If the average volume flow of blood through the aorta is 8.5 × 10-5 m 3/s and the cross-sectional area of the aorta is 3.0 × 10 -4 m2, what is the average speed of blood in the aorta?

Help me:)

Answer:

See image

Step-by-step explanation:

I'm guessing a little bit, bc although you attached an image, it doesn't say what you are trying to prove, nor what you are given. Usually that is provided for a proof.

But we can see that the parallel segments are marked, so we'll call that the given information. Then there are actually two pairs of corresponding angles that are congruent by the Corresponding Angles postulate. But we only need one pair. Then Angle A is congruent to itself by Reflexive Property. Finally what we have proven is that the two triangles ABC and ART are similar by AA

Answer:

23 starfish, 7 octopi

Step-by-step explanation:

x=starfish

y=octopi

x+y=30

5x+8y=171

-5(x+y=30)

5x+8y=171

-5x-5y=-150

5x+8y=171

3y= 21

y=7

x+7=30

x=23

23 starfish, 7 octopi

Answer:

x= 2597/335

Step-by-step explanation:

collect like terms

2.4x-9.1x= -6.7x

-39.44-12.5 = -51.94

-6.7x=-51.94

divide both sides by -6.7

x= 2597/335

[tex]50 + angle \: \: u \: \: = 115 \\ = > angle \: \: u \: = 115 - 50 \\ = > angle \: \: u \: \: = 65[/tex]

Answer:

Angle U is 65°.

Hope you could get an idea from here.

Doubt clarification - use comment section.

Answer:

380

Step-by-step explanation:

area of a circle is pir^2

3.14(11)^2

3.14(121)

=380sqft

Step-by-step explanation:

Well. Let's call α the 120° angle, and β its supplementary angle (80°). Let's draw also the height of the triangle. We'll call it CH. We know, from goniometric relations, that BC * sinβ = CH and BC * cosβ = BH. We just apply the pythagorean theorem so we get: AC = [tex]\sqrt{(AB+BH)^2+CH^2}.[/tex] By inserting all the values you'll get the result.

Answer:

D. –5.2 + (–6.4) = –11.6

Step-by-step explanation:

First, you can eliminate A and C because 5.2 is positive. Since the red arrow is pointing left, it indicates that the number (-5.2) is negative.

Then, you look at the second arrow, the green one. It is pointing left, so it would be -6.4.

I hope this helps :)

Answer:

25*1/5(or 0.2)=

5

she gives a way 5 toys

Hope This Helps!!!

The number of toys that she gives away will be 5.

The analysis of mathematical representations is algebra, and the handling of those symbols is logic.

It is also known as the product. If the object n is given to m times then we just simply multiply them.

Cynthia gave 1/5 of her toys to her little sister.

If she had 25 toys.

Then the number of toys that she gives away will be given by the product of 25 and 1/5.

⇒ 25 x 1 / 5

⇒ 5

The number of toys that she gives away will be 5.

More about the Algebra link is given below.

https://brainly.com/question/953809

#SPJ2

Answer:

Step-by-step explanation:

Conclusion:

Therefore, the answer is 'x = 36'.

Hoped this helped.

[tex]BrainiacUser1357[/tex]

Answer: C) 2200

Step-by-step explanation:

Answer:

[tex]\huge\purple{\overline{\quad\quad\quad\quad\quad\quad\quad\quad\quad \ \ \ }}[/tex]

»ANSWER«

(1) Write properties of function:

x intercept/zero:

[tex] x_{1} = \frac{3}{4} [/tex]

y intercept:

[tex]y = - 12[/tex]

domain:

[tex]( - \infty \: \infty )[/tex]

type of function: cubic fraction

standard form:

[tex]f(x) = 4 {x}^{3} - 3 {x}^{2} + 16x - 12[/tex]

factorize form:

[tex]f(x) = (4x - 3)( {x}^{2} + 4)[/tex]

even/odd/neither: neither

bounce/cross x axis:

[tex]x = \frac{3}{4} \: across[/tex]

increasing interval:

[tex]( - \infty \: \infty )[/tex]

decreasing interval: no

number of positive real zeros: 1

number of possible turning point: 2

order/degree: 3

leading term:

[tex]4x ^{3} [/tex]

leading coefficent: 4

constant term: -12

end behavior:

[tex]as \: x \: → \infty f(x) → \infty \: as \: x → - \infty f(x) → - \infty [/tex]

#CarryOnLearning

Answer:

Area is 5 cm and perimeter is 12 cm

Step-by-step explanation:

Area: top left sqare:

1cm * 1cm = 1 cm

bottom rectangle:

1cm * 3 cm = 3 cm

top right square:

1cm * 1cm = 1 cm

Perimeter:

1 cm + 2 cm+ 3 cm+ 2 cm+ 1 cm + 1 cm + 1cm + 1cm  = 12 cm

Answer:

h = - 103/8

Step-by-step explanation:

1) Re-order terms so constants are on the left

8h = = -2(8)²+4(8)-7

2) Evaluate the exponent

8h = -2·64+4(8)-7

3) Multiply the numbers

8h = -128+4(8)-7

4) Multiply the numbers

8h = -128+32-7

5) Add the numbers

8h = -103

6) Divide both sides of the equation by the same term

8h/8 = -103/8

7) Simplify

- Cancel terms that are in both the numerator and denominator

h = -103/8

Answer:

Number of chairs = 24

Number of stools = 12

As about the question number 2, I think you should check whether the question you copied is correct are not.

Step-by-step explanation:

1. One person,

Three hours for a chair and two hours for a stool

Therefore, 12 people working for 8 hours;

Per person produced two chairs and one stool as 3+3+2=8 hours

12×2= 24 chairs and 12×1=12 stools.

Simplifying h(x) gives

h(x) = (x² - 3x - 4) / (x + 2)

h(x) = ((x² + 4x + 4) - 4x - 4 - 3x - 4) / (x + 2)

h(x) = ((x + 2)² - 7x - 8) / (x + 2)

h(x) = ((x + 2)² - 7 (x + 2) - 14 - 8) / (x + 2)

h(x) = ((x + 2)² - 7 (x + 2) - 22) / (x + 2)

h(x) = (x + 2) - 7 - 22/(x + 2)

h(x) = x - 5 - 22/(x + 2)

An oblique asymptote of h(x) is a linear function p(x) = ax + b such that

[tex]\displaystyle \lim_{x\to\pm\infty} h(x) - p(x) = 0[/tex]

In the simplified form of h(x), taking the limit as x gets arbitrarily large, we obviously have -22/(x + 2) converging to 0, while x - 5 approaches either +∞ or -∞. If we let p(x) = x - 5, however, we do have h(x) - p(x) approaching 0. So the oblique asymptote is the line y = x - 5.

Answer:

( x + 1 ) ^ 3

Step-by-step explanation:

f(x) = 3√x - 1

replace x with y

x = 3√y - 1

solve for y,

x = 3√y - 1

x^3 + 3x^2 + 3x + 1 = (x+1)^3

HOPE THIS HELPS :)

[tex]\huge \bf༆ Answer ༄[/tex]

Total distance covered is equal to ~

Hence distance covered = 2200 m = 2.2 km

Answer:

(i) In △ABD and △ACD,

AB=AC ....(since △ABC is isosceles)

AD=AD ....(common side)

BD=DC ....(since △BDC is isosceles)

ΔABD≅ΔACD .....SSS test of congruence,

∴∠BAD=∠CAD i.e. ∠BAP=∠PAC .....[c.a.c.t]......(i)

(ii) In △ABP and △ACP,

AB=AC ...(since △ABC is isosceles)

AP=AP ...(common side)

∠BAP=∠PAC ....from (i)

△ABP≅△ACP .... SAS test of congruence

∴BP=PC ...[c.s.c.t].....(ii)

∠APB=∠APC ....c.a.c.t.

(iii) Since △ABD≅△ACD

∠BAD=∠CAD ....from (i)

So, AD bisects ∠A

i.e. AP bisects∠A.....(iii)

In △BDP and △CDP,

DP=DP ...common side

BP=PC ...from (ii)

BD=CD ...(since △BDC is isosceles)

△BDP≅△CDP ....SSS test of congruence

∴∠BDP=∠CDP ....c.a.c.t.

∴ DP bisects∠D

So, AP bisects ∠D ....(iv)

From (iii) and (iv),

AP bisects ∠A as well as ∠D.

(iv) We know that

∠APB+∠APC=180

∘

....(angles in linear pair)

Also, ∠APB=∠APC ...from (ii)

∴∠APB=∠APC=

2

180

∘

=90

∘

BP=PC and ∠APB=∠APC=90

∘

Hence, AP is perpendicular bisector of

Step-by-step explanation:

HOPE ITS HELP YOU

Answer:

3780 m

Step-by-step explanation:

First, we find the perimeter of the scale drawing.

perimeter = 2(L + W)

perimeter = 2(10.1 cm + 8.8 cm)

perimeter = 2(18.9 cm)

perimeter = 37.8 cm

Now that we have the perimeter of the drawing, we use the scale to find the real perimeter.

1 cm (drawing) = 100 m (real)

37.8 cm × 100 m/cm = 3780 m

Answer: 3780 m

Answer:

The answer is 27%, 6/22, and 3/11.

Pls mark brainliest. :D

Answer:

They measure the area, volume, length, and width, in construction

10 - 15 = -5

Step-by-step explanation:

HOPE THIS HELPED

Answer:

C. 1 to 4

Step-by-step explanation:

The ratio is used to describe situations like "for how many x's, there are many y's". In this case, we are trying to find the ratio for A baskets scored to B baskets scored, team A scores one basket, then team B will score 4 baskets. Then we can write the ratio of A to B as 1:4, which is 1 to 4.

Hope I did this correctly since it was long ago that I lastly worked with ratios

Answer:

10 eggs for 40 dozens

Step-by-step explanation:

40÷8=5

5*2=10

Our created proportion is 8:2::40:x

Therefore, for 40 dozen cookies, 10 eggs are required.

Hoped this helped.

[tex]BrainiacUser1357[/tex]