Let f be the function given by f(x)=(x^2+x)cos(5x). What is the average value of f on the closed interval 2≤x≤6 ?a. -7.392b. -1.848c. 0.722

Answer:

a

Step-by-step explanation:

(a)

Let's call the distance that April travels from her starting point to the rest station "d". Then the distance that May travels from her starting point to the rest station is also "d". Since they both end up at the midpoint of the trail, we know that:

d + d = 15

Simplifying:

2d = 15

d = 7.5

We also know that April arrived at the rest station 40 minutes earlier than May. Since they both travelled the same distance, we can use the formula:

time = distance / speed

Let's call the time taken by April to reach the rest station "t". Then the time taken by May is:

t + 40/60 = t + 2/3

We know that April jogged at an average speed of r km/h, so:

t = d / r = 7.5 / r

May walked at an average speed that was 3 km/h less than April's jogging speed, so:

t + 2/3 = d / (r - 3) = 7.5 / (r - 3)

Now we can express t in terms of r:

7.5 / r + 2/3 = 7.5 / (r - 3)

Multiplying both sides by 3r(r - 3):

22.5(r - 3) + 2r(r - 3) = 22.5r

Expanding and simplifying:

24r - 135 = 0

(b)

To get the equation in the required form, we need to express r in terms of x, where x = r - 12. Substituting x + 12 for r in the equation above, we get:

24(x + 12) - 135 = 0

24x + 273 = 0

24x = -273

x = -273/24

Multiplying both sides by -12 and subtracting from 477, we get:

477 - 12x - 135 = 0

(c)

Substituting the value we got for x into x + 12, we get:

r = -273/24 + 12

r = 15/8

So April's average jogging speed was 15/8 km/h, or approximately 1.875 km/h.

Answer:

42°

Step-by-step explanation:

Measured with potractor

Part A:

An open circle on a number line represents that the value at that point is not included in the solution set of the inequality.

This means that the boundary point is not a valid solution to the inequality. It is used when the inequality is strict, such as x < 5, where 5 is not included in the solution set.

Part B:

A closed circle on a number line represents that the value at that point is included in the solution set of the inequality.

This means that the boundary point is a valid solution to the inequality. It is used when the inequality is non-strict, such as x ≤ 5, where 5 is included in the solution set.

Part C:

The shading on the number line represents the set of all values that satisfy the inequality.

The shaded region includes all the points that satisfy the inequality, and may extend to either the left or right of the boundary points, depending on the direction of the inequality.

The shading may be above or below the line, depending on whether the inequality involves greater than or less than.

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Each Algebra ticket cost $5.125 for kids and $20.50 for adults, while each Geometry ticket cost $4.46 for pupils and $30.125 for adults.

For Algebra I:

Cost per student ticket = Total cost of student tickets / Number of student tickets

Cost per student ticket = $164.00 / 32

Cost per student ticket = $5.125

For Geometry:

Cost per student ticket = Total cost of student tickets / Number of student tickets

Cost per student ticket = $120.50 / 27

Cost per student ticket = $4.46 (rounded to two decimal places)

Next, we can find the cost of one adult ticket for each class using the same method.

For Algebra I:

Cost per adult ticket = Total cost of adult tickets / Number of adult tickets

Cost per adult ticket = $164.00 / 8

Cost per adult ticket = $20.50

For Geometry:

Cost per adult ticket = Total cost of adult tickets / Number of adult tickets

Cost per adult ticket = $120.50 / 4

Cost per adult ticket = $30.125

Therefore, the price of each ticket for Algebra I was $5.125 for students and $20.50 for adults, while the price of each ticket for Geometry was $4.46 for students and $30.125 for adults.

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Answer:

First, we need to find the volume of the cylinder:

V = πr^2h = π(7.6 cm)^2(16.2 cm) = 2,945.27 cm^3

Next, we can find the amount of trace elements collected:

0.091 g/cm^3 x 2,945.27 cm^3 = 267.68 g

Rounded to the nearest tenth, Valeria collected approximately 267.7 grams of the trace element.

First, we need to convert the speed from miles per hour to inches per second. There are 5280 feet in a mile and 12 inches in a foot, so:

15 miles per hour = (15 x 5280 x 12) inches per hour, = 950400 inches per hour
To get inches per second, we divide by 3600 (the number of seconds in an hour):
950400 inches per hour ÷ 3600 seconds per hour = 264 inches per second
Next, we need to use the formula for angular velocity:

angular velocity = velocity / radius, The radius of the tire is half the diameter, or 15 inches. So: angular velocity = 264 inches per second / 15 inches, = 17.6 radians per second, Rounding to the nearest hundredth and using pi in our answer, we get: angular velocity ≈ 17.60π radians per second.

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hope this helps you.

(a) (A^T)^T = A: The transpose of a matrix A, denoted as A^T, is obtained by interchanging its rows and columns. If we take the transpose of A^T, we will revert back to the original arrangement of elements in A. Thus, (A^T)^T = A.

(b) (AB)^T = B^T A^T: When we multiply two matrices A and B, we get a new matrix AB. The transpose of this product, (AB)^T, is obtained by interchanging its rows and columns

In exercise 1, we have the following matrices and scalars:
- A = [1 2 3; 4 5 6]
- B = [7 8; 9 10; 11 12]
- c = 3
- d = -2
Now, let's verify the properties in exercises 3-4 using these values:
Exercise 3:
(a) (A^T)^T = A
To verify this property, we need to take the transpose of A and then take the transpose of the result. If we end up with the original matrix A, then the property is satisfied.
Transpose of A:
[1 2 3;
4 5 6]
becomes
[1 4;
2 5;
3 6]
Now we take the transpose of this result:
[1 2 3;
4 5 6]
which is the original matrix A. Therefore, (A^T)^T = A and the property is satisfied.
(b) (AB)^T = B^T A^T
To verify this property, we need to take the transpose of AB and compare it to the product of B^T and A^T. If they are equal, then the property is satisfied.
Transpose of AB:
[58 64 70;
139 154 169]
B^T:
[7 9 11;
8 10 12]
A^T:
[1 4;
2 5;
3 6]
Now we take the product of B^T and A^T:
[58 64 70;
139 154 169]
which is the same as the transpose of AB. Therefore, (AB)^T = B^T A^T and the property is satisfied.
Exercise 4:
(a) (cA)^T = cA^T
To verify this property, we need to take the transpose of cA and compare it to the product of c and A^T. If they are equal, then the property is satisfied.
Transpose of cA:
[3 6 9;
12 15 18]
cA^T:
[3 6 9;
12 15 18]
They are equal, therefore (cA)^T = cA^T and the property is satisfied.
(b) (dA)^T = dA^T
To verify this property, we need to take the transpose of dA and compare it to the product of d and A^T. If they are equal, then the property is satisfied.
Transpose of dA:
[-2 -4 -6;
-8 -10 -12]
dA^T:
[-2 -4 -6;
-8 -10 -12]
They are equal, therefore (dA)^T = dA^T and the property is satisfied.
To answer your question, let's verify the properties of matrix transposition for the given matrices A and B, and the scalars in exercise 1.
(a) (A^T)^T = A
The transpose of a matrix A, denoted as A^T, is obtained by interchanging its rows and columns. If we take the transpose of A^T, we will revert back to the original arrangement of elements in A. Thus, (A^T)^T = A.
(b) (AB)^T = B^T A^T
When we multiply two matrices A and B, we get a new matrix AB. The transpose of this product, (AB)^T, is obtained by interchanging its rows and columns. According to the property of matrix transposition, the transpose of the product of two matrices is equal to the product of their transposes in reverse order. Therefore, (AB)^T = B^T A^T.
These verifications confirm that the matrices and scalars in exercise 1 satisfy the stated properties.

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The coordinates of z with respect to the basis E are:

[z]E = (1/3, 7/9)^T.

To determine the coordinates of a vector in the basis E, we need to express the vector as a linear combination of the basis vectors and then solve for the coefficients.

First, let's write the vectors x, y, and z in terms of their coordinates with respect to the standard basis:

x = (1, 1)^T
y = (1, -1)^T
z = (10, 7)^T

To find the coordinates of x with respect to the basis E, we need to write x as a linear combination of the basis vectors in E:

x = a(5, 3)^T + b(3, 2)^T

Solving for a and b, we get:

a = (2/3) and b = (1/3)

Therefore, the coordinates of x with respect to the basis E are:

[x]E = (2/3, 1/3)^T

Similarly, we can find the coordinates of y with respect to the basis E:

y = a(5, 3)^T + b(3, 2)^T

Solving for a and b, we get:

a = (1/3) and b = (-1/3)

Therefore, the coordinates of y with respect to the basis E are:

[y]E = (1/3, -1/3)^T

Finally, we can find the coordinates of z with respect to the basis E:

z = a(5, 3)^T + b(3, 2)^T

Solving for a and b, we get:

a = (1/3) and b = (7/9)

Therefore, the coordinates of z with respect to the basis E are:

[z]E = (1/3, 7/9)^T.

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To find the orthogonal trajectories of the family of curves y = 17kx, we need to follow some steps including differentiation or reciprocal etc.

Steps are:
Step 1: Differentiate the given equation with respect to x.
Differentiating both sides with respect to x, we have:
dy/dx = 17k

Step 2: Find the negative reciprocal of dy/dx.
The negative reciprocal of dy/dx is the slope of the curve orthogonal to the given family of curves: -(dx/dy) = -1/(17k)

Step 3: Solve the new differential equation.
Now, we need to solve the new differential equation: dx/dy = 1/(17k)

Notice that k is a constant, so let's rewrite the equation as: dx/dy = C, where C = 1/(17k)

Step 4: Integrate both sides of the equation.
Integrate dx/dy with respect to y:
∫(1) dx = ∫(C) dy

x = Cy + D, where D is the constant of integration.

Step 5: Express the equation in terms of y and x.
Now, substitute the original equation y = 17kx back into our orthogonal trajectory equation:

y = (1/C)(x - D)

This is the equation for the orthogonal trajectories of the family of curves y = 17kx, where C and D are constants related to k.

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(a) The conditional PDF is f_X(x|A) = 1/14 for -7 ≤ x ≤ 7 and 0 otherwise.

A continuous uniform random variable defined on the interval (-9, 9) and the event A = {X: |X| ≤ 7}.


The event A implies that the random variable X lies in the interval [-7, 7]. In this interval, X is still uniformly distributed.

Since the length of the interval is 14, the PDF is 1/14, indicating a constant probability density within the given interval. Outside of this interval, the probability density is 0, as the event A does not cover those values of X.

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Answer:

34

Step-by-step explanation:

Note that maximum profit is $26. This point is obtained when the baker has made 4 batches of chocolate chip cookies and 2 bactches of oatmean raisons cookies.

Lets define x as the number of batches of chocolate chip cokies

We want to maximize profit, which is given by:

P = 5x + 3y

subject to the constraints:

4x + 2y ≤ 20 (egg constraint)

3x + 3y ≤ 18 (flour constraint)

x, y ≥ 0 (non-negativity constraint)

We can rewrite the constraints as:

2x + y ≤ 10

x + y ≤ 6

Graphing these constraints on a coordinate plane, we see that the feasible region is a triangle with vertices at (0,0), (0,6), and (4,2)

See agraph attached.

We want to find the point (x,y) within this region that maximizes P.

One way to do this is to calculate P at each vertex of the feasible region:

P(  0,0) = 0

P (0, 6) = 3(6) = 18

P (4,2) =
5(4) + 3(2) =

26

So the point of profit maximization is at  $ 26.

Thica can happen when the baker is baking 4 batches of chocolate chip cookies and 2 batches of oatmeal raisin cookies.

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The points (3,5) and (6,5) would be good choices for the line of best fit.

To find the line of best fit, we want to draw a straight line through the points that best represents the overall trend of the data. This line should pass through as many points as possible while minimizing the distance between the points and the line.

To find the two points that the line of best fit should pass through, we want to select points that are close to the overall trend of the data and are not outliers.

To find the equation of the line of best fit, we can use a method called linear regression. This involves finding the equation of the straight line that minimizes the sum of the squared distances between the line and the points on the scatter plot.

Once we have the equation of the line of best fit, we can use it to make predictions about the data.

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The following parts can be answered by the concept of Operations.

a) shl(x): The result of left shifting x by 1 bit is 0010 0100 0111 1010.

b) shr(x): The result of right shifting x by 1 bit is 0100 1100 0111 1011.

c) cil(x): The result of circularly left shifting x by 1 bit is 0010 0100 0111 1010.

d) cir(x): The result of circularly right shifting x by 1 bit is 1100 1101 1001 1110.

e) ashl(x): The result of arithmetic left shifting x by 1 bit is 0010 0100 0111 1010.

f) ashr(x): The result of arithmetic right shifting x by 1 bit is 1100 1101 1001 1110.

g) dshl(x): The result of double precision left shifting x by 1 bit is 0010 0100 0111 1010 0000.

h) dshr(x): The result of double precision right shifting x by 1 bit is 0000 1001 0100 1000 1111.

a) shl(x): Left shifting x by 1 bit means shifting all the bits in x to the left by 1 position. The leftmost bit is lost, and a 0 is shifted in from the right. Therefore, the result is 0010 0100 0111 1010.

b) shr(x): Right shifting x by 1 bit means shifting all the bits in x to the right by 1 position. The rightmost bit is lost, and a 0 is shifted in from the left. Therefore, the result is 0100 1100 0111 1011.

c) cil(x): Circularly left shifting x by 1 bit means shifting all the bits in x to the left by 1 position, and the leftmost bit is shifted to the rightmost position. Therefore, the result is 0010 0100 0111 1010.

d) cir(x): Circularly right shifting x by 1 bit means shifting all the bits in x to the right by 1 position, and the rightmost bit is shifted to the leftmost position. Therefore, the result is 1100 1101 1001 1110.

e) ashl(x): Arithmetic left shifting x by 1 bit is similar to logical left shifting, except that the sign bit (the leftmost bit) is preserved. Therefore, the result is 0010 0100 0111 1010.

f) ashr(x): Arithmetic right shifting x by 1 bit is similar to logical right shifting, except that the sign bit (the leftmost bit) is preserved. Therefore, the result is 1100 1101 1001 1110.

g) dshl(x): Double precision left shifting x by 1 bit means shifting all the bits in x, including the sign bit, to the left by 1 position. The leftmost bit is lost, and a 0 is shifted in from the right. Therefore, the result is 0010 0100 0111 1010 0000.

h) dshr(x): Double precision right shifting x by 1 bit means shifting all the bits in x, including the sign bit, to the right by 1 position. The rightmost bit is lost, and the sign bit is duplicated to fill the leftmost bit positions. Therefore, the result is 0000 1001 0100 1000 1111

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The following parts can be answered by the concept of Operations.

a) shl(x): The result of left shifting x by 1 bit is 0010 0100 0111 1010.

b) shr(x): The result of right shifting x by 1 bit is 0100 1100 0111 1011.

c) cil(x): The result of circularly left shifting x by 1 bit is 0010 0100 0111 1010.

d) cir(x): The result of circularly right shifting x by 1 bit is 1100 1101 1001 1110.

e) ashl(x): The result of arithmetic left shifting x by 1 bit is 0010 0100 0111 1010.

f) ashr(x): The result of arithmetic right shifting x by 1 bit is 1100 1101 1001 1110.

g) dshl(x): The result of double precision left shifting x by 1 bit is 0010 0100 0111 1010 0000.

h) dshr(x): The result of double precision right shifting x by 1 bit is 0000 1001 0100 1000 1111.

a) shl(x): Left shifting x by 1 bit means shifting all the bits in x to the left by 1 position. The leftmost bit is lost, and a 0 is shifted in from the right. Therefore, the result is 0010 0100 0111 1010.

b) shr(x): Right shifting x by 1 bit means shifting all the bits in x to the right by 1 position. The rightmost bit is lost, and a 0 is shifted in from the left. Therefore, the result is 0100 1100 0111 1011.

c) cil(x): Circularly left shifting x by 1 bit means shifting all the bits in x to the left by 1 position, and the leftmost bit is shifted to the rightmost position. Therefore, the result is 0010 0100 0111 1010.

d) cir(x): Circularly right shifting x by 1 bit means shifting all the bits in x to the right by 1 position, and the rightmost bit is shifted to the leftmost position. Therefore, the result is 1100 1101 1001 1110.

e) ashl(x): Arithmetic left shifting x by 1 bit is similar to logical left shifting, except that the sign bit (the leftmost bit) is preserved. Therefore, the result is 0010 0100 0111 1010.

f) ashr(x): Arithmetic right shifting x by 1 bit is similar to logical right shifting, except that the sign bit (the leftmost bit) is preserved. Therefore, the result is 1100 1101 1001 1110.

g) dshl(x): Double precision left shifting x by 1 bit means shifting all the bits in x, including the sign bit, to the left by 1 position. The leftmost bit is lost, and a 0 is shifted in from the right. Therefore, the result is 0010 0100 0111 1010 0000.

h) dshr(x): Double precision right shifting x by 1 bit means shifting all the bits in x, including the sign bit, to the right by 1 position. The rightmost bit is lost, and the sign bit is duplicated to fill the leftmost bit positions. Therefore, the result is 0000 1001 0100 1000 1111

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To write the vector w in the form [c1,c2,c3,c4], we can simply list the components of w in order. So our final answer is w = [c1, c2, c3, c4] (where c1, c2, c3, and c4 are the components of the vector w that we found using the cross product).

To find a non-zero vector w∈R4 which is orthogonal to all of the given vectors, we can use the cross product. Let's call the given vectors u1, u2, u3, and u4. Then we can find w as:

w = u1 x u2 x u3 x u4

where "x" represents the cross product. This means we take the cross product of u1 and u2, then take the cross product of that result with u3, and so on until we have taken the cross product of all four vectors.

The resulting vector w will be orthogonal to all of the given vectors, since the cross product of two vectors is always orthogonal to both of the original vectors.

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Step-by-step explanation:

126 ski sets  /  (3 ski sets / 5 snowboards)

= 126 * 5/3 = 210 snowboards

The Total taxes owed: $6,919.00 which is option B

To calculate taxes owed on a $51,100 income using the marginal tax rate chart:

10% bracket: $1,027.50

12% bracket: $3,708.00

22% bracket: $2,183.50

Total taxes owed: $6,919.00 which is option B

Taxes are compulsory obligations billed by individuals and firms to the state to fund public utilities and services like infrastructure, instruction, and medical care.

The sum of taxes paid varies depending on income, assets, and other elements, and not settling them can end up in fines or court sanctions.

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The statement which does not represent the distance is

C) In 3 hours car will travel the distance of 160 miles and D).

What is proportion?

A percentage is created when two ratios are equal to one another. We write proportions to construct equivalent ratios and to resolve unclear values.

Here the car can travel 55 miles in one hour.

Then in 1.5 hour distance traveled by car is x.

Using proportion,

=> x = 55*1.5 = 82.5 miles

Now in 2 hours distance traveled by car = 55*2=110 miles

In 2.5 hours distance traveled by car  = 55*2.5 = 137.5 miles

In 3 hours distance traveled by car = 55*3 = 165 miles.

Then distance = 55t . where t = time

Hence the statement which does not represent the distance is

C) In 3 hours car will travel the distance of 160 miles and D).

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Answer:

1. 25/18 ft³

2. 1/216 ft³

Step-by-step explanation:

So all we need to do to calculate the volume is multiply each length gollowing the formula: V= S1×S2×S3

so that being said we transform each unit into sixth parts:

6/6 ft×5/6 ft× 10/6ft.

so we multiply the numerators and denominators, leaving us with 300/216 ft³ (ft×ft=ft², ft×ft×ft=ft³)

if we simplify by dividing both factors by 12, because that is the same result ( 3/6 is the same as 1/2) and we are left with 25/18 ft³

So that is answer 1

Answer 2, because we already have 300/216, that is the full prism, we just divide it by the number of cubes there are, and that is 300.

We are left with 1/216.

I hope this was helpful.

The correct option is (B) [tex]A^-1, B^-1[/tex], and [tex]C^-1[/tex], shows that ABC is also invertble

Since A, B, and C are invertible matrices, they have inverse matrices [tex]A^-1, B^-1,[/tex] and [tex]C^-1,[/tex] respectively.

To show that ABC is invertible, we can introduce a matrix D such that (ABC)D = I and D(ABC) = I, where I is the identity matrix.

We can use the associative property of matrix multiplication to rearrange the product ABCD as follows:

(ABC)D = A(BCD)

Since A, B, and C are invertible, their product ABC is also invertible. Therefore, we can write:

(ABC)D = A(BCD) = I

Multiplying both sides of the equation by [tex]A^-1,[/tex] we get:

[tex]A^-1(ABC)D = A^-1[/tex]

Using the associative property again, we can rearrange the left-hand side as follows:

[tex]A^-1(ABC)D = (A^-1AB)CD = ICD = D[/tex]

Substituting ICD with D, we get:

[tex](A^-1AB)CD = D[/tex]

Since[tex]A^-1A[/tex] is equal to the identity matrix I, we can simplify the equation as follows:

BCD = D

Now we can use a similar approach to show that D(ABC) = I. Multiplying both sides of the equation (ABC)D = I by [tex]C^-1,[/tex] we get:

[tex](ABC)DC^-1 = C^-1[/tex]

Using the associative property, we can rearrange the left-hand side as follows:

[tex]A(BCD)C^-1 = AIC^-1 = A^-1[/tex]

Substituting BCD with D, we get:

[tex]AD^-1C = A^-1[/tex]

Multiplying both sides by [tex]C^-1[/tex], we get:

[tex]AD^-1CC^-1 = A^-1C^-1[/tex]

Since [tex]CC^-1[/tex] is equal to the identity matrix I, we can simplify the equation as follows:

[tex]AD^-1 = A^-1C^-1[/tex]

Multiplying both sides by BC, we get:

[tex]ABCD^-1 = B(A^-1C^-1)C = BI = B[/tex]

Therefore, we have shown that ABC has an inverse matrix D, which implies that ABC is invertible.

Answer: The correct option is (B) [tex]A^-1, B^-1,[/tex] and [tex]C^-1[/tex]exist.

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X can be any real number, there are infinite values of c that will make the system consistent and dependent.

To have an infinite number of solutions, the system must be consistent and dependent. Thus, we need to find the value of 'c' for which the third equation is a linear combination of the first two equations.

Multiplying the second equation by 3 and adding it to the third equation, we get:

2y - z + 3(2x + 3z) = 12.0 + 3(2.7)

Simplifying, we get:

2y - z + 6x + 9z = 20.1

6x + y + 13z = 20.1

Now we have a system of two equations with three variables. To have an infinite number of solutions, one of the variables must be a free variable. Let's solve for z:

z = (20.1 - 6x - y) / 13

Now we can substitute this expression for z into the first two equations:

3x + y + 4[(20.1 - 6x - y) / 13] = c

2x + 3[(20.1 - 6x - y) / 13] = 2.7

Simplifying, we get:

39x + 13y = 52c - 321.6

39x - 6y = 41.7

To have an infinite number of solutions, the two equations must be linearly dependent. We can multiply the second equation by 13 and add it to the first equation to eliminate y:

754x = 52c - 525.9

Solving for c, we get:

c = (754x + 525.9) / 52

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Answer:

Range

Step-by-step explanation:

Mean (Average) 34

Median 37

Mode All values appeared just once.

Range 41

Answer: Range

Step-by-step explanation:

Mean, means average, add all of the numbers and divide by how many there are.

Mean = [tex]\frac{(42+28+35+39+53+12+19+44)}{y\8}[/tex]  = 34

Median, put all the numbers in order and the middle number is your median.

12    19    28    35    39    42    44    53

                             |

The line indicates the middle.  Since the middle is not on a number, you must take the average of the 2 middle numbers.  Meaning add the 2 numbers and divide by 2

Median = (35+39)/2 = 37

Mode, the number that occurs the most times is the mode.  Since none of the numbers occurs more than once. There is no mode

Mode = none

Range, largest number minus smalles number.  The numbers range from 12 to 53

Range = 53-12 =41

If Mean=34

Median =37

Mode=none

Range=41     Range is highest

Answer:

RS = 24, so tan R = 18/24 = 3/4

Answer:

a) 5p (or 5q)

b) 5p ( or 5q)

c) 10p (or 10q)

Step-by-step explanation:

We will use the following information for solving and using the given figure

Preliminary computation

We have [tex]\overrightarrow{AB} = \overrightarrow{BC}[/tex]

Therefore 4p + q = 5p

5p = 4p + q

5p-4p = q

p = q

[tex]\overrightarrow{AB} = 4p + q = 4p + p = 5p = 5q\\[/tex]

So each side is 5p in length which is also equal to 5q since p = q

Part a

[tex]\overrightarrow{AO} = \overrightarrow{OA} = \overrightarrow{AB} = 5p[/tex]  (same as 5q)

Part b

[tex]\overrightarrow{OB} = \overrightarrow{OA} = 5p[/tex]   (same as 5q)

Part c
[tex]\overrightarrow{EB} = 2 \cdot \overrightarrow{OB} = 2 \cdot 5p = 10p[/tex]   (also 10q)

The measure of angle A and B shown in triangle ABC are 61.4° and 28.6° respectively

An equation is an expression that shows how numbers and variables are related to each other using mathematical operations.

From the image shown, using trigonometric rations:

tanA = 11/6

A = 61.4°

Also, for the angle B:

tanB = 6/11

B = 28.6°

The measure of angle A and B are 61.4° and 28.6° respectively

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We can convert all the fractions to decimals and then arrange them in ascending order:

- 16/22 ≈ 0.727

- -5/18 ≈ -0.278

- 2/-21 ≈ -0.095

- -7/12 ≈ -0.583

Therefore, the ascending order would be:

2/-21 ≈ -0.095 < -5/18 ≈ -0.278 < -7/12 ≈ -0.583 < 16/22 ≈ 0.727

So the final arrangement in ascending order is:

2/-21, -5/18, -7/12, 16/22

The example of non polyhydrons the length of a fields are equals to the cone and sphere. So, option (b) and (c) is rigth choices for answering this problem.

The solid objects which have faces (flat faces) are called polyhedra (singular is polyhedron) and the solid objects which have curved faces are called non-polyhedra. Some examples of non-polyhedra are sphere, cylinder, cone . A sphere is not a polyhedron because it is not composed of flat faces connected at straight edges, thus it does not form a shape. Cone is not a polyhedron because it has a curved surface. Rectangle is a polyhedron because it has a curved shape.

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Complete question:

Write the example of non polyhydrons the length of a fields and

a) a rectangular

b) cone

c) sphere

d) semi- circle

a. Bella should estimate her cost per year to be $17,150.

b. It looks like Bella's family is contributing more than her estimated cost per year, so she may not need to contribute anything.

The act of deleting items from a collection is represented by subtraction. Subtraction is denoted by the minus sign. For instance, suppose there are nine oranges stacked. If four oranges are then transferred to a basket, there will now be nine oranges left in the stack (9 – 4).

a. To estimate Bella's cost per year, we need to subtract her financial aid from the total cost of attendance. Let's assume the total cost of attendance is $30,000 per year. Then, Bella's estimated cost per year would be:

Total cost of attendance - Financial aid = Estimated cost per year

$30,000 - $9,750 - $3,100 = $17,150

Therefore, Bella should estimate her cost per year to be $17,150.

b. If Bella's family is contributing $20,000 towards her expenses each year, she needs to contribute the remaining amount. To calculate how much she needs to contribute each year, we can subtract her family's contribution from her estimated cost per year:

Estimated cost per year - Family contribution = Bella's contribution

$17,150 - $20,000 = -$2,850

It looks like Bella's family is contributing more than her estimated cost per year, so she may not need to contribute anything. However, it's important to keep in mind that these are just estimates and actual costs may vary.

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First, let's recall the definition of the subspace spanned by e1 and e2. This means that s is the set of all linear combinations of e1 and e2. In other words, any vector in s can be written as a scalar multiple of e1 plus a scalar multiple of e2.

Now, to find L(S) for each linear operator L in exercise 17, we simply need to apply L to every vector in s. Since s is spanned by e1 and e2, we can express any vector in s as a linear combination of e1 and e2:

v = ae1 + be2 where a and b are scalars. Then, we can apply L to v: L(v) = L(ae1 + be2)

Since L is a linear operator, we know that it satisfies the properties of linearity: L(x + y) = L(x) + L(y) L(cx) = cL(x) for any vectors x and y and any scalar c.

Therefore, we can apply these properties to L(ae1 + be2): L(v) = L(ae1) + L(be2) = aL(e1) + bL(e2) where we have used the fact that e1 and e2 are vectors in R^3 and therefore can be operated on by L.

So, to summarize: - We start with a vector v in s, which can be expressed as v = ae1 + be2

We apply L to v, using the linearity properties of L: L(v) = L(ae1 + be2) = L(ae1) + L(be2) = aL(e1) + bL(e2)

Therefore, L(S) is the set of all vectors that can be expressed in the form aL(e1) + bL(e2), where a and b are scalars.

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The null and alternative hypothesis: H0: p = 0.35, HA: p ≠ 0.35

What is hypothesis?

A hypothesis is an idea or explanation that is proposed and then tested through research and analysis to determine if it is supported by evidence or not. In statistics, a hypothesis is a statement about a population parameter, such as a mean or proportion, that is either true or false.

In this situation, we want to test whether the percentage of CEOs with an MBA has changed or not. We can set up two hypotheses, the null hypothesis (H0) and the alternative hypothesis (HA). The null hypothesis is the default position, which we assume to be true unless there is sufficient evidence to reject it. The alternative hypothesis represents the opposite of the null hypothesis, and it is what we want to test for.

In this case, the null hypothesis is that the percentage of CEOs with an MBA is equal to 35%, which means there is no change in the proportion. The alternative hypothesis is that the percentage of CEOs with an MBA is different from 35%, which implies a change in the proportion. Therefore, we have:

H0: P = 0.35

HA: P ≠ 0.35

where P represents the proportion of CEOs with an MBA.

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