If the measure of the third angle of the triangle is 45 ​° more than three time the measure of either of the other two​ angles, find the measure of each angle of the triangle.​ (Recall that the sum of the measures of the angles of a triangle is​ 180°.)

Answer:

The first and second angles are 27° and the third angle is 126°.

Step-by-step explanation:

We have that the third angle (β) is 45° more than three times the measure of either of the other two​ angles (θ):

[tex] \beta = 45 + 3\theta [/tex]     (1)

Also, the sum of the measures of the 3 angles is 180°:

[tex] \beta + \theta + \theta = 180 ^{\circ} [/tex]   (2)

By entering equation (1) into equation (2) we have:

[tex] 45 + 3\theta + \theta + \theta = 180 [/tex]  

[tex] 5\theta = 180 - 45 [/tex]

[tex] \theta = 27 [/tex]

Hence, the third angle is:

[tex] \beta = 45 + 3\theta = 45 + 3*27 = 126 [/tex]                                  

Therefore, the first and second angles are 27° and the third angle is 126°.

I hope it helps you!

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