Answer:
No, no precipitate is formed.
Explanation:
Hello there!
In this case, since the reaction between ammonium sulfide and aluminum nitrate is:
[tex]3(NH_4)_2S(aq)+2Al(NO_3)_3(aq)\rightarrow Al_2S_3(s)+6NH_4NO_3(aq)[/tex]
In such a way, we can calculate the concentration of aluminum and sulfide ions in the solution as shown below, and considering that the final total volume is 140.00 mL:
[tex][Al^3^+]=\frac{120.00mL*0.0082M}{140.00mL}=0.00703M[/tex]
[tex][S^2^-]=\frac{20.00mL*0.0090M}{140.00mL}=0.00129M[/tex]
In such a way, we can calculate the precipitation quotient by:
[tex]Q=[Al^3^+]^2[S^2^-]^3=(0.00703)^2(0.00129)^3=1.05x10^{-13}[/tex]
Which is smaller than Ksp and meaning that the precipitation does not occur.
Regards!
3. Determine the moles of sodium, Na, containing 7.9x1024 atoms.
Answer:
12.7mol Na.
Explanation:
Hello there!
In this case, according to the concept of mole, which stands for the amount of substance, we can recall the concept of Avogadro's number whereby we understand that one mole of any substance contains 6.022x10²³ particles, for the given atoms of sodium, we can calculate the moles as shown below:
[tex]7.9x10^{23}atoms*\frac{1mol}{6.022x10^{23}atoms} \\\\[/tex]
Thus, by performing the division we obtain:
[tex]12.7molNa[/tex]
Regards!
CH4 +2H2S = CS2+ 4H2
If the reaction shifts to the right what are the products?
If the reaction shifts to the right, which chemicals decrease in The process?
If the reaction shifts to the left what are the products?
If the reaction shifts to the left, which chemicals decrease in the process?
3. Bacteria communicate with each other through electronic pulses.
O True
O False
Answer:
All in All, All in All.
Explanation:
During energy conversions, some energy is always lost as _____.
heat
electricity
chemical energy
light
Answer:
electricity
Explanation:
I know this because I am currently learning about this and remember doing it
21. What are the individual ion
22. If the C2H302 ion concentration in a solution is 0.554 M, what is the concentration of
Ca(C2H2O2)2?
Answer:
hi hi hi hi hi hi hi hi hi hi hib uj hi u Inuit hi hi hi. hi hi hi hi hib hi hib hi hi hi hi hi hi hi hi hi hi hi hi hi b
Explanation:
vugjb oh in luv ug ug yf fyi dxezw f f g gjhc ydzt
PLEASE HELP Describe at least two advantages and two disadvantages of using hydropower as a
source of energy.
PLS ONLY ANSWER THE FULL QUESTION ON HERE DO NOT SEND A LINK FOR ME TO CLICK!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
Advantage: Hydropower is a fueled by water, so it's a clean fuel source.
Advantage: It is a domestic source of energy in the US.
Disadvantage: Fish populations can be impacted if fish cannot migrate upstream past impoundment dams to spawning grounds or if they cannot migrate downstream to the ocean.
Disadvantage: Hydropower plants can be impacted by drought. When water is not available, the hydropower plants can't produce electricity.
Explanation:
Describe one way that carbon and silicon are alike.
ASAP
Answer:
they have the same density
An organism is living in a rapidly changing environment. Sexual reproduction is advantageous to an organism in this situation because–
sexual reproduction produces more offspring than asexual reproduction within a given time period.
sexual reproduction produces offspring with more variation, some of which may be better adapted to a new environment.
sexual reproduction requires more time to complete, allowing the environment to become more stable.
offspring produced by sexual reproduction grows to maturity more rapidly.
Answer:
sexual reproduction produces offspring with more variation, some of which may be better adapted to a new environment.
Explanation:
this allows more of the organisms to survive a change in the environment
Answer:
sexual reproduction produces offspring with more variation, some of which may be better adapted to a new environment.
Explanation:
what are the physical properties of matter?
Answer:
Physical properties are typically things you can detect with your senses.
Explanation:
The solution you identified in question (1) acts as a buffer due to reactions that occur within the solution when an acid or a base is added. Write the net ionic chemical equation for the reaction that occurs within this buffer solution when HCl(aq) is added. (Phase labels should be included in all net ionic chemical equations.)
Answer:
The answer is "[tex]\bold{CH_3COO^{-} \ (aq) + H^{+}\ (aq) \longrightarrow CH_3COOH \ (aq)}[/tex]"
Explanation:
When [tex]HCI[/tex] is added in the chemical equation it reacts with sodium acetate so, it will give the following chemical equation:
[tex]CH_3COONa\ (aq) + HCl\ (aq)\longrightarrow CH_3COOH\ (aq) + NaCl\ (aq)\\\\[/tex]
In this, the [tex]CH_3COOH[/tex] is a weak acid so, it not completely dissociated.
[tex]CH_3COONa \ (aq) \ \ and \ NaCl[/tex] were strong electrolytes they are completely dissociated.
The [tex]HCl[/tex] is a strong acid so, it is completely dissociated So, the net ionic equation is:
[tex]CH_3COO^{-} \ (aq) + H^{+}\ (aq) \longrightarrow CH_3COOH \ (aq)[/tex]
what would be the observation when pineapple juice is dipped in a red litmus paper
Answer:
red litmus paper change into blue when it is dipped into Pineapple juice.
hope it helps
The red litmus paper will stay red when dipped in pineapple juice.
What are acids and bases?Acids are substances that can donate a proton to another substance. A base is a substance that can accept a hydrogen ion from an acid.
Acidic substances are often characterized by their sour taste. An acid commonly can be energetically favorable after a loss of H⁺ ion and is also known to turn blue litmus paper into red.
Bases are generally recognized for their bitter taste and slippery texture. A base that can dissolve in water is also referred to as alkali and is also known to turn red litmus paper into blue.
The pH value of the pineapple juice lies between 2.5 to 3.9. Therefore, it is acidic in nature as the pH of acidic substances lies in the range of 0 to 7. So the red litmus paper will stay red in pineapple juice.
Learn more about acids and bases, here:
brainly.com/question/3941445
#SPJ2
4NH3 + 502 - 6H20 + 4NO
How many grams of O2 are required to produce 0.3 mol of H20?
4NH3 + 5O2 --> 6H2O + 4NO
How mant grams of NO are produced from 1.55 mol of NH3?
4NH3 + 5O2 --> 6H2O + 4NO
How many grams of NO is produced if 12g of 02 is combined with ammonia?
Explanation:
4NH3 + 502 - 6H20 + 4NO
How many grams of O2 are required to produce 0.3 mol of H20?
4NH3 + 5O2 --> 6H2O + 4NO
How mant grams of NO are produced from 1.55 mol of NH3?
4NH3 + 5O2 --> 6H2O + 4NO
How many grams of NO is produced if 12g of 02 is combined with ammonia?
Explain why bicarbonate soda would be the best option to treat a bee sting?
soda is fuzzy and can help heal the swell caused by a bee sting
20 grams of hydrogen fluoride gas, HF, is dissolved in 0.5 liters of solution. Determine the molarity (M).
Answer:
40
Explanation:
M = n/v hope this helps :b
A compound containing phosphorus and oxygen has a molar mass of 157.9 g/mol and an empirical formula of PO3 .
Answer: The molecular formula of the compound is [tex]P_2O_6[/tex]
Explanation:
The molecular formula is the chemical formula that tells about the number of atoms of each element present in a compound. Molecular formula and empirical formula can also be the same when the number of atoms is in the simplest whole-number ratio.
To calculate the molecular formula, the number of atoms of the empirical formula is multiplied by a factor known as valency that is represented by the symbol, 'n'.
[tex]n=\frac{\text{Molecular mass}}{\text{Empirical mass}}[/tex] ...(1)
Given empirical formula is [tex]PO_3[/tex]
Empirical mass = [tex][(1\times 30.97) + (3\times 15.99)]=78.94 g/mol[/tex]
Molecular mass = 157.9 g/mol
Plugging values in equation 1:
[tex]n=\frac{157.9 g/mol}{78.94g/mol}\\\\n=2[/tex]
Molecular formula of the compound becomes [tex]P_{2\times 1}O_{2\times 3}=P_2O_6[/tex]
Hence, the molecular formula of the compound is [tex]P_2O_6[/tex]
12. Photosynthesis builds sugars out of small molecules, making it an
Answer:
Condensation reaction/ direct synthesis reaction
Explanation:
Combines simple molecules to form complex molecules producing water
A 27.5g piece of aluminum sits in a room and cools. It loses 6120.0 J of heat. If the initial
temperature of aluminum is 157.3°C, what is the final temperature? The specific heat
capacity of aluminum is 0.900 J/gºC.
Answer:
[tex]T_2= -90.0°C[/tex]
Explanation:
Hello!
In this case, according to the given description of how the temperature changes for aluminum in agreement to the loss of heat of 6120.0 J, we can use the following equation:
[tex]Q=mC\Delta T=mC(T_2-T_1)\\\\[/tex]
Thus, by knowing Q, m, C and the initial temperature, we are able to obtain:
[tex]T_2=T_1+\frac{Q}{mC}\\\\T_2=157.3\°C+\frac{-6120.0J}{27.5g*0.900 J/g\ºC}\\\\T_2= -90.0°C[/tex]
Regards!
What is the total number of Joules lost when 10. grams of water at 80.°C is cooled to 60.°C?
Answer:
[tex]\boxed {\boxed {\sf 836.8 \ Joules \ lost}}[/tex]
Explanation:
Since we are given the mass and change in temperature, we should use the following formula for heat.
[tex]q= mc \Delta T[/tex]
In this formula, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.
We know the mass of the water is 10 grams. We will have to look up water's specific heat, because it is not given. It is 4.184 J/g °C.
Let's find the change in temperature. This is the difference of the final and initial temperature. The water started at 80 °C and cooled to 60°C.
ΔT= final temperature - initial temperature ΔT= 60° C - 80°C ΔT= -20 °CNow we have values for each variable.
m= 10 gc= 4.184 J/g°C ΔT= -20°CSubstitute the values into the formula.
[tex]q= 10 \ g * 4.184 \ J/g \textdegree C * -20 \textdegree C[/tex]
Multiply the first 2 numbers. The units of grams will cancel each other out.
[tex]q= 41.84 \ J/ \textdegree C * -20 \textdegree C[/tex]
Multiply again. This time, the degrees Celsius cancel.
[tex]q= -836.8 \ J[/tex]
A total of 836.8 Joules are lost.
Here are the atomic masses of hypothetical elements:
X = 13.25 amu
Y = 69.23 amu
Z = 109.34 amu
3.8 moles of X2Y5Z3 is equivalent to how many grams?
Enter your answer to zero decimal places (round to the ones place). Do
not include the units of "g", just the numerical answer.
Answer:
2663 g
Explanation:
We'll begin by calculating the molar mass Of X₂Y₅Z₃. This can be obtained as follow:
Molar mass of X₂Y₅Z₃ = (13.25×2) + (69.23×5) + (109.34×3)
= 26.5 + 346.15 + 328.02
= 700.67 g/mol
Finally, we shall determine the mass of 3.8 moles of X₂Y₅Z₃. This can be obtained as follow:
Molar mass of X₂Y₅Z₃ = 700.67 g/mol
Mole of X₂Y₅Z₃ = 3.8 moles
Mass of X₂Y₅Z₃ =?
Mass = mole × molar mass
Mass of X₂Y₅Z₃ = 3.8 × 700.67
Mass of X₂Y₅Z₃ = 2663 g
Therefore, the of 3.8 moles of X₂Y₅Z₃ is
2663 g
1) Heat is the ______ of energy and a unit is ____.
A: Measure; Joule
B: Measure; Kelvin
C: Movement; Kelvin
D: Movement; Joule
2) ______ is the internal energy of particles and when this motion is measured, the unit used is ___.
A: Heat; Joule
B: Thermal Energy; Kelvin
C: Thermal Energy; Joule
D: Heat; Kelvin
Answer:
Q1) B
Q2) C
Kelvin is the SI unit of temperature.
A chemistry student heated 2.255 g of oxygen gas in the presence of 5.145
Answer:
a
Explanation:
Calculate the final concentration of each of the following:
2.0 L of a 6.0 M HCl solution is added to water so that the final volume is 6.0 L
--
Water is added to 0.50 L of a 12 M NaOH solution to make a 3.0 L of a diluted NaOH solution
Answer:
1. 2 M
2. 2 M
Explanation:
1. Determination of the final concentration.
Initial Volume (V₁) = 2 L
Initial concentration (C₁) = 6 M
Final volume (V₂) = 6 L
Final concentration (C₂) =?
The final concentration can be obtained as follow:
C₁V₁ = C₂V₂
6 × 2 = C₂ × 6
12 = C₂ × 6
Divide both side by 6
C₂ = 12 / 6
C₂ = 2 M
Therefore, the final concentration of the solution is 2 M
2. Determination of the final concentration.
Initial Volume (V₁) = 0.5 L
Initial concentration (C₁) = 12 M
Final volume (V₂) = 3 L
Final concentration (C₂) =?
The final concentration can be obtained as follow:
C₁V₁ = C₂V₂
12 × 0.5 = C₂ × 3
6 = C₂ × 3
Divide both side by 3
C₂ = 6 / 3
C₂ = 2 M
Therefore, the final concentration of the solution is 2 M
Bears stop coming to a river ecosystem where they have been eating many fish each day. The fish the bears eat normally eat smaller fish, which eat plants along the river bottom.
What happens to the ecosystem?
Both the larger and the smaller fish populations grow quickly but then die out because the plant life is insufficient for them all to eat.
The larger fish population will drop first, and the smaller fish population will grow quickly. The plants will die off because too many of the smaller fish are eating them.
The larger fish population explodes at first, and the smaller fish population begins to drop. Eventually, the river runs out of smaller fish so larger fish die out, and the plant population grows.
The smaller fish population begins to eat more plants and to grow. The larger fish have more food to eat so their population is able to grow, too.
Answer:
The larger fish population explodes at first, and the smaller fish population begins to drop. Eventually, the river runs out of smaller fish so larger fish die out, and the plant population grows.
Explanation:
What is the molarity of a solution containing 7.47 moles of solute in 4.31 liters of
solvent?
Answer:
1.73 M
Explanation:
Molarity is moles per liter, so we need to divide 7.47 moles by 4.31 liters to get the molarity of the solution.
7.47/4.31 ≈ 1.73 M
what reaction type is
4+22⟶4+22
Answer: [tex]CF_{4} + 2Br_{2} \rightarrow CBr_{4} + 2F_{2}[/tex] is a single replacement reaction.
Explanation:
A chemical reaction in which one element of a compound is replaced by another element is called single replacement reaction.
For example, [tex]CF_{4} + 2Br_{2} \rightarrow CBr_{4} + 2F_{2}[/tex]
Here, fluorine element in the compound [tex]CF_{4}[/tex] is replaced by the element bromine.
Therefore, it is a single replacement reaction.
Thus, we can conclude that [tex]CF_{4} + 2Br_{2} \rightarrow CBr_{4} + 2F_{2}[/tex] is a single replacement reaction.
What type of molecule is 2-methylpentene?
O A. Alkane
O B. Branched alkene
O C. Alkyne
O D. Cyclic
Answer:
B. Branched Alkene
HOPE THIS HELPS :-)
7.In the oxidation of ethane: 2 C2H6 + 7 02 + 4CO2 + 6H2O how many
liters of O2 are required to react with 90 grams of ethane?
Answer:
If reaction is taking place at room temperature and pressure(rtp)
= 360 litres of O₂ at rtp
If reaction is taking place at standard temperature and pressure(stp):
= 336 litres of O₂ at stp
Explanation:
2C₂H₆ + 70₂ → 4CO₂ + 6H₂O
1 mole of C₂H₆ = (12 × 2) + (1 × 6) = 24 + 6 = 30g
2 moles of C₂H₆ = 30 × 2 = 60g
From the equation:
1 mole of 0₂ reacts with 2 moles of C₂H₆
1 mole of 0₂ reacts with 60g of C₂H₆
? moles of 0₂ react with 90g of C₂H₆
[tex]\frac{90}{60}[/tex]= 1.5 moles of O₂
Considering condition of reaction taking place whether room temperature and pressure(rtp) or standard temperature and pressure(stp)
If room temperature and pressure(rtp):
1 mole of 0₂ occupies 24 liters/24000 cm³/ 24 dm³ of O₂
1.5 moles of O₂ occupies (24 × 1.5) litres of O₂
= 360 litres of O₂ at rtp
If standard temperature and pressure(stp):
1 mole of 0₂ occupies 22.4 liters/22400 cm³/ 22.4 dm³ of O₂
1.5 moles of O₂ occupies (22,4 × 1.5) litres of O₂
= 336 litres of O₂ at stp
I need help to get the correct answers for this task.
Answer:
*Numbering from left to right.
Synthesis: 1,2,9
Decomposition: 4,7,11
Single Replacement: 3,6
Double Replacement: 5,8,10, 12
Explanation:
Synthesis=A+B->AB; 2 separate elements getting together
Decomposition=AB->A+B; 2 Elements that are bonded separating
Single Replacement=A+BC->AX+B; a single swap
Double replacement=AX+BY-> AY+BX; a double swap
How many grams are there in 1.8055 x 10^25 molecules of sodium sulfate? Hint: Convert to moles first
Answer:
4258.82 g of Na₂SO₄
Explanation:
From the question given above, the following data were obtained;
Number of molecules of Na₂SO₄ = 1.8055x10²⁵ molecules.
Number of mole of Na₂SO₄ =?
From Avogadro's hypothesis,
6.02×10²³ molecules = 1 mole
Therefore,
6.02×10²³ molecules = 1 mole of Na₂SO₄
Next, we shall determine the mass of 1 mole of Na₂SO₄. This can be obtained as follow:
1 mole of Na₂SO₄ = (23×2) + 32 + (16×4)
= 46 + 32 + 64
= 142 g
Thus,
6.02×10²³ molecules = 142 g of Na₂SO₄
Finally, we shall determine the mass of Na₂SO₄ that contains 1.8055x10²⁵ molecules. This can be obtained as follow:
6.02×10²³ molecules = 142 g of Na₂SO₄
Therefore,
1.8055x10²⁵ molecules
= (1.8055x10²⁵ × 142) / 6.02×10²³
= 4258.82 g of Na₂SO₄
Thus, 4258.82 g of Na₂SO₄ contains 1.8055x10²⁵ molecules
how many liters of N2 gas is needed to produce 500 L NH3?