The reasons why the units are included mainly at the top of columns and the beginning of rows in a data table includes.
The column and row headers are used to clarify the information contained in the cells of the tableThe units are placed at the specified locations at the column or row headers to reduce repetition and improve efficiencyPlacing the units only at the top, reduces the size of the tableIt allows for access to the raw data by programs for further analysisThe raw values of the data are mainly used during manual analysis, such as graphing and therefore are transferred and may be stored into further data table using the same formatWhat is a data table?A data table consists of a range of cells forming a document with content that can be addressed using row or column locations in which values are stored. The data in the cells of a data table can be accessed or retrieved or updated as required, later.
The title of the data table and the top of columns, known as column headers, and the beginning of rows, known as row headers are used to present more details of the content or information in the cells, in order to clarify their meaning.
Placing such details only in the column and row headers reduces repetition of the same details in all cells, improves clarity as usually only values that may be different are placed in the cells, such that it is easier to focus on the values.
The method of including units only at the top, reduces the amount of space required to store the data, it also facilitates the comparison of values in the dataset.
Including units only at the tops of columns and at the beginning of rows also allows the data table to be used for computerized data analysis, such as the programming of the required monthly payment on a home mortgage, through which different interest rate and loan amount can be experimented with to programmatically calculate the required or affordable monthly payment.
During manual analysis, such as graphing of the data, use is made of mainly the values in the table rather than units in calculations, as the number of data points may me much.
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An ideal incompressible fluid flows at 12 m/s in a horizontal pipe. If the pipe widens to twice its original radius, what is the flow speed in the wider section?.
The flow speed in the wider section of horizontal pipe is 3 m/s
How to find the value of flow speed in the wider section?Based on the Law of Continuity which states that a flowing fluid will have a constant discharge, where this discharge has a formula:
Q = A × v
where
Q = fluid discharge (m³/s)
A = pipe area (m²/s)
v = fluid speed (m/s)
From that formula, we can solve the problem by the formula of Q1 = Q2, here it is
A1 x v1 = A2 x v2
(π · r²) x 12 = (π · (2r)²) x v2
r² x 12 = (4) r² x v2
v2 = 12/4 m/s
v2 = 3 m/s
v2 is the speed from the pipe section that widens to twice from its original radius.
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Questions High-speed video can record sporting events at a frame rate of 60 frames per second (frame/s). 8 a What is the time interval between one frame and the next?
The frame interval will be 1/60th of a second.
Solution:
60f = 1sec
1f = x
x = 1/60 sec.
The 24 frames per second standard are prevalent in film and video technology. This frame rate allows a video from a series of images to be perceived as a fluid whole. The I-frame interval configures the number of fields that occur between frames in the video stream.
A timeframe is defined as a span of seconds minutes days, hours weeks months, or years in which something occurs or occurs. For example, a project with a two-week deadline indicates a timeframe. A time interval is the length of time between two specific points in time. For example, The time difference between 3:00 and 4:00 is 1 hour.
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two pole-vaulters just clear the bar at the same height. the first lands at a speed of 7.41 m/s, while the second lands at a speed of 7.71 m/s. the first vaulter clears the bar at a speed of 0.749 m/s. ignore air resistance and friction and determine the speed at which the second vaulter clears the bar.
The second vaulter clears the bar at speed of 7.43 m/s.
Velocity is the directional speed of an item in motion as an indication of its price of change in role as located from a particular body of reference and as measured by a specific general of the time.
The velocity of the first vaulter at jump v1 = 7.50 m/s
Horizontal component of v1 v1x = v1 * cos ?1
1.00 = 7.50 * cos ?1
?1 = cos-1 (1.00 / 7.50
= 82.340
Hence vertical component v1y = v1 * sin ?1
= 7.5 * sin 82.340
= 7.43 m/s
Since both vaulters rise to the same height, their initial vertical velocity is the same. i.e.
v2y = v1y = 7.43 m/s
then v2y = v2 * sin ?2
?2 = sin-1 (7.43 / 7.70)
given v2 = 7.70 m/s
= 74.780
Hence velocity of the second vaulter as he clears the bar v2x = v2 * cos ? 2
= 7.70 * cos 74.780
= 2.02 m/s
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the work done by a spring depends on ________.
Answer:
the change in length of the spring.
Explanation:
E = W = 1 ⁄ 2kx²
The amount of work the spring performs is influenced by its length change. Equal amounts of compression and extension result in the same amount of work being completed by the spring.
The diameter of the coil turns, the number of turns per unit length, the total length of the spring, and the stiffness of the spring material will all affect the spring constant. It also depends on the thickness of the wire from which the spring is wound. Work performed by a Spring: When a spring is extended or compressed, it applies force to the object that is doing the stretching or compression. It is possible to employ this force to convert an object's energy into elastic potential energy.
Let's lengthen the spring a little way, say d x dx dx. If F is the force used to stretch the spring, then the work involved in doing so is given by the equation d W = F d x, dW=Fdx, and dW=Fdx.
Positive work is produced when a spring is stretched or compressed. Reason: When force is applied and displacement is in the same direction, work is said to be positive.
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g a concave mirror has a focal length of 40 cm. if an object is placed 50 cm in front of the mirror, where will its image be located, and how will its size (height) compare to the original object?
image is formed at a distance 10 cm in front of the mirror
the focal length of concave mirror is 8cm.
What is concave mirror ?
A concave or converging mirror has a reflective surface that is recessed inward (away from the incident light). A concave mirror reflects light inwards towards a focal point. They are used to focus light. Unlike convex mirrors, concave mirrors display different types of images depending on the distance between the object and the mirror.
The mirror is called a "collecting mirror". This is because they tend to collect the light that hits the mirror and refocus the parallel incident rays to a focal point. This is because the normal to the mirror surface is different at each point, so light is reflected at different angles at different points on the mirror.
Given u=40 cm (negative)
m=14 (negative for the real image)
a. From m=−vu,−14=−v(−40) or v=-10 cm
Thus the image is formed at a distance 10 cm in front of the mirror.
b. Now from relation 1u+1v=1f
1f=1(−40)+1(−10)
=−540
or f=−405=−8cm
i.e., the focal length of concave mirror is 8cm.
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What is the value of the magnetic flux at coil 2 due to coil 1, which has a current i passing through it?.
Magnetic flux is zero
Magnetic flux (B) =
Magnetic field x area x cosစ
And စ being the angle between magnetic field and area vector
So we are given စ= 90°
B = magnetic field x area x cos(90)
B= 0
The quantity of magnetic field lines that travel through a specific closed surface is known as the magnetic flux. It offers a way to measure the total magnetic field that traverses a specific surface area.
The quantity of magnetic field lines that flow regularly through a surface is known as the magnetic flux associated with that surface. Weber is the SI unit for it.
The magnetic flux equation is provided by. When B = B A Cos,
The magnetic flux alters as the surface oscillates or spins between two poles of a magnet. According to Faraday's law, a change in magnetic flux results in the creation of an induced electric current with an electromotive force, or EMF.
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A student is subjected to a reaction force of 10 n northward from a 5 kg block while pushing the block over a smooth, level surface. Ignoring friction, what is the acceleration of the block?.
Ignoring the Friction, the Acceleration of the block would be 2 [tex]ms^{-2}[/tex].
The relation of force with mass and acceleration is given by :
Force = Mass * Acceleration
Here the Force is 10N and the mass of the block is 5 Kg so substituting the values in the formula we get
Acceleration = [tex]\frac{Force}{Mass}[/tex] = [tex]\frac{10}{5}[/tex] = 2 [tex]ms^{-2}[/tex] .
What is force-
According to physics. A force can cause an object with mass to accelerate when it changes its velocity, for as when it moves away from rest. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction. It is calculated using the newton SI unit (N). Force is denoted by the letter F. (formerly P).
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find the mass and center of mass of a solid hemisphere of radius if the density at any point is proportional to its distance from the base.
center of mass of a solid hemisphere of radius R is 3R / 8 and the Mass of the solid is M.
An elemental disc at a height of h from the base of the hemisphere is taken.
The mass of the elemental disc is taken dM
and the width is taken dy.
et the solid hemisphere be of mass M and has the radius R.
The center of mass will lie vertically which passes through the center of the hemisphere.
Taking the elemental disc at a height h from the base of the hemisphere’s base. The DM is the mass of the elemental disc and the width is dy.
the radius of the disc is:
R = R²- y²
Mass of the disc dM
= (3 M/ 2π R³) × ( πr² dy ) …..(2)
eq.(1) in eq.(2)..................
dM = ( 3M / 2 π R³ ) × π ( R² – y² ) dy)
Y - coordinate of Centre of mass,
Yc = (1 / M) ഽ y dM
Here y is the y - coordinate representing the height of the elemental disc from the base.
Putting the dM and calculating the center of mass, we get
yc= (1/M) ഽ y(3M /2 R^3) × ( R^2 - y^2) dy)
Integrating between 0⟶R
yc = (1/M) ഽ y (3M / 2 R^3) × (R^2 - y^2) dy)
yc = ( 3/2r^3 ) ഽ × (R^3 y- y^3 ) dy
= ( 3/ 2R2)[ (R4 / 2 ) – ( R4 / 4)] = 3R / 8
yc = 3 R /8
Centre of Mass of solid hemisphere (yc) = 3 R / 8.
Mass of solid = M
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an object of mass 0.8 kg is attached to an ideal horizontal spring of spring constant 180 n/m. the object is initially at rest at equilibrium. how much work would it take to set the object into an oscillation with amplitude 0.02 m?
0.072 J is the work would the spring take to set the object into an oscillation with amplitude 0.02 m
What is amplitude?A periodic variable's amplitude is a gauge of its change over a single period. A non-periodic signal's magnitude in relation to a standard value is its amplitude. There are several ways to define amplitude, and they are all dependent on how much the extreme values of the variable deviate from one another.
What is a spring constant?The stiffness of the spring is how we determine spring constant. In other words, we can define the spring constant as the force used to produce the specified displacement when the spring's displacement is one unit. It follows that a spring's spring constant will increase with increasing spring stiffness.
Now to calculate the work done by spring we use the Hookes’s law
F=kx
Where F is the force required
K is the spring constant
X is the amplitude or distance
So F=kx
F=180x0.02
F=3.6 N
Now to calculate work :
Work = Force × Distance.
Work=3.6 N x0.02m
Work =0.072 J
Hence, 0.072 J is the work would the spring take to set the object into an oscillation with amplitude 0.02 m
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a body with initial velocity 8 m/s moves along a straight line with constant acceleration and travels 744 m in 42 s. for this given time interval, find the acceleration in m/s2.
Answer: ACCELARATION = 0.462M/S²
Explanation: INITIAL VELOCITY (VI) = 8M/S
DISTANCE COVERED (S) = 744M
TIME (t) = 42 S
ACCELERATION (A)= ?
BY APPLYING 2ND EQUATION OF MOTION
S = VIT +1/2 AT²
744 = 8 X 42 +1/2 A X42²
744 - 336 = 1/2 A X 42²
408 X 2/1764 = A
A = 816 /1764
A = 0.462M/S²
2. As a shot putter in track, you want to throw as far as you can. You as the coach give your
best advice based on the Physics you learned. Give 2 suggestions to help your student and
explain why? (6 Pts.)
As a shot putter in track, if you want to throw far then throw it fast and at angle approximately 45 degrees.
How can shot putter throw farther?As a thrower spins, his body acts as an axis of rotation and therefore, farther the object is from the axis of rotation, larger is its moment of inertia.
The angle of release in the shot-put event is of great importance. The estimation of the optimum angle of release such that the distance thrown is maximized is a key. Theory has shown that the optimum angle of release is between 41 to 43 degrees.
Release velocity is also a important factor in determining the distance of a throw. Release velocities of about 13 m/s are necessary for elite-level throws.
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a motorboat accelerates uniformly from a ve- locity of 6.7 m/s to the west to a velocity of 2.2 m/s to the west. if its acceleration was 3.2 m/s2 to the east, how far did it travel during the acceleration? answer in units of m.
The acceleration, Distance is 7.407 m
What is acceleration?
The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics. They are vector quantities and accelerations. The direction of the net force acting on an object determines the direction of its acceleration.
Let the west direction is positive so the east direction is taken as negative.
initial velocity, u = 6.5 m/s
Final velocity, v = 1.5 m/s
acceleration, a = - 2.7 m/s^2
Let it travels a distance s during this acceleration.
Using the third equation of motion, we get
v²=u²+2as
1.5²= 6.5²-2x 2.7 xs
s = 7.407 m
Thus, the distance traveled is 7.407 m.
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Based on the marble and the steel ball bearing, what happens to the kinetic energy of an object when the mass is cut in half?.
The kinetic energy of an object will be halved when the mass is cut in half.
What is kinetic energy?Kinetic energy may be described as the energy that an object possesses due to its motion. It is defined as the work required to accelerate a body of specified mass from rest to a specified velocity. After the body acquires this energy during acceleration, it retains this kinetic energy as long as the velocity does not change.
Kinetic energy (KE) is the energy that moves matter. Everything that moves has kinetic energy. The amount of kinetic energy of a moving object is directly related to its mass and velocity.
KE = 1/2 mass × velocity²
For the given question:
Since,
KE = ¹/₂ mv²
If mass is cut in half i.e m/2, then the KE will be:
KE = ¹/₂ m/2 v²
KE = ¹/₄ mv²
KE = ¹/₂ (¹/₂ m/2 v²)
This indicates that kinetic energy is halved as the mass is cut in half.
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What is the total energy of a stationary 350g ball 12m above the ground? What type of energy is it?
What is the total energy of the same ball right before it hits the ground? What type of energy is it?
If the same ball is 2m above the ground, what is the Potential Energy and what is the Kinetic Energy?
Calculate the velocity of the ball when it is 2m above the ground.
*with steps
The velocity of the ball is obtained as 6.26 m/s.
What is the energy?We know that the kinetic energy is the energy that is possessed by a body by virtue of the fact that it is in motion while the potential energy is the energy that is possessed by a body that is at rest.
Now we have that;
Mass of the ball = 350g or 0.35 Kg
Height of the ball = 12m
The energy of the ball at this height is potential energy. The total energy before the ball hits the ground is; 0.35 * 12 * 9.8 m/s^2 = 41.2 J and this energy is kinetic energy.
If the ball is 2m above the ground its potential energy is 2 * 2 * 9.8 m/s^2 = 39.2 m/s and the kinetic energy of the ball is zero m/s.
The velocity with which the ball hits the ground is;
mgh = 1/2mv^2
gh = 1/2v^2
v = √2gh
v = √2 * 9.8 * 2
v = 6.26 m/s
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Describe where gamma rays are found on the ems compared to the other six forms of radiation. In your description, compare and contrast its wavelength, frequency and energy with those of other regions of the ems.
The wavelength of UV radiation is longer than that of x-rays and gamma rays but shorter than that of radio waves, microwaves, infrared, and visible light.
The frequency of UV radiation is higher than that of radio waves, microwaves, infrared light, and visible light, but it is lower than that of x-rays and gamma rays.
UV radiation has a lower level of hazard.
What do you mean by wavelength, frequency and energy?Wavelength:
Distance between the crests of two waves, or from one wave's point to the same of the second.
Frequency:
Wavelength and frequency are inversely proportional, the larger the wavelength the lesser the frequency
Energy: The relationship between frequency and energy is straightforward.
From longest to shortest wavelengths, this is a list of electromagnetic waves.
Radio wave, Microwave, Infrared, Access to light, Ultraviolet rays, X-ray, Gamma rays
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A type of air cooler works by blowing air from the room through
a sponge soaked in water.
Explain how blowing air through a sponge soaked in water lowers
the temperature of the air.
Which of the following is true of Earth’s atmosphere?
A. It is mostly made up CO2.
B. It gets more dense as you go higher in altitude.
C. It has more nitrogen than oxygen.
D. No one has ever been above it.
Answer:
c) It has more nitrogen than oxygen.
Explanation:
Our Earth’s atmosphere has more nitrogen (78%) than oxygen (21%). Hence, the option (c) is the correct answer.
Answer:
C. It has more nitrogen than oxygen.
Explanation:
Earth's atmosphere is composed of about 78% nitrogen, 21% oxygen, and one percent other gases. These gases are found in layers (troposphere, stratosphere, mesosphere, thermosphere, and exosphere).
A man falls 2.0 m to the floor (assume down to be the negative direction.)
How long does the fall take?
What is his velocity when he hits the floor?
With the use of equation of motion formulas, the time taken for him to fall is 0.64 s and his final velocity when hitting the floor is 6.3 m/s
Motion Under GravityThe motion of an object under gravity is the vertical motion of the object under the influence of acceleration due to gravity.
Given that a man falls 2.0 m to the floor and it is assumed that downward direction to be the negative direction.
To know how long it will take the object to fall, we will make use of the formula h = ut + 1/2gt²
Where
Height h = 2 mInitial velocity u = 0Acceleration due to gravity g = 9.8 m/s²Time t = ?Substitute all the parameters into the formula
2 = 1/2 × 9.8 × t²
2 = 4.9t²
t² = 2/4.9
t² = 0.408
t = √0.408
t = 0.64 s
His velocity when he hits the floor can be calculated by using the formula
v = u + gt
where u = 0
v = 9.8 × 0.64
v = 6.3 m/s
Therefore, it takes 0.64 s to fall and his velocity when he hits the floor is 6.3 m/s
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he magnetic field inside a 25-cm-diameter solenoid is increasing at 2.4 T/s. How many turns should a coil wrapped around the outside of the solenoid have so that the emf induced in the coil is 15 V?
Using induced emf inside the magnetic field which is Faraday’s Law of Induction, we can calculate the number of turns a coil wrapped around the outside of the solenoid should have is 127 turns to induce 15v.
According to the Faraday’s Law of Induction, Faraday's law of induction is a basic law of electromagnetism predicting how a magnetic field will interact with an electric circuit to produce an electromotive force (emf) a phenomenon known as electromagnetic induction.
Induced emf = N ( dФ / dt )
where, N is the number of coil
and dФ is the change in magnetic flux
again, as we know,
dФ / dt = A (db/dt)
so, Induced emf = N A ( db/dt )
where A is the area of solenoid
Area of solenoid = πr² = π * ( 0.125 )² (diameter is 25cm)
putting the appropriate values, we get
15 = N x π x ( 0.125 )² x 2.4
N = [tex]\frac{15}{\pi * 0.015625 * 2.4}[/tex]
N = 15/0.11775
N = 127.38
N = 127 turns
hence 127 turns is needed to generate 15 v emf.
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0.000789kg/m3 divided by 2m3
Answer:
0.0003945 kg / m6
Explanation:
a runner travels 500m in a straight line then pauses for a water break. He continues traveling straight for another 700m in the same direction. What is the runners total displacement.
Answer:
1200m
Explanation:
700+500=1200m
which of the following statements correctly describe the information provided by quantum numbers? select all that apply.
a. the quantum number "n" indicates the principle energy level of an orbital.
b. the quantum number "l" indicated the shape of an orbital.
c. the relative size of the orbital is indicated by the value of "n"
Statements A and B have correctly described the information provided by quantum numbers.
A. The quantum number "n" indicates the principal energy level of an orbital.
B. The quantum number "l" indicated the shape of an orbital.
In quantum physics and chemistry, quantum numbers describe values of conserved quantities within the dynamics of a quantum system. Quantum numbers correspond to eigenvalues of operators that shuttle with the Hamiltonian—quantities that can be recognized with precision at the equal time as the system's strength—and their corresponding eigenspaces. collectively, a specification of all the quantum numbers of a quantum device absolutely symbolizes a basic kingdom of the system and might in principle be measured collectively.
A crucial thing of quantum mechanics is the quantization of many observable quantities of the hobby. This leads to quantum numbers that take values in discrete units of integers or half-integers; even though they might technique infinity in a few instances. This distinguishes quantum mechanics from classical mechanics in which the values that signify the gadget which include mass, price, or momentum, all vary constantly.
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two forces, f1 and f2, are applied to a block on a frictionless, horizontal surface as shown. if the magnitude of the block's acceleration is 2 m/s^2, what is the mass of the block?
The mass of the block on the frictionless horizontal surface is 5 kg.
How to determine the mass of the block?The mass of the block is determined by applying Newton's second law of motion:
F = ma
The given parameters are
the magnitude of the first force, F₁ = 12 N
the magnitude of the second force, F₂ = 2 N
acceleration of the block, a = 2 m/s²
So, determining the mass of the block is
F = ma
∑F = ma
F₁ - F₂ = ma
12 - 2 = 2m
10 = 2m
m = 5 kg
Thus, the mass of the block on the frictionless horizontal surface is 5 kg.
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. in this activity, you will be looking for a relationship between the force on the cart and the acceleration of the cart. which variable do you need to keep constant during this experiment?
A push or pull on an object is a force. All of the forces operating on an object are added together to form a net force. When an object is subject to a net force, the object will change its speed in that direction. The acceleration of an object reveals how much it accelerates or decelerates.
We can determine what occurs with the acceleration and force while maintaining the mass constant.
A connection between the mass of the cart and its acceleration. Taking into consideration Newton's second law, which states that
force = mass × acceleration
As a result, the force will change if the acceleration does. Keeping the mass constant will allow us to determine how changing the acceleration will affect the force. Once the mass is kept constant, you can determine what will happen. Therefore, if we want to maintain the acceleration constant while also changing, we must alter the mass of the car. This means adding mass to the cart—whether it be in the form of mass blocks or larger carts—or otherwise altering its mass.
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a block of unknown mass is attached to a spring of spring constant 3.3 n/m and undergoes simple harmonic motion with an amplitude of 5.8 cm. when the mass is halfway between its equilibrium position and the endpoint, its speed is measured to be 26.4 cm/s. calculate the mass of the block. answer in units of kg.
The correct answer of mass of the block is 16.379 Kg.
How is energy conserved in a spring?
The mass's kinetic energy is converted into elastic potential energy as the spring contracts and it slows down. The complete amount of mechanical energy is conserved throughout this transformation.
Energy is conserved for the block-spring system between the maximum-displacement and the half-maximum points:
(K+U)i=(K+U)f
0+1/2 kA²=1/2 mv²+1/2 kx²
0.5 (3.3 N/m) (0.058 m) ²=1/2 m (0.26 m/s) ²+1/2(3.3 N/m) (2.90×10−² m) ²
=> 0.555 = 0.0338 m + 0.00138
=> mass = (0.555 – 0.00138) / 0.0338 = 16.379 Kg
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s the force that will stretch it right to its breaking point larger than, smaller than, or equal to 5000 N?
Yes, the force that will stretch is rights to the breaking point equal to 5000 N. Because the longer wire will аlso breаk аt 5000 N. The force per unit аreа is the sаme in both cаses.
What happens to stretch wire to breaking point?When а stress is аpplied to а piece of mаteriаl, the mаteriаl undergoes а corresponding deformаtion or strаin. Under а tensile stress, the mаteriаl stretches. Initiаlly, the аmount by which it stretches is proportionаl to the аpplied force. Thаt is, the mаteriаl obeys Hooke’s Lаw, which is expressed by the equаtion F = -kx, where k is а constаnt аnd x is the chаnge in the length of the mаteriаl.
Your question is incomplete, but most probably your full question was
A wire is stretched right to the breaking point by a 5000 N force. A longer wire made of the same material has the same diameter. Is the force that will stretch it right to the breaking point larger than, smaller than, or equal to 5000 N?
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What is the displacement for a trip from the math classroom in Figure 2.4 to the music classroom and then to the library? What is the distance for this trip?
14 m is the displacement for a trip from the math classroom in Figure 2.4 to the music classroom and then to the library
Displacement= final position-initial position
Displacement=14m-0
Displacement=14m
distance= total route= 14m
Distance is all covered distance but displacement is shortest distance. Being a vector quantity, displacement has both a magnitude and a direction. The vector (or straight line) distance between an initial and final position is what is meant by this term. Knowing these two places is consequently all that is necessary to determine the resultant displacement.
Calculate the inverse tangent of the ratio of the displacement components in the y- and x-directions to determine the direction of the displacement vector.
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What is the value of work done on an object when a 70–newton force moves it 9. 0 meters in the same direction as the force?.
The value of work done on an object when a 70-newton moves it 9.0m in the same direction as the force is 6.3 * 10^2 J
In physics, it measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement. In its simplest form, for a constant force aligned with the direction of motion, it equals the product of the force strength and the distance traveled.
How to calculate the value of work done on an object?
The formula for work (w) done is = force * distance
f = 70 N
d = 9 m
w = 70 × 9m
w = 630 J = 6 × 10² J
work is positive because work is being done on the object.
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Celine is measuring all of the dry ingredients she needs for a recipe by packing them into containers and measuring their what?.
The term "visual weight" refers to a visual power that emerges from the contrasts of light among some of the individual visual elements that make up an image.
How does measuring work?Associating numerals with quantities and events is the process of measuring. The sciences, engineering, building, and other technological professions, as well as practically all daily activities, all depend on measurement.
What does measuring mean?Comparing a physical quantity to a recognized standard amount of the same kind is the activity of measurement. For instance, measuring length with Vernier Calipers and determining wire diameter with a screw gauge.
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if we lived in a system with only one planet, which of kepler's laws could never be discovered observationally?
Answer:
If we lived in a system with only one planet, Kepler's Third Law could never be discovered observationally.