Part A
A model car is for sale online. Beginning on day one, the owner discounts the price by 5% each day until it sells. On the third day the car sells.
If the original price of the model car was $40, how much did the car sell for to the nearest cent?
Part B
What percent discount does this represent from the original price? Round to the nearest whole percent.

Answer:

Brand A

Step-by-step explanation:

Brand A has a box of 25 forks for 1.99

Take the price per fork

1.99 /25 = .0796

              .08 per fork

Brand B has a box of 42 totals for 3.89

3.89 / 42

.092319048

.09 per fork

Answer:

"Multiply to remove the fraction then set it equal to 0 and solve."

Exact form

x = - 39/2

Decimal Form:

x = -19.5

Mixed Number Form:
x = - 19 1/2

Hope this helped...!

Answer: I don't know

Step-by-step explanation:

I have no idea

Triangle C forms a right angle triangle.

Given:

Triangle A : 8 cm , 13 cm , 5 cm

Triangle B : 14 cm , 30 cm , 17 cm

Triangle C : 26 cm , 10 cm , 24 cm

To form a right angled triangle the longest side square is equal to the sum of squares of other sides.

In triangle A :

[tex]13^{2} = 8^{2} +5^{2}[/tex]

169 = 64 + 25

169 ≠ 89.

This is not a right angle triangle.

In triangle B:

[tex]30^{2} =17^{2} +14^{2}[/tex]

900 =  289 + 196

900 ≠ 485

This is not a right angle triangle.

In triangle C:

[tex]26^{2} = 10^{2} +24^{2}[/tex]

676 = 100 + 576

676 = 676

so it is a right angle triangle.

Therefore Triangle C forms a right angle triangle.

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Answer:

percentage = 80÷4000=0.02

Answer: 19.2, I think.

Step-by-step explanation: 10*1.2 = 12.

To keep the ratio balanced, you must also do 16*1.2, which is 19.2. Making the ratio 12 : 19.2

The different possibilities available for selecting an executive board in Student Council in election is 990 ways

In permutation, order matters hence in choosing or making selection specific order should be followed. an instance here is arranging the 3 letters word from ABC. ₃P₃ = 6

The problem is a permutation problem trying to select 3 from 11 where order matters. The order include choosing the president the ramainig position is left 2 for 10. and so on.

This is shown in permutation as follows

₁₁P₃  = 11! / (11 - 3)!

= 11! / 8!

= 990 ways

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Answer:

-3≥11.5

Step-by-step explanation:

-3≥1/2+11

-3≥11.5

The correct number of servings would be = 12/25

A cooking class is defined as the class that is made up of students that are being thought how to prepare and serve different types of food.

The total amount of quarts of food made by the students = 4½.

The number of servings to friends = ⅘

The quantity of quarts in each serving = ⅗ quarts

Total number of quarts served = ⅘ × ⅗= 12/25

The correct number of servings = 12/25

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The union of the sets P and Q does not have the integer 5 since it is neither a multiple of 3 or a multiple of 4.

P is the set of integers between 1 and 10 and multiple of 3.

∴P = {3,6,9}

Q is the set of positive integers less than 15 and multiple of 4.

∴Q = {4,8,12}

Now the union of the sets P and Q is given by :

P∪Q = {3,4,6,8,9,12}

Now the union of the sets does not contain the integer 5.

Any collection of items, including a set of raw materials, the seven days of the week, several car types, etc., can be categorized as a set.

Any set component counts as an element of the set. Curly brackets are used to write a set. A very basic set would resemble something like this:

Q = {4,8,12}.

Therefore the integer 5 does not belong to the union of P and Q .

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Answer:

1. y ⇒ ∞ as x ⇒ ∞ AND y ⇒ ∞ as x ⇒ -∞; Domain:  (-∞, ∞); Range:  [0, ∞)

2. y ⇒ -∞ as x ⇒ ∞ AND y ⇒ ∞ as x ⇒ -∞; Domain:  (-∞, ∞); Range:  (-∞, ∞)

3. y ⇒ -∞ as x ⇒ ∞ AND y ⇒ ∞ as x ⇒ -∞; Domain:  (-∞, ∞); Range:  (-∞, ∞)

4. y ⇒ ∞ as x ⇒ ∞ AND y ⇒ ∞ as x ⇒ -∞; Domain:  (-∞, ∞); Range:  [0, ∞)

Step-by-step explanation:

Rule for end behavior of polynomials:

(a) Positive leading coefficient, even degree:  y ⇒ ∞ as x ⇒ ∞ AND y ⇒ ∞ as x ⇒ -∞

(b) Negative leading coefficient, even degree: y ⇒ -∞ as x ⇒ ∞ AND y ⇒ -∞ as x ⇒ -∞  

(c) Positive leading coefficient, odd degree:  y ⇒ ∞ as x ⇒ ∞ AND y ⇒ -∞ as x ⇒ -∞

(d) Negative leading coefficient, odd degree:  y ⇒ -∞ as x ⇒ ∞ AND y ⇒ ∞ as x ⇒ -∞

Domain and range for a polynomial function with an odd degree will always be all real numbers, whether or not there's a constant or not.

Domain will always be all real numbers for a polynomial function with an even, whether or not there's a constant.

For a polynomial function with an even degree, the range will extend from the y-coordinate of the vertex to ∞, if the leading coefficient is positive

For a polynomial function with an even degree, the range will extend from -∞ to the y-coordinate of the vertex if the leading coefficient is negative.

Answer:

B, C

Step-by-step explanation:

A is incorrect, it should be seventy-six hundredths.

D is incorrect, the place value for the third term is wrong - it should be 0.06.

Answer:

The third option, as x approaches infinity y approaches infinity and as x approaches negative infinity y approaches negative infinity.

Step-by-step explanation:

The equation y = -|x - 3| + 2 written as a piecewise function is;

f(x) = {y = x - 1, if x < -3

        {y = -x + 1, if x ≥ -3

A function can be written as piecewise function if it changes its behavior ( increasing or decreasing ) about a point.

The function f(x) = y = |x| changes its behavior at |x| = 0 i.e , x = 0 .

y = | x | = x , if x < 0

= - x , if x > 0

| x | = a => x = ± a

• | x | ≥ a ( a ≥ 0 ) => x € ( -∞ , -a ] U [ a , ∞ )

• | x | ≤ a ( a ≥ 0 ) => x € [ -a , a ]

The given function is : y = -|x - 3| + 2

The function will change its behavior when; -| x - 3 | = 0

-x + 3 = 0

x = -3

If x < -3 , then ;

y =  -(-(x - 3)) + 2

y = x -3 + 2

y = x - 1

If x ≥ -3, then ;

y = -(x - 3) + 2

y = -x + 3 + 2

y = -x + 1

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Each student should work for 7 hours on the project.

Given, the equation the quantity x plus 56 end quantity over 3 equals 5 times x models the workload of a class project,

where x is the number of hours each student must contribute.

Now, according to question,

56 - 3x = 5x

56 = 5x + 3x

8x = 56

x = 7

So, x = 7 hours

Hence, each student should work for 7 hours on the project.

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Answer:

4 hours

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

Exact Form:

x = 14/3

Decimal Form:

x = 4.6

Mixed Number Form:

x = 4 2/3

Therefore, 4 hours is how much the students work on the project.

The required value of the given expression : [tex]\frac{79 - 75 }{ 75 }[/tex] × 100 = 5.3

The Bodmas rule is based on the BODMAS acronym, which stands for Brackets, Order of Powers or Roots, Division, and Multiplication. Subtraction is represented by the letter S, while addition is represented by the letters A and S. According to the BODMAS rule, mathematical expressions with multiple operators must be resolved in the order of BODMAS, starting from the left. As with addition and subtraction, division and multiplication are interchangeable and depend on which comes first in the expression.

Given : [tex]\frac{79 - 75 }{ 75 }[/tex] × 100

on calculating it further

we get :

[tex]\frac{4}{75}[/tex] × 100

0.0533 X 100

=> 5.3

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The following equation expressed in scientific notation would be as follows:

SCIENTIFIC NOTATION FORM:

[tex]1.28*10^1^3[/tex]

Hope this helps!

The expression will be i.e., 2(8 + 7).

The correct option is (D)

Given,

In the question:

Joan has a vegetable garden in her backyard that measures 8 feet 7 feet.

To find the which expression would not calculate the garden's perimeter?

Now, According to the question;

Based on the given conditions:

Formulate:

Measurement of garden is :

Length and breadth is 7 ft. and 8 ft.

Calculate:

2 x (7 + 8)

= 30

Hence, The expression will be i.e., 2(8 + 7).

The correct option is (D)

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The length of q, to the nearest 10th of a centimeter, is 8.8 cm.

We are given the following;

In ΔQRS, s = 7.9 cm, ∠Q=125° and ∠R=23°.

The third angle can be calculated using the angle sum property:

angle Q + angle R + angle S = 180 degrees

125 degrees + 23 degrees + angle S = 180 degrees

angle S = 180 - (125 + 23) degrees

angle S = 180 - 148 degrees

angle S = 32 degrees

To find the length of q we shall apply the Sine rule.

q / Sin Q = s / Sin S

q / Sin 125 = 7.9 / Sin 32

by cross multiplication we will get;

q = (7.9 x Sin 125) / Sin 32

q = (7.9 x 0.61) / 0.55

q = 8.8 cm (approximately)

So,  the length of q is 8.8 cm.

Thus, the length of q, to the nearest 10th of a centimeter, is 8.8 cm.

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The measure of the exterior angle is 139 degrees.

The sum of the interior angle of a triangle is 180 degree.

The sum of angles on a straight line is 180 degrees.

From the diagram;

First, we determine the third interior angle of the triangle.

Angle 1 + Angle 2 + Angle 3 = 180

64 + 75 + Angle 3 = 180

139 + Angle 3 = 180

Angle 3 = 180 - 139

Angle 3 = 41 degrees

Now, angle 3 and the exterior angle forms a angle on a straight line.

Hence;

Angle 3 + Exterior angle = 180

41 +  Exterior angle = 180

Exterior angle = 180 - 41

Exterior angle = 139 degrees.

Therefore, 139 degrees is the exterior angle.

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Therefore , the solution of the given problem of interest comes out to be $4,088.14 is the new balance.

Divide the number by the expense of borrowing, the remaining time, and other factors to get the simple interest rate. In marketing, the straightforward return plan is principal interest payments plus hours. This technique is the simplest way to figure out interest. The most common way to determine income is as a percentage of the principal sum.

Here,

We must first figure out the interest on the present balance.

The interest rate is 27.99%/12, or 0.0233, per month.

As a result, the current balance's interest rate is:

=> 3,109.87 x 0.0233 = $72.43

When this interest is added to the outstanding amount, Kye's new balance is as follows:

=>  3,109.87 + 72.43 + 532.42 = $3,714.72

The minimum payment for the new amount must now be determined:

=>  3,714.72 x 0.02 = $74.29

Kye's minimum payment for the following month will be $159.00 because the minimum payment is the higher of $74.29 or that amount.

Kye's new balance with interest as a result of making the required minimum contribution and spending $532.42 is as follows:

=>  3,714.72 - 159.00 + 532.42 = $4,088.14.

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The linear equation that represents the hours Yuson has left after x days is (A) y = -2x + 30

Given in question,

Hours she should complete = 30 hours

Hours she complete each day = 2 hours

Hours completed in x days = 2x

Hours left after x days = 30 -2x

Hence, the linear equation that represents the hours Yuson has left after x days is y = -2x + 30.

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Jimmy has to write 369 words per day for the next 6 days to finish the paper.

The total number of words in the paper has to be 3000

Jimmy has already written = 786 words.

3000-786 = 2214

So, Jimmy still has to write 2214 words.

He has 6 days to write the paper and he wants to write the same number of words per day.

With this in mind to find out how many words he has to write per day we can divide 2214 by 6.

2214/6 = 369 words

So, Jimmy has to write 369 words per day for the next 6 days to finish the paper.

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Answer:

X=3

Step-by-step explanation:

I'm not sure what statements below you want me to confirm that X=Y, Y=3

The equation that can be used to find the length of the afternoon practice is B. 4(h + 3) = 20

An equation is the statement that illustrates that the variables given. In this case, two or more components are taken into consideration to describe the scenario.

In this case, during the summer the team practices 4 days per week and each of those days, they practice for 3 hours in the morning and practice again in the afternoon.

Let the afternoon practice be h.

Therefore, the equation will be:

4(h + 3) = 20

In conclusion, the correct option is B.

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Answer:

Convergence

Step-by-step explanation:

Use the Squeeze Theorem,

I know that

[tex] \frac{k \sin {}^{2} (k) }{1 + k {}^{3} } [/tex]

lies between 0 and 1 so

[tex]0 \leqslant \frac{k \sin {}^{2} (k) }{1 + {k}^{3} } \leqslant \frac{k}{1 + k {}^{3} } [/tex]

The final series behaves like

[tex] \frac{1}{k {}^{2} } [/tex]

Using the p series, since p is 2, the series

[tex] \frac{k}{1 + k {}^{3} } \: converges[/tex]

Since the 0 and k/1+k^3 converges, the series converge.

Convergence

The probability that the person is between 67.1 and 68.3 inches, using the normal distribution, is of:

0.1056 = 10.56%.

The z-score of a measure X of a variable that has mean symbolized by [tex]\mu[/tex] and standard deviation symbolized by [tex]\sigma[/tex] is obtained by the rule presented as follows:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The mean and the standard deviation for the heights of UCB students are given as follows:

[tex]\mu = 65, \sigma = 2.4[/tex]

The probability that the person is between 67.1 and 68.3 inches is the p-value of Z when X = 68.3 subtracted by the p-value of Z when X = 67.1, hence:

X = 68.3:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

Z = (68.3 - 65)/2.4

Z = 1.38.

Z = 1.38 has a p-value of 0.9162.

X = 67.1:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

Z = (67.1 - 65)/2.4

Z = 0.88.

Z = 0.88 has a p-value of 0.8106.

0.9162 - 0.8106 = 0.1056 = 10.56%.

The problem asks for the probability that the person is between 67.1 and 68.3 inches.

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Answer: Symmetry Property of Equality