NEED HELP ASAP!!!! WILL MARK BRAINLIEST!!!!!

Which statement best compares the rate of change of the two functions?

O The rate of change of both functions is 2

O The rate of change of both functions is 3.

O The rate of change of function A is greater. than the rate of change of function B.

O The rate of change of function B is greater than the rate of change of function A.​

Answer:

C

Step-by-step explanation:

The number of tips that the server gets is dependent on how many customers she serves.

Hope this helps!

Answer:

i dont understand

Step-by-step explanation:

but probably c

Answer:

$20 + $15m ≥ $80

Step-by-step explanation:

He starts off with $20.

He adds $15 each month, so $15m.

He wants to save at least $80, which means greater than or equal to $80. So, you use this symbol: ≥

Put it all together.

$20 + $15m ≥ $80

Hope that helps.

Answer:

3 +9 does not belong because it doesn't equal 10 like the rest of them do.

Answer:

Irrational means it can not be written completely. If there was a line above the last number/the number was infinite, it would be irrational. But because it stops, its not irrational. It can be written as a fraction, so it is rational.

Answer:

I believe the answer is '2 solutions'.

Step-by-step explanation:

Combine each equation, solve the resulting question which comes out as two seperate variables, x = -1.197-- and y = 7.3990. I believe your answer is '2 solutions' because of this.

Answer:

1 solution

Step-by-step explanation:

Answer:

The second one or the last one, but those two are the ones i came up with

Step-by-step explanation:

Answer:

Christina has 30 quarters and 20 dimes.

Step-by-step explanation:

Given that a quarter is worth 0.25 dollars and a dime is worth 0.10 dollars, if Christina has 50 coins and these add up to a total of $ 9.50, to determine the number of quarters and dimes that she has in her possession, the following calculation must be carried out, taking into account that the difference between a quarter and a dime is 0.15 dollars:

50 x 0.25 = 12.5

12.5 - 9.5 = 3

Thus, the difference between the value that Christina has and the value that she would have if all of her coins were quarters is 3 dollars. Thus, since 0.15 x 20 equals 3, of the 50 coins Christina has, 30 are quarters and 20 are dimes.

This is confirmed through the following equation:

30 x 0.25 + 20 x 0.1 = X

7.5 + 2 = X

9.5 = X

Answer: 1) $0.76 per serving of pumpkin pie

2) 64 people

3)

1 1/3 cup sweet potatos

2 tablespoons + 2 teaspoons of white sugar

1 egg

1/4 teaspoon of salt

2 tablespoons of butter

2 tablespoons + 2 teaspoons of milk

1/4 teaspoon of vanillia

2 tablespoons + 2 teaspoons of brown sugar

1 tablespoon + 2 1/3 teaspoons flour

2 tablespoons + 2 teaspoons of peacans

Step-by-step explanation:

1) the total cost of the ingredients needed to prepare a pumpkin pie = $1.50 + ($2.59 / 6) + ($5.99 / 6) + $1.25 + ($3.79 / 2) = $6.075

if we cut 8 servings per pie, then the cost per serving = total cost of the pie/number of servings = $6.075 / 8 = $0.759375 ≈ $0.76 per serving of pumpkin pie

2) 1lb=16oz

24/6=4

4x16=64

Answer:

0.76 per serving of pumpkin pie

2) 64 people

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

–x + 6 = 0.5x

–(4) + 6 =.5(4)=2

-x-.5x=-6

-1.5x=-6

X=4

Answer:

x=4

Step-by-step explanation:I took the test

Answer:

ok im convuzed how do you buy a 90ft tree cuz that sounds fun

Step-by-step explanation:

pls lemme know

Step-by-step explanation:

Answer:

1.358899 or 3-\sqrt{19}

Step-by-step explanation:

either or

Answer:

correct answer it's A

give me a like at least please

Answer:

True

Step-by-step explanation:

Set up the problem in slope intercept i.e y = mx + b. Add 4x to both sides to create y = 4x -2.  Any number or fraction in the m part is the slope. So the slope is 4.

True, the slope of the line y - 4x = -2 is 4.

The equation of a line in slope-intercept form with slope m is,

y = mx + c

Where 'c' is the y-intercept of the line.

Given that,

The equation of a line is,

y - 4x = - 2

Now it can be written in a slope-intercept form as,

y - 4x = - 2

Add 4x on both sides,

y - 4x + 4x = - 2 + 4x

y = 4x - 2

By comparing with slope - intercept of the equation,

Slope (m) = 4

Therefore, the statement is true.

To learn more about the equation of line visit:

https://brainly.com/question/18831322

#SPJ6

Answer:

37.68

Step-by-step explanation:

Answer:

the water rises 50ft  per minute so for 60min you have to multiply 60 x 50 which will be 3000ft in 60mins

Step-by-step explanation:

Answer:

2:30pm

I hope this helps :)

Answer: her daddy was a mummy

Step-by-step explanation:

They will need 4 buses.

The division in mathematics is one kind of operation. In this process, we split the expressions or numbers into the same number of parts.

Given:

For the class field trip,

the fourth grades at Jefferson Elementary School need to take buses.

Each bus fits 55 students,

and there are 200 students in fourth grade.

The number of buses,

= 200/55

= 3.63

≈ 4.

Therefore, the need is for 4 buses.

To learn more about the division;

https://brainly.com/question/13263114

#SPJ2

Answer:

you didnt add the attachment

Answer:

I don't know how to draw it out but...

Step-by-step explanation:

For every 3 kids there is 1 candy bar. For every 2 candy bars there are 6 kids. 2 candy bars divided by 6 kids equals, a third of a candy bar per kid.

Answer: 2

Step-by-step explanation:

7-3/4-2 = 4/2 = 2

Answer:

7x-21

Step-by-step explanation:

Answer:

12.231

Step-by-step explanation:

you add them with the zeros

Answer:

12.231

Step-by-step explanation:

0.031+10+2.2

10.031+2.2

12.231

Answer:

B y= -5/4x+3

Step-by-step explanation:

Answer:

A

explanation:

When something has a constant rate of change, one quantity changes in relation to the other by a constant factor. One concrete example of this is the relation of distance rate and time

Answer:

c is the correct answer i think not sure

Answer:

a+3300=b

5a+3300=6a

minus 5a both sides

a=3300

3300*5=16500

3300*6=19800

16500+19800=36300

$36,300

Answer:

a) [tex]k \approx 0.0602\,\frac{1}{min}[/tex] ([tex]k\approx 6.02\,\frac{\%}{min}[/tex]), b) [tex]k \approx 0.0648\,\frac{1}{min}[/tex] ([tex]k \approx 6.48\,\frac{\%}{min}[/tex]), c) [tex]t_{1/2} \approx 60.274\,days[/tex], d) [tex]t_{1/2}\approx 4.305\,min[/tex], e) [tex]k \approx 0.3\,\frac{1}{min}[/tex] ([tex]k\approx 30\,\frac{\%}{min}[/tex]), f) [tex]k \approx 0.0120\,\frac{1}{min}[/tex] ([tex]k \approx 1.20\,\frac{\%}{min}[/tex]), g) [tex]k \approx 2.876\times 10^{-5}\,\frac{1}{yr}[/tex] ([tex]k \approx 2.876\times 10^{-3}\,\frac{\%}{yr}[/tex])

Step-by-step explanation:

All radioactive isotopes decay exponentially, the mass of the isotope as a function of time ([tex]m(t)[/tex]), measured in grams, is defined by:

[tex]m(t) = m_{o}\cdot e^{-k\cdot t}[/tex] (1)

Where:

[tex]m_{o}[/tex] - Initial mass of the isotope, measured in grams.

[tex]k[/tex] - Decay rate, measured in [tex]\frac{1}{min}[/tex] or [tex]\frac{1}{day}[/tex] or [tex]\frac{1}{yr}[/tex].

[tex]t[/tex] - Time, measured in minutes, days or years.

We define the decay rate in terms of half-life by using the following expression:

[tex]k = \frac{\ln 2}{t_{1/2}}[/tex] (2)

Where [tex]t_{1/2}[/tex] is the half-life of the isotope, measured in minutes or years.

Now we proceed to determine the missing values:

a) Polonium-200 ([tex]t_{1/2} = 11.5\,min[/tex])

[tex]k = \frac{\ln 2}{11.5\,min}[/tex]

[tex]k \approx 0.0602\,\frac{1}{min}[/tex]

b) Lead-194 ([tex]t_{1/2} = 10.7\,min[/tex])

[tex]k = \frac{\ln 2}{10.7\,min}[/tex]

[tex]k \approx 0.0648\,\frac{1}{min}[/tex]

c) Iodine-125 ([tex]k = 0.0115\,\frac{1}{day}[/tex])

[tex]t_{1/2} = \frac{\ln 2}{k}[/tex]

[tex]t_{1/2} = \frac{\ln 2}{0.0115\,\frac{1}{day} }[/tex]

[tex]t_{1/2} \approx 60.274\,days[/tex]

d) Kryption-75 ([tex]k = 0.161\,\frac{1}{min}[/tex])

[tex]t_{1/2} = \frac{\ln 2}{k}[/tex]

[tex]t_{1/2} = \frac{\ln 2}{0.161\,\frac{1}{min} }[/tex]

[tex]t_{1/2}\approx 4.305\,min[/tex]

e) Strontium-79 ([tex]t_{1/2} = 2.3\,min[/tex])

[tex]k = \frac{\ln 2}{2.3\,min}[/tex]

[tex]k \approx 0.3\,\frac{1}{min}[/tex]

f) Uranium-229 ([tex]t_{1/2} = 58\,min[/tex])

[tex]k = \frac{\ln 2}{58\,min}[/tex]

[tex]k \approx 0.0120\,\frac{1}{min}[/tex]

g) Plutonium-239 ([tex]t_{1/2} = 24100\,yr[/tex])

[tex]k = \frac{\ln 2}{24100\,yr}[/tex]

[tex]k \approx 2.876\times 10^{-5}\,\frac{1}{yr}[/tex]