does the nitro group on the pyridine ring make the ring more electron rich or more electron deficient
Answer:
more electron deficient
Explanation:
The nitro group is an electron withdrawing group. It withdraws electrons from the pyridine ring by resonance.
This electron withdrawal by resonance makes the pyridine ring less electron rich or more electron deficient.
Hence, the nitro group makes the pyrinde ring more electron deficient
how will you know whether the crystallization point is reached
Answer:
Place a glass rod in the solution, if the crystallisation point has been reached, you should notice small crystals formed on it.
decay mode for cesium-137
Answer:
Beta decay
Explanation:
Radioactive decay changes one nucleus to another. The type of decay that a particular nucleus undergoes depends on the number of neutrons and protons present in such nucleus.
Radioactive decay tends to lead to the attainment of a stable neutron/proton ratio.
The decay mode for cesium-137 is beta decay. The beta decay of cesium-137 yields Barium-137.
Beta decay decreases the neutron - proton ratio.
Which nuclear equation represents a spontaneous decay?
Answer:A
Explanation:
1. [tex]^{222}Rn_{86}[/tex] → [tex]^{218}Po_{84} + ^{4}He_{2}[/tex]
What is a spontaneous decay?
Spontaneous fission (SF) is a form of radioactive decay where an atom's nucleus splits into two smaller nuclei and generally one or more neutrons.Out of the given options, only option 1. [tex]^{222}Rn_{86}[/tex] → [tex]^{218}Po_{84} + ^{4}He_{2}[/tex] is an example of spontaneous decay since an atom nucleus is splitting into two daughter nuclei's.Spontaneous decay would refer to whether or not decay was stimulated by bombardment with neutrons or alphas while random decay refers to the selection of which nuclei actually decayLearn more:
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In the laboratory a student finds that it takes 103 Joules to increase the temperature of 12.6 grams of solid diamond from 22.4 to 39.4 degrees Celsius. The specific heat of diamond calculated from her data is
Answer:
The correct solution is "[tex]0.480 \ J/g^{\circ}C[/tex]".
Explanation:
Given:
q = 103 J
Mass,
m = 12.6 grams
Temperature,
[tex]T_1=22.4[/tex]
[tex]T_2=39.4[/tex]
[tex]\Delta T=T_2-T_1[/tex]
[tex]=39.4-22.4[/tex]
[tex]=17^{\circ}C[/tex]
Now,
⇒ [tex]C=\frac{q}{m\times \Delta T}[/tex]
⇒ [tex]=\frac{103}{12.6\times 17}[/tex]
⇒ [tex]=\frac{103}{214.2}[/tex]
⇒ [tex]=0.480 \ J/g^{\circ}C[/tex]
200 grams of iron (III) chloride reacts with ammonium carbonate [(NH4)2CO3] in the following equation.
FeCl3 + (NH4)2CO3 ---------> NH4Cl + Fe2(CO3)3
The number of grams of iron (III) carbonate Fe2(CO3)3 that will be produced is _ grams.
a
181
b
198
c
229
d
395
Answer. First things first... Balance the Chemical Equation
2FeCl3 + 3(NH4)2CO3 ---------> 6NH4Cl + Fe2(CO3)3
Its balanced Now.
200g of FeCl3 ---Given this... We can get jts reacting Moles
Mole = Mass/Molar Mass
Molar Mass of FeCl3 = 56 + (35.5)x3=162.5gmol-¹
Mole=200/162.5 =1.231moles of FeCl3
From the equation of Reaction
When 2mole of FeCl3 reacts.... It produces 1mole of Iron III carbonate [Fe2(CO3)3]
Since Mole ratio of reaction between both is 2:1
Therefore When 1.231moles of FeCl3 react....
1.231/2 moles of Fe2(CO3)3 will be produced.
= 1.231/2 = 0.616moles.
0.616Moles of Fe2(CO3)3 will be produced
Recall MASS =MOLE X MOLAR MASS
MOLAR MASS OF FE2(CO3)3= 56(2) + (60)(3)=292gmol-¹
MASS = 0.616 x 292 =179.872g ~ 180g of Fe2(CO3)3 Will Be Produced.
OPTION A SEEMS TO BE THE CLOSEST. THAT SHOULD BE OUR ANSWER. I MAY HAVE MISSED IT A BIT BECAUSE OF SOME APPROXIMATIONS.
BYE!
Answer:
[tex]FeCl₃ + (NH₄)₂CO₃ → NH₄Cl + Fe₂(CO₃)₃[/tex]
first balance the chemical equation
first balance the chemical equation[tex]2FeCl₃ + 3(NH₄)₂CO₃ → 6NH₄Cl + Fe₂(CO₃)₃[/tex]
2FeCl₃=2*162=324g
6NH₄Cl=6*53.5=321g
324 g of FeCl₃ gives 321 g of NH₄Cl
200g of FeCl₃ gives 321/324*200=198.14 g of NH₄Cl
in nearest value it is 198g/mole
The number of grams of ammonium chloride (NH4Cl) that will be produced is C.198___ grams.
Which of the following mixtures will react the fastest?
a. Iron DUST and 2 moles HCI
b. Iron DUST and 4 moles HCI
c. Solid Iron CUBE and 2 moles HCI
d. Solid Iron CUBE and 4 moles HCI
Answer:
I think the answer would be A.
what is the atomic mass of an element with 40 protons 40 electrons and 46 neutrons
Answer:
The 40 represents the atomic number and the number of proton in Zirconium. The "Zr" on the tile is the symbol of the elementp
Calculate the percent composition by mass of iron in Fe(NO3)3
Answer:
It's 23.14 percent
Explanation:
First, the mass of all the elements are:
N = 14
O = 16
Fe = 56
In this molecule you have 3 atoms of N, and 9 atoms of O, so:
3•14 = 42
16•9 = 144
The whole mass of the molecule is:
56 + 42 + 144 = 242
242/100 = 2.42, so 1% is 2.42
56/2.42 = 23.14%
How many moles would be in 85.OmL of 0.750M KOH?
Answer: There are 0.0637 moles present in 85.0 mL of 0.750 M KOH.
Explanation:
Given: Volume = 85.0 mL (1 mL = 0.001 L) = 0.085 L
Molarity = 0.750 M
It is known that molarity is the number of moles of solute present in liter of a solution.
Therefore, moles present in given solution are calculated as follows.
[tex]Molarity = \frac{moles}{Volume (in L)}\\0.750 M = \frac{moles}{0.085 L}\\moles = 0.0637 mol[/tex]
Thus, we can conclude that there are 0.0637 moles present in 85.0 mL of 0.750 M KOH.
how many moles of Carbon are in 3.06 g of Carbon
Answer:
[tex]\boxed {\boxed {\sf 0.255 \ mol \ C }}[/tex]
Explanation:
If we want to convert from grams to moles, the molar mass is used. This is the mass of 1 mole. They are found on the Periodic Table as the atomic masses, but the units are grams per mole (g/mol) instead of atomic mass units (amu).
Look up the molar mass of carbon.
Carbon (C): 12.011 g/molSet up a ratio using the molar mass.
[tex]\frac {12.011 \ g \ C}{ 1 \ mol \ C}[/tex]
Since we are converting 3.06 grams to moles, we multiply by that value.
[tex]3.06 \ g \ C*\frac {12.011 \ g \ C}{ 1 \ mol \ C}[/tex]
Flip the ratio. This way, the ratio is still equivalent, but the units of grams of carbon cancel.
[tex]3.06 \ g \ C* \frac{1 \ mol \ C}{12.011 \ g\ C}[/tex]
[tex]3.06 * \frac{1 \ mol \ C}{12.011 }[/tex]
[tex]\frac {3.06}{12.011 } \ mol \ C[/tex]
[tex]0.25476646 \ mol \ C[/tex]
The original measurement of grams (3.06) has 3 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place.
0.25476646The 7 in the ten-thousandth place tells us to round the 4 up to a 5.
[tex]0.255 \ mol \ C[/tex]
3.06 grams of carbon is approximately 0.255 moles of carbon.
Equal masses of gaseous N2 and Ar are placed in separate flasks of equal volume at the same temperature. Tell whether each of the following statements is true or false. a. There are more molecules of N2 present than atoms of Ar. Blank 1 b. The pressure is greater in the Ar flask. Blank 2 c. The N2 molecules collide more frequently with the walls of the flask than do the Ar atoms.
Answer:
c. The N2 molecules collide more frequently with the walls of the flask than do the Ar atoms.
Explanation:
The statements are:
a. There are more molecules of N2 present than atoms of Ar. FALSE. Because 1 mol of molecules of N2 = 28g and 1 mol of molecules of Ar = 40g. As there are equal MASSES, you will have more molecules of N2 than Ar molecules
b. The pressure is greater in the Ar flask. FALSE
Because pressure is directly proportional to amount of molecules. As molecules N2 > Molecules Ar. The pressure is greater in N2 flask
c. The N2 molecules collide more frequently with the walls of the flask than do the Ar atoms. TRUE
The collision probability of N2 is higher because there are more molecules presents
Im stuck on these two questions anyone have the right answer?
List five general properties of organic
Compound
Answer:
Five general properties of organic compounds:
Organic compounds include complex structures and high molecular weights.Organic compounds have low melting points and boiling points. They are volatile in nature. They are generally insoluble in water but soluble in organic solvents. They are poor bad conductors of electricity.Write the equilibrium expression for the following reactions:
1. 4NH3 (g) + 5O2 (g) ↔ 4NO (g) +6H2O (g)
2. ZrI4 (s) ↔ Zr (s) + 2I2 (g)
3. NH3 (g) + HCl (g) ↔ NH4Cl (s)
Answer:
1. Kc = [NO]⁴ [H₂O]⁶ / [NH₃]⁴ [O₂]⁵
2. Kc = [I₂]²
3. Kc = 1/[NH₃] [HCl]
Explanation:
The equilibrium constant (Kc) is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactant raised to their stoichiometric coefficients. It only includes gases and aqueous species.
1. 4 NH₃(g) + 5 O₂(g) ↔ 4 NO(g) + 6 H₂O(g)
Kc = [NO]⁴ [H₂O]⁶ / [NH₃]⁴ [O₂]⁵
2. ZrI₄(s) ↔ Zr(s) + 2 I₂(g)
Kc = [I₂]²
3. NH₃(g) + HCl(g) ↔ NH₄Cl(s)
Kc = 1/[NH₃] [HCl]
Boron has five protons and six neutrons. What is the atomic mass of boron?
A. 11
B. 10
C. 12
D. 1
Answer:
11
Explanation:
becauase 5 +6
Under the right conditions aluminum will react with chlorine to produce aluminum chloride.
2 Al + 3 Cl2 - 2 AlCl3
How many grams of aluminum are needed to react completely with 11.727 liters of chlorine?
Answer:
[tex]m_{Al}=9.42gAl[/tex]
Explanation:
Hello there!
In this case, according to the given chemical reaction:
2 Al + 3 Cl2 --> 2 AlCl3
Whereas there is a 2:3 mole ratio of aluminum to chlorine; it will be possible for us to calculate the required grams of aluminum by using the equality 22.4 L = 1 mol, the aforementioned mole ratio and the atomic mass of aluminum (27.0 g/mol) to obtain:
[tex]m_{Al}=11.727LCl_2*\frac{1molCl_2}{22.4LCl_2}*\frac{2molAl}{3molCl_2} *\frac{27.0gAl}{1molAl} \\\\m_{Al}=9.42gAl[/tex]
Regards!
C. Balance these fossil-fuel combustion reactions. (1 point)
The question is incomplete. The complete question is :
C. Balance these fossil-fuel combustion reactions. (1 point)
C8H18(g) + 12.5O2(g) → ____CO2(g) + 9H2O(g) + heat
CH4(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat
C3H8(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat
C6H6(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat
Solution :
C8H18(g) + 12.5O2(g) → __8__CO2(g) + 9H2O(g) + heat
When 1 part of octane reacts with 12.5 parts of oxygen, it gives 8 parts of carbon dioxide and 9 parts of water along with liberation of energy.
CH4(g) + __2__O2(g) → __1__CO2(g) + __2__H2O(g) + heat
When 1 part of methane reacts with 2 parts of oxygen, it gives 1 part of carbon dioxide and 2 parts of water along with liberation of energy.
C3H8(g) + __5__O2(g) → __3__CO2(g) + __4__H2O(g) + heat
When 1 part of propane reacts with 5 parts of oxygen, it gives 3 part of carbon dioxide and 4 parts of water along with liberation of energy.
C6H6(g) + __1/2__O2(g) → __6__CO2(g) + __3__H2O(g) + heat
When 1 part of propane reacts with 1/2 parts of oxygen, it gives 6 part of carbon dioxide and 3 parts of water along with liberation of energy.
If the volume of water in a cylinder is 8.0mL, but changes to 10.0mL when a solid is carefully lowered into it, the volume of the solid is?
Answer:
2 mL.
Explanation:
From the question given above, the following data were obtained:
Volume of water = 8 mL
Volume of water + solid = 10 mL
Volume of solid =?
The volume of the solid can be obtained as follow:
Volume of solid = (Volume of water + solid) – (Volume of water)
Volume of solid = 10 – 8
Volume of solid = 2 mL
Therefore, the volume of the solid is 2 mL
If a solution has a concentration of 3.2x10-3 [OH-] what is the pOH of the solution?
Answer:
The solution with [OH-] = 3.2x10-3 M will have an [H+] of 3.09x10–12 M.Explanation:
What happens to the speed of motion of the particles of a gas when a certain volume of the gas is heated at constant pressure? Explain your answer.
Answer:
The particles begin to move faster as the gas is heated. Since the gas remains at a constant pressure and volume, the particles are not able to spread out, so they move around the container even faster.
Explanation:
its just what happens
When a. certain volume of gas is heated at constant pressure, the speed of motion of the gas increases with temperature increase.
Amontons’s law.Anontons law states that If the temperature is increased, the average speed and kinetic energy of the gas molecules increase. If the volume is held constant, the increased speed of the gas molecules results in more frequent and more forceful collisions with the walls of the container, therefore increasing the pressure.
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The base area of a pyramid is 1,225m2.if the pyramid is 11.3m high,what is it's volume
Answer:
Volume = 4614 m³
Explanation:
The volume of a pyramide is given by the following formula:
Volume = 1/3 * base area * heightWe are already given all the required information to calculate the volume by inputting the data:
Volume = 1/3 * 1225 m² * 11.3 mVolume = 4614 m³The pyramid's volume is 4614 cubic meters.
What does the number 7 mean in the following example-73Li?
a. The number of protons
b. The atomic mass
c. The atomic number
d. The number of electrons
Answer:
7 is the mass number of li and 3 is the atomic number
a 3
b 7
c 3
d 4
Given the reaction: N2 + O2 = 2NO for which the Keq at 2273 K is 1.2 x 10-4
a. Write the equilibrium constant expression for the reaction.
b. Write the equation that would allow you solve for the concentration of NO.
c. What is the concentration of NO if [NZ] = 0.166M and [02] = 0.145M?
Answer:
(a): The expression of equilibrium constant is [tex]K_{eq}=\frac{[NO]^2}{[N_2][O_2]}[/tex]
(b): The equation to solve the concentration of NO is [tex][NO]=\sqrt{K_{eq}\times [N_2]\times [O_2]}[/tex]
(c): The concentration of NO is 0.0017 M.
Explanation:
The equilibrium constant is defined as the ratio of the concentration of products to the concentration of reactants raised to the power of the stoichiometric coefficient of each. It is represented by the term [tex]K_{eq}[/tex]
(a):
The given chemical equation follows:
[tex]N_2+O_2\rightarrow 2NO[/tex]
The expression for equilbrium constant will be:
[tex]K_{eq}=\frac{[NO]^2}{[N_2][O_2]}[/tex]
(b):
The equation to solve the concentration of NO follows:
[tex][NO]=\sqrt{K_{eq}\times [N_2]\times [O_2]}[/tex] ......(1)
(c):
Given values:
[tex]K_{eq}=1.2\times 10^{-4}[/tex]
[tex][N_2]_{eq}=0.166M[/tex]
[tex][O_2]_{eq}=0.145M[/tex]
Plugging values in equation 1, we get:
[tex][NO]=\sqrt{(1.2\times 10^{-4})\times 0.166\times 0.145}[/tex]
[tex][NO]=\sqrt{2.88\times 10^{-6}}[/tex]
[tex][NO]=0.0017 M[/tex]
Hence, the concentration of NO is 0.0017 M.
Consider the equation A(aq) 2B(aq) 3C(aq) 2D(aq). In one experiment, 45.0 mL of 0.050 M A is mixed with 25.0 mL 0.100 M B. At equilibrium the concentration of C is 0.0410 M. Calculate K. g
Answer:
K = 0.0396
Explanation:
Based on the reaction:
A + 2B ⇄ 3C + 2D
Where equilibrium constant, K, is:
K = [C]³[D]² / [A] [B]²
The initial concentrations of A and B are:
[A]₀ = 0.050M * (45.0mL / 70.0mL) = 0.0321M
[B]₀ = 0.100M * (25.0mL / 70.0mL) = 0.0357M
As [C] = 0.0410M, the molar concentration of D is:
0.0410M * (2mol D / 3mol C) = 0.0273M = [D]
And the concentration of A and B that reacted was:
0.0410M * (2mol B / 3mol C) = 0.0273M B
0.0410M * (1mol A / 3mol C) = 0.0137M A
Equilibrium concentration B and A:
0.0357M - 0.0273M = 0.0084M = [B]
0.0321M - 0.0137M = 0.0184M = [A]
And K is:
K = [0.0410M]³[0.0273M]² / [0.0184M] [0.0084M]²
K = 0.0396Why Phenol is acidic in nature but benzene is not acidic in nature?
A solution is prepared by mixing 50.00 mL of 0.100 M HNO3 and 100.00 ml of 0.200 M Ca(NO3)2. Calculate the molarity of the nitrate ion in the final solution.
A solution is prepared by mixing 50.00 mL of 0.100 M HNO3 and 100.00 ml of 0.200 M Ca(NO3)2. The molarity of the nitrate ion in the final solution is 0.1667 M.
What is molarity ?The amount of a substance in a specific volume of solution is known as its molarity (M). The number of moles of a solute per liter of a solution is known as molarity. The molar concentration of a solution is another name for molarity.
Molarity (M), which is determined by dividing the solute's mass in moles by the volume of the solution in liters, is the most widely used unit to express solution concentration: liters of solution/moles of solute equals M. One liter of a solution with a 1.00 molar concentration (1.00 M) contains 1.00 moles of solute.
50.0 mL x 0.100 M
= 5.00 millimoles of HNO3
=0.00500 moles
100.0 mL x 0.200 M
= 20.0 millimoles of HNO3
=0.0200 moles
The whole solution has a volume of 150.0 mL
= 50.0+100.0
= 150
The whole solution contains 25.0 millimoles of HNO3
= 5.00+20.0
= 25
millimoles / mL = Molarity
25.0 / 150.0
= 0.1667 M
moles / Liters = Molarity
0.0250 / 0.1500
= 0.1667 M
Thus, The molarity of the nitrate ion in the final solution is 0.1667 M.
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What is the perfect composition of calcium in calcium chloride?
Answer: 63.96%.
Explanation:
In 111g of Calcium chloride, there is 40g of Calcium and 71g of Chlorine. Percentage Composition of Chlorine is 63.96%.
Hope This Helps!
he correct statements about thermal conductivity are: A. The thermal conductivity of metals is generally higher than that of liquids. B. The thermal conductivity of solids is generally higher than that of liquids. C. The thermal conductivity of gases is generally higher than that of liquids.
Answer: The correct statements about thermal conductivity are:
The thermal conductivity of metals is generally higher than that of liquids.The thermal conductivity of solids is generally higher than that of liquids.Explanation:
The rate at which transfer of heat takes place from one object to another by conduction over a unit cross section area of a material is called thermal conductivity.
Hence, more is the distance between atoms of a substance less will be its thermal conductivity. This is because more is the space between molecules of a substance more will be their random motion due to which there will be less effective energy transport.
The thermal conductivity of metals is very high than liquids.
Also, the thermal conductivity of solids is generally higher than that of liquids.
As gases have more space between its molecules so they have less thermal conductivity.
Thus, we can conclude that the correct statements about thermal conductivity are:
The thermal conductivity of metals is generally higher than that of liquids.The thermal conductivity of solids is generally higher than that of liquids.Calculate the number of grams of Fe and the number of grams of Coz formed
when 0.150 kg of Fe2O3 reacts.
Answers to other questions on the sheet are appreciated!