No, you would be obtaining a convenience sample and not a random sample.(A)
By walking around your school campus and asking people you met how many keys they were carrying, you would be obtaining a convenience sample. A convenience sample is a type of non-random sampling method where the participants are chosen based on their availability and accessibility.
This method is not truly random, as it relies on your chance encounters with people and does not give every individual within the population an equal chance of being included in the sample.
A random sample, on the other hand, would involve selecting participants in a way that ensures each person has an equal opportunity to be chosen, which can reduce potential biases and increase the representativeness of the sample.(A)
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complete question:
If you walked around your school campus and asked people you met how many keys they were carrying, would you be obtaining a random sample? Chose the correct answer below.
A. No, you would be obtaining a convenience sample and a random sample.
B. Yes, you would be obtaining a random sample.
C. As long as you surveyed at least 100 people you would be obtaining a simple random sample.
D. No, you would be obtaining a biased sample.
The position vector r describes the path of an object moving in space. Position Vector Time r(t)= 3ti + tj + 1/4t^2k t=2 Find the velocity vector, speed and acceleration vector of the object. v(t)=___
s(t)=___
a(t)=___
The velocity vector at t=2 is 3i + j + k.
The speed at t=2 is sqrt(11).
The acceleration vector at t=2 is 1/2k.
To find the velocity vector, we need to take the derivative of the position vector with respect to time:
v(t) = dr/dt = 3i + j + 1/2t k
Substituting t=2, we get:
v(2) = 3i + j + k
To find the speed, we need to take the magnitude of the velocity vector:
s(t) = |v(t)| = sqrt(3^2 + 1^2 + 1^2) = sqrt(11)
Substituting t=2, we get:
s(2) = sqrt(11)
To find the acceleration vector, we need to take the derivative of the velocity vector with respect to time:
a(t) = dv/dt = 1/2k
Substituting t=2, we get:
a(2) = 1/2k
Therefore, the velocity vector at t=2 is 3i + j + k, the speed at t=2 is sqrt(11), and the acceleration vector at t=2 is 1/2k.
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find f. f ''(x) = 8 cos(x), f(0) = −1, f(7/2) = 0
The final answr is F(x) = -8 cos(x) + (8cos(7/2)/7)x - 1.
Integrating, also known as integration, is a fundamental concept in calculus that involves finding the area under a curve or the accumulation of a quantity over a given interval. Integration is the opposite of differentiation, which involves finding the slope of a curve at a given point.
There are two main types of integrals: definite integrals and indefinite integrals. A definite integral involves finding the area under a curve over a specific interval, while an indefinite integral involves finding a function whose derivative is equal to the original function.
To find f given that f''(x) = 8 cos(x), we need to integrate this expression twice with respect to x to obtain f(x).
Integrating f''(x) once gives:
f'(x) = ∫ f''(x) dx = ∫ 8 cos(x) dx = 8 sin(x) + C1
where C1 is the constant of integration.
Integrating f'(x) once more gives:
f(x) = ∫ f'(x) dx = ∫ (8 sin(x) + C1) dx = -8 cos(x) + C1x + C2
where C2 is another constant of integration.
We can solve for the constants of integration using the initial conditions:
f(0) = -1 implies -8cos(0) + C1(0) + C2 = -1, so C2 = -1
f(7/2) = 0 implies -8cos(7/2) + C1(7/2) - 1 = 0, so C1 = 8cos(7/2)/7
Thus, the solution for f(x) is:
f(x) = -8 cos(x) + (8cos(7/2)/7)x - 1
Therefore, f(x) = -8 cos(x) + (8cos(7/2)/7)x - 1.
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halp il give all the points just help me
Answer:
Step-by-step explanation:
-5/2
To find the slope you need to use rise/run which is basically difference of y coordinates over difference of x coordinates
so first, pick 2 coordinates that you know in that linear relationship like in this case
(0,3) and (2,-2)
do rise/run which will look like this
=(y2-y1)/(x2-x1)
=(3-(-2))/(0-2)
=-5/2
Which action is an example of a medium-term savings goal?
A. Saving to buy a house
B. Saving to buy concert tickets
C. Saving to make a down payment on a used car
D. Saving for a new smartphone
A train travelled along a track in 120 minutes, correct to the nearest 5 minutes
Sue finds out that the track is 290 km long.
She assumes that the track has been measured correct to the nearest 10 km.
a) Could the average speed of the train have been greater than 145 km/h? You must show how you get your answer and your final line must clearly say, 'Yes' or 'No'.
Sue's assumption was wrong.
The track was measured correct to the nearest 5 km.
b) What will the new maximum average speed be in km per minute? Give your answer correct to 2 decimal places.
Correct Answer gets brainliest.
help someone need help with this
The area of the figure which consists of two trapezoids is calculated as: 186.0 cm².
What is the Area of the Figure?The figure is composed of two trapezoids. Therefore, the area of the figure would be the sum of the areas of both trapezoids.
Area of trapezoid 1 = 1/2 * (a + b) * h
a = 20.0 cm
b = 12.0 cm
h = 6.0 cm
Area of trapezoid 1 = 1/2 * (20.0 + 12.0) * 6.0 = 96.0 cm²
Area of trapezoid 2 = 1/2 * (a + b) * h
a = 20.0 cm
b = 10.0 cm
h = 6.0 cm
Area of trapezoid 2 = 1/2 * (20.0 + 10.0) * 6.0 = 90.0 cm²
Area of the figure = 96.0 + 90.0 = 186.0 cm²
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A= 5 0 0 09 1 -3 4-4 -1 -2 1-4 -1 -7 6has two distinct real eigenvalues λ1<λ2. find the eigenvalues and a basis for each eigenspace. the smaller eigenvalue λ1 is_____ and a basis for its associated eigenspace is___ The larger eigenvalue λ2 is____ and a basis for its associated eigenspace is ____
The smaller eigenvalue λ1 is -2 and a basis for its associated eigenspace is {-1, 2, -1, 0}. The larger eigenvalue λ2 is 3 and a basis for its associated eigenspace is {0, -1, -1, 1}.
How to find the eigenvalues and eigenvectors?We need to solve the characteristic equation and the corresponding eigenvector equations.
The characteristic equation is:
det(A - λI) = 0
where I is the 4x4 identity matrix.
Expanding the determinant, we get:
(5 - λ)((1 - λ)(-7 - λ) - 6) - 0 + 0 - 0 = 0
Simplifying and solving for λ, we get:
λ^2 - λ - 6 = 0
(λ - 3)(λ + 2) = 0
So, the eigenvalues are λ1 = -2 and λ2 = 3.
Now, we need to find the eigenvectors corresponding to each eigenvalue.
For λ1 = -2, we need to solve the equation:
(A - λ1I)x = 0
Substituting λ1 = -2 and solving the system of equations, we get:
x1 = -1, x2 = 2, x3 = -1, x4 = 0
So, a basis for the eigenspace associated with λ1 is:
{-1, 2, -1, 0}
For λ2 = 3, we need to solve the equation:
(A - λ2I)x = 0
Substituting λ2 = 3 and solving the system of equations, we get:
x1 = 0, x2 = -1, x3 = -1, x4 = 1
Basis for the eigenspace connected to λ2 is:
{0, -1, -1, 1}
Therefore, the smaller eigenvalue λ1 is -2 and a basis for its associated eigenspace is {-1, 2, -1, 0}. The larger eigenvalue λ2 is 3 and a basis for its associated eigenspace is {0, -1, -1, 1}.
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Find the sum of the following series. Round to the nearest hundredth if necessary.
The sum of the finite geometric series in the problem is given as follows:
26,240.
How to obtain the sum of the finite geometric series?The first term of the series is given as follows:
[tex]a_1 = 8[/tex]
The common ratio of the series is given as follows:
r = 3.
(as each term is the previous term multiplied by 3).
The rule for the nth term of the series is given as follows:
[tex]a_n = 8(3)^{n - 1}[/tex]
Considering that the final term is of 17496, the value of n is given as follows:
[tex]17496 = 8(3)^{n - 1}[/tex]
3^(n - 1) = 2187
3^(n - 1) = 3^7
n - 1 = 7
n = 8.
Hence the sum of the series is given as follows:
S = [8 - 8 x 3^8]/-2
S = 26,240.
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Working alone John can wash the windows of a building in 2.5 hours Caroline can wash the building windows by her self in 4 hours if they work together how many hours should it take to wash the windows
It should take John and Caroline approximately 0.1538 hours, or about 9.2 minutes, to wash the building windows when working together.
To solve this problem, we can use the formula:
Time taken when working together = (product of individual times) / (sum of individual times)
Let's first find the individual rates of work for John and Caroline:
John's rate of work = 1/2.5 = 0.4 windows per hour
Caroline's rate of work = 1/4 = 0.25 windows per hour
Now, we can substitute these values into the formula to find the time taken when working together:
Time taken = (0.4 x 0.25) / (0.4 + 0.25)
= 0.1 / 0.65
= 0.1538 hours
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Determine the Inverse Laplace Transform of F(s)=(9)+(15/s)+(16/s∧2) The form of the answer is f(t)=Adel(t)+B+ Ct where del(t) is the delta function equal to 1 at t=0 and zero everywhere else.
The Inverse Laplace Transform of F(s)=(9)+(15/s)+(16/s∧2) is f(t) = 9*del(t) + 15 + 16*t.
To determine the Inverse Laplace Transform of F(s) = 9 + (15/s) + (16/s^2), we will use the given form f(t) = A*del(t) + B + Ct, where del(t) is the delta function equal to 1 at t=0 and zero everywhere else.
Step 1: Identify the corresponding inverse Laplace transforms for each term.
- For the constant term 9, its inverse Laplace transform is 9*del(t), where A = 9.
- For the term 15/s, its inverse Laplace transform is 15, where B = 15.
- For the term 16/s^2, its inverse Laplace transform is 16*t, where C = 16.
Step 2: Combine the inverse Laplace transforms.
f(t) = 9*del(t) + 15 + 16*t
So, the Inverse Laplace Transform of F(s) = 9 + (15/s) + (16/s^2) is f(t) = 9*del(t) + 15 + 16*t.
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Exercise Oo.: Carter's desk lamp uses a lightbulb that has an exponential life- time with a mean of 6 months. When the lightbulb goes out, it is immediately replaced. It is now New Year's Eve. What is the probability that exactly three bulbs will be replaced before the end of March?
The probability of exactly three bulbs being replaced before the end of March is approximately 0.0126 or 1.26%.
To solve this problem, we need to use the exponential distribution formula:
f(x) = (1/β) * e^(-x/β)
where β is the mean and x is the time period.
In this case, β = 6 months, and we need to find the probability of exactly three bulbs being replaced before the end of March, which is three months from New Year's Eve.
So, we need to find the probability of three bulbs being replaced within three months, which can be calculated as follows:
P(X = 3) = (1/6)^3 * e^(-3/6)
= (1/216) * e^(-0.5)
≈ 0.011
Therefore, the probability that exactly three bulbs will be replaced before the end of March is approximately 0.011.
To answer this question, we will use the Poisson distribution since it deals with the number of events (in this case, lightbulb replacements) occurring within a fixed interval (the time until the end of March). The terms used in this answer include exponential lifetime, mean, Poisson distribution, and probability.
The mean lifetime of the lightbulb is 6 months, so the rate parameter (λ) for the Poisson distribution is the number of events per fixed interval. In this case, the interval of interest is the time until the end of March, which is 3 months.
Since the mean lifetime of the bulb is 6 months, the average number of bulb replacements in 3 months would be (3/6) = 0.5.
Using the Poisson probability mass function, we can calculate the probability of exactly three bulbs being replaced (k = 3) in the 3-month period:
P(X=k) = (e^(-λ) * (λ^k)) / k!
P(X=3) = (e^(-0.5) * (0.5^3)) / 3!
P(X=3) = (0.6065 * 0.125) / 6
P(X=3) = 0.0126
So the probability of exactly three bulbs being replaced before the end of March is approximately 0.0126 or 1.26%.
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A home has a rectangular kitchen. If listed as ordered pairs, the corners of the kitchen are (11, 5), (−6, 5), (11, −2), and (−6, −2). What is the area of the kitchen in square feet?
A. 119 ft2
B. 49 ft2
C. 48 ft2
Answer:
A. 119 ft2
Step-by-step explanation:
(11, 5) and (-6, 5)
= 11 - (-6)
= 17 feet
(11, 5) and (11, -2)
= 5 - (-2)
= 7 feet
17 × 7 = 119 square feet
solve differential equation dy/dx=y^2 . 16y(2)=0
The particular solution corresponding to the initial condition 16y(2) = 0 (which I assume means y(2) = 0), we can plug x = 2 and y = 0 into the equation:
-1/0 = 2 + C
To solve the differential equation dy/dx=y^2, we can separate the variables and integrate both sides.
dy/y^2 = dx
Integrating both sides:
-1/y = x + C
where C is the constant of integration. Solving for y:
y = -1/(x+C)
To solve the second part of the question, 16y(2) = 0, we substitute y(2) into the equation we just found:
y(2) = -1/(2+C)
16y(2) = 16*(-1/(2+C)) = -16/(2+C) = 0
Solving for C:
-16 = 0*(2+C)
Thus, C can be any value since 0 multiplied by any number is 0. Therefore, the solution to the differential equation dy/dx=y^2 and the equation 16y(2)=0 is y = -1/(x+ C), where C is any constant.
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Tom buys a radio for £40
Later he sells it and makes a profit of 20%
Tom says:
"The ratio of the price I paid for the radio to the price I sold the radio is 5:6”
Enter a ratio that, when simplified, would show that Tom is correct.
Answer: he is correct
Step-by-step explanation:
40 x 1.2 = 48
40:48
divided by 8
=5.6
Jerry’s grandmother worked in a department store for many years. Now that she has retired,she receives a monthly Social Security check.Jerry’s grandmother and her employer paid a tax during her working years that helped fund Social Security. Which is the tax?
fill in the table using the function rule. y=19-2x
Using the function rule, y = 19 - 2x, the table can be filled as follows:
x y
1 17
3 13
4 11
6 7.
What is a function?A function is a mathematical equation that represents the relationship between the independent variable and the dependent variable.
The independent variable is the domain while the dependent variable is the codomain of the function.
The codomain depends on the domain.
x y
1 17 (19 -2(1)
3 13 (19 -2(3)
4 11 (19 -2(4)
6 7 (19 -2(6)
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Evaluate the following integral by converting to polar coordinates.
∫10∫√2−x2x(x+2y)dydx
The value of the given integral is 1/2.
To convert the integral to polar coordinates, we need to find the polar limits of integration and the Jacobian.
The region of integration is the half-disk with radius 1 centered at the origin in the first quadrant. In polar coordinates, this region is described by 0 ≤ r ≤ 1 and 0 ≤ θ ≤ π/2.
The Jacobian is r.
So, we have:
∫10∫√2−x2x(x+2y)dydx = ∫0π/2 ∫01 (r cosθ)(r cosθ + 2r sinθ) r dr dθ
= ∫0π/2 ∫01 r3(cos2θ + 2sinθ cosθ) dr dθ
= ∫0π/2 [(1/4)(cos2θ + 2sinθ cosθ)] dθ
= [(1/4)(sin2θ + 2sin2θ/2)]|0π/2
= (1/2)
Therefore, the value of the given integral is 1/2.
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The value of the given integral is 1/2.
To convert the integral to polar coordinates, we need to find the polar limits of integration and the Jacobian.
The region of integration is the half-disk with radius 1 centered at the origin in the first quadrant. In polar coordinates, this region is described by 0 ≤ r ≤ 1 and 0 ≤ θ ≤ π/2.
The Jacobian is r.
So, we have:
∫10∫√2−x2x(x+2y)dydx = ∫0π/2 ∫01 (r cosθ)(r cosθ + 2r sinθ) r dr dθ
= ∫0π/2 ∫01 r3(cos2θ + 2sinθ cosθ) dr dθ
= ∫0π/2 [(1/4)(cos2θ + 2sinθ cosθ)] dθ
= [(1/4)(sin2θ + 2sin2θ/2)]|0π/2
= (1/2)
Therefore, the value of the given integral is 1/2.
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Suppose the following system of equations has a solution of (
–
5,
–
1), where A, B, C, D, E, and F are real numbers.
Ax+By=C
Dx+Ey=F
Which systems are also guaranteed to have a solution of (–5,–1)? Select all that apply.
As a result, none of the above systems have a solution of (-5,-1).
How to find the system has a solution or not?To see which systems have a solution of (-5, -1), enter x=-5 and y=-1 into the two equations and see if they are both true at the same time.
So, let's enter the values:
A(-5) + B(-1) = C is the solution to the first equation.
To simplify: -5A - B = C
D(-5) + E(-1) = F is the solution to the second equation.
Simplifying: -5D - E = F
As a result, the equation system can be represented as:
-5A = C -5D = E = F
Now we may enter x=-5 and y=-1 into the system and see if the equations still hold true.
When A=1, B=-5, and C=20, the expression -5A - B = C should be true.When D=1, E=-5, and F=30, D - E = F should be true.
As a result, the equation system becomes:
1x - 5y = 20
1x - 5y = 30
If we attempt to solve We have a contradiction in this system since the two equations are incompatible. As a result, there is no solution to this system of equations that meets (-5,-1).
As a result, none of the above systems have a solution of (-5,-1).
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Complete question:
Suppose the following system of equations has a solution of
where A, B, C, D, E, and F are real numbers.
Ax+By=C
Dx+Ey=F
Which systems are also guaranteed to have a solution of (–5,–1)? Select all that apply.
consider the finite geometric series: 14 14(0.1) 14(0.1)2 14(0.1)23 what is the exact sum of the finite series? express your answer in the form a(1-bc)/1-b
a=
b=
c=
The exact sum of the finite geometric series is 14(1 - 0.1 * 0.0001) / (1 - 0.1).
To find the exact sum of the finite geometric series 14 + 14(0.1) + 14(0.1)² + 14(0.1)³, we can use the formula for the sum of a finite geometric series: S = a(1 - rⁿ) / (1 - r), where 'a' is the first term, 'r' is the common ratio, and 'n' is the number of terms.
In this case, we have:
a = 14 (the first term)
r = 0.1 (the common ratio)
n = 4 (the number of terms)
Now, let's plug these values into the formula:
S = 14(1 - 0.1⁴) / (1 - 0.1)
Calculating the values:
S = 14(1 - 0.0001) / (0.9)
Now, we can write the answer in the form a(1 - bc) / (1 - b):
a = 14
b = 0.1
c = 0.0001
Therefore, the exact sum of the finite geometric series is 14(1 - 0.1 * 0.0001) / (1 - 0.1).
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A histogram of the sale price of (a subset of) homes in Ames, and a scatterplot of first floor area vs. sale price of the same homes are given below. 400 300 6e+05 200 4e+05 count Sale Price (dollars) 100 - 2e+05 Oe+00 - Oe+00 2e+05 8e+C 1000 3000 4e+05 6e+05 Sale Price (dollars) 2000 First Floor Area (sq. feet) (a) Describe the shape of the histogram of sale price of houses. (Where are the majority of sale prices located? Where are the minority of sale prices located?) (b) Are exponential, normal, or gamma distributions reasonable as the population distribution for the sale price of homes? Justify your answer. (c) Describe the relationship between first floor sq footage and sale price. (What happens to price as the area increases? What happens to the variability as area increases?)
The histogram of the sale price of houses appears to be skewed to the right, indicating that the majority of sale prices are located on the lower end of the price range. The majority of sale prices seem to be located between $100,000 and $400,000, with very few sale prices above $600,000.
An exponential distribution would not be a reasonable fit for the sale price of homes because it assumes a continuous variable with a constant rate of change. The sale price of homes is not a continuous variable, as it is determined by factors such as location, condition, and size. A normal distribution could potentially be a reasonable fit if the data was centered around a mean and did not have any significant outliers. However, as the histogram shows a skewed distribution, a gamma distribution may be a more appropriate fit as it allows for skewness in the data.
The scatterplot of first floor area vs. sale price shows a positive relationship between the two variables. As the first floor area increases, the sale price tends to increase as well. However, there appears to be a lot of variability in the sale price as the area increases. This suggests that other factors may be influencing the sale price of homes, in addition to the size of the first floor area.
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The baker made a batch of chocolate chip, oatmeal raisin, and sugar cookies. If P(chocolate chip) = 50%, interpret the likelihood of randomly selecting a chocolate chip cookie from the batch.
Likely
Unlikely
Equally likely and unlikely
This value is not possible to represent probability of a chance event.
prove that 2n > n2 if n is an integer greater than 4.
By mathematical induction we know that P(n) is true for all integers n > 4
We have proven that [tex]2^n > n^2[/tex] for all integers n > 4.
=> Let P(n) be the proposition that [tex]2^n > n^2[/tex], n > 4
Put n = 5
[tex]2^5 > 5^2[/tex]
32 > 25
It is true for n = 5
=> For the inductive hypothesis we assume that P(k) holds for an arbitrary integer k > 4
Let P(k) be true where k is greater than 4
That is, we assume that
[tex]2^k > k^2[/tex], k > 4
Under this assumption, it must be shown that, it is true for p(k+1).
[tex]= > 2^k^+^1=2.2^k\\\\=2^k+2^k > k^2+k^2\\\\=k^2+k.k > k^2+4k\\\\=(k+1)^2\\\\[/tex]
This shows that P(k + 1) is true under the assumption that P(k) is true.
This completes the inductive step.
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57 .99 rounded to two decimals places
Find the distance from (-2,5) to (5,9) (round to the nearest tenth)
Answer:
8.1 hope this helps
Step-by-step explanation:
7 to the power of 2 and 4 to the power of 2
16 + 49 = 65
65 rounded to the nearest tenth is 8.1
Answer:
8.1
Step-by-step explanation:
Distance (d) = √(5 - -2)2 + (9 - 5)2
= √(7)2 + (4)2
= √65
= 8.0622577482985
After rounding
8.1
express the quotient z = 1 3i 6 8i as z = reiθ .
The polar form of the complex number quotient z = (1+3i)/(6+8i) is z = (1/sqrt(10))e^(i0.262)
To express the complex number quotient z = (1+3i) / (6+8i) in polar form, we need to find its magnitude (r) and argument (θ).
First, we find the magnitude of z:
|z| = sqrt( (1^2+3^2) / (6^2+8^2) )
|z| = sqrt(10/100)
|z| = sqrt(1/10)
|z| = 1/sqrt(10)
Next, we find the argument of z:
θ = arctan(3/1) - arctan(8/6)
θ = arctan(3) - arctan(4/3)
θ ≈ 0.262 radians
The polar form is z = (1/sqrt(10))e^(i0.262)
This represents the magnitude and direction of the complex number in terms of its distance from the origin (magnitude) and its angle with respect to the positive real axis (direction).
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The given question is incomplete, the complete question is:
Express the quotient z = 1+3i / 6 +8i as z = re^(iθ)
PLEASE HELP ME
The figure below shows roads near a pond. Each segment of the triangle represents a road or a path, except AB, which represents the distance across the pond.
Are the two triangles similar?
Yes the two triangles ΔCDE & ΔABC are similar according to the rules of similarity of triangles.
What is similarity?
If two triangles have the same proportion of matching sides to matching angles, they are said to be similar. Similar figures are items that share the same shape but differ in size between two or more figures or shapes.
Given that in ΔCDE,
∠DEC=55°
EC=40 ft
DE=25 ft
Also Given that in ΔCAB,
∠ABC=55°
BE=60 ft
Consider ΔCDE & ΔCAB
∠ABC = ∠DEC = 55°
∠C = ∠C
∠CAB =180-( ∠C+∠B)
=180-(∠C +55)
∠CDE= 180- (∠C+∠E)
=180-(∠C +55)
∠CAB =∠CDE=180-(∠C +55)
As three angles are congruent, the triangles are similar.
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if 3/4 cup of flour is used to make 4 individual pot pies, how much flour should be used to make 12 pot pies
Using proportion, amount of flour used to make 12 pot pies is 2.25 cups.
Given that,
Amount of flour used to make 4 individual pot pies = 3/4 cups
We have to find the amount of flour used to make 12 individual pot pies.
This can be found using the concept of proportion.
Using the concept of proportion,
Amount of flour used to make 1 individual pot pie = 3/4 ÷ 4
= 3/16 cups
Amount of flour used to make 12 individual pot pies = 12 × 3/16 cups
= 2.25 cups.
Hence the amount of flour used is 2.25 cups.
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find the absolute maximum and absolute minimum values of f on the given interval. give exact answers using radicals, as necessary. f(t) = t − 3 t , [−1, 6]
The absolute maximum value is 2 at t = -1, and the absolute minimum value is -12 at t = 6.
To find the absolute maximum and minimum values of the function f(t) = t - 3t on the interval [-1, 6]. We'll use the following terms: critical points, endpoints, and first derivative test.Find critical points: To identify where the function may have maxima or minima, we first calculate the first derivative f'(t) of the function.For more such question on absolute maximum
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in each of problems 4 through 6, find the laplace transform of the given function. 4. f (t) = t 0 (t − τ ) 2 cos(2τ ) dτ
The Laplace transform of the given function is:
L{f(t)} = (6 - 4s/(s²+4) + 2s²/(s²+4)²) / s⁴
To find the Laplace transform of the given function:
f(t) = t∫0 (t-τ)² cos(2τ) dτ
We will first factor out the constants outside the integral and write the function as:
f(t) = t ∫0 (t² - 2tτ + τ² ) cos(2τ) dτ
We can then break the integral into three parts and take the Laplace transform of each part separately, using the properties of the Laplace transform:
L{t} = 1/s²
L{t²} = 2/s³
L{cos(2τ)} = s/(s² + 4)
Using these Laplace transforms, we can write the Laplace transform of the given function as:
L{f(t)} = L{t ∫0 (t²- 2tτ + τ²) cos(2τ) dτ}
= L{t³} - 2L{t²}L{∫0 τ cos(2τ) dτ} + L{t}L{∫0 τ²cos(2τ) dτ}
= 6/s⁴ - 4/s⁴ * (s/(s²+4)) + 2/s⁴ * (s²(s²+4)² )
Simplifying this expression, we get:
L{f(t)} = (6 - 4s/(s²+4) + 2s²/(s²+4)²) / s⁴
Therefore, the Laplace transform of the given function is: L{f(t)} = (6 - 4s/(s²+4) + 2s²/(s²+4)²) / s⁴
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(1 point) find a particular solution to ″ 6′ 8=54.
Therefore, a particular solution to the equation y″ + 6y′ + 8y = 54 is yp = 27/4.
To find a particular solution to the equation y″ + 6y′ + 8y = 54, we can use the method of undetermined coefficients.
First, identify the general form of the particular solution based on the non-homogeneous term: Since the right side of the equation is a constant (54), we can guess that the particular solution will be in the form of yp = A, where A is a constant.
Next, substitute the guess into the equation: The first and second derivatives of yp = A are both 0 (y′ = 0, y″ = 0). So, substituting into the equation, we get 0 + 6(0) + 8A = 54.
Now, solve for the constant A: 8A = 54, so A = 54/8 = 27/4.
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