In a rectangle KLMN, the diagonals KM and LN intersect at O. (i) If KO = 4y + 6 and ON = 3y + 11, find the lengths of its diagonals. (ii) If ∠NKM = 32°, find ∠KON and ∠KMN. GUYS, IT'S VERY URGENT. I HAVE TO SUBMIT TOMORROW. PLS ANS. PLS DON'T GIVE WRONG ANSWERS
Answers
Answer:
1). Length of diagonals = 52
2). m∠KON = 103°, m∠KMN = 45°
Step-by-step explanation:
KLMN is a rectangle.
Diagonals KM and LN intersect at point O.
1). Since, diagonals of the rectangle equally bisect each other.
KM = 2(KO)
KM = 2(4y + 6)
And LN = 2(ON)
LN = 2(3y + 11)
Since, length of diagonals of a rectangle are equal in measure.
2(4y + 6) = 2(3y + 11)
4y + 6 = 3y + 11
4y - 3y = 11 - 6
y = 5
Therefore, length of diagonals = 2(3y + 11)
= 2(15 + 11)
= 52 units
2). m∠NKM = 32°
Since, m∠KNM = 90° [internal angle of a rectangle]
And diagonal LN bisects this angle,
m∠KNO = 45°
In ΔKNO,
m(∠NKM) + m(∠KNO) + m(KON) = 180°
32° + 45° + m∠KON = 180°
m∠KON = 180° - 77°
= 103°
Since, m∠KMN = [tex]\frac{1}{2}[/tex](m∠LMN)
m∠KMN = [tex]\frac{1}{2}(90)[/tex] = 45°
Answer:
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Step-by-step explanation:
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