Answer:
[tex]g=2.513m/s^2[/tex]
Explanation:
From the question we are told that:
Mass Taken [tex]m=100g \approx 100*10^{-3}[/tex]
Strain on Spring [tex]l_s=22.6cm \approx 22.6*10^{2}[/tex]
Distance pulled down [tex]d_d=10.9[/tex]
Time for ten oscillations take [tex]t=18.8s[/tex]
Generally the equation for angular velocity is mathematically given by
[tex]\omega=2\pi\\\omega=2\pi*\frac{10\ oscillations}{t}\\\\\omega=2\pif=2\pi*\frac{10\ oscillations}{18.8}\\Also\\\omega=\sqrt{\frac{k}{m}} \\\omega=\sqrt{\frac{k}{100*10^{-3}}}[/tex]
Therefore
[tex]{2\pi*\frac{10\ oscillations}{18.8}}=\sqrt{\frac{k}{100*10^{-3}}} \\k=\sqrt{2\pi*\frac{10\ oscillations}{18.8}}*100*10^{-3}\\k=1.112N/m[/tex]
Generally the equation for Acceleration due to gravity is mathematically given by
[tex]F=mg\\mg=k l_s\\g=\frac{k l_s}{m}\\g=\frac{1.112*2.6*10^{2}}{100*10^{-3}}[/tex]
[tex]g=2.513m/s^2[/tex]
A 1200 kg car accelerates from rest to 10.0 m/s in a time of 4.50 seconds. Calculate the force that the car’s tires exerted on the road.
please help me i need the answer in 10 mins
Answer:
the force that the car’s tires exerted on the road is 2,666.67 N.
Explanation:
Given;
mass of the car, m = 1,200 kg
initial velocity of the car, u = 0
final velocity of the car, v = 10.0 m/s
time of motion, t = 4.50 s
The force the car’s tires exerted on the road is calculated as follows;
[tex]F = ma= \frac{m(v-u)}{t} \\\\F = \frac{1200(10-0)}{4.5} \\\\F = 2,666.67 \ N[/tex]
Therefore, the force that the car’s tires exerted on the road is 2,666.67 N.
A truck gradually starts off from rest with a uniform
acceleration of 2 m/s2
. It reaches a velocity of 16 m/s. Using the
equation
[tex] {v}^{2}={u }^{2}+2as[/tex]
,calculate the distance it travels while it is
accelerating
What do diffraction and refraction have in common? They both involve interference. They both involve wave interactions. They both involve reflection. They both involve construction.
Answer:
They both involve wave interactions.
Explanation:
Diffraction is defined as the bending of waves around obstacles. Refraction can be defined as the bending of the light when it transfers from one substance to another. The main similarity between the diffraction and refraction is that both involves the interaction of the waves with the substance and also causes the waves to bend and change their direction. Hence, they both involve wave interaction is the correct option.
What diffraction and refraction have in common is that they both involve wave interactions. This is further explained below.
What are diffraction and refraction?When waves travel from one medium to another and refract, This causes them to change direction. while Diffraction is simply defined as the bending of waves around barriers.
In conclusion, diffraction and refraction are properties of waves.
Read more about Wave
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4. Coloca las partes en orden para formar una frase.
Se – La – se – transforma – sólo – no – ni – destruye – energía – crea – se
La energía no se crea ni se destruye solo se transforma
Explanation:
espero y te ayude
1. Jen is stepping out of a boat on to a dock. She has one foot on the dock and one foot in
the boat. No one holds on to the boat. It begins to move away from the dock. Jen's legs
split wider and wider. Which law applies?
you tend to push off with the foot still on the boat.
Newtons 3rd law of motion hold that every action has an equal and opposite reaction.
So, the amount of force you use on your back foot to push yourself onto the dock, has an equal end opposite amount of force going the other way from your sole of your foot, which pushes the boat the other way.
The same principle applies when you fire a cannon - in the pirate films, you see the body of the cannon forced back as it is fired.
Take it one step further, Henry VIII flagship, “Mary Rose fired all its cannons together one day in a broad side, the opposite force rolled the ship over and sank it.
How does refraction allow thin convex lenses to work?
Answer:
https://www.khanacademy.org/science/physics/geometric-optics/lenses/v/convex-lenses
Explanation:
Here is a link to a video to tell you about this.
WORTH 15 POINTS WILL GIVE BRAINLIEST
What is the mechanical advantage of a handle on a water well that requires 5 newtons of force to lift a 40-Newton bucket of water?
200
8
0.125
12.5%
Option B. The mechanical advantage of a handle on a water well that requires 5 newtons of force to lift a 40-Newton bucket of water is 8.
Mechanical advantage is a measure of the force amplification completed by means of the usage of a device, mechanical tool or gadget device. The device trades off input forces towards motion to gain a preferred amplification in the output pressure.
The version for this is the regulation of the lever. The mechanical advantage is the degree how which tons of force is increased with the aid of using a device or gadget. it is equal to the pressure exerted with the aid of the tool or system divided via the carried-out effort.
calculation:-
Mechanical advantage = load/effort
= 40/5
= 8
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Activities that can help reduce the stress level in a family include A. exercising B. reading C. going for a walk D. all of the above Please select the best answer from the choices provided. A B. ОС
Answer:
D. all the above
Explanation:
Took the quiz.
Answer: D) all the above
Explanation: :)
what determines an atom identity
a. electrons
b. protons
c. neutrons
d. atomic mass
Answer:
atomic mass
Explanation:
the identify of the atom is determined by the number of protons
Of the 5000 species of mammals, 250 species are carnivorous. What is the ratio of carnivorous to mammals?
Answer: The ratio of carnivorous species to all mammal species is 1:20
Explanation:
250:5000 = 250/250 = 1
250:5000 = 5000/250 = 20
Answer = 1:20
A student pushes a box to the right with a force of 10 N. At the same time, another
student pushes the same box to the left with a force of 5N.
What is the net force
Answer:
5 N
Explanation:
To find the net force of 2 objects pushing against each other you subtract them and that’s how you get your answer.
The net force acting on a system is defined as the resultant of all the force acting on all the body. The value of net force will be 5N.
What is force?Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration. Its unit is Newton.
The given data in the problem will be;
F₁ is the force act to the right = 10 N
F₂ is the force act to the left= 5N
F is the net force=?
According to the equilibrium concept, the net force acting on the body is equal to zero.
F = F₁ - F₂
F = 10-5
F = 5N
Hence the value of net force will be 5N.
To learn more about the force refer to the link;
https://brainly.com/question/26115859
Describe or identify some uses of an electromagnet.
Answer:
Electromagnets are widely used as components of other electrical devices, such as motors, generators, electromechanical solenoids, relays, loudspeakers, hard disks, MRI machines, scientific instruments, and magnetic separation equipment.Explanation:
My next photo How's it
Answer:
Pretty good
Explanation:
is there nxt 1
2) 1. A vibration of an electric charge.
2.Transmits energy from the Sun to Earth
3. A wave which has both an electric and a magnetic component
4. The speed of this wave decreases as the medium becomes
denser.
What type of wave is being described by the statements above?
A) electromagnetic
B) longitudinal
C) mechanical
D) sound
Explanation:
Answers1.Electromagnetic waves
2.Electromagnetic radiation
3.Electromagneticwaves
If one light bulb breaks in a series circuit containing three bulbs will it remain lit?
In a series circuit, every device must function for the circuit to be complete. One bulb burning out in a series circuit breaks the circuit. In parallel circuits, each light has its own circuit, so all but one light could be burned out, and the last one will still function
2. Give at least 2 major roles of mining in our lives.
Answer:
Mined materials are needed to construct roads and hospitals, to build automobiles and houses, to make computers and satellites, to generate electricity, and to provide the many other goods and services that consumers enjoy.
Explanation:
En una feria, se gana una jirafa de peluche lanzando una moneda a un platito, el cual está sobre una repisa más arriba del punto en que la moneda sale de la mano y a una distancia horizontal de 2.1 m desde ese punto (figura 3.41). Si lanza la moneda con velocidad de 6.4 m>s, a un ángulo de 60° sobre la horizontal, la moneda caerá en el platito. Ignore la resistencia del aire. A) ¿A qué altura está la repisa sobre el punto donde se lanza la moneda? B) ¿Qué componente vertical tiene la velocidad de la moneda justo antes de caer en el platito?
Answer:
A) La altura de la repisa sobre el punto donde se lanza la moneda es de aproximadamente 0,42 m
B) La velocidad de la moneda justo antes de que golpee el platillo es de aproximadamente 0,895 m/s hacia abajo
Explanation:
A) Los parámetros dados son;
La distancia horizontal del plato desde donde se lanza la moneda = 2,1 m
La velocidad con la que se lanza la moneda, u = 6,4 m / s
El ángulo al que se lanza la moneda, θ = 60 °
La componente horizontal de la velocidad, vₓ = 6.4 m / s × cos (60°) = 3.2 m/s
El tiempo que tarda la moneda en recorrer una distancia horizontal de 2,1 m, 't' se calcula de la siguiente manera;
t = 2,1 m/(3,2 m/s) = 0,65625 segundos
Por tanto, la altura de la moneda a 0,65625 segundos se da de la siguiente manera;
y = u × sin (θ) × t - (1/2) × g × t²
En t = 0,65625 segundos, obtenemos;
y = 6,4 × sin (60°) × 0,65625 - (1/2) × 9,81 × (0,65625) = 0,41840044589
La altura de la repisa sobre el punto donde se lanza la moneda, y ≈ 0.42 m
B) La velocidad vertical de la moneda justo antes de que golpee el platillo, [tex]v_y[/tex], se da como sigue;
[tex]v_y[/tex] = u × sin(θ) - g·t
∴ [tex]v_y[/tex] = 6.4 × sin(60°) - 9.81 × 0.65625 ≈ -0.895
La velocidad de la moneda justo antes de golpear el platillo, [tex]v_y[/tex] ≈ 0.895 m/s (hacia abajo)
07. 1
Explain why the light refracts as it passes from air into glass. GCSE PHYSICS HIGHER
Answer:
Light is faster in air than in glass so the speed of light decreases when it passes through glass.
A rigid body of moment of inertia 0.5 kg.M^2 rotates with 2 RPM. How much torque is needed to increase the rotation to 10 RPM in 5 seconds.
Answer:
T = 0.084 Nm
Explanation:
First, we will calculate the angular acceleration:
[tex]\alpha = \frac{\omega_f - \omega_i}{t}[/tex]
where,
α = angular acceleration = ?
ωf = final angular speed = (10 RPM)(2π rad/1 rev)(1 min/60 s) = 1.05 rad/s
ωi = initial angular speed = (2 RPM)(2π rad/1 rev)(1 min/60 s) = 0.21 rad/s
t = time = 5 s
Therefore,
[tex]\alpha = \frac{1.05\rad/s - 0.21\ rad/s}{5\ s}\\\\\alpha = 0.168\ rad/s^2[/tex]
Now, for the torque:
[tex]T = I\alpha[/tex]
where,
T = torque = ?
I = moment of inertia = 0.5 kg.m²
Therefore,
[tex]T = (0.5\ kg.m^2)(0.168\ rad/s^2)\\[/tex]
T = 0.084 Nm
An object on the moon feels lighter than the same object on earth. which statement explains this phenomenon?
A. The moon has less mass than earth.
B. The object has a greater gravitational attraction to the moon.
C. The object has less mass on the moon then on earth.
D. The moon is in orbit around earth.
Answer:
B
Explanation:
cause
Answer: A
Explanation:
The moon has less mass than Earth.
Just took the test.
A machine used 20 J of energy to make a
bicycle start. However, 6 J of energy was
wasted as heat. What is the percentage
efficiency of the machine?
a 30%
b 75%
C 70%
d 60%
Answer:
a. 30%
Explanation:
Given the following data;
Energy as effort, Ee = 20 J
Energy as heat, Eh = 6 J
To find the percentage efficiency (P.E);
P.E = Eh/Ee * 100
Substituting into the formula, we have;
P.E = 6/20 * 100
P.E = 6 * 5
P.E = 30 %
Therefore, the percentage efficiency of the machine is 30 %.
8. Jay drives his truck to football practice. He gives Jen a ride. The truck stalls in the parking
lot. He gets out and pushes it, but it won't budge. He tells Jen to get out and help him
push. They manage to push the truck into a parking space. (Thank goodness he is a
tackle!) Which law applies?
Answer:
Action Reaction
Explanation:
Linear vectore F
Gold atoms find their "birth" inside of huge _________.
Explanation:
he is very keen on taking up and is the age
How do media literacy , information literacy and technology literacy and media and information literacy differ in terms of use?
Answer:
Media literacy creates a conscious awareness, the ability to understand, analyze, the messages various media like the newspapers, the radio, that is for the consumer, and it also promotes how best media create information for production.
While information literacy and technology literacy differs from other literacy asked in the question above, as information literacy and technology could be used when describing getting information through adequate research and further dishing out this available information so as to effectively use the information with the aim to solve problems, create awareness, or educate, through technologies such as for example, email.
Lastly, media and information literacy differ in terms of use from the other two explained above, as media and information literacy describes discerning information credibility, accuracy, and objectivity of sources they come from, and it shows people how important it is to have credible information to make informed judgments and the ethical use of the information they consume.
An aircraft with a landing speed of 295km/h lands on an aircraft carrier with a landing area 205m long . Find the maximum constant deceleration required for the a safe landing
A lens with f=15.0 cm is held 29.0 cm from an object. Where does the image form
Answer:
Magnification, m = 3
Explanation:
It is given that,
Focal length of the lens, f = 15 cm
Object distance, u = -10 cm
Lens formula :
v is image distance
Magnification,
So, the magnification of the lens is 3.
Answer:
31.1
Explanation:
Trust brother
If a person meets an accident, which of the following factors will have more effect on his Kinetic energy and hence on the fatality of the accident?
A.velocity of the vehicle
B.Mass of the vehicle
Answer:
b
Explanation:
A cannon and a supply of cannonballs are in a sealed system railroad car. The car has a length of 20 meters, and a mass of 2000kg. The cannon fires to the right, the car recoils to the left. Fired cannonballs remain in the car after hitting the wall and land on the floor at the end of the car. The cannonballs have a mass of 15 kg each, and there are ten of them. (neglect mass of cannon) How far will the car move after all ten have been fired
Answer:
The distance the car moves after all ten cannonballs have been fired is 1.5 meters
Explanation:
The parameters given in the question are;
The length of the car = 20 meters
The mass of the of the cannon ball, m₁ = 2,000 kg
The direction the cannon fires = The right
The direction the car recoils = The left
The mass of each cannonball, m₂ = 15 kg
The number of cannonballs = 10
Let v₁ represent the speed of the car and let v₂ represent the speed of the cannonball, where momentum is conserved, we have;
m₁·v₁ = m₂·v₂
2000 × v₁ = 15 × v₂
400·v₁ = 3·v₂
Therefore, when the cannon ball travels 400 meters, the railroad car travels 3 meters
Similarly, when the cannon ball travels 400/20 = 20 meters, the distance the railroad car travels, d = 3/20 meters
We not that the railroad car and the car are brought to a stop each time the cannonball hits the watt
Therefore, the total distance moved by the car after all ten have been fired, [tex]d_{total}[/tex], is given as follows;
[tex]d_{total}[/tex] = d × The number of balls fired
∴ [tex]d_{total}[/tex] = 3/20 meters per ball × 10 balls = 3/2 meters = 1.5 meters
The total distance moved by the car, [tex]d_{total}[/tex] = How far the car moves after all ten have been fired = 1.5 meters.
A 1,000 kg ball traveling at 5 m/s would have kinetic energy. A 10 kg ball traveling at 5 m/s would have kinetic energy. A 100 kg person falling at 5 m/s would have kinetic energy.
Question : 1
mass (m) = 1000 kgvelocity (v) = 5 m/s=》
[tex]k.e = \dfrac{1}{2}mv {}^{2} [/tex]
=》
[tex]k.e = \dfrac{1}{2} \times 1000 \times (5) {}^{2} [/tex]
=》
[tex]k.e = 500 \times 25[/tex]
=》
[tex]k.e = 12500 \: joules[/tex]
kinetic energy = 12500 joules
Question : 2
mass (m) = 10 kgvelocity (v) = 5 m/s=》
[tex]k.e = \dfrac{1}{2} mv {}^{2} [/tex]
=》
[tex]k.e = \dfrac{1}{2} \times 10 \times ({5})^{2} [/tex]
=》
[tex]k.e = 5 \times 25[/tex]
=》
[tex]k.e = 125 \: joules[/tex]
kinetic energy = 125 joules
Question : 3
mass = 100 kgvelocity = 5 m/s=》
[tex]k.e = \dfrac{1}{2} mv {}^{2} [/tex]
=》
[tex]k.e = \frac{1}{2} \times 100 \times (5) {}^{2} [/tex]
=》
[tex]k.e = 50 \times 25[/tex]
=》
[tex]k.e = 1250 \: joules[/tex]
kinetic energy = 1250 joules
please explain application of Stephan boltzmann law
Answer:
This law is used to find the luminosity (the rate of energy released), for an object given its surface temperature. This law assumes the body acts as a black-body radiator (an object that emits energy from the entire EM spectrum)
For a given object with a constant surface area, the Stefan-Boltzmann law says that luminosity is proportional to the temperature raised to the fourth power.
Explanation: