Answers
Answer:
Step-by-step explanation:
Nhgbbhhgffgh
(a+b)2×h = (6.5+15.1)/2× 5= 54 in²
Related Questions
c and d for 20 pts
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Answers
Answer:
C. a = 7
D. c = -3
Step-by-step explanation:
C. 7(2a + 3) + 21 = 100+ 40
14a + 21 + 21 = 140
14a = 140 - 21 - 21
14a = 98
a = 7
D. 6+ 14 - 12c = 56
20 - 12c = 56
-12c = 56 - 20
-12c = 36
c = - 3
Answer:
Step-by-step explanation:
c.7(2a+3)+21=100+40
14a+21+21=140
14a+42=140
14a=140-42
a=98/14
a=7
d.6+14-12c=56
20-12c=56
-12c=56-20
c=36/-12
c=-3
Last week at the business where you work , you sold 120 items. The business paid $1 per item and sold them for $3 each. What profit did the business make from selling the 120 items
Answers
Answer:
240
Step-by-step explanation:
They spent $120 buying 120 items, so they have -$120. By selling the items at 3x the price, they gained the 120 back and made a profit of 240 (120 x 2).
3-1=2
120 x 2=240
What is the median of these numbers 2.4,2.8,2.3,2.9,2.9
Answers
Answer:
2.8
Step-by-step explanation:
x2.3, x2.4, 2.8, x2.9, x2.9
GIVING OUT BRAINLIEST PLS HELP! ALMOST DUE
Answers
Answer:
I think it's option B
Which is the inverse of the following statement?
If the measure of an angle is 90°, then it is a right angle.
Answers
I need help with this three problems (with procedure)
Answers
Answer:
13. [tex]x^{3} y^3[/tex] cubic units
14. 43 million; 79 million; 3.6 × [tex]10^7[/tex]
15. 2.68 × [tex]10^5[/tex]
Step-by-step explanation:
Find the value of x.
Answers
The track team has 12 more boys than girls. There are a total of 142 team members. How many boys and girls are on the team?
Answers
Answer:
77 boys, 65 girls
Step-by-step explanation:
x as the variable to represent amount of girls, and there are 12 more boys than girls (x+12). So the equation would be:
x + x + 12 = 142
2x + 12 = 142
x = 65
65 girls
then 65+ 12 = 77 boys
Find the solution of the differential equation f' (t) = t^4+91-3/t
having the boundary condition f(1) =1/4
Answers
Answer:
[tex]\displaystyle f(t) = \frac{t^5}{5} + 91t - 3ln|t| - \frac{1819}{20}[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
BracketsParenthesisExponentsMultiplicationDivisionAdditionSubtractionLeft to RightEquality Properties
Multiplication Property of EqualityDivision Property of EqualityAddition Property of EqualitySubtraction Property of EqualityAlgebra I
FunctionsFunction NotationCalculus
Derivatives
Derivative Notation
Antiderivatives - Integrals
Integration Constant C
Integration Rule [Reverse Power Rule]: [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]
Integration Property [Addition/Subtraction]: [tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]
Integration Property [Multiplied Constant]: [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]
Step-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle f'(t) = t^4 + 91 - \frac{3}{t}[/tex]
[tex]\displaystyle f(1) = \frac{1}{4}[/tex]
Step 2: Integration
Integrate the derivative to find function.
[Derivative] Integrate: [tex]\displaystyle \int {f'(t)} \, dt = \int {t^4 + 91 - \frac{3}{t}} \, dt[/tex]Simplify: [tex]\displaystyle f(t) = \int {t^4 + 91 - \frac{3}{t}} \, dt[/tex]Rewrite [Integration Property - Addition/Subtraction]: [tex]\displaystyle f(t) = \int {t^4} \, dt + \int {91} \, dt - \int {\frac{3}{t}} \, dt[/tex][1st Integral] Integrate [Integral Rule - Reverse Power Rule]: [tex]\displaystyle f(t) = \frac{t^5}{5} + \int {91} \, dt - \int {\frac{3}{t}} \, dt[/tex][2nd Integral] Integrate [Integral Rule - Reverse Power Rule]: [tex]\displaystyle f(t) = \frac{t^5}{5} + 91t - \int {\frac{3}{t}} \, dt[/tex][3rd Integral] Rewrite [Integral Property - Multiplied Constant]: [tex]\displaystyle f(t) = \frac{t^5}{5} + 91t - 3\int {\frac{1}{t}} \, dt[/tex][3rd Integral] Integrate: [tex]\displaystyle f(t) = \frac{t^5}{5} + 91t - 3ln|t| + C[/tex]Our general solution is [tex]\displaystyle f(t) = \frac{t^5}{5} + 91t - 3ln|t| + C[/tex].
Step 3: Find Particular Solution
Find Integration Constant C for function using given condition.
Substitute in condition [Function]: [tex]\displaystyle f(1) = \frac{1^5}{5} + 91(1) - 3ln|1| + C[/tex]Substitute in function value: [tex]\displaystyle \frac{1}{4} = \frac{1^5}{5} + 91(1) - 3ln|1| + C[/tex]Evaluate exponents: [tex]\displaystyle \frac{1}{4} = \frac{1}{5} + 91(1) - 3ln|1| + C[/tex]Evaluate natural log: [tex]\displaystyle \frac{1}{4} = \frac{1}{5} + 91(1) - 3(0) + C[/tex]Multiply: [tex]\displaystyle \frac{1}{4} = \frac{1}{5} + 91 - 0 + C[/tex]Add: [tex]\displaystyle \frac{1}{4} = \frac{456}{5} - 0 + C[/tex]Simplify: [tex]\displaystyle \frac{1}{4} = \frac{456}{5} + C[/tex][Subtraction Property of Equality] Isolate C: [tex]\displaystyle -\frac{1819}{20} = C[/tex]Rewrite: [tex]\displaystyle C = -\frac{1819}{20}[/tex]Substitute in C [Function]: [tex]\displaystyle f(t) = \frac{t^5}{5} + 91t - 3ln|t| - \frac{1819}{20}[/tex]∴ Our particular solution to the differential equation is [tex]\displaystyle f(t) = \frac{t^5}{5} + 91t - 3ln|t| - \frac{1819}{20}[/tex].
Topic: AP Calculus AB/BC (Calculus I/II)
Unit: Integration
Book: College Calculus 10e
Can someone help me pls pls help with this question
Answers
Answer:
D.
Step-by-step explanation:
The mean is 11,000
Plz help me!!(ᗒᗣᗕ)՞
Plz!
Answers
Answer:
A) 64 cm²
Step-by-step explanation:
Trapezoid area formula:
[tex]A=\frac{a+b}{2} h[/tex]
Given:
a = 6
b = 10
h = 8
Work:
[tex]A=\frac{a+b}{2} h\\\\A=\frac{6+10}{2} *8\\\\A=\frac{16}{2} *8\\\\A=8*8\\A=64[/tex]
Which is the volume of a sphere with diameter
50 cm?
Answers
Answer:
V =65416.666666 cm^3
Step-by-step explanation:
The volume of a sphere is given by
V = 4/3 pi r^3
The diameter is 50 so the radius is 1/2 of the diameter
r = 1/2 (50) = 25
V = 4/3 ( pi) (25)^3
V = 4/3 (pi) 15625
V =20833.3333 pi
Using 3.14 for pi
V =65416.666666 cm^3
Answer:
V =65416.666666 cm^3
Step-by-step explanation:
The volume of a sphere is given by
V = 4/3 pi r^3
The diameter is 50 so the radius is 1/2 of the diameter
r = 1/2 (50) = 25
V = 4/3 ( pi) (25)^3
V = 4/3 (pi) 15625
V =20833.3333 pi
Using 3.14 for pi
V =65416.666666 cm^3
What is the outlier for the data set?
19, 19, 27, 21, 77, 18, 23, 29
Answers
Answer: 77
Step-by-step explanation:
The cost of producing x units of a product is $1.25 per unit plus $1,000 in flat production costs. If you spend $3,000 on production costs, how many units were produced?
3,000=1.25x+1,000
Answers
Answer:
1600
Step-by-step explanation:
1.25x + 1000 = 3000
Subtract 1000 from both sides
1.25x = 2000
Divide both sides by 1.25
x = 1600
jack bought a mother bike the original price was 1300 but he got a discount of 20% what was the discounted price of the bike
Answers
The hypotenuse function is correct, but the main function has a problem. Explain why it may not work, and show a way to fix it. Your fix must be to the main function only; you must not change the hypotenuse function in any way.
Answers
Answer: hello your question is incomplete attached below is the missing codes
Answer : It may not work because; the double pointer P was not allotted a double using a new double ( I.e. Error in the main function ) also the cout statement was not written in the main function
Step-by-step explanation:
It may not work because; the double pointer P was not allotted a double using a new double ( I.e. Error in the main function ) also the cout statement should be moved to the Main
The correction is below
{
double* p = new double;
hypotenuse(1.5, 2.0, p);
cout << "The hypotenuse is " << *p << endl;
}
find the largest prime factor of 6108
Answers
Answer:
509
Step-by-step explanation:
There are 4 prime factors of 6108
6108 ÷ 2 = 3054
3054 ÷ 2 = 1527
1527 ÷ 3 = 509
509 ÷ 509 = 1
Determine the missing angle in the picture below.
Answers
Answer:
x =41.18114952
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
We know the hypotenuse and adjacent sides
cos theta = adjacent / hypotenuse
cos x = 14.3/19
taking the inverse cos of each side
cos^-1 (cos x) = cos ^-1 ( 14.3/19)
x =41.18114952
Answer:
Step-by-step explanation:
take x degree as reference angle
using cos rule
cos x=adjacent/hypotenuse
cos x=14.3/19
cos x=0.75
x=cos 41
x= 41 degree
Student spend 5 minutes of every 60 minutes at school moving from class to class. Which fraction is equivalent to the number of minutes student spend moving from class to class?
A. 10/120
B.no answer provided
C. 2/10
D. 10/60
E. 1/15
Answers
What is 8.75% of 172?
Answers
Answer:
15.05 is your answer.
Step-by-step explanation:
To find our answer we will first divide 8.75 by 100 since it is a percentage. 8.75 ÷ 100 = 0.0875
Now we will take 0.0875 and multiply it by 172 and we get 15.05. Therefore, 15.05 is our answer
Hey there!
8.75% of 172
The word “of” means multiply in mathematical terms.
8.75% * 172
8.75% = 8.75/100 = 0.0875
0.0875 * 172
= 301/20
= 15.05
Answer: 301/20 OR 15.05
(BOTH ANSWERS WORK because they are both equivalent)
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
4d = -16
what’s the value of d
Answers
[tex]4d = - 16 \\ \\ d = \cancel \frac{ - 16}{4} \\ \\ d = - 4[/tex]
Hope This Helps YouAnswer:
The value of d is -4. When you multiply 4 by -4 you get -16. If you want me to elaborate, let me know.
Step-by-step explanation:
plsss help!! is this a right triangle if no or yes please explain why??
Answers
Answer:
yes, it is a right triangle
Step-by-step explanation:
the other two angles are 35 and 55 degrees
Answer:
is NOT a right triangle
Step-by-step explanation:
is a right triangle if it checks the Pythagorean Th.
12² = 10² + 7²
144 = 100+49
144 = 149 False
Choose the best estimate for the multiplication problem below. 56 x 51
A. 2000
B. 3000
C. 4100
Answers
Answer:
B
Step-by-step explanation:
Explanation: 56 multiply 51 is 2856 and 3000 is the closest to 2856.
Also pls mark me as brianliest!!
A 15-foot ladder leans against the side of a house with its base 4 feet from the house. Use the Pythagorean Theorem to approximate how high the ladder reaches up the side of the house. Round your answer to the nearest hundredth.
Answers
Answer: The ladder reaches 14.46 feet up of the building.
Step-by-step explanation:
According to Pythagorean theorem,
In a right triangle,
(Hypotenuse)²= (Base)²+(perpendicular)^2
Using given information, we have
[tex](15)^2=(4)^2+(height)^2\\\\225=16+(height)^2\\\\(height)^2=209\\\\ (height)^2=\sqrt{209}\approx14.46\ feet[/tex]
Hence, the ladder reaches 14.46 feet up of the building.
How many solutions will the following equation have? 2x - 7 = -3x + 5
a. One Solution
b. Infinite Solutions
c. No Solutions
Answers
Answer:
one solution lets see[tex]2x - 7 = 3x + 5 \\ - x = 12 \\ x = - 12[/tex]
If you just want to check then substitute the value
[tex]2x - 7 = 3x + 5 \\ 2 \times ( - 12) - 7 = 3 \times ( - 12) + 5 \\ - 24 - 7 = - 36 + 5 \\ - 31 = - 31[/tex]
Hope it helps
The value of the 2 in 43,290 is
times the value
of the 2 in 32,865.
Answers
9514 1404 393
Answer:
1/10
Step-by-step explanation:
The value of any digit is found by setting all other digits to zero.
The value of the 2 in 43,290 is 200.
The value of the 2 in 32,865 is 2,000.
200 is 200/2000 = 1/10 times 2000
The value of 2 in 43,290 is 1/10 times the value of 2 in 32865.
Help will be appreciated
Answers
Answer:
48
hope this helps
have a good day :)
Step-by-step explanation:
Answer:
48
the picture 20 words or longer for the answer so this is extra text
Suppose you are investigating the relationship between two variables, traffic flow and expected lead content, where traffic flow is a predictor of lead content. You find the 95% CI for expected lead content when traffic flow is 15, based on a sample of n= 10 observations, is (461.7, 598.1).
Required:
What parameter is this interval estimating?
Answers
Answer:
The answers is " Option B".
Step-by-step explanation:
[tex]CI=\hat{Y}\pm t_{Critical}\times S_{e}[/tex]
Where,
[tex]\hat{Y}=[/tex] predicted value of lead content when traffic flow is 15.
[tex]\to df=n-1=8-1=7[/tex]
[tex]95\% \ CI\ is\ (463.5, 596.3) \\\\\hat{Y}=\frac{(463.5+596.3)}{2}\\\\[/tex]
[tex]=\frac{1059.8}{2}\\\\=529.9[/tex]
Calculating thet-critical value[tex]t_{ \{\frac{\alpha}{2},\ df \}}=-2.365[/tex]
The lower predicted value [tex]=529.9-2.365(Se)[/tex]
[tex]463.5=529.9-2.365(Se)\\\\529.9-463.5=2.365(Se)\\\\66.4=2.365(Se)\\\\Se=\frac{66.4}{2.365} \\\\Se=28.076[/tex]
When [tex]99\%[/tex] of CI use as the expected lead content: [tex]\to 529.9\pm t_{0.005,7}\times 28.076 \\\\=(529.9 \pm 3.499 \times 28.076)\\\\=(529.9 \pm 98.238)\\\\=(529.9-98.238, 529.9+98.238)\\\\=(431.662, 628.138)\\\\=(431.6, 628.1)[/tex]
Pedro solves the quadratic equation x^2+6x –14 using the quadratic formula. In which step did Pedro make an error?
Answers
9514 1404 393
Answer:
correct choice is marked
Step-by-step explanation:
The error is in step 2. The square root cannot be distributed to a sum.
HELPPPP PLZZZZZzz HELLP FAST I NEED TO PASS
Answers
Answer:
✬ m∠Q= 105°➬➬➬➬➬➬➬➬
[tex]6x+5+(11x-5)+x=180^o[/tex]
[tex]18x=180[/tex]
[tex]x=10[/tex]
☄m∠Q=105°
❆❆❆❆❆❆❆❆❆❆❆❆
hope it helps....
have a great day!!