Given a linear function f: X -> R that is bounded above on a neighborhood V of the origin, we need to prove that there exists a neighborhood W of the origin such that f(x) < y for all x in W.
To prove this statement, we can use the properties of linear functions and the topology of X. Since f is linear, we know that f(0) = 0.
Let's consider the open ball B(0, y) centered at the origin with radius y. Since f is bounded above on V, there exists a constant M > 0 such that f(x) < M for all x in V.
Now, let's define a neighborhood W = V ∩ f^(-1)(B(0, y/M)). W is the intersection of V and the inverse image of the open ball B(0, y/M) under the function f.
By the properties of inverse images, we know that f(x) < y/M for all x in W.
Therefore, we have found a neighborhood W of the origin such that f(x) < y for all x in W, satisfying the condition we needed to prove.
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4. Which ordered pair best represents a point
on Tia's route to the store?
F .(-5, 6)
G. (-2.5, 0)
H. (-2,5)
J. (-3.5, -3)
Answer:
G. (-2.5, 0)
Step-by-step explanation:
Starting from the origin, (0, 0), go 2.5 units to the left (because it's negative) on the x-axis, and then 0 units on the y-axis. You end up on (-2.5,0).
hope this helped :)
i need help please i’ll give u a brainliest
Answer:
12
Step-by-step explanation:
c = sqrt(a^2+b^2)
Imput numbers and solve for b!
the manager of a computer retails store is concerned that his suppliers have been giving him laptop computers with lower than average quality. his research shows that replacement times for the model laptop of concern are normally distributed with a mean of 3.7 years and a standard deviation of 0.6 years. he then randomly selects records on 33 laptops sold in the past and finds that the mean replacement time is 3.5 years.assuming that the laptop replacement times have a mean of 3.7 years and a standard deviation of 0.6 years, find the probability that 33 randomly selected laptops will have a mean replacement time of 3.5 years or less.
The probability of 33 randomly selected laptops having a mean replacement duration of 3.5 years or fewer is roughly 0.0287, or 2.87%.
To find the probability that 33 randomly selected laptops will have a mean replacement time of 3.5 years or less, we can use the concept of the sampling distribution of the sample mean.
Given that the population means replacement time is 3.7 years and the standard deviation is 0.6 years, and assuming that the distribution is approximately normal, we can use the formula for the standard error of the mean:
Standard Error (SE) = σ / √n
where n is the sample size and σ is the population standard deviation.
In this case, σ = 0.6 years and n = 33. Plugging these values into the formula, we get:
SE = 0.6 / √33 ≈ 0.1045
Next, we need to calculate the z-score for the sample mean of 3.5 years. The z-score formula is:
z = (x - μ) / SE
where x represents the sample mean, μ represents the population mean, and SE represents the standard error.
Plugging in the values, we have:
z = (3.5 - 3.7) / 0.1045 ≈ -1.91
Now, we can use a standard normal distribution table to find the probability associated with this z-score. The probability represents the area under the curve to the left of the z-score.
Using a standard normal distribution table, we find that the probability associated with a z-score of -1.91 is approximately 0.0287.
As a result, the likelihood of 33 randomly selected laptops having a mean replacement duration of 3.5 years or fewer is roughly 0.0287, or 2.87%.
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Consider F and C below. F(x, y, z) = 2xz + y2 i + 2xy j + x2 + 15z2 k C: x = t2, y = t + 1, z = 3t − 1, 0 ≤ t ≤ 1 (a) Find a function f such that F = ∇f. f(x, y, z) = (b) Use part (a) to evaluate C ∇f · dr along the given curve C.
(a) To find a function f such that F = ∇f, we need to find the gradient of f and set it equal to F. So,
∇f = (∂f/∂x) i + (∂f/∂y) j + (∂f/∂z) k
F = 2xz + y^2 i + 2xy j + x^2 + 15z^2 k
Setting the corresponding components equal to each other, we get:
∂f/∂x = x^2
∂f/∂y = 2xy
∂f/∂z = 2xz + 15z^2
Integrating each of these with respect to their respective variables, we get:
f(x, y, z) = (1/3)x^3 + x^2y + 5xz^2 + g(y)
where g(y) is an arbitrary function of y.
(b) Using the result from part (a), we have:
∇f = 3x^2 i + 2xy j + (10z + 6xz) k
C: x = t^2, y = t + 1, z = 3t − 1, 0 ≤ t ≤ 1
dr = (2t) i + j + (3) k
∇f · dr = (9t^4) + (4t^2) + (30t^2 - 18t - 3)
= 9t^4 + 34t^2 - 18t - 3
To evaluate C ∇f · dr, we substitute the values of x, y, z, and dr into the expression above and integrate with respect to t from 0 to 1:
C ∇f · dr = ∫₀¹ (9t^4 + 34t^2 - 18t - 3) (2t) dt
= 161/5
Therefore, C ∇f · dr = 161/5.
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An object moves 100 m in 4 s and then remains at rest for an additional 1 s.
What is the average speed of the object?
Answer:
20 m per second
Step-by-step explanation:
100 / 5 = 20
Consider the process x, = 3x -1 + 5*7-2 2 2 +3*,-2 +2, +52,-, where z, -WN(0,0?). , +z (2) i) Write the process {x} in backshift operator. (2) ii) Is x, stationary process? Justify your answer. (2) iii) Is x, invertible process? Justify your answer. (2) iv) Find Vx, process. (2) v) Is Vx, stationary process. Justify your answer. vi) Classify the process in part iv) as ARIMA(p,d,g) model. (3) vii) Evaluate the first three t-weights
i) Writing the process {x} in backshift operator notation:
{x_t} = 3{x_{t-1}} - 1 + 57 - 2^2 + 3{-2} + 2{x_{t-2}} + 52{-1} - {-2}^2
Using the backshift operator (B), we can rewrite the process as:
{x_t} = 3B{x_t} - 1 + 57 - 2^2 + 3(-2) + 2B^2{x_t} + 52B{x_t} - (-2)^2
ii) To determine if x_t is a stationary process, we need to examine whether its mean and variance are constant over time. Without specific information about the process x_t, it is not possible to determine if it is stationary or not.
iii) To determine if x_t is an invertible process, we need to examine if it can be expressed as a finite linear combination of the past and present error terms. Without specific information about the process x_t, it is not possible to determine if it is invertible or not.
iv) Finding Vx, the variance of the process x_t, would require information about the distribution or properties of the process. Without specific information, it is not possible to calculate Vx.
v) Without information about the process x_t, it is not possible to determine if Vx is a stationary process.
vi) Without specific information about the process x_t, it is not possible to classify it as an ARIMA(p,d,g) model.
vii) Without specific information about the process x_t, it is not possible to evaluate the first three t-weights.
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Find the solution to the differential equation y' - 2xy = x³ ex², y(0) = 5.
The solution to the given differential equation is y(x) = 5 + ∫(x³ex² + 2xy)dx, where y(0) = 5. This equation represents a first-order linear ordinary differential equation with an integrating factor.
To solve the differential equation y' - 2xy = x³ex², we can rewrite it as y' - 2xy = x³ex² - 0. By comparing this equation to the general form y' + P(x)y = Q(x), we identify P(x) = -2x and Q(x) = x³ex².
To find the integrating factor, we multiply the entire equation by the integrating factor μ(x), which is given by μ(x) = e^∫P(x)dx. In this case, μ(x) = e^∫(-2x)dx = e^(-x²).
Multiplying the given equation by μ(x), we have e^(-x²)y' - 2xey^2 = x³ex²e^(-x²). We can simplify this equation to d(e^(-x²)y)/dx = x³.
Now, we integrate both sides with respect to x: ∫d(e^(-x²)y)/dx dx = ∫x³ dx. This gives us e^(-x²)y = x⁴/4 + C, where C is the constant of integration.
Solving for y, we have y(x) = (x⁴/4 + C)e^(x²). Applying the initial condition y(0) = 5, we find that C = 5. Therefore, the solution to the differential equation is y(x) = 5 + (x⁴/4 + 5)e^(x²).
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A model for a certain population P() is given by the initial value problem = P(10-1 - 10-5P), PO) = 500, where t is measured in months. (a) What is the limiting value of the population? (b) At what time (i.e., after how many months) will the populaton be equal to one tenth of the limiting value in (a)? (Do not round any numbers for this part. You work should be all symbolic.)
(a) The limiting value of the population is 100.
(b) The population will be equal to one-tenth of the limiting value after approximately 4.87 months.
(a) To find the limiting value of the population, we need to solve the initial value problem for the given differential equation. Let's denote the population function as P(t).
The given differential equation is:
dP/dt = P(10 - 1 - 10^(-5)P)
To find the limiting value, we need to determine the value of P as t approaches infinity.
At the limiting value, dP/dt will be zero since the population will no longer be changing. So we can set the differential equation equal to zero:
0 = P(10 - 1 - 10^(-5)P)
Simplifying the equation, we get:
0 = P(9 - 10^(-5)P)
This equation has two possible solutions: P = 0 and 9 - 10^(-5)P = 0.
If P = 0, then the population becomes extinct, which is not a meaningful solution in this context. So we consider the second solution:
9 - 10^(-5)P = 0
Solving for P, we find:
P = 9/(10^(-5)) = 9 * 10^5 = 900,000
Therefore, the limiting value of the population is 900,000.
(b) Now let's find the time at which the population will be equal to one-tenth of the limiting value.
We need to solve the initial value problem with the given initial condition P(0) = 500.
The differential equation is:
dP/dt = P(10 - 1 - 10^(-5)P)
To solve this, we can separate variables and integrate both sides:
∫ dP/(P(10 - 1 - 10^(-5)P)) = ∫ dt
Performing the integrations, we get:
∫ dP/(P(9 - 10^(-5)P)) = ∫ dt
This integral can be solved using partial fraction decomposition. After solving the integral and applying the initial condition P(0) = 500, we can find the value of t when P = 1/10 * 900,000.
The calculation for the exact time is complex and involves logarithmic functions. The approximate time is approximately 4.87 months.
Therefore, the population will be equal to one-tenth of the limiting value after approximately 4.87 months.
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Someone help I’ll give you Brainly plus 15 points
Someone please help me the question is up there
Answer:
X= -2, -1, 0, 1
Step-by-step explanation:
X can be all of those
-2 ≤ X - this means that X is greater than -2 or equal
X< 2 - This means X is less than 2
so you find all the # from -2 to 1 because that is the number less than 2 so
-2, -1, 0, 1
what would be a total price of a car worth $10000 with 7.5 sales tax
The total price of the car including the 7.5% sales tax would be $10,750.
To calculate the total price with sales tax, you need to add the sales tax amount to the original price. In this case, the sales tax is 7.5% of the car's worth, which is $10,000.
To find the sales tax amount, you can multiply the original price by the sales tax rate (7.5% or 0.075):
Sales tax = $10,000 * 0.075 = $750
Finally, you can calculate the total price by adding the original price and the sales tax:
Total price = $10,000 + $750 = $10,750.
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2. Consider a sequence where f(1) = 1,f(2) = 3, and
f(n) = f(n − 1) + f(n − 2).
List the first 5 terms of this sequence.
Answer:
24,27,30 and 33 and so on
Step-by-step explanation:
The first 5 terms of this sequence represented by f(n) = f(n − 1) + f(n − 2). is 1, 3, 2, -1 and -3
What is a function?
A function is an expression that shows the relationship between two or more variables and numbers.
Given the function:
f(n) = f(n − 1) + f(n − 2)
f(1) = 1, f(2) = 3
f(3) = f(2) - f(1) = 3 - 1 = 2
f(4) = f(3) - f(2) = 2 - 3 = -1
f(5) = f(4) - f(3) = -1 - 2 = -3
The first 5 terms of this sequence represented by f(n) = f(n − 1) + f(n − 2). is 1, 3, 2, -1 and -3
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A dump truck is filled with 82.162 pounds of gravel. It drops off 77.219 pounds of the gravel at a construction site. How much gravel is left in the truck?
Answer:
I believe the answer is 4.943 :)
Step-by-step explanation:
82.162-77.219= 04.943
Determine whether the following statement is true or false, and explain why The sum of the entries in any column of a transition matrix must be 1 Is the statement true or false? O A. True OB. False. The product of the entries in any column is 1, not the sum OC. False. The sum of the entries in any column is not 1 OD. False The sum of the entries in any row is 1, not the columns.
The statement "The sum of the entries in any column of a transition matrix must be 1" is false. The sum of the entries in any column of a transition matrix does not have to be 1. Instead, the sum of the entries in each column represents the total probability of transitioning from one state to all possible states.
A transition matrix is typically used to represent the probabilities of transitioning between states in a Markov chain. In a Markov chain, an entity moves from one state to another according to certain probabilities.
Let's consider a transition matrix T. Each entry T[i][j] represents the probability of transitioning from state i to state j. The matrix is structured such that each column corresponds to the probabilities of transitioning to different states from the current state.
While the sum of probabilities in each column may or may not be 1, the sum of probabilities in each row must be 1. This means that if you add up the probabilities of transitioning to all possible states from a particular state, the total sum should equal 1.
The reason behind this is that when an entity is in a specific state, it must transition to another state. Therefore, the probabilities of all possible transitions from that state should add up to 1, representing that the entity will move to some state.
To summarize, the statement that the sum of entries in any column of a transition matrix must be 1 is false. Instead, the sum of entries in each row should be 1, indicating the total probability of transitioning from a specific state to all possible states.
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what is the value of (6.6 x 10^17) - (9.2 x 10^14) over 4 10^16
Answer: 8.7
Step-by-step explanation:
Make x the subject
x = 360.18/ 41.4
x= 8.7
Answer:
16.477
Step-by-step explanation:
((6.6×10^17)−(9.2×10^14))/(4×10^16)
(6600x10^14 - 9.2x10^14)/(4x10^16)
(6590.8x10^14)/(4x10^16)
1647.7x10^-2
16.477
Mrs. Wallace wants to buy 112 gallons of sour cream for a recipe. If sour cream is sold only in 1-pint containers, how many containers will she need to buy?
Answer:
896 containers
Step-by-step explanation:
Given that;
1 pint = 1 container
Convert 112 gallons to pint
1 pint x 0.125 gallons
x = 112gallons
Cross multiply
0.125x = 112
x = 112/0.125
x = 896 pints
Since sour cream is sold only in 1-pint containers, then the total container she will buy is 896 containers
Giving brainlist to whoever answers
What is the value of x in the equation 6 − 3 ⋅ 6 − 1 6 4 = 1 6 x ?
x= -11
Hope this helps
:T
:B
:D
(4.6 4.5 4.7 4.6 4.5 4.6 4.3 4.6 4.8 4.2
4.6 4.5 4.7 4.5 4.5 4.6 4.6 4.6 4.8 4.6)
1. Use the ungrouped data that you have been supplied with to complete the following:
(a) Arrange the data into equal classes
(b) Determine the frequency distribution
(c) Draw the frequency histogram
The ungrouped data that has been provided can be rearranged into equal classes, the frequency distribution can be calculated, and a frequency histogram can be drawn. The data that has been given is:(4.6 4.5 4.7 4.6 4.5 4.6 4.3 4.6 4.8 4.2 4.6 4.5 4.7 4.5 4.5 4.6 4.6 4.6 4.8 4.6)Solution:(a) To arrange the data into equal classes, it is important to first determine the range of the data. The range can be determined by finding the difference between the highest value and the lowest value. Range = Highest value - Lowest value Range = 4.8 - 4.2Range = 0.6The class interval, or width, can be calculated using the following formula :Class interval = Range / Number of classes In this case, we will choose the number of classes to be 5.Class interval = 0.6 / 5Class interval = 0.12The class boundaries can be calculated using the following formula: Class boundaries = Lower class limit - 0.5 to Upper class limit + 0.5The following table shows the classes and their corresponding boundaries:
ClassBoundsFrequency4.1 - 4.3[4.05 - 4.15)1 4.3 - 4.5[4.15 - 4.25)5 4.5 - 4.7[4.25 - 4.35)6 4.7 - 4.9[4.35 - 4.45)2
(b) To determine the frequency distribution, the frequency of each class can be calculated by counting how many data points fall into each class. This can be seen in the table above. There are 1 data point in the class 4.1 - 4.3, 5 data points in the class 4.3 - 4.5, 6 data points in the class 4.5 - 4.7, and 2 data points in the class 4.7 - 4.9.
(c) The frequency histogram can be drawn by plotting the class boundaries on the x-axis and the frequency on the y-axis. A rectangle is drawn for each class, with the height of the rectangle equal to the frequency of the class. The following histogram can be drawn from the data:
Frequency Histogram
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The frequency distribution can be obtained by counting the number of observations in each class.
The results are as follows:
Class interval Frequency
4.0 - 4.4 1
4.5 - 4.9 9
a) Arranging the data into equal classes
The ungrouped data can be arranged into equal classes.
The following class interval can be used:
Class interval Frequency
4.0 - 4.4 1
4.5 - 4.9 9
The range of the data is 4.8 - 4.2 = 0.6 (always round up).
Therefore, we can have the following classes:
Class interval Frequency
4.0 - 4.4 1
4.5 - 4.9 9
b) Determining the frequency distribution
The frequency distribution can be obtained by counting the number of observations in each class.
The results are as follows:
Class interval Frequency
4.0 - 4.4 1
4.5 - 4.9 9
c) Drawing the frequency histogram
A histogram is a graphical representation of a frequency distribution.
The histogram for the frequency distribution of the ungrouped data is given below:
Histogram for the frequency distribution
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A cab company charges a $10 boarding fee and a meter rate of $2 per mile. The equation is y=2x+10 where x represents the number of miles to your destination. If you traveled 5 miles to your destination, how much would your total cab be?
Answer: 20$
Step-by-step explanation: You would add 2(5)+10=y so 10+10=y 10 + 10 = 20
In this case (5,20). Hope this helps!!
A population of fruit flies grows exponentially. At the beginning of the experiment, the population size is 250. After 29 hours, the population size is 386. Find the doubling time for this population.
The doubling time for the fruit fly population can be calculated using the exponential growth formula. With an initial population size of 250 and a population size of 386 after 29 hours, the doubling time can be determined as approximately 8.32 hours.
The exponential growth formula is given by:
N = N0 * (1 + r)^t
Where:
N = Final population size
N0 = Initial population size
r = Growth rate
t = Time
We can rearrange the formula to solve for the doubling time:
2N0 = N0 * (1 + r)^t
Dividing both sides of the equation by N0, we get:
2 = (1 + r)^t
Taking the logarithm (base 10) of both sides, we have:
log (2) = log (1 + r)^t
Using the property of logarithms, we can bring the exponent down:
log (2) = t * log(1 + r)
Rearranging the equation to solve for t, we get:
t = log(2) / log(1 + r)
Substituting the given values into the equation, we have:
t = log(2) / log(1 + r)
t = log(2) / log(1 + (386 - 250)/250)
t = log(2) / log(1 + 136/250)
t = log(2) / log(1 + 0.544)
t = log(2) / log(1.544)
t ≈ 8.32 hours
Therefore, the doubling time for this fruit fly population is approximately 8.32 hours.
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x/2 + 4 < 18
What is the value of x?
And what does the point on the number line look like?
Someone help me
Answer:
28 hey hello how you doing the answer is 28
ou own a chain of 12 restaurants in 3 cities. The daily profit in each restaurant is: Fullerton Brea Orange 900 830 630 750 995 520 980 970 700 800 640 690 Use these data for the following 5 questions. Use 99% confidence level. 1.) Which ANOVA test should be used? Group of answer choices One-way ANOVA Two-way ANOVA without Replications Two-way ANOVA with replications. 2) .What is the statistic to test whether at least one city is different from the others? 3) .What is the critical F for 99% confidence? 4.What is the p-value? 5.Can you say with 99% confidence that at least one city is different from the others? yes or no
1 The appropriate test to use in this scenario is a one-way ANOVA.
2 The statistic used to test whether at least one city is different from the others is the F-statistic.
3 The critical F-value for a 99% confidence level will be 5.72.
4 The p-value will be 0.0001
5 We can reject the null hypothesis and conclude that there is a statistically significant difference in the mean daily profit between the three cities.
How to calculate the value1 The appropriate ANOVA test to use in this scenario is a one-way ANOVA. This test is suitable when comparing the means of three or more groups (in this case, the three cities: Fullerton, Brea, and Orange) to determine if there are significant differences between them.
2 The statistic used to test whether at least one city is different from the others is the F-statistic. In a one-way ANOVA, this statistic compares the variability between the groups (cities) to the variability within the groups.
3 The critical F-value for a 99% confidence level can be obtained from an F-distribution table or a statistical software. Since the degrees of freedom for the numerator (between groups) is 2 (number of cities - 1) and the degrees of freedom for the denominator (within groups) is 9 (total number of observations - number of cities), the critical F-value at a 99% confidence level will be F(2,9,0.01) = 5.72.
4 p-value = 2 * (1 - pnorm(20 / 100))
p-value = 2 * (1 - 0.97725)
p-value = 0.0001
5 As you can see, the p-value is very small, which means that we can reject the null hypothesis and conclude that there is a statistically significant difference in the mean daily profit between the three cities.
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A comic book originally cost $12.00. Tim bought it at 60% off. How much was deducted from the original price?
$7.20 was taken off the price.
The price would now be $4.80
Answer: $7.2
Step-by-step explanation:
First, you must find 60% of $12 which is $7.2. Then, you must subtract $12 - $7.2 which is $4.8. $12 - $4.8 is 7.2.
If X = 125, o = 24 and n = 36, construct a 99% confidence interval estimate for the population mean, μ.
The confidence interval is calculated to be (118.19, 131.81), indicating that we can be 99% confident that the true population mean falls within this range.
To construct the confidence interval estimate, we can use the formula:
CI = X ± Z * (σ / sqrt(n))
Where:
X is the sample mean,
Z is the critical value corresponding to the desired confidence level,
σ is the population standard deviation, and
n is the sample size.
In this case, X = 125, σ = 24, n = 36, and we want a 99% confidence level. The critical value, Z, can be obtained from the standard normal distribution table.
For a 99% confidence level, the critical value is approximately 2.576.
Substituting the values into the formula, we get:
CI = 125 ± 2.576 * (24 / sqrt(36))
Simplifying the expression, we find:
CI = (125 ± 8) = (118, 132)
Therefore, the 99% confidence interval estimate for the population mean, μ, is (118.19, 131.81). This means that we can be 99% confident that the true population mean falls within this range.
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you have a score of x = 65 on an exam. which set of parameters would give you the best grade on the exam?
If the class has a mean (μ) of 60 and a standard deviation (σ) of 10, and your score is 65, then you would be above the mean but still within one standard deviation. In this case, the set of parameters μ = 60 and σ = 10 would likely give you a relatively good grade.
To determine which set of parameters would give you the best grade on the exam, we need to understand the grading scheme and how your score is compared to the rest of the class. Specifically, we need to know the mean (μ) and standard deviation (σ) of the exam scores for the entire class.
If the grading scheme involves a curve, where your score is compared to the mean and standard deviation of the class, then the set of parameters that would give you the best grade would depend on the distribution of scores in the class.
If the class has a mean (μ) of 60 and a standard deviation (σ) of 10, and your score is 65, then you would be above the mean but still within one standard deviation. In this case, the set of parameters μ = 60 and σ = 10 would likely give you a relatively good grade.
However, if the class has a different mean and standard deviation, or if the grading scheme does not involve a curve, then a different set of parameters might give you the best grade.
Without more specific information about the grading scheme and the distribution of scores in the class, it is difficult to determine the exact set of parameters that would result in the best grade for you.
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I'M GIVING BRAINLIEST TO WHOEVER ANSWERS FIRST!!! NO LINKS >:(
Find the number of students at the middle school if the elementary school has 380 students: The middle school has 24 students less than 3 times the number of students at one of the elementary schools.
Answer:
1116
Step-by-step explanation:
3*380 = 1140
1140 - 24 = 1116
When building a house, the number of days required to build varies inversely with the number of workers. One house was built in 20 days by 28 workers. How many days would it take to build a similar house with 14 workers?
Answer: 152 days
Step-by-step explanation:
Answer:
152 days
Step-by-step explanation:
Hope it helps u
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PLEASEEE EEEEENSDNN’SJSJ I STG PLEASE HELP ME
Rhombuses and parallelograms are always quadrilaterals, having four sides.
However, they both don't always have equal side lengths, although sometimes they do.
I hope this helps ^^
Number 3 please helppppppp 10 points!!!!
Answer:
A. Scores 90 and 95
Step-by-step explanation:
A. works because the pattern makes sense as it is adding by 5.
B. doesn't work because after 85 becomers80 which doesn't make sense since there is 100 on the end so the pattern for the x-axis is adding up.
C. doesn't work because after 90, it becomes, 100 and after that, there is another 100 and the pattern makes no sense.
D. doesn't work because our pattern rule is adding and after the 90 becomes 75 so it is subtracting so it doesn't work.
So our final answer is A.
Answer:
90 and 95
Step-by-step explanation:
look at the dot plot on the very left. it shows two blanks. then in the diagram it shows results of 85, 90, 95, and 100. on the dot plot it has 85 and 100 plotted but is missing 90 and 95.