Please help on this one ASAP please

Answer:

1) the correct answer is B ,  2)  θ= 45º,

3) the projectile A must have a greater angle ,

4A)   vₓ (B)> vₓ (A) ,  

5B)  The maximum height is reached by the projectile with the highest speed, from the front this is projectile B

7) if the vertical velocity of both projectiles is the same time is the same

therefore the two projectiles have equal flight times

Explanation:

In this long exercise you are asked to answer a series of questions about the launching of projectiles

1) Path type

since they indicate that the air resistance is negligible the horizontal displacement is

       x = v₀ₓ t

On the vertical axis, a relationship acts, which is gravity, therefore its displacement is

      y = [tex]v_{oy}[/tex] t - ½ g t²

let's substitute to eliminate time

     y = v_{oy} (x / v₀ₓ) - ½ g (x / v₀ₓ)²

    y = (tan θ) x - (g / v₀ₓ²) x²

we can see that this is the equation of a parabola

therefore the correct answer is B

2) From the missile launch expressions the range is

           R = x = v₀² sin² 2θ / g

for the range to be maximum sin 2θ = 1, this occurs for

          2θ = 90

         θ= 45º

the correct answer is "The projectile fired at an angle close to 45º lands farther"

In response D implies that the projectile has been divided into two parts, in this case it is true that the lighter part must go further.

3) From the expression of scope we can see that as the angle increases the square sine becomes smaller, for example without 180 = 0

therefore to reach the nearest ship A must launch with a greater angle, therefore the projectile A must have a greater angle

Respect the questions are a bit strange.

* If the projectiles are fired at the same angle and in the statement they indicate that the velocities are equal, the two must reach the same height 4

4A. If the vertical speed is equal, the projectile that must reach the furthest ship (B) must have more horizontal speed

          vₓ (B)> vₓ (A)

5B. Both are launched with the same horizontal speed.

which is higher

            [tex]v_{y}[/tex]² =   v_{oy}² - 2 g y

at maximum height vertical velocity is zero (v_{y} = 0)

            0 = v_{oy}² - 2 g y

            y = v_{oy}² / 2g

the maximum height is reached by the projectile with the highest speed, from the front this is projectile B

7) they both reach the same height

As the value of the acceleration due to gravity is constant, the time to go up is the same time to go down, therefore if the two projectiles reach the maximum height, the time used is

             [tex]v_{y}[/tex] = v_{oy} - g t

              0 = v_{oy} - gt

              t = v_{oy} / g

if the vertical velocity of both projectiles is the same time is the same

therefore the two projectiles have equal flight times

Answer:

Explanation:

Let the tension in horizontal rope be T₁ and in the other rope be T₂ which is making angle of 51.3⁰

The vertical component of tension T₂ will balance the weight .

= T₂ cos 51.3 = 2.9 x 9.8

T₂ = 2.9 x 9.8  / cos 51.3

= 28.42 / .625

= 45.47 N

The horizontal component of T₂ will balance T₁

T₂ sin 51.3 = T₁

45.47 sin 51.3 = T₁

T₁ = 35.48 N .

Answer:

Ro = 133 [kg/m³]

Explanation:

In order to solve this problem, we must apply the definition of density, which is defined as the relationship between mass and volume.

[tex]Ro = m/V[/tex]

where:

m = mass [kg]

V = volume [m³]

We will convert the units of length to meters and the mass to kilograms.

L = 15 [cm] = 0.15 [m]

t = 2 [mm] = 0.002 [m]

w = 10 [cm] = 0.1 [m]

Now we can find the volume.

[tex]V = 0.15*0.002*0.1\\V = 0.00003 [m^{3} ][/tex]

And the mass m = 4 [gramm] = 0.004 [kg]

[tex]Ro = 0.004/0.00003\\Ro = 133 [kg/m^{3}][/tex]

Answer:24

Explanation:

First you need to calculate the acceleration, for this use can use the following formula Force (F) = Mass (M) x Acceleration (A). If we extract A out of this, you can get the following equation A = F/M = 4/0.5 = 8 m/s^2. So, the object accelerates each second by 8 m/s, if the object does this for 3 second, the velocity would be 8 x 3 = 24

Answer:

Explanation:

14

Answer:

h = 250 m

Explanation:

Given that,

The helicopter exerts 6480  N of force on the water while rising high enough to fly over a mountain.

The helicopter does [tex]1.62\times 10^6\ J[/tex] of work on the water lifting it.

We need to find how high does it lift the water. Work done is given by :

[tex]W=Fh\\\\h=\dfrac{W}{F}\\\\h=\dfrac{1.62\times 10^6}{6480}\\\\h=250\ m[/tex]

So, it can lift the water to a height of 250 m.

Answer:

Explanation: Correct on Edg 2020/2021 for my school.

Answer:

a) 0.1

b) density = mass/volume

                 = 0.5 /0.1

                 = 5 kg/[tex]m^{3}[/tex]

Answer:

social cognitive theory

Explanation:

Albert Bandura's theory, originally called social learning theory, is now referred to as social cognitive theory, and it suggests cognitive processes play a role in influencing one's personality.

Albert Bandura's theory, originally called social learning theory, is now referred to as social cognitive theory, and it suggests cognitive processes play a role in influencing one's personality.

Cognitive processes refer to the mental processes involved in perception, attention, memory, reasoning, problem-solving, and decision-making. They involve the use of knowledge, experience, and understanding to process information and make sense of the world around us.

Here, examples of cognitive processes include perception, attention, memory, language processing, and executive functions such as planning and decision-making. Cognitive processes are essential for learning, problem-solving, and adaptive behavior, and they are an important focus of study in psychology and cognitive science.

Albert Bandura's theory, originally called social learning theory, is now referred to as social cognitive theory, and it suggests cognitive processes play a role in influencing one's personality.

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Answer:

The horizontal component of the 70 N force = 35·√3 N

The vertical component of the 70 N force = 35 N

Explanation:

The magnitude of the given force, F = 70 N

The angle of inclination of the given force to the horizontal, θ = 30°

By the resolution of forces, we can resolve the given force, F, into its horizontal component, Fₓ, and vertical components, [tex]F_y[/tex], as follows;

The horizontal component of the given force = Fₓ = F × cos(θ)

Substituting the values, we have;

The horizontal component of the 70 N force, Fₓ = 70 × cos(30°) = 35·√3 N

The vertical component of the given force = [tex]F_y[/tex] = F × sin(θ)

Substituting the values, we have;

The vertical component of the 70 N force, [tex]F_y[/tex] = 70 × sin(30°) = 35 N.

Answer:

7.07 hours

Explanation:

divide the distance by the speed

so in this case, divide 672 by 95

Answer:

c > √(2ab)

Explanation:

In this exercise we are asked to find the condition for c in such a way that the results have been real

The given equation is

              ½ a t² - c t + b = 0

we can see that this is a quadratic equation whose solution is

             t = [c ±√(c² - 4 (½ a) b)]  / 2

for the results to be real, the square root must be real, so the radicand must be greater than zero

              c² -2a b > 0

              c > √(2ab)

Small gaps which function as expansion joints are deliberately left between the rail ends to allow for expansion of the rails in hot weather. ... Because of these small gaps, when trains pass over jointed tracks they make a "clickety-clack" sound.

Answer:

μk = 0.106

Explanation:

When the box is moving across the flat surface with a constant velocity, the force applied on it must be equal to the kinetic frictional force applied on the object:

F = μk*W = μk*mg

Where,

F = Force applied on box = 52 N

m = mass of box = 50 kg

g = 9.8 m/s²

μk = coefficient of kinetic friction between box and floor = ?

Therefore,

52 N  = μk(50 kg)(9.8 m/s²)

μk = (52 N)/(490 N)

μk = 0.106

The coefficient of kinetic friction between the box and the floor will be 0.106.

A force that acts among sliding parts is referred to as kinetic friction. A body moving on the surface is subjected to a force that opposes its progressive motion

The size of the force will be determined by the kinetic friction coefficient between the two materials.

The given data in the problem is;

μ is the coefficient of kinetic friction=?

m is the mass = 50 kg

g is the acceleration due to gravity= 9.81 m/s²

v is the speed =3.5 m/sec

Force(F)= 52 Newton

The formula for kinetic friction force is;

[tex]\rm F= \mu_k R \\\\ R=mg \\\\ F= \mu_k mg \\\\\ 52 = \mu_k \times 50 \times 9.81 \\\\ \mu_k = 0.106[/tex]

Hence,the coefficient of kinetic friction between the box and the floor will be 0.106.

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the first one is c

second is b

third is c

forth is b

Answer:

1. i think its therml...it could be sound too

2. 16m

3.45

4.5.0

Answer:

More force

Explanation:

Object A has more mass than object B

  For object A to accelerate at the same rate as object B, it will need more force.

According to Newton's second law of motion "the net force on a body is the product of its mass and acceleration".

  Net force  = mass x acceleration

Now, if a body has more mass and needs to accelerate at the same rate as another one with a lower mass, the force on it must be increased.

Answer:

force×distance

Explanation:

work is the ability of an object to move a distance as a result of the force being applied

Answer:

(a) 0.081 A (b) 1358.02 ohms

Explanation:

Voltage, V = 110 volt

Power of a LED bulb, P = 9 Watt

(a) Let the current is I. The formula for ower in terms of voltage and power is given by :

P = VI

[tex]I=\dfrac{P}{V}\\\\I=\dfrac{9}{110}\\\\=0.081\ A[/tex]

(b) Let R is the resistance of the bulb. Using Ohm's law as follows :

V = IR

[tex]R=\dfrac{V}{I}\\\\R=\dfrac{110}{0.081}\\\\=1358.02\ \Omega[/tex]

Hence, this is the required solution.

(a) The current in the bulb is 82mA

(b) The resistance of the bulb is 1340 Ω

Given information:

Supply voltage, V = 110V

The power rating of the bulb, P = 9 W

(a) Current in the bulb:

The electrical power is given by:

P = VI

where V is the voltage, and I is the current

So, I = P/V

I = 9W / 110V = 0.082A

I = 82 mA

(b) Resistance of the bulb:

According to the Ohm's Law:

The relation between voltage (V), current (I), and resistance (R) is given by:

V = IR

110 = 0.082R

R = 1340 Ω

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Answer:

D) 1414 nm

Explanation:

This is correct on Edge.

Using the equation dsin(angle)=n(wavelength), we can solve for wavelength.

First we must convert the 500 lines per mm to nm. We do this by 1/500, giving you 0.002. Then move the decimal over six places to the right, resulting in 2000.

Then by plugging in the other values, we have 2000sin(45)=1(wavelength).

N is one because we are just solving for a first-order band.

So 2000sin(45)=wavelength

By using a calculator, we can see that the wavelength equals approximately 1414nm.

I hope this helped. If it did, I would really appreciate a Brainliest!!

Have a great day:)

Answer:

1414

Explanation:

took the test :)

Answer:

its the third one

Explanation:

Answer:

i think its 20m for b

Explanation:

Question

Earthquakes are essentially sound waves—called seismic waves—traveling through the earth. Because the earth is solid, it can support both longitudinal and transverse seismic waves. The speed of longitudinal waves, called P waves, is 8000 m/s Transverse waves, called S waves, travel at a slower 4500 m/s. A seismograph records the two waves from a distant earthquake. The S wave arrives 2.0 min after the PP wave.How far away is the Earthquake.  Assume that the waves travel in straight lines, although actual seismic waves follow more complex routes.

Answer:

The distance is  [tex]d = 1.23 *10^{6} \ m[/tex]

Explanation:

From the question we are told that

   The speed of longitudinal seismic  wave is  [tex]v_p = 8000 \ m/s[/tex]

    The speed of Transverse seismic  wave is  [tex]v_s = 4500 \ m/s[/tex]

     The time difference between the arrival of longitudinal seismic with respect to Transverse waves is  [tex]\Delta t = 2.0\ min = 120\ seconds[/tex]

Generally the  time difference between the arrival of longitudinal seismic with respect to Transverse waves is mathematically represented as

     [tex]\Delta t = t_p - t_s[/tex]

=>  [tex]\Delta t =\frac{d}{v_p} -\frac{d}{v_s}[/tex]

=>   [tex]d = \frac{\Delta t}{ \frac{1}{v_p} - \frac{1}{v_s} }[/tex]

=>   [tex]d = \frac{120 }{ \frac{1}{8000} - \frac{1}{4500} }[/tex]

=>   [tex]d = 1.23 *10^{6} \ m[/tex]

Answer:

is it 20kg. Two opposing forces pushing onto each other

Answer:

D

Explanation:

I took the test

The procedure that would best demonstrate that moving magnet causes an electric current to flow in a wire coil is connect a wire coil to an ammeter. Move a bar magnet into and out of the wire coil as you observe the ammeter. The correct option is D.

The flow of electricity in an electronic circuit, as well as the amount of electricity flowing through a circuit, are referred to as electric current. It is expressed in amperes (A).

The greater the value in amperes, the more electricity flows through the circuit.

When an electron is introduced into a wire, a free electron is attracted to a proton in order to be neutral.

Forcing electrons out of their orbits can result in an electron shortage. Electric current is the continuous movement of electrons in a wire.

Connecting a wire coil to an ammeter is the best way to demonstrate that a moving magnet causes an electric current to flow in a wire coil. As you watch the ammeter, move a bar magnet in and out of the wire coil.

Thus, the correct option is D.

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Answer:

direction

size

Explanation:

Vectors are physical quantities with both magnitude or size and direction.

Scalars are physical quantities with only size but not direction.

When describing a vector, on must specify its magnitude and direction.

Only the size of scalar quantities are needed to describe them.

Answer:

A. Both A and R are true and R is the correct explanation of A

Answer:

Because you have no force, the acceleration is zero and the body moves at a constant speed