If F = 4.0 N and m = 2.0 kg, what is the magnitude a of the acceleration for the block shown below? The surface is frictionless. *
Answers
The magnitude of the acceleration of the block is 3.5 [tex]\bold{m/s^2.}[/tex]
The correct option is (C) 3.5 [tex]\bold{m/s^2.}[/tex]
What do you mean by acceleration?Acceleration is the rate of change of velocity with time.
By Newton’s Second law
This law establishes the relationship between the net applied force on an object with the resultant acceleration. For a constant magnitude of force, the more is the mass of the object, the lesser will be its acceleration.
Given,
The mass of the block is 2.0 kg.
The force in the horizontal direction on the block is [tex]\bold{4.0 N + 4.0 N \cos 40{}^\circ.}[/tex]
a is the acceleration in the horizontal direction.
The acceleration for the block can be determined using Newton’s Second law,
[tex]\begin{aligned} \Sigma F&=ma \\ F+F\cos 40{}^\circ &=ma \\ a&=\frac{F\left( 1+\cos 40{}^\circ \right)}{m} \\ &=\frac{4.0\text{ N}\left( 1.766 \right)}{2.0\text{ kg}} \\ &=3.5\text{ m/}{{\text{s}}^{2}} \end{aligned}[/tex]
Thus, the acceleration is 3.5 [tex]\bold{m/s^2.}[/tex]
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Related Questions
A train travelling along a straight track starts from rest at point A and accelerates uniformly to 10 m si in 20 s. It travels at this speed for 60 s, then slows down uniformly to rest in 40 sat point C. It stays at rest at C for 30 s, then reverses direction, accelerating uniformly to 5 ms. in 10 s. It travels at this speed for 30 s, then slows down uniformly to rest in 10 s when it reaches point B.
1. Plot a graph of the motion of the train.
II. Use your graph to calculate:
III. the train's displacement from point A when it reaches point C
IV. the train's displacement from point A when it reaches point 13
V. the train's acceleration each time its speed changes.
Answers
Please find attached photographs for your answer.
Hope it helps.
Do comment if you have any query.
If a person is pushing a cart with a force of 40 Newtons and it
accelerates at 0.5 m/s², what is the mass of the cart?
Answers
Answer:
80kg
Explanation:
A = Fm
0.5 = 40m
m = 40/0.5
m = 80kg
What do you mean by 100w power?
Answers
A car accelerates from rest to 40 m/s. Later, on a highway it accelerates from 40 m/s to 80 m/s. Which takes more energy, going from 0 to 40, or from 40 to 80
Answers
Answer:
40 to 80
Explanation:
A car's kinetic energy changes with the speed. Cars going slower have less potential energy than cars going faster.
What is the equation for density?
O D= m
V
O D= V
-
m
O D= m
O D= { mu?
2
Answers
Which statement describes the flow of heat? Question 8 options: Heat moves from a warmer object to a cooler object. Heat moves from a cooler object to a warmer object. Heat moves from a cooler object to a warmer object. Heat moves only between two cold objects.
Answers
Answer:
A
Explanation:
HELPPPPPPPPPPPPPPPPPPP
Answers
Answer:
directly proportional
Explanation:
how does the hypothesis of inflation account for the existence of the seed of density from which galaxies and other large structures formed
Answers
3. If John leaves his house to walk his dog and he walks around the block, what is
his distance?
180 Meters
180 Meters
180 Meters
180 Meters
Answers
Answer:
180 meters
Explanation:
The steepest street in the world is Baldwin Street in Dunedin, NZ. It is inclined at an angle of 380 , with the horizontal. A child slides down the street with a constant velocity on a sled with high friction runners. What is the coefficient of friction between the sled runners and the street?
Answers
Newton's second law allows to find the result for the friction coefficient of the street is:
The friction coeficinwete is: μ = 0.78
Newton's second law establishes a relationship between the net force, the mass and the acceleration of the body.
∑ F = m a
Where bold indicates vectors, m is to mass and acceleration.
In the attached we see a free body diagram, it is a diagram of the forces without the details of the body, the x-axis is parallel to plane also shown with the positive in the direction of movement, going down the plane and the y-axis perpendicular to the plane.
Let's use trigonometry to break down the weight.
Sin θ = [tex]\frac{W_x}{W}[/tex]
cos θ = [tex]\frac{W_y}{W}[/tex] / W
Wₓ = W sin θ
[tex]W_y[/tex] = W cos θ
We write Newton's second law for each axis.
y-axis
N- [tex]W_y[/tex] = 0
N = mg cos θ
x-axis
Wₓ - fr = ma
Since they indicate that the body goes down at a constant speed, the acceleration is zero.
W sin θ = fr
The friction force is the macroscopic representation of the interactions between the two surfaces and the formula.
fr = μ N
we substitute.
fr = μ mg cos θ
mg sin θ = μ cos θ
μ = tan θ
Let's calculate.
μ = tan 38.0
μ = 0.78
In conclusion using Newton's second law we can find the results for the friction coefficient of the street is:
The frivtion coefficient is: μ = 0.78
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three cars with identical engines and tires start from rest, and accelerate at their maximum rate. car x is the most massive, and car z is the least massive. which car needs to travel the farthest before reaching a speed of 60 mi/h?
Answers
Answer: The most massive car, x, will take the longest to reach 60 mph.
Explanation: The inertia of a car is dependent on its mass. F=ma. Given that each car has the same force (identical engines) the one with the higher mass will accelerate more slowly.
What is the correct definition of rarefaction
Answers
Answer:
Explanation:
A decrease in the density of something is rarefaction. ... Most of the time, rarefaction refers to air or other gases becoming less dense. When rarefaction occurs, the particles in a gas become more spread out. You may come across this word in the context of sound waves.
please help me thank you
Answers
Answer:
Refer to the attachment
if you exert a force on an object, but the object remains stationary as you apply the force, then how much work have you done on the object?
Answers
Answer:
no work done
Explanation:
unless you moved the object
When we apply a force on an object, but the object remains at rest when the force is applied, then we have zero work done on the object because the object does not move.
What is Work done?Work done by a force is defined as the product of the displacement and the component of the force exerted by the object in the direction of displacement. Work done is expressed as:
Work done= Force* Displacement
When an object is at rest, there is no external force on it except gravity acting on it, in which case work will be zero because the force acting on it is perpendicular. Thus displacement is zero and if displacement is zero then work done will be zero.
Suppose that displacement is zero then,
W=f×0
Work done is zero
Thus, the work done is zero.
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a car traveled 5,300 km in 1 hour whats the average speed is
Answers
Answer:
5300km/h
Explanation:
That's an easy question. You can solve it yourself.
The answer can be found by dividing the Distance traveled by the Time.
Now you can solve all the problem of this rule.
Fuses of ________________________
a. same kind are used for different purposes
b. different kind are used for different purposes
c. both of the above are correct
d. none of these
Answers
Answer:
C
Explanation:
fuses of same kind can be used for different things, and of different kinds could be used for different things as well.
why are some small jovian planet moons geologically active?
Answers
Answer:
tidal heating and/or their composition
Explanation:
1. A rocket is launched from a 300 cm rail. The upper Launch Lug is placed 1 point 150 cm from the bottom of the rocket. What is the effective distance of the Launch Rail? 300 cm 150 cm 3 m 300 m O 1m O 1.5 m
Answers
Answer:
i think its going to be 150 because its half of 300
Explanation:
If the momentum of the NASA space shuttle as it leaves the atmosphere is 3.75 x 10^8 kg ·m/s and its mass is 75000 kg, what is its speed?
Answers
Hi there!
We know that:
Momentum (p) = mass (kg) × velocity (m/s)
Or:
P = mv
We can rearrange the equation to solve for speed:
P/m = v
Plug in the given values:
(3.75 × 10⁸)/75000 = 5000 m/s
6. Two skaters, Jim (65 kg) and Mary (50 kg) are standing at rest on the ice. They push each other
and Mary recedes at 2.5 m/s towards the east. Find Jim's velocity (magnitude and direction).
Answers
Hi there!
This is an example of a recoil collision.
Let m1, v1 be Mary
Let m2, v2 be Jim
Utilize the conservation of momentum:
m1v1 + m2v2 = m1v1' + m2v2'
The initial velocities are zero (at rest), so:
0 = m1v1' + m2v2'
Let east be positive, so Jim recoils with a negative velocity:
0 = m1v1' - m2v2'
Set the two equal and solve:
m1v1' = m2v2'
m1v1'/m2 = v2'
(50)(2.5)/65 = v2' = 1.92 m/s to the WEST
You have a particle of length 68 nm. What is this in meters?
A. 6.8 x 10^10 m
B. 6.8 x 10^14 m
C. 6.8 x 10^-11 m
D. 6.8 x 10^-8 m
The number after "^" that symbol are exponents
Answers
Don’t pay attention to this part
The energy transferred per unit electric charge in a circuit is .
A current
B charge
C power
D potential difference
Answers
you moved from the top bunk of a bunk bed to the bottom and noticed that the air is colder. the cold air stays at the bottom because of
Answers
Answer:
heat transfer? sorry if I'm wrong!
newtons 2nd law of the law of…
Answers
What is an ellipse?
I want an accurate answer. No spam.
Answers
Answer:
It is defined as an astronomical phenomenon which occurs when one spatial object comes within the shadow of another spatial object.
Seismic waves do not travel along the Earth’s surface.
Please select the best answer from the choices provided
T (true)
F (false)
Answers
Both choices are correct.
Some seismic waves travel along the Earth's surface.
Others don't.
Answer:
False
Explanation:
Edge2022
what is the magnitude of the torque that the axle must apply to prevent the disk from rotating?
Answers
The required torque at the axle, is given by the difference between the
moments of the applied forces.
The torque required is 19.62 N·m counterclockwise
Reasons:
The given parameters are;
Mass of the disk, m = 5.0 kg
Location of the axle = Half the radius of the disk
Diameter of the disk, D = 40 cm = 0.4 m
Applied mass, 0.1 m from the axle = 15 kg
Applied mass, 0.3 m from the axle = 10 kg
Required:
Magnitude of torque at the axle that prevent the disk from rotating
Solution:
Torque needed = Clockwise moment - Counterclockwise moment
Clockwise moment = (10 kg × 0.3 m + 5 kg × 0.1 m) × 9.81 m/s² = 34.335 N·m
Counterclockwise moment = 15 kg × 0.1 m × 9.81 m/s² = 14.715 N·m
τ + Counterclockwise moment = Clockwise moment
τ + 14.715 N·m = 34.335 N·m
Torque required, τ = 34.335 N·m - 14.715 N·m = 19.62 N·m
Torque required, τ = 19.62 N·m counterclockwise
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The probable question drawing obtained from a similar question online is attached
1 point
What is the potential energy of a 12543 kg tank this on the ground? (only
put the number, no units or commas) *
Answers
Answer:
PE=0
Explanation:
If the tank is on the ground, there is 0 height which means the equation of PE=mh will be PE=12543(0)=0, hope this helps!
Entomology is the application of__________ to be used in a criminal investigation??
A/ soil science
B/insect science
C/plant science
D/glass science
Answers
the second law of thermodynamics imposes what limit on the efficiency of a heat engine?
Answers
A heat engine cannot have a thermal efficiency of 100% For all reversible processes, the second-law efficiency is 100%. The second-law efficiency of a heat engine cannot be greater than its thermal efficiency. The second-law efficiency of a process is 100% if no entropy is generated during that process