Lila collected 116gallons of honey. After using some of the honey she collected for baking, Lila found that she only had 34 gallon of honey left. How much honey did she use for baking?

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation that goes through (5,4) and (10,2)

[tex](\stackrel{x_1}{5}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{10}-\underset{x_1}{5}}}\implies \cfrac{-2}{5} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{2}{5}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{5}{2}}\qquad \stackrel{negative~reciprocal}{+\cfrac{5}{2}\implies \cfrac{5}{2}}}[/tex]

Answer:

Step-by-step explanation:

f(x) = 2x + 1

g(x) = ?

h(x) = ln(x)

hgf(x) = ½ln(2x - 3)

All h(x) does is take a natural log of a number, therefore the output

gf(x) = [tex]\sqrt{2x - 3}[/tex]

the change between f(x) and fg(x) is a subtraction of 4 then raising the result to a power of ½.

g(x) = [tex]\sqrt{x - 4}[/tex]

Answer:

Measure of Angle B = 25°

Step-by-step explanation:

Something to keep in mind: Angle A and B are Vertical Angles so they will always be equal

so;

Angle A = Angle B

(4x + 5) = (-2(x - 17.5))

4x + 5 = -2x + 35   (<= Solved by distributive property)

6x + 5 = 35

6x = 30

x = 5

Now we can find the measure of Angle B, by substituting x by 5 in the B equation;

-2 (x - 17.5) = Angle B

-2 (5 - 17.5) = Angle

-2 (-12.5) = Angel B

25 = Angle B

so measure of angle B = 25

Hope this helps!

Answer:

5.62790697674

Step-by-step explanation:

there you go

Answer:

the annswer is 5

Step-by-step explanation: you just have to divide the highlighted numbers, which are 20 ÷ 5

Answer: 12% of people responded as City D

Answer:

p = 0.07

p-hat = 0.035

p0 = 0.07

p-value = 0.003

Step-by-step explanation:

p = population parameter, in this case, the rate of infestations across all trees in the forest

p-hat = test statistic, in this case, the rate of infestations found in the sample of trees, i.e. those in Doug's backyard

p0 = the null hypothesis, in this case, the rate of infestations within the forest is correctly evaluated at 0.07 or 7%

p-value = the likelihood any difference between p and p-hat is down to chance

In this case 0.003 as the p-value means there is only 0.3% probability of our statistic value of 0.035 being down to variability and chance meaning it is 99.7% likely that there is some reason behind this difference;

We would accept the alternative hypothesis which says the current parameter value, 0.07, is in fact incorrect (either too high or too low, in this case, likely too high).

Step-by-step explanation:

subject arts and architecture what primary

Answer:

[tex]\huge\colorbox{blue}{A}\huge\colorbox{orange}{N}\huge\colorbox{gray}{S}\huge\colorbox{red}{W}\huge\colorbox{yellow}{E}\huge\colorbox{purple}{R}[/tex]

hitsss

Answer:

Solution:

3/7x = 12

3/7x ÷ 3/7 = 12 ÷ 3/7 ( divide 3/7 in both sides )

x = 12 ÷ 3/7 (divide)

x = 84/3 (simply divide 84 and 3)

x = 28

_______________________

(solution for dividing the fraction and the whole number 12 and 3/7, for those who don't know how to divide fractions and whole numbers...)

12/1 ÷ 3/7

12/1 ÷ 7/3 (reciprocal method)

12/1 × 7/3 (change operation to multiplication)

12/1 × 7/3 = 84/3 (multiply)

84/3 ⇒ 28 (simplify)

There are 100 numbers in the range 100-199. Find the smallest and largest multiple of 13 in this range. We have

104 = 8•13

195 = 15•13

so there are 15 - 8 + 1 = 8 multiples of 13 between 100 and 199.

Then the sum we want is

[tex]\displaystyle \sum_{k=100}^{199} k - \sum_{\ell=8}^{15}13\ell[/tex]

or equivalently,

(100 + 101 + 102 + … + 199) - 13 (8 + 9 + … + 15)

To compute these sums, recall the following formula:

[tex]\displaystyle \sum_{i=1}^n i = 1 + 2 + 3 + \cdots + n = \frac{n(n+1)}2[/tex]

Then

[tex]\displaystyle \sum_{k=100}^{199} k = \sum_{k=1}^{199} k - \sum_{k=1}^{99} k = \frac{199\cdot200}2 - \frac{99\cdot100}2 = 14,950[/tex]

and

[tex]\displaystyle \sum_{\ell=8}^{15} 13\ell = 13 \left(\sum_{\ell=1}^{15} \ell - \sum_{\ell=1}^7 \ell\right) = 13 \left(\frac{15\cdot16}2 - \frac{7\cdot8}2\right) = 1,196[/tex]

which means the sum we want is 14,950 - 1,196 = 13,754.

Answer:

B

d(P,Q) = sqrt((xO-xQ)^2 + (yP-yQ)^2) = sqrt(16+9) = 5

Check the picture below.

notice, we have three pair of sides, let's add them all up to get the area

[tex]\stackrel{\textit{left and right}}{2(8\cdot 14)}+\stackrel{\textit{front and back}}{2(3.5\cdot 8)}+\stackrel{\textit{top and bottom}}{2(3.5\cdot 14)}\implies 378~in^2[/tex]

Answer:

OOO

OOO

OO

Step-by-step explanation:

Where OOO is == 1.

OO is 2/3 of OOO.

Answer: y= 1/2x + 7

Step-by-step explanation:

Answer:

35 degrees celsius

Answer: I'll give you formula

Step-by-step explanation: circumference = 2 x π x radius

radius = diameter÷2      area = π × radius²

Answer:

Step-by-step explanation:

Initial class size = 30 students

Class size now is 40% larger:

First let's find larged amount

[tex]\\ \sf\longmapsto 40\%\:of\:30[/tex]

[tex]\\ \sf\longmapsto 0.4(30)[/tex]

[tex]\\ \sf\longmapsto 12[/tex]

Class size=30+12=42students

Answer:

c

brainlest

Step-by-step explanation:

Answer:

Answer ️️

Step-by-step explanation:

5.1÷104 = 4.903846154

Answer:

Jill plz tell if i am right

Step-by-step explanation:

give me schoology website

Answer:

Your tip is $15.00

Step-by-step explanation:

Have a nice day ^^

Answer:

.

Step-by-step explanation:

Answer:

Uuuuh thats kind of suspicious, maybe you could post your question without  a link? But links are usually scams, so dont do that :)

Answer:

B

Step-by-step explanation:

If you go to -4, 0 the line intersects that point

Answer:

xd

Step-by-step explanation:

3X+4y=8

this is the graph that represents the solution

[tex]6x^2-x=2\implies 6x^2-1x-2=0 \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{6}x^2\stackrel{\stackrel{b}{\downarrow }}{-1}x\stackrel{\stackrel{c}{\downarrow }}{-2}=0 \qquad \qquad x= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}[/tex]

[tex]x = \cfrac{ -(-1) \pm \sqrt { (-1)^2 -4(6)(-2)}}{2(6)}\implies x = \cfrac{1\pm\sqrt{1+48}}{12} \\\\\\ x = \cfrac{1\pm\sqrt{49}}{12}\implies x = \cfrac{1\pm 7}{12}\implies x = \begin{cases} \frac{8}{12}\to &\frac{2}{3}\\[1em] -\frac{6}{12}\to &-\frac{1}{2} \end{cases}[/tex]

Answer: IJ = 15

J

15. x

H. I

14

Two congruent Angles —-> Isosceles Triangle

Opposite sides must be congruent.

J

15 15

H. I

14

Answer:

-5x + 3

Step-by-step explanation:

1/3 x - 4x -5/3x + 1/3 x +3

2/3 x -4 -5/3x + 3

3/3x -4x +3

-1 1x -4x + 3

- 5x + 3

:)

Answer:

Do in calculator simple answer

Answer:

.25

Step-by-step explanation: