One gallon of gasoline in an automobiles engine produces on average 9.50 kg of carbon dioxide, which is a greenhouse gas; that is, it promotes the warming of Earth's atmosphere. Calculate the annual production of carbon dioxide in kilograms if there are exactly 40.0 million cars in the United States and each car covers a distance of 7930 mi at a consumption rate of 23.6 miles per gallon. Enter your answer in scientific notation.

Answer:

NH3 < NF3 < BCl3

Explanation:

The vapour pressure of a substance has something to do with the nature of intermolecular forces between its molecules. If the molecules of a substance are held together by strong intermolecular forces, the substance will display a low vapour pressure at a given temperature and vice versa.

Ammonia has the lowest vapour pressure because of strong intermolecular hydrogen bonds that hold its molecules together.

The trend for increasing vapor pressure will be:

NH₃<NF₃<BCl₃

We know that,

The stronger the intermolecular forces, the lower the vapor pressure, and the higher the boiling point.

Thus to solve this question we need to look the intermolecular attractions in the given molecules.

1. In ammonia molecule, since it is polar in nature. It exhibits, dipole-dipole interactions and also there is hydrogen bonding between nitrogen and hydrogen atoms. So these interactions are strongest  thus NH₃ will have lower value of vapor pressure.

2. Forces of attractions in NF₃ is also stronger in comparison to BCl₃ but weaker than NH₃ thus in terms of vapor pressure it will come after NH₃.

3. Lastly, in BCl₃ it is a non-polar molecule; it exhibits London forces which are the weakest thus it will have the higher value of vapor pressure.

Trend for intermolecular attraction:

ion-dipole>hydrogen bonding>dipole-dipole> London forces > Van der Waals forces

Therefore,

Increasing order of vapor pressure will be:

NH₃<NF₃<BCl₃

Learn more:

https://brainly.com/question/14220340

Answer: As altitude increases, there is less air pushing down from above, which decreases the pressure.

Explanation:

Atmospheric pressure is the result of air particles being pulled to the surface of the Earth by gravity. As they are pulled, they will exert more pressure on the Earth and this is what atmospheric pressure is.

It makes sense therefore that as we move higher into the atmosphere, the atmospheric pressure will decrease because less air particles are exerting pressure as we go further off the ground.

Another way to look at it is that there is air in the earth's atmosphere and all that air has weight that is pushing down on us. As we go higher into the atmosphere, there'll be less air pushing down on us so the weight will be less.

Answer:

A as te altitude increases

Explanation:

Answer:

manganese has greater ionization energy than Selenium

Answer: Cl-35

Explanation:

Answer:

y = 35.06 %.

Explanation:

The reaction of fermentation is:

C₆H₁₂O₆  →  2C₂H₅OH + 2CO₂      (1)        

From the reaction (1) we have that 1 mol of C₆H₁₂O₆ produces 2 moles of C₂H₅OH, then the number of moles of C₂H₅OH is:

[tex]n = \frac{2 moles C_{2}H_{5}OH}{1 mol C_{6}H_{12}O_{6}}*1 mol C_{6}H_{12}O_{6} = 2 moles C_{2}H_{5}OH[/tex]

Now, we need to find the mass of C₂H₅OH:

[tex]m = n*M = 2 moles*46.07 g/mol = 92.14 g[/tex]  

Finally, the percent yield of C₂H₅OH is:

[tex] \% = \frac{32.3 g}{92.14 g}*100 = 35.06 \% [/tex]

Therefore, the percent yield of C₂H₅OH is 35.06 %.

I hope it helps you!

The percent yield of C2H5OH should be 35.06% also it have the 1.00 moles.

Since

The reaction of fermentation should be

C₆H₁₂O₆  →  2C₂H₅OH + 2CO₂      (1)        

Here  1 mol of C₆H₁₂O₆ generated 2 moles of C₂H₅OH, so the number of moles of C₂H₅OH should be

= 2 moles / 1mole * 1 mole

= 2 moles C₂H₅OH

So here the percent yield should be

= 32.3 / (2 * 4607)

= 32.3 / 92.14

= 35.06%

Hence, The percent yield of C2H5OH should be 35.06% also it have the 1.00 moles.

Learn more about moles here: https://brainly.com/question/19669595

Answer:

A particular kind of matter

Explanation:

Answer:

pH=3.40

Explanation:

For this question, we can start with the general ionization reaction of a general acid:

[tex]HA~<->~A^-~+~H^+[/tex]

The acids can produce the hydronium ion ([tex]H^+[/tex]). If we can to calculate the pH we have to use the equation:

[tex]pH=-Log[H^+][/tex]

So, if we want to calculate the pH value we have to know the concentration of the hydronium ion. For this, we can check the percentage of ionization. If we have 0.2 % of ionization, we will have only  0.2 % of hydronium ions from the initial concentration. In other words, we can calculate the concentration of [tex]H^+[/tex], if we do the 0.2% of the initial concentration, so:

[tex]0.2~M*\frac{0.2}{100}~=~0.0004~M[/tex]

With the concentration we can calculate the pH:

[tex]pH=-Log[0.0004~M]~=~3.40[/tex]

The pH value is 3.40

I hope it helps!