a pressure of 76 kPa and a temperature of 298 K.

Explanation:

Charles's law states that for a given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases. This mathematical law expresses that the quotient that exists between the volume and the temperature will always have the same value:

[tex]\frac{V}{T} =k[/tex]

Gay-Lussac's law says that when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases. This law mathematically says that the quotient between pressure and temperature is constant:

[tex]\frac{P}{T} =k[/tex]

Finally, Boyle's law says that the volume occupied by a certain gaseous mass at constant temperature is inversely proportional to the pressure. This law is expressed mathematically as

P * V = k

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

[tex]\frac{P*V}{T} =k[/tex]

Analyzing an initial state 1 and a final state 2, it is satisfied:

[tex]\frac{P1*V1}{T1} =\frac{P2*V2}{T2}[/tex]

In this case:

Replacing:

[tex]\frac{38 kPa*500 mL}{298 K} =\frac{76 kPa*250 mL}{T2}[/tex]

Solving:

[tex]T2*\frac{38 kPa*500 mL}{298 K} =76 kPa*250 mL[/tex]

[tex]T2=\frac{76 kPa*250 mL*298 K}{38 kPa*500 mL}[/tex]

T2= 298 K

A gas occupies a volume of 250 mL at a pressure of 76 kPa and a temperature of 298 K.

Explanation:

Its value is 6.02 kj/mol. This means for every mole of ice we melt we must apply 6.02 kj of heat. We can calculate the heat needed with the following equation:

q

=

n

×

Δ

H

where:

q

= heat

n

= moles

Δ

H

= enthalpy

In this problem we would like to calculate the heat needed to melt 35 grams of ice at 0 °C. This problem can be broken into three steps:

1. Calculate moles of water

2. multiply by the enthalpy of fusion

3. Convert kJ to J

Step 1: Calculating moles of water

35

g

×

(

1

m

o

l

18.02

g

)

=

1.94

m

o

l

s

Step 2: Multiply by enthalpy of fusion

q

=

n

×

Δ

H

=

1.94

×

6.02

=

11.678

k

J

Step 3: Convert kJ to J

11.678

k

J

×

(

1000

J

1

k

J

)

=

11

,

678

J

Finally rounding to 2 sig figs (since 34°C has two sig figs) we get

q

=

12

,

000

J

One last note, if the temperature were not 0 °C then the ice would have to be heated in addition to melted. This would be a phase change problem combined with a heat capacity problem.