Natalia cut a pie into eighths. She ate 3/4 of the whole pie. What fraction of the pie
did she eat?

Answer:

U need to just do

[tex] \sqrt{3 \div 4} a {}^{2} [/tex]

Answer:

4[tex]\sqrt{5}[/tex]

Step-by-step explanation:

The segment from a vertex to the side opposite is a perpendicular bisector.

The equilateral Δ is divided into 2 right triangles with legs 8 and 4

let height be h, then using Pythagoras' identity

h² = 4² + 8² = 16 + 64 = 80 ( take the square root of both sides )

h = [tex]\sqrt{80}[/tex] = 4[tex]\sqrt{5}[/tex] ← exact value

Answer:

edfsefesfwefwefwf

Step-by-step explanation:

fwefewfweefwefwefwefewfwefwefwefwef

Answer:

74-2c

Step-by-step explanation:

you know that craig's age is c. You multiply c by two, which is twice craig's age. Then you subtract that from c.

Answer: C.) y = 2x + 5

Answer:

The correct answer is C. y = 2x + 5

Step-by-step explanation:

I got it right. Hope this helps.

Answer:

81.4285714286

Step-by-step explanation:

Answer: Slope intercept form is y=mx+b, where m is slope and b is the y-intercept. We can use this form of a linear equation to draw the graph of that equation on the x-y coordinate plane.

Step-by-step explanation:

Answer:

Slope intercept form is y=mx+b which is m is slope and b is the y-intercept.

Step-by-step explanation:

Answer:

Step-by-step explanation:

here you go mate

step 1

x + 7 < 9  equation

step 2

x + 7 < 9  subtract -7

x+7(-7)<9(-7)

answer

x<2

Answer:

I'm pretty sure it is yes

Step-by-step explanation:

7/1=7. 14/2=7. 21/3=7. 28/4=7. 35/5=7.

Answer:

A. x + 9

Step-by-step explanation:

x² + 5x - 36 = (x + 9) (x - 4)

Answer:

the two numbers are 12 and -1.

Step-by-step explanation:

Let the large number be represented by x and the smaller number by y.

So that;

x = 8y + 20 .................. 1

x + y = 11 ................... 2

From equation 2,

x = 11 - y .......... 3

Substitute equation 3 into equation 1 to have,

11 - y = 8y + 20

11 - 20 = 8y + y

-9 = 9y

divide through by 9 to have,

y = -1

Substitute the value of y in equation 3,

x = 11 - (-1)

  = 11 + 1

  = 12

x = 12

x = 12, y = -1

The two numbers are 12 and -1.

Answer:

11(4-1)

Step-by-step explanation:

11 is the greatist common factor of 44 and 11 so you factor an 11 out of both terms

44/11=4

11/11=4

Therefore the answer is 11(4-1)

Answer:

0.850

Step-by-step explanation:

Answer: 120.7008 Kilometers per Hour

Answer:

The slope of the required line is 1

Step-by-step explanation:

The Slope of a Line

Suppose we know the line passes through points A(x1,y1) and B(x2,y2). The slope can be calculated with the equation:

[tex]\displaystyle m=\frac{y_2-y_1}{x_2-x_1}[/tex]

The graph shows a line whose slope can be calculated by selecting two points it goes through. Let's pick points (0,0) and (2,-2). Thus the slope is:

[tex]\displaystyle m=\frac{-2-0}{2-0}=-1[/tex]

The slope (m') of a line that is perpendicular to the line in the graph can be found by using the equation:

m*m'=-1

Solving for m':

[tex]m'=-\frac{1}{m}=-\frac{1}{-1}=1[/tex]

Thus the slope of the required line is 1

hypothesis is a guess that you test run.

Answer:

71

Step-by-step explanation:

i just want to ask a question sorry for not being helpful

Answer:

Number cube, 5, and 3/16

Answer:

y=1/5x+0

Step-by-step explanation:

Answer:

52% of the shape is green

Step-by-step explanation:

13 out of 25 blocks are shaded green = 13/25

13/25 = 52%

First, we see a rectangle shape with little squares in it. The length is 5 and the width is 4. If we multiply them, we get 20 square units. However, we will use the 20 to solve the question. Also, we see that there are only 3 squares.

3/20

Let's divide the fraction. 3 / 20 is 0.15. We result with 0.15. Now, we multiply  the decimal by 100 to get a percent; we are converting from decimal to percent. As a result, we get 15% as our answer.

3/20 = 0.15 x 100 = 15%

Answer:

5952

Step-by-step explanation:

6000

Answer:

Step-by-step explanation:

Perimeter=a+b+c=6+8+10=24 m

Area=1/2*a*b=1/2*6*8=24 m^2

Answer:

The correct answer is: Option 1: x≤-3

Step-by-step explanation:

Given inequality is:

[tex]-6x-4\geq -2(x-4)[/tex]

First of all, we will distribute -2 into the bracket

[tex]-6x-4\geq -2x+8[/tex]

Then we will add 4 on both sides

[tex]-6x-4+4\geq -2x+8+4\\-6x \geq -2x+12[/tex]

Adding 2x on both sides

[tex]-6x+2x\geq -2x+12+2x\\-4x\geq 12[/tex]

Dividing both sides by 4

[tex]\frac{-4x}{4} \geq \frac{12}{4}\\-x \geq 3[/tex]

As there should be only x on the left side of the inequality we will multiply the inequality with -1.

Multiplying the inequality with -1 reverses the sign of inequality

So,

[tex]x \leq -3[/tex]

Hence,

The correct answer is: Option 1: x≤-3

Answer:

its a scale factor of 4

Step-by-step explanation:

Answer:

the answer is A

Step-by-step explanation:

(a) Applying T to p(t) = 2 - t + t ² gives

T ( p(t) ) = (t - 2) (2 - t + t ²) = -4 + 4t - 3t ² + t ³

(b) T is a linear transformation if for any p(t) and q(t) in P₂ and complex scalars a and b, the image of any linear combination of p and q is equal to the linear combination of the images of p and q. In other words,

T ( a p(t) + b q(t) ) = a T ( p(t) ) + b T ( q(t) )

Let

p(t) = α₀ + α₁ t + α₂ t ²

q(t) = β₀ + β₁ t + β₂ t ²

Compute the images of p and q :

T ( p(t) ) = (t - 2) (α₀ + α₁ t + α₂ t ²)

… = -2α₀ + (α₀ - 2α₁) t + (α₁ - 2α₂) t ² + α₂ t ³

Similarly,

T ( q(t) ) = -2β₀ + (β₀ - 2β₁) t + (β₁ - 2β₂) t ² + β₂ t ³

Then

a T ( p(t) ) + b T ( q(t) ) = a (-2α₀ + (α₀ - 2α₁) t + (α₁ - 2α₂) t ² + α₂ t ³) + b (-2β₀ + (β₀ - 2β₁) t + (β₁ - 2β₂) t ² + β₂ t ³)

… = c₀ + c₁ t + c₂ t ² + c₃ t ³

where

c₀ = -2 (a α₀ + b β₀)

c₁ = a (α₀ - 2α₁) + b (β₀ - 2β₁)

c₂ = a (α₁ - 2α₂) + b (β₁ - 2β₂)

c₃ = a α₂ + b β₂

Computing the image of a p(t) + b q(t) would give the same result; just multiply it by t - 2 and expand. This establishes that T is indeed linear.

(c) Find the image of each vector in the basis for P₂ :

T (1) = (t - 2) × 1 = t - 2

T (t ) = (t - 2) t = t ² - 2t

T (t ²) = (t - 2) t ² = t ³ - 2t ²

Then

[tex]T=\begin{bmatrix}-2&0&0\\1&-2&0\\0&1&-2\\0&0&1\end{bmatrix}[/tex]