The time it takes the object to fall to the ground from a height of 12 m is 1.56 seconds.
What is time?Time can be defined as an ongoing and continuous sequence of events that occur in succession, from past through the present, and to the future.
To calculate the time it takes the object to fall to the ground, we use the formula below.
Formula:
H = ut+gt²/2.............. Equation 1Where:
H = Heightg = Acceleration due to gravityt = Timeu = Intial velecityFrom the question,
Given:
u = 0 m/s (drop from height)g = 9.8 m/s²H = 12 mSubstitute these values into equation 1 and solve for t.
12 = (0×t)+(9.8t²)/29.8t² = 12×2t² = 12×2/9.8t² = 2.45t = √2.45t = 1.56 seconds.Hence, the time it takes the object to fall to the ground is 1.56 seconds.
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1. If I drop a watermelon from the top of one of the tower dorms at JMU, and it takes
3.50 seconds to hit the ground, how tall the building is in meters.
What is the acceleration of the watermelon as it falls?
Answer:
Below
Explanation:
The accelerateinon, a, of the watermelon is just the acceleration of gravity on Earth = 9.81 m/s^2
the height will be found by
Height = 1/2 a t^2 = 1/2 (9.81)(3.50)^2 = 60.1 m
what is the range of frequency that the 3 db point occurs in? group of answer choices 0 to 10 hz 10 to 100 hz 100 to 1000 hz 1000 to 10000
The correct option is 10 to 100 Hz. A low pass and high pass filter are cascaded to create a band pass filter. It has two reactive elements, making it a second order filter.
The signal strength to frequency graph looks like this because this filter favors high frequencies: We may do a variety of signal processing operations using the low-pass and high-pass filters, including picking out a certain frequency band. We can easily sketch the perfect filter response since the -3dB point is also quite near to the place where the "unity gain" line and the asymptote for the filter's roll-off curve intersect.
Drawing piecewise-linear approximations for filter performance is no longer necessary in modern times thanks to the usage of computers, but this was not the case when electrical circuit design and analysis first started. Even with the introduction of electronic calculators, the majority of these activities were still done by hand.
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Where loads are likely to be ON for 4 hours, the computed load for sizing branch-circuit conductors and OCPDs must be calculated by multiplying the actual load current times ___.
We have to multiply the actual load current times by 1.25 (2017 NEC: 210.20(A)).
NEC 210.20(A) Continuous and Noncontinuous Loads:
The rating of the overcurrent device must be no less than the noncontinuous load plus 125 percent of the continuous load when a branch circuit delivers continuous loads or any combination of continuous and noncontinuous loads.
With one exception, the ampere rating of the overcurrent device may not be less than the total of the continuous load and the noncontinuous load when the assembly, including the overcurrent devices safeguarding the branch circuit(s), is rated for operation at 100% of its rating.
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Many animals use __?__to find prey.
2. A porpoise sends out an ultrasonic burst and hears the echo off his favorite food in 0.13 seconds. How far away is the food source? Assume that sound travels at 1,530 m/sec in water.
Answer:
Below
Explanation:
"echo location"
The sound travels the distance, d , to the food and back for a total distance of 2d
2d = 1530 m/s * .13 s
d = ~ 99 m away
In a game of shuffleboard (played on a horizontal surface), a puck is given an initial speed of 6. 0 m/s. It slides a distance of 9. 0 m before coming to rest. What is the coefficient of kinetic friction between the puck and the surface?.
The coefficient of kinetic friction between the puck and surface id 0.20.
What is coefficient of kinetic friction?
Coefficient of kinetic friction is the ratio between frictional force present in the motion of two surfaces that are in contact to the normal force that presses the two surface together.
It is calculated mathematically as: μ = F/N, where
F= frictional force and N= normal force.
v2 = u2 +2as
0= 62 + 2a9
18a + 36= 0
18a = -36
a= -2
friction = μ × normal force
or friction =ma
ma= μN
ma= μ(mg)
μ = a/g where g = 9.8 N
μ= -2/9.8
⇒0.20.
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The parallax angle for the star Hadar is 0.010 arcseconds. How far away is Hadar?
The parallax angle for the star Hadar is 0.010 arcseconds. 100 PC far away is Hadar.
Parallax angle is a displacement or distinction in the apparent function of an item considered alongside two one-of-a-kind lines of sight and is measured by the attitude or semi-perspective of inclination among those two lines. because of foreshortening, close-by objects display a bigger parallax than farther items when found from distinct positions, so parallax may be used to determine distances.
To a degree of big distances, including the gap between a planet or a star from Earth, astronomers use the precept of parallax. right here, the term parallax is the semi-perspective of inclination between sightlines to the megastar, as observed while Earth is on contrary sides of the solar in its orbit. those distances shape the lowest rung of what's called "the cosmic distance ladder", the first in a succession of methods by which astronomers determine the distances to celestial items, serving as a basis for other distance measurements in astronomy forming the higher rungs of the ladder.
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scientists attribute some global warming and cooling periods to the culmination of the effects of the milankovitch cycles. milankovitch cycles are variances in earth's axis and orbit that correspond to the earth's position in relation to the sun. classify each constituent of the milankovitch cycles as pertaining to orbital eccentricity, axial tilt, or axial precession.
Each constituent of the Milankovitch cycles as pertaining to orbital eccentricity, axial tilt, or axial precession are classified accordingly.
The constituents of the Milankovitch cycles as pertaining to orbital eccentricity are:
Path varies from round to elliptical.100000 year cycleThe earth's changing distance from sun during orbit impacts the climate , sometimes producing glacial periods.The constituents of the Milankovitch cycles as pertaining to axial tilt are:
41000 year cycle.Changes to earth's orientation to the sun affect the severity of seasons.The angle of earth's tilt change as it spins on its axis.When the angle from vertical is greater , seasons become greater in variability.The constituents of the Milankovitch cycles as pertaining to axial precession are:
20000 year cycle.The earth "wobbles" on its axis, which can change the orientation of the axis with celestial bodies.Therefore, each constituent of the Milankovitch cycles as pertaining to orbital eccentricity, axial tilt, or axial precession are classified accordingly.
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You charge your cell phone every night while you are sleeping.
Throughout the school day you see your cell phone battery slowly decline. By
lunchtime your cell phone is almost dead. You remember in science class your
teacher saying that energy can't be created or destroyed. If the energy in your cell
phone battery wasn't destroyed, where did it go? Explain your answer,
Answer:Simple, it gets used up by the phone.
Explanation:Your phone uses the energy stored in the battery to perform the functions it does. Chemical energy gets converted to light (display), sound (speakers), electrical (internal processing of the phone), thermal (phone getting heated up), and to other forms.
Candace is a goalie on her hockey team who has a reputation for stopping every puck before it enters the goal. Which skill most likely helps candace respond as the puck flies in her direction?.
Reaction time is the skill that mostly helps candace respond as the puck flies in her direction
Reaction time (RT) is a measure of the quickness with which a person responds to some sort of stimulus. It is defined as the interval of time between the stimulus and voluntary response in the subject.
Her reaction time is really quick , She reacts quickly to the different areas that the puck is going and is able to go across the crease to stop it
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An air-filled toroidal solenoid has a mean radius of 15.0cm and a cross-sectional area of 5.00cm2 . When the current is 12.5A , the energy stored is
0.390J .How many turns does the winding have?
The number of turns the winding have in an air-filled toroidal solenoid that has a mean radius of 15.0cm and a cross-sectional area of 5.00cm2 is 2745 turns
According to Ampere's law,
B = μo N I / 2 π r
Φ[tex]_{B}[/tex] = B A
Φ[tex]_{B}[/tex] = μo N I A / 2 π r
B = Magnetic field
μo = Absolute permeability of free space
N = Number of turns
I = Current
r = Radial distance
A = Cross sectional area
U = Energy stored
U = 1 / 2 L I²
L = 2 U / I²
L = N Φ[tex]_{B}[/tex] / I
μo = 4 π * [tex]10^{-7}[/tex] H / m
U = 0.39 J
r = 15 cm = 0.15 m
I = 12.5 A
A = 5 cm² = 5 * [tex]10^{-4}[/tex] m²
Equating,
2 U / I² = N Φ[tex]_{B}[/tex] / I
2 U / I² = μo N² I A / 2 π r I
4 π r U / μo I² A = N²
N² = ( 4 * 3.14 * 0.15 * 0.39 ) / ( 4 * 3.14 * [tex]10^{-7}[/tex] * 12.5² * 5 * [tex]10^{-4}[/tex] )
N² = 0.74 / 9812.5 * [tex]10^{-11}[/tex]
N² = 7.54 * [tex]10^{6}[/tex]
N = 2.745 * 10³
N = 2745 turns
Therefore, the number of turns the winding have are 2745 turns
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an athlete swings a ball, connected to the end of a chain, in a horizontal circle. the athlete is able to rotate the ball at the rate of 7.80 rev/s when the length of the chain is 0.600 m. when he increases the length to 0.900 m, he is able to rotate the ball only 5.99 rev/s.
1276.9 m/s² is the angular acceleration of 0.900 m, he is able to rotate the ball only 5.99 rev/s.
v=33.9m/s
r=0.9 m
a=v²/r
a=1149.21/0.9
a=1276.9 m/s²
The rate at which the angular velocity in a circular motion varies over time is known as the angular acceleration. Rotational acceleration is another name for it. Given that it has both a magnitude and a direction, it is a vector quantity. Angular acceleration is represented by the letter alpha.
Variable velocity is what causes the acceleration. The phrase "angular acceleration" is used to describe variations in rotational speed in spinning objects. According to the connection, the angular displacement of a spinning object depends on time t. Every time a body rotates, it experiences angular acceleration. A quantitative vector can be used to express the change in angular velocity per unit of time.
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How long does it take to use 266 W of power pushing at 113 N for a distance of 9 meters?
The power pushing at 113 N for a distance of 9 meters. The time taken is 0.22 seconds.
Power :
Power is defined as the speed at which work is performed on an object.
work done = Force x Distance
Power = Work done/ Time
Power = (Force x Distance)/Time
Power = 226 Watt
Force = 113 N
Distance taken = 9 meters
To calculate power we use :
Power = (Force x Distance)/Time
266W = (113N x 9s)/Time
Time = 266W/(113N x 9m)
Time = 266W/(113N x 9m)
Time = 0.22 seconds
The power pushing at 113 N for a distance of 9 meters. The time taken is 0.22 seconds.
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a
b
с
3
A brick is shown in Figure 1.9. It has a mass of
2.8 kg.
65 mm
102.5 mm
215 mm
Figure 1.9: A brick labelled with its dimensions.
Give the dimensions of the brick in metres.
Calculate the volume of the brick.
Calculate the density of the brick.
Answer: A 0.065 METER 0.1025 METER 0.215 METER
B 0.001432 meter^3
C 1955.307 kg/m^3
Explanation:
the drawing shows a skateboarder moving at 6.90 m/s along a horizontal section of a track that is slanted upward by 0
The maximum height H to which she rises above the end of the track that is slanted upward by 48° above the horizontal at its end is 1.11 m
KE = 1 / 2 m v²
PE = m g h
According to law of conservation of energy,
KE ( Initial ) + PE ( Initial ) = KE ( Final ) + PE ( Final )
h ( Initial ) = 0
v ( Initial ) = 6.9 m / s
g = 9.8 m / s²
h = 0.4 m
1 / 2 m vi² + m g hi = 1 / 2 m v² + m g h
1 / 2 m vi² = 1 / 2 m v² + m g h
vi² = v² + 2 g h
6.9² = v² + ( 2 * 9.8 * 0.4 )
v² = 47.61 - 7.84
v² = 39.77 m / s
H = vi² sin²θ / 2 g
θ = 48°
H = 39.77 * sin²48° / ( 2 * 9.8 )
H = 21.78 / 19.6
H = 1.11 m
Therefore, the maximum height H to which she rises above the end of the track is 1.11 m
The given question is incomplete. The complete question is;
The drawing shows a skateboarder moving at 6.9 m/s along a horizontal section of a track that is slanted upward by 48° above the horizontal at its end, which is 0.40 m above the ground. When she leaves the track, she follows the characteristic path of projectile motion. Ignoring friction and air resistance, find the maximum height H to which she rises above the end of the track.
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a weather balloon is floating at a constant height above earth when it releases a pack of instruments. if the pack hits the ground with a velocity of -76.5 m/s what is the packs displacement? how long does the pack fall?
Answer:
below
Explanation:
vf = 76.5
vf= at
76.5 = 9.81 t shows t = 7.798 s
d = 1/2 a t^2 = 1/2 ( 9.81)(7.798)^2 = 298.3 m
A patient with end-stage heart disease asks, "after i meet the physical criteria for a heart transplantation, will i then be selected as a candidate?" which response from the nurse is the most appropriate?.
Patients ought to meet physical and psychological standards to make sure that they may be candidates for coronary heart transplantation.
The Recipient affected person has to be referred to the transplant center with an irreversible and in any other case fatal disease ensuing in organ failure, whilst still being otherwise wholesome enough to live to tell the tale and gain from an organ transplant and to comply with a lifestyles-long medication routine.
Physical criteria indications for transplant in continual heart failure include sufferers who've disabling signs regardless of most fulfilling medical control or refractory arrhythmias no matter scientific and electrophysiological methods.
The doctor will make an incision on your chest. Your health care professional will separate your chest bone and open your rib cage in order that he or she will perform for your coronary heart. Your medical professional then removes the diseased heart and sews the donor heart into place. she or he then attaches the important blood vessels to the donor's coronary heart.
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Please help really confused?
At point A the spinning wheel will experience least centripetal force.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
Centripetal force is applied on object depends on the centre and object distance. So B will experience maximum force while A is least.
At point A the spinning wheel will experience least centripetal force.
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5. Distance covered by a moving body is always greater than 0.
Displacement of a particle can be >,< or=0
a.Both assertions and reason are correct, reason is the the correct explanation
b. Both assertions and reason are correct; reason isn't the correct explanation of the assertion.
c. Assertion is correct but reason isn't
d Assertion is not correct but reason is
Answer:
Explanation:
c. Assertion is correct but reason isn't
g consider a wire 2 ft long cut into two pieces. one piece forms a circle with radius r and the other forms a square with side length x. (a) determine a formula for the radius r in terms of x .
The radius in terms of x is 2/(π+4)
What is area?Area, a quantity that describes the extent of an area on a plane or curved surface. The area of a planar region refers to the area of a shape or planar layer, while surface area refers to the area of an open surface or boundary of a three-dimensional object.
Given that,
y forms a circle of radius r
y = 2πr
r = y/2π
(2-y) forms Square Side x
(2-y) = 4x
x = (2-y)/4
Now Sum of Areas = Area of Square + Area of Circle
Sum = πr² + x²
Substitute the values of r and x in above equation:
A(y) = y²/4π + (y-2)²/ 16
To maximize Area A(y)
A'(y) = 0
2y/4π + 2(y-2)/16 = 0
y/2π + (y-2)/8 =0
y = 2π/(π+4)
For maximum sum of areas,
x = 2/π + 4
Hence, The formula for the radius r in terms of x and for the maximum areas is x=2/(π+4)
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Classify the disadvantages of unconventional oil and gas extraction as belonging to ei sands mining. ther hydraulic fracturing or tar Hydraulic fracturing Tar sands mining Answer Bank local groundwater contamination huge lakes of acidic and toxic wastewater Output outpaces transportation capacity requires heated pipelines for transport destroys habitat and pollutes watersheds corporate rights to oil and gas on private property The breakeven price is S60 per barrel. ye more greenhouse gas emissions Wastewater in injection wells triggers earthquakes.
The disadvantages of unconventional oil and gas extraction as belonging to tar sands mining are as follows:-
Oil and gas extraction:-
Local groundwater contaminationCorporate rights to oil and gas on private propertyWaste water in injection wells triggers earthquakesOutput outpaces transportationsTar sand mining:-
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Disclaimer:- your question is incomplete, please see below for the complete question.
Classify the disadvantages of unconventional oil and gas extraction as belonging to ei sands mining.
a. ther hydraulic fracturing or tar Hydraulic fracturing Tar sands.
b. mining Answer Bank local groundwater contamination huge lakes of acidic and toxic.
C. wastewater Output outpaces transportation capacity requires heated pipelines for transport destroys habitat and pollutes watersheds corporate rights to oil and gas on private property
D.The breakeven price is S60 per barrel. ye more greenhouse gas emissions Wastewater in injection wells triggers earthquakes
consider two satellites s1 and s2 in circular orbits with periods of 8 hours and 16 hours how high are the satellites above the earth's surface?
Consider two satellites s1 and s2 in circular orbits with periods of 8 hours and 16 hours . satellites will be 80129 m and 130829 m high above the earth's surface
h1 = [tex]{(GM(e) * T^{2} / 4 pi^{2} )}^{1/3}[/tex] - R(e)
= ( 6.67 * [tex]10^{-11}[/tex] * 5.97 * [tex]10^{24}[/tex] * [tex]8^{2}[/tex] / 4 * [tex]3.14^{2}[/tex]) - 6371
= 80129 m
h2 = (6.67 * [tex]10^{-11}[/tex] * 5.97 * [tex]10^{24}[/tex] * [tex]16^{2}[/tex] / 4 * [tex]3.14^{2}[/tex]) - 6371
= 130829 m
satellites will be 80129 m and 130829 m high above the earth's surface
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A charming friend of yours who has been reading a little bit about astronomy accompanies you to the campus observatory and asks to see the kind of star that our sun will ultimately become, long, long after it has turned into a white dwarf. Why is the astronomer on duty going to have a bit of a problem satisfying her request?.
Following cooling, a white dwarf becomes too cold and dark to emit visible light.
What is white dwarf?
Like our Sun, medium-mass stars generate helium by fusing hydrogen within their cores. Our Sun is now performing this. An outward pressure results from the heat the Sun produces during the nuclear fusion of hydrogen into helium. The Sun will run out of hydrogen in its core in about 5 billion years.
The Sun begins to collapse when it runs out of hydrogen to fuse, tipping the scales in favor of gravity. However, compacting a star makes it heat up once more, allowing it to fuse what little hydrogen is left in a shell surrounding its core.
We can learn about the age of the universe from white dwarfs. Our galaxy and the age of the universe would be lowered if we could calculate how long it takes for a white dwarf to cool into a black dwarf.
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when a traffic accident is investigated, it is common for the length of the skid marks to be measured. how could this information be used to estimate the initial speed of the vehicle that left the skid marks?
This information could be used in the following ways: the braking distance of a skidding car will depend on its initial speed and the coefficient of kinetic friction.
Thus, if the coefficient of friction is known the initial speed can be determined from the length of the skid marks.
What do you mean by Initial speed?
Initial speed can be described as how fast an object travels when gravity first applies force on the object. It can be represented in the form of (u) and is generally measured in metres per second (m/s).
It can be represented in three ways.
v2=u2+2as v=u+ats=ut+0.5at2Through these formulas we can calculate the initial speed of any object. It helps in understanding various velocities, time principles.
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Explain why increasing temperature from 3°C to 6°C does not double temperature. In Charles law.
Celsius does not measure at an absolute temperature , hence increasing temperature from 3°C to 6°C does not double temperature. In Charles law.
Heat or bloodless is measured in terms of temperature. It demonstrates how warmth electricity certainly flows from a warmer body to a cooler body and may be expressed in phrases of any range of arbitrary scales (one at a decrease temperature).
A match is burning at a far greater temperature than an iceberg, yet an iceberg has a considerably better total warmth electricity than a in shape. Temperature isn't always similar to the electricity of a thermodynamic system.
Temperature, along side strain, density, and different like qualities, is known as an excessive belongings as opposed to vast functions, together with mass or extent—one this is independent of the quantity of stuff being addressed.
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write the formula for newton's method and use the given initial approximation to compute the approximations x1 and x2
Using Newton's method , the approximations value of x₁ and X₂ are 7.1 and 7.0 respectively.
Newton's method: Newton’s method is a procedure for approximating the solutions of an equation f(x) =0. These are also called the zeros of f. Newton’s method is an iterative procedure that finds an approximation to a rootof f(x) =0 and then uses the approximation to help find a better approximation. This gives a list of numbers x1, x2, x3, . . . which we call successive approximations. We begin by explaining the main step of method with shows us how to find xn+1 from xn.
Given an approximation xn, compute the next approximation by xₙ+1 = xₙ− f(xₙ)/f'(xₙ).•
We have given that,
f(x) = x²−2x−35, and x₀= 6
approximation relation for succive approximation
is xₙ + 1 = xₙ − (xₙ2 - 2xₙ- 35) / 2xₙ− 2
Now , we compute the values of x1 and X2 using approximation relation
put n= 0 , in above formula we get
X₁ = x₀- ( x₀²- 2x₀ - 35)/2x₀ -2
using initial condition, x₁ = 6 - ( 36-12-35)/10 = 7.1
again put, n= 1
x₂ = x₁ - ( x₁ ² - 2x₁ -35)/2x₁ -2 = 7.1 - ((7.1)² - 14.2 -35)/12.2 = 7.00
Hence, the value of first succive approximation (x₁) is 7.1 and second approximation (x₂) is 7.00
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Complete Question:
Write the formula for Newton's method and use the given initial approximation to compute the approximations x1 and x2.
f(x)=x2−2x−35, x0 =6
Write the formula for Newton's method for the given function. Choose the correct answer below.
xn+1=xn−(xn2−2xn−35 )/ 2xn−2
Use the given initial approximation to compute the approximations x1 and x2.
what is the difference between average speed, average velocity, and instantaneous velocity mathematically?
Divided by the amount of time passed, the average speed is obtained. The limit of average velocity as elapsed time approaches zero is the instantaneous velocity of an object. v (t) = d d t x (t). v (t) = d d t x (t).
The average velocity rate of change is a measure of how much one variable has changed overall relative to another. The instantaneous rate of change, also known as the derivative, quantifies the precise rate at which one variable changes in relation to a precise, extremely small change in another variable.Average speed is the ratio of an object's total distance travelled to its total travel time. Average acceleration is calculated by dividing the change in velocity by the amount of time that has passed; instantaneous acceleration is the acceleration at a specific time. Average acceleration is the acceleration at a specific moment in time; instantaneous acceleration is the velocity change divided by the amount of time that has passed. As a result, only when the body is moving at a constant speed can instantaneous speed and average speed be equal. Instantaneous speed and instantaneous velocity have the same magnitude.
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Which form of electromagnetic radiation has photons with the highest energy? Group of answer choices Infrared Radiation Gamma Rays Microwaves Radio Waves X-rays
Gamma rays is a form of electromagnetic radiation that has photons with the highest energy.
Gamma rays are a form of electromagnetic radiation (EMR). They are the similar to X-rays, distinguished only by the fact that they are emitted from an excited nucleus.
The energy of the photon is directly proportional to the frequency, that is Ε α υ. It means that if the photon has high frequency, then the energy of that photon will be high, and if the photon has lower frequency then the energy that the photon will be less.
Here it is given to determine the radiation that has high energy, which in turn means that radiation with the highest frequency is needed to be found. Hence, from the data of electromagnetic spectrum, the radiation with the highest frequency is the gamma rays with frequencies up to 10^19 Hz.
As gamma rays have the highest frequency, gamma rays will also have the highest energy, with energy extending up to few trillion electron volts.
Hence, the radiation with the highest energy is gamma rays.
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suppose three planets all have similar rocky surfaces but different average densities as in the choices below. which planet is likely to have a large iron core? a)6000 kg/m3
b)3000 kg/m3
c)4500 kg/m3
The planet that is likely to have a large iron core if all three planets have similar rocky surfaces but different average densities is 6000 kg / m³
Density is directly proportional to he size of iron core. Larger the density of the planet larger will be the size of iron core of the planet. Smaller the density of the planet smaller will be the size of iron core of the planet.
Average density of a planet is the value of total mass divided by the total volume. If the average density of a planet is higher than 3000 kg / m³, the planet is terrestrial. If the average density of a planet is lesser than 2000 kg / m³, the planet is Jovian.
Therefore, the planet that is likely to have a large iron core if the planet with 6000 kg / m³
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With our current techniques, astronomers can typically only measure the minimum mass of a planet orbiting another star. To know the precise mass of the planet, they must also be able to determine.
To know the exact mass of a planet, we also need to be able to determine the angle at which the planet's orbit is tilted toward us.
How do you calculate the minimum mass of a planet orbiting another star?To determine the mass of a planet, astronomers usually measure the small motions of the star caused by the gravitational pull of the orbiting planet. For a planet, figuring out the mass of the Earth is an extraordinary challenge with current technology.
Therefore, to measure the mass of a planet, measure the period and orbital radius of all satellites orbiting the planet, plot graph against R³/T² for all satellites, and calculate the mass of the planet. This is one way to do that.
According to Kepler's laws: If the orbital size (a) is expressed in astronomical units (1 AU is the average distance between the Earth and the Sun) and the period (P) is measured in years, Kepler's third law states that his P² = a³ increase. where P is the Earth year, a is the AU, and M is the mass of the central body in units of the mass of the Sun.
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Why are the inner planets (those which orbit inside the asteroid belt) all relatively small and rocky, whereas the outer planets are large and mostly composed of gas?
Answer:
The temperature of the early solar system explains why the inner planets are rocky and the outer ones are gaseous.
Explanation:
The outer planets are much larger than the inner planets. Because of their large mass and cooler temperature, they have a very different composition; they are mostly made of light elements with extended atmospheres in a gaseous form. Outer planets exist in much bigger systems than inner planets.
The reason for different composition of planets has to do with how the solar system formed. In the early solar system, there was a disk of material rotating around the Sun, from which the planets eventually formed. However, to form planets required some kind of initial clump in the protoplanetary disk. These clumps were probably formed from collisions of solid particles. Different elements become solid at different temperatures: the most common elements, hydrogen and helium, never became solid, but hydrogen compounds (like water) can solidify at colder temperatures, like those in the outer solar system. In the inner solar system, it was too hot for these compounds to solidify; only rocks and metals can solidify at these temperatures. Hence, only small planetesimals formed in the inner solar system.