If DEF=GJH, find each missing measure

a) DF =

d) F =

b) JH =

|||

e) m&G =

c) GJ =

f) m =

I need help it’s due in 20 minutes:(

Answers

Answer 1

Congruent triangles have equal corresponding sides and angles.

The measure of the side lengths are: [tex]\mathbf{DF = 16m}[/tex], [tex]\mathbf{JH = 14m}[/tex] and [tex]\mathbf{GJ = 19m}[/tex]The measure of the angles are: [tex]\mathbf{\angle G = 34^o}[/tex], [tex]\mathbf{\angle J = 41^o}[/tex] and [tex]\mathbf{\angle F = 105^o}[/tex]

The given parameters are:

[tex]\mathbf{\triangle D EF \cong \triangle GJH}[/tex]

[tex]\mathbf{EF = 14m}[/tex]

[tex]\mathbf{D E = 19m}[/tex]

[tex]\mathbf{GH = 16m}[/tex]

[tex]\mathbf{\angle D = 34^o}[/tex]

[tex]\mathbf{\angle H = 105^o}[/tex]

[tex]\mathbf{\triangle D EF \cong \triangle GJH}[/tex] means that triangles DEF and GHJ are congruent triangles.

So, we have:

[tex]\mathbf{DF = GH}[/tex]

This gives

[tex]\mathbf{DF = 16m}[/tex]

Also, we have:

[tex]\mathbf{JH = EF}[/tex]

This gives

[tex]\mathbf{JH = 14m}[/tex]

Also, we have:

[tex]\mathbf{GJ = DE}[/tex]

This gives

[tex]\mathbf{GJ = 19m}[/tex]

The following angles are also congruent

[tex]\mathbf{\angle F = \angle H}[/tex]

This gives

[tex]\mathbf{\angle F = 105^o}[/tex]

Also, we have:

[tex]\mathbf{\angle G = \angle D}[/tex]

This gives

[tex]\mathbf{\angle G = 34^o}[/tex]

The measure of angle J is then calculated using

[tex]\mathbf{\angle J + \angle H + \angle G = 180^o}[/tex]

This gives

[tex]\mathbf{\angle J + 105 + 34= 180^o}[/tex]

[tex]\mathbf{\angle J + 139= 180^o}[/tex]

Subtract 139 from both sides

[tex]\mathbf{\angle J = 41^o}[/tex]

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If DEF=GJH, Find Each Missing Measurea) DF =d) F =b) JH =|||e) M&G =c) GJ =f) M =I Need Help Its

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Answer:   [tex]G(F(x)) = x^3-21x^2+147x-343\\\\[/tex]

===================================================

Work Shown:

[tex]G(x) = x^3\\\\G(F(x)) = \left(F(x)\right)^3\\\\G(F(x)) = \left(x-7\right)^3\\\\G(F(x)) = \left(x-7\right)\left(x-7\right)^2\\\\G(F(x)) = \left(x-7\right)\left(x^2-14x+49\right)\\\\G(F(x)) = x\left(x^2-14x+49\right)-7\left(x^2-14x+49\right)\\\\G(F(x)) = x^3-14x^2+49x-7x^2+98x-343\\\\G(F(x)) = x^3-21x^2+147x-343\\\\[/tex]

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Step-by-step explanation:

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Anneyonghaseyo!!

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꧁✿ ᴿᴬᴵᴺᴮᴼᵂˢᴬᴸᵀ2222 ✬꧂

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