need help pleaseee !

Answer:

The contributions of the following scientist in the DEVELOPMENT OF MAGNETIC THEORY

Explanation:

George Green was the first personality to formulate a mathematical principle of magnetism and electricity and his system created the framework for the work of different scientists such as William Thomson, James Clerk Maxwell, and others. Magnetism is the power exercised by magnets when they drag or deflect each other. Magnetism is produced by the movement of electric charges.

The contributions of James Clerk Maxwell  and Hans Christian Oersted, et al in the DEVELOPMENT OF MAGNETIC THEORY are as follows:

According to the given question, we are asked to show the contributions which the aforementioned scientists had in the development of the magnetic theory.

As a result of this, we can see that James Maxwell first developed this theory in the nineteenth century and the theory was modified by other scientists who made the framework for the electrical system and magnetism.

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Answer:

(a) λ = 0.1224 m

(b) λ = 12500 m = 12.5 km

Explanation:

The wavelength can be calculated with the help of the frequency of the waves. The formula utilized for this purpose is given as follows:

[tex]\lambda = \frac{c}{f}[/tex]

where,

c = speed of light = 3 x 10⁸ m/s

λ = wavelength of the wave

f =  frequency of the wave

(a)

f = 2.45 GHz = 2.45 x 10⁹ Hz

λ = ?

Therefore,

[tex]\lambda = \frac{3\ x\ 10^{8}\ m/s}{2.45\ x\ 10^{9}\ Hz}\\[/tex]

λ = 0.1224 m

(b)

f = 24 KHz = 2.45 x 10³ Hz

λ = ?

Therefore,

[tex]\lambda = \frac{3\ x\ 10^{8}\ m/s}{24\ x\ 10^{3}\ Hz}\\[/tex]

λ = 12500 m = 12.5 km

Answer:

t = 3 [s]

Explanation:

To solve this problem we must use the following equation of kinematics.

[tex]v_{f}=v_{o}-g*t[/tex]

where:

Vf = final velocity [m/s]

Vo = initial velocity = 15 [m/s]

g = gravity acceleration = 10 [m/s²]

t = time [s]

Now replacing we have:

[tex]0 = 15 -10*t\\10*t=15\\t= 1.5[s][/tex]

Note: In the equation above the gravity acceleration is negative, because the movement of the ball bearing is pointing againts the gravity acceleration.

The time calculated is only when the ball bearing reaches the highest elevation, and it will take the same time for descending, therefore the total time is:

t = 1.5 + 1.5 = 3 [s]

Answer:

       d = 6 i^   m

Explanation:

This is an exercise in kinematics, where the position vector is the displacement of the body from one point to another.

In this case we are told that for t = 0 the worm is at x₀ = 3m and with velocity starts from zero, after t = 1 s it is at x₁ = 9m and with a velocity of

v₁ = 5 m / s

They ask what is the displacement for the time of 1 s

               d = x₁ - x₀

               d = 9 -3 m

               d = 6 m

Bold indicates vector, displacement vector is

             d = 6 i ^ m

Answer:False

Explanation:The Earth rotates faster at the equator than at the poles.

Answer:

600 Kg

Explanation:

From the question given above, the following data were obtained:

Extention (∆x) = 30 cm

Spring constant (K) = 200 N/cm Acceleration due to gravity (g) = 10 m/s²

Mass (m) of object =?

Next, we shall determine force exerted. This can be obtained as follow:

Extention (∆x) = 30 cm

Spring constant (K) = 200 N/cm

Force (F) =?

F = K∆x

F = 200 × 30

F = 6000 N

Finally, we shall determine the mass of the object. This can be obtained as follow:

Acceleration due to gravity (g) = 10 m/s²

Force (F) = 6000 N

Mass (m) of object =?

F = mg

6000 = m × 10

Divide both side by 10

m = 6000 / 10

m = 600 Kg

Thus, the mass of the object is 600 Kg

Answer:

Its A. door because liquids expand better than solids

Answer:

0.25 kg

Explanation:

p = mv

2 = m(8)

2/8 = m(8)/8 *cancels

m = 1/4 OR 0.25 kg

Answer:

Explanation:

From the given information;

Let assume that:

the wheel radius = 15 inches

the driveline slippage = 3%;  &

the gear reduction ratio (overall) = 2.5 to 1

So; using the equation:

[tex]v_1= \dfrac{2 \pi r n_o (1 -i)}{\varepsilon_o}[/tex]

[tex]v_1= \dfrac{2 \times 3.14 \times \dfrac{15}{12} \times \dfrac{85}{100} (1 -0.03)}{2.5}[/tex]

[tex]v_1= \dfrac{2 \times 3.14 \times \dfrac{15}{12} \times \dfrac{85}{100} (0.97)}{2.5}[/tex]

[tex]v_1 = 126.92 \ fp^3[/tex]

[tex]frl = 0.01 ( 1+ \dfrac{v}{147}) \ if \ v \ is \ ft/sec[/tex]

[tex]frl = 0.01 \Bigg( 1+ \dfrac{\dfrac{126.92 +(20)1.47 }{2} }{147}\Bigg)[/tex]

[tex]S = \dfrac{v_b ( v_1^r-v_2^r)}{2g(n_b \mu + frl \pm sin \ y}[/tex]

where;

[tex]\mu = 0.6[/tex]

[tex]291 = \dfrac{1.64( 126.92^2-29.9^2)}{64.4(n_b \times 0.6 +0.01532 +0.03}[/tex]

[tex]n_b = 1.33 \to which \ is \ not \ possible[/tex]

However;

[tex]n_b \mu = 1.33(0.6) = 0.80[/tex]

[tex]\mu = 0.9 \to[/tex] if the car's anti-clock breaking system did not fail

Thus;

[tex]n_b (0.9) = 0.80[/tex]

[tex]n_b =\dfrac{ 0.80}{(0.9) }[/tex]

[tex]n_b = 0.89[/tex]

Hence, the distance is possible if the anti-clock breaking system did not fail.

Answer:  Choice A) 2 meters per second

=======================================================

Explanation:

The smaller ball has momentum of

p = m*v

p = (1 kg)*(4 m/s)

p = 4 kg*m/s

All of this momentum transfers into the larger ball because the smaller ball comes to a complete stop.

For the larger ball, we have p = 4 and m = 2. Let's find v.

p = m*v

4 = 2*v

4/2 = v

2 = v

v = 2 m/s which is why the answer is choice A

The larger ball moves at a speed of 2 meters per second. The speed is cut in half compared to the smaller ball because the larger ball has more inertia (aka more mass), and therefore it takes more energy to move it. If you apply the same energy to each, then the smaller object moves faster.

Answer:

TRUE

Explanation:

IM SMART

Answer:

Stay  Safe! ,God bless you . The answer is false ,

Explanation:

Answer:

The rotation frequency required is 23.78 RPM

Explanation:

Given;

radial acceleration, a = 32.7 m/s²

length of the beam, r = 5.29 m

The linear velocity is calculated as;

[tex]a = \frac{v^2}{r} \\\\v^2 = ar\\\\v = \sqrt{ar}[/tex]

where;

v is linear velocity

The angular velocity is calculated as;

[tex]\omega = \frac{v}{r} \\\\Recall, v = \sqrt{ar} \\\\Then, \omega = \frac{\sqrt{ar}}{r}} \\\\ \omega = \frac{\sqrt{32.7 \times5.29}}{5.29}\\\\\omega = 2.49 \ rad/s\\\\Angular \ frequency \ is \ calculated \ as;\\\\\omega = 2\pi f\\\\f = \frac{\omega}{2\pi} \\\\f = \frac{2.49}{2\pi} \\\\f = 0.396 \ rev/s\\\\f = 23.78 \ rev/min[/tex]

Therefore, the rotation frequency required is 23.78 RPM

Answer:

[tex]12\:\mathrm{N}[/tex]

Explanation:

Force is given by the equation [tex]F=ma[/tex].

Plugging in given values, we have:

[tex]F=ma=2.6\cdot 4.5=11.7=\fbox{$12\:\mathrm{N}$}[/tex] (two significant figures).

Answer:

(a) 6.67 m/s  (b) 3.33 m/s

Explanation:

if i understood your question correctly, the jogger goes 150m east before going in the opposite direction west for 50m. (see diagram)

in avg speed, we use the total distance (150m + 50m = 200m)  and total time (30s)

v = d/t =200/30 =6.67 m/s

in avg velocity, we use the total displacement  (150m - 50m = 100m) and total time (30s)

v= d/t = 100/30 = 3.33 m/s

Answer:

From plants and animals that die and fall to forests floor

Explanation:

Hope it helps

Mark brainliest

Answer:

the current value is [tex]0.335 \mu A[/tex]

Explanation:

The computation of the value of the current is given below:

[tex]z_i = I_s e^{\frac{0.7}{ut} }= 10^{-3}\\\\Z_z = I_s e^{\frac{0.5}{ut} }\\\\\frac{Z_z}{Z_i}= \frac{Z_z}{10^{-3}} = e^{\frac{0.5\times 0.7}{0.025} }\\\\= 0.335 \mu A[/tex]

Hence, the current value is [tex]0.335 \mu A[/tex]

Answer:

See the answer below

Explanation:

The elastic potential energy can be calculated by means of the following equation:

[tex]E_{el}=\frac{1}{2} *k*x^{2}[/tex]

where:

Eel = elastic energy = 1500 [J]

k = spring constant = 45000 [N/m]

x = extension [m]

[tex]1500=\frac{1}{2} *45000*x^{2} \\3000=45000*x^{2} \\x=\sqrt{0.06666}\\x=0.258[m] = 25.8 [cm][/tex]

Answer:

Second and Last Option Are Correct

Explanation:

Answer:

45.9m

Explanation:

Given parameters:

Mass of roller coaster train  = 12000kg

Velocity  = 30m/s

Unknown:

Tallest hill the roller coaster train can reach = ?

Solution:

Kinetic energy is the energy due to the motion of body.

Potential energy is the energy due to the position of a body.

So;

             [tex]\frac{1}{2}[/tex]  m v²    =  mgh  

 m is the mass, g is the acceleration due to gravity, h is the height and v is the velocity

                 m v²   = 2mgh

                     v²   = 2gh

                   h  = [tex]\frac{v^{2} }{2g}[/tex]  

                  h  = [tex]\frac{30^{2} }{2 x 9.8}[/tex]   = 45.9m  

Answer:

The wagon will move to the right.

Explanation:

From the question given above, the following data were obtained:

Force applied to the left (Fₗ) = 10 N

Force applied to the right (Fᵣ) = 30 N

Direction of the wagon =.?

To determine the direction in which the wagon will move, we shall determine the net force acting on the wagon. This can be obtained as follow:

Force applied to the left (Fₗ) = 10 N

Force applied to the right (Fᵣ) = 30 N

Net force (Fₙ) =?

Fₙ = Fᵣ – Fₗ

Fₙ = 30 – 10

Fₙ = 20 N to the right

From the calculations made above, the net force acting on the wagon is 20 N to the right. Hence the wagon will move to the right.

Answer:

Explanation:

These tectonic plates rest upon the convecting mantle, which causes them to move. The movements of these plates can account for noticeable geologic events such as earthquakes, volcanic eruptions, and more subtle yet sublime events, like the building of mountains.

Answer:

Tectonic plates recurring over and over again cause a rupture in the Earth's crust. This agitates the magma in volcanoes, causing the volcano to erupt.

Explanation:

Answer:

Open system, because an external force is applied to the car that causes it to accelerate.

Explanation:

In this case, the system under study is the toy car. A system may be open or closed.

An open system is acted upon by external forces but a closed system is not acted upon by any external force.

Since an external force acted on the toy car causing it to accelerate, then it is an open system.

Answer:

(d)

Explanation:

John- convex mirror

Tom - plane mirror

Answer:

(d) convex mirror and plane mirror

Explanation:

A plane mirror forms an image that is : virtual { behind the mirror } , image and object are at the same distance from the flat mirror, image is upright and image size is the same as object size. Tom's image.

A concave mirror form both real and virtual images. When a concave mirror is very near to an object , the image is virtual and magnified. When the distance between object and mirror is increased, a real image is formed and the size is reduced.

In  a convex mirror, the image formed is smaller than the object, it is upright and is located behind the mirror. The image is virtual. John's image.

Answer:

20 N

Explanation:

From the question given above, the following data were obtained:

Mass (m) of block = 3 Kg

Spring constant (K) = 250 N/m

Extention (e) = 8 cm

Force (F) =?

Next, we shall convert 8 cm to m. This can be obtained as follow:

100 cm = 1 m

Therefore,

8 cm = 8 cm × 1 m / 100 cm

8 cm = 0.08 m

Thus, 8 cm is equivalent to 0.08 m.

Finally, we shall determine the force when the block is at 8 cm (i.e 0.08 m). This can be obtained as follow:

Spring constant (K) = 250 N/m

Extention (e) = 0.08 m

Force (F) =?

F = Ke

F = 250 × 0.08

F = 20 N

Thus, the force is 20 N.