Newton’s second law of motion is also known as law of _____

Answer:

a = 30 m/s²

Explanation:

Given: 250 kg, 7500N    

To find: Acceleration (a)    

Solution: To find the acceleration (A), divide the force by the weight  

A = F ÷ m

=  7500 ÷  250

= 30 m/s²

Newtons are derived units, equal to 1 kg-m/s². In other words, a single Newton is equal to the force needed to accelerate one kilogram one meter per second squared.

Answer:

The arrangement of the following from loudest to softest include:

crowd at sporting event

airplane

rainfall

whisper

Explanation:

When it comes to the arrangements, the pitch of the noise which emerge is what was considered. For example, crowd at sporting event has the highest pitch especially during football matches followed by the airplane sounds during its take-off and landing in the airports. As for whisper, it happens to be the one with softest sound.

Answer:

Airplane. 1

Whisper. 4

Crowd at sporting event. 2

Rainfall. 3

Explanation:

hope this helps

Answer:

[tex]\frac{n}{t} = 30\ photons/s[/tex]

Explanation:

The radiated power can be given in terms of the wavelength as follows:

[tex]Rasiated\ Power = \frac{nE}{t} = \frac{nhc}{\lambda t}[/tex]

where,

Radiated Power = 1.2 x 10⁻¹⁷ W

n = no. of photons = ?

h = plank's constant = 6.625 x 10⁻³⁴ J.s

c = speed of light = 3 x 10⁸ m/s

λ = wavelength = 500 nm = 5 x 10⁻⁷ m

t = time

Therefore,

[tex]1.2\ x\ 10^{-17}\ W = \frac{n(6.625\ x\ 10^{-34}\ J.s)(3\ x\ 10^8\ m/s)}{(5\ x\ 10^{-7}\ m)(t) }\\\\\frac{n}{t} = \frac{1.2\ x\ 10^{-17}\ W}{3.975\ x\ 10^{-19}\ J}\\\\\frac{n}{t} = 30\ photons/s[/tex]

Answer:

Sorry I I’m a little lost

Explanation:

Answer:

hmm the relation ship would be bad 1 because its not cooperating because I would have to do allot of force to pick up the mass with a tiny string, what an idiot, 2nd the distance is far now that its not a good relationship

Explanation:

hope this helps old pal ( :

Question 1.

now, we know :

=》

[tex]p.e = mgh[/tex]

=》

[tex]67500 = 4500 \times 10 \times h[/tex]

=》

[tex]67500 = 45000 \times h[/tex]

=》

[tex]h = \dfrac{67500}{45000} [/tex]

=》

[tex]h = 1.5 \: m[/tex]

note : if we take acceleration due to gravity as 9.8, then height = 1.53 m

Question 2.

we know,

=》

[tex]k.e = \dfrac{1}{2} mv {}^{2} [/tex]

=》

[tex]63000 = \dfrac{1}{2} \times 4500 \times {v}^{2} [/tex]

=》

[tex] {v}^{2} = \dfrac{63000 \times 2}{4500} [/tex]

=》

[tex] {v}^{2} = 28[/tex]

=》

[tex]v = \sqrt{28} [/tex]

=》

[tex]v = 2 \sqrt{7} \: \: ms {}^{ - 1} [/tex]

or

=》

[tex]5.29 \: \: ms {}^{ - 1} [/tex]

Answer:

The impulse experienced by the car is 52,500 kg.m/s.

Explanation:

Given;

mass of the car, m = 1500 kg

initial velocity of the car, u = 55 m/s

final velocity of the car, v = 90 m/s

The impulse experienced by the car is the change in linear momentum, calculated as follows;

J = ΔP = mv  - mu

ΔP = m(v - u)

ΔP = 1500(90 - 55)

ΔP = 52,500 kg.m/s

Therefore, the impulse experienced by the car is 52,500 kg.m/s.

Answer:

modern world

Explanation:

Answer:

   q = 224 mm,   h ’= - 98 mm, real imagen

Explanation:

For this exercise let's use the constructor equation

        [tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}[/tex]

where f is the focal length, p and q are the distance to the object and the image respectively.

In a mirror the focal length is

        f = R / 2

indicate us radius of curvature is equal to the diameter of the eye

       R = 3,50  10² mm

       f = 3.50 10² /2 = 1.75 10² mm

they also say that the distance to the object is p = 0.800 10³ mm

        1 / q = 1 / f - 1 / p

        1 / q = 1 / 175 - 1 /800

        1 / q = 0.004464

         q = 224 mm

to calculate the size let's use the magnification ratio

          m = [tex]\frac{h'}{h} = - \frac{q}{p}[/tex]

          h '= [tex]- \frac{q}{p} \ h[/tex]

          h ’= - 224 350 / 800

          h ’= - 98 mm

in concave mirrors the image is real.

Answer: I may not have the awser but

Explanation: Try calculating 8.932 times

10^22 kg

Answer:

F = 2.68 x 10²³ N

Explanation:

The force between lo and Jupiter is given by Newton's Gravitational Formula:

[tex]F = \frac{Gm_1m_2}{r^2} \\[/tex]

where,

F = Force = ?

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ Nm²/kg²

m₁ = mass of lo = 8.932 x 10²² kg

m₂ = mass of Jupiter = 1.9 x 10²⁷ kg

r = distance between lo and Jupiter = 4.22 x 10⁸ m

Therefore,

[tex]F = \frac{(6.67\ x\ 10^{-11}Nm^2/kg^2)(8.932\ x\ 10^{22}\ kg)(1.9\ x\ 10^{27}\ kg)}{(4.22\ x\ 10^8\ m)^2}[/tex]

F = 2.68 x 10²³ N

Answer:

Explanation:

Hydrant

Answer:

he would have to run at a 7 and a half mile to get 8 miles in an hour

Explanation:

Answer:

7.5 minutes

Explanation:

We know that there are 60 minutes in an hour. So, we can say that Rogan can run 8 miles per 60 minutes. Now, we can create an equation to solve for how many minutes it would take per mile.

8/60 = 1/x

x = 7.5

So, it would take Rogan approximately 7.5 minutes to travel 1 mile.

Answer:

Q_c = Q_abs

Explanation:

You are asked to describe the process when placing a hot block in cold water.

The first thing to do is put all the quantities in the same units

block temperature      T_bloque = T_h = 300 K = 300 -273 = 27ºC

water temperature     T_water = T_c = 15ºC

* initially the block cools down decreasing its temperature

* the water temperature increases

* the equilibrium is established when the thermal energy of the two bodies is equal, therefore they have the same temperatures T_f

* Conservation of energy requires that the energy released by the hot block is equal to the energy absorbed by the cold body (water)

transferred thermal energy Q_c = m_block ce_block (T_h-T_f)

absorbed thermal energy Q_abs = m_agua ce_agua (T_f - T_c)

* if we subtract the energy transferred and the absorbed gives zero, therefore the net energy transferred is zero

                               Q_c = Q_abs

Answer:

constructive interference.

Explanation:

Electromagnetic waves is a propagating medium used in all communications device to transmit data (messages) from the device of the sender to the device of the receiver.

Generally, the most commonly used electromagnetic wave technology in telecommunications is radio waves.

Radio waves can be defined as an electromagnetic wave that has its frequency ranging from 30 GHz to 300 GHz and its wavelength between 1mm and 3000m.

In this scenario, an experiment is conducted by Pierce in which waves collide in a way that the energy increases. Thus, this is an example of constructive interference i.e constructive interference has occurred.

An interference occurs when two pair of waves such as sound and light waves pass through each other i.e crossing each other's path while traveling through the same medium or space.

Answer:

constructive interference.

Explanation:

Answer:

Peer Review

Explanation:

When scientist check other scientists the process is dubbed "peer review".

Answer:

0.16 A

Explanation:

V = IRtotal

24V = I(100 + 40 + 10)

I = 0.16 A

Answer: 0.16 is correct

Explanation:

Answer:

1 gram

Explanation:

Formula -- (density / mass)

3 x 3 x 3 = 27.

27g / 27 g =

=1

-I hope this helps, have a good day/night if so.

Answer:

A car exerts a force on a bug as they collide and the bug exerts an equal force on the car.

Explanation:

Newton's third law of motion states that for every action there is an equal and opposite reaction.

Action-reaction force pairs make it possible for fishes to swim, birds to fly, cars to move etc,

Furthermore, take for example, While driving down the road, a firefly strikes the windshield of a car (Action) and makes a quite obvious mess in front of the face of the driver (Reaction) i.e The firefly hit the car and the car hits the firefly.

Hence, the statement which best describes an interacting force pair represented by the third law of motion is, a car exerts a force on a bug as they collide and the bug exerts an equal force on the car.

The ultimately implies that, in every interaction, there is a pair of forces acting on the two interacting objects in this case, the car and bug. The size of the force on the car equals the size of the force on the bug. These two forces are called action and reaction forces and are the subject of Newton's third law of motion.

I'm not sure but I think that if objects are closer (less distant), than the gravitational pull is stronger. I'm sorry if I couldn't really help I remember learning about this kind of.

Answer:

The magnitude of the impulse is 1.4 Ns in the West direction.

Explanation:

The impulse equation is given by:

[tex]\Delta p=m\Delta v[/tex]

Where:

So we will have:

[tex]\Delta p=0.140(25-15)[/tex]

[tex]\Delta p=1.4\: Ns[/tex]

Therefore, the magnitude of the impulse is 1.4 Ns in the West direction.

I hope it helps you!

Answer:

it makes most recourses and gives us most of a materials

Explanation:

Answer:

The argument make the assumption that;

(A) The exploration of Mars will be carried out by people travelling in spacecraft and not by robots alone

Explanation:

The argument is made for the importance of a space station where astronauts live for an appreciable time to aid in the understanding of human capacities for living in the space so as to increase the successful space travel human to Mars, which is a distance further than the Moon and therefore, will require sufficient time travel

Answer:

No the statement is incorrect.

Explanation:

Mathematically, force F experience of a charge particle of magnitude q in an uniform electric field E is given as

F = E/q

In uniform electric field is where the intensity of electric field remains same throughout. However, from the above equation it is clear that force experience by the charge particle also depends upon the magnitude of charge particle as well. So, with change in charge particles the force experienced by it also changes.

Answer:

W = 30 N

Explanation:

Applying the summation of torques about the wedge for equilibrium, taking the clockwise direction as negative. Since the ruler is balanced horizontally about the wedge. Therefore, the summation of all torques acting about the wedge must be equal to zero.

[tex](70\ N)(40\ cm - 10\ cm)-(30\ N)(50\ cm-40\ cm)-(W)(100\ cm - 40\ cm) = 0\\W(60\ cm) = (70\ N)(30\ cm)-(30\ N)(10\ cm)\\\\W = \frac{1800\ N.cm}{60\ cm}[/tex]

W = 30 N

Answer:

What the quote means is that if a person contains so much hatred they would be able to light up the whole world beacuse they hate so much and love so little.

Answer:

Explanation: lifehack.org explains this quote as, "Passions or emotions can fire up enough energy to upset events. It is better to be able to deal with negative emotions and make them count in a positive way. Rather than allow your hate to be dominant, try and focus on making your love an umbrella above everything you do."

Answer:

The distance travelled on the freeway is 149.5 miles.

Explanation:

The school bus travels on the freeway at constant speed. According to the statement, we need to calculate the distance travelled by the vehicle by means of the following formula:

[tex]x = v\cdot t[/tex] (1)

Where:

[tex]x[/tex] - Traveled distance, in miles.

[tex]v[/tex] - Speed, in miles per hour.

[tex]t[/tex] - Time, in hours.

If we know that [tex]v = 65\,\frac{mi}{h}[/tex] and [tex]t = 2.3\,h[/tex], then the distance travelled by the school bus is:

[tex]x = v\cdot t[/tex]

[tex]x = \left(65\,\frac{mi}{h} \right)\cdot (2.3\,h)[/tex]

[tex]x = 149.5\,mi[/tex]

The distance travelled on the freeway is 149.5 miles.

None

Friction in Volleyball

Frication plays a huge role in every aspect of our lives; it can play a negative or positive role. In volleyball there are various types of friction that have positive influences on the way the game is played and there are others that play a negative role in the way the game is played.

Positive friction in volleyball.

In volleyball the aim of the game is to strike a ball into play that your opponent cannot return or finds it difficult to return. A friction force that makes this possible is the friction of the air on the ball, for example when a player hits a ball with topspin into play, the friction of the air on the ball makes it spin faster than it otherwise would. Topspin makes a ball harder to pick-up and pass to the setter.  

Another force that is present is the ball itself, if there was no friction it would be virtually impossible to pass set, or hit the ball, the ball would just slip through your arms or hands.

When jumping a player also uses the frictions of their feet on the floor to gain a higher jump to strike the ball at maximal height, if this didn't exist players would be slipping and sliding around all over the court.  

Negative friction in volleyball.

Friction also plays a negative part in the game of volleyball, when a player dives for a ball the friction of the court on their skin causes court burn or friction burn. Although the friction of the rubber soles of shoes on the court is a positive it can also be a negative, if there is too much friction players can become injured from the sudden stopping that the friction can cause. Some injuries that can result from this would be hyperextensions of the knees and or ankle injuries.