Please help these are just practice problems before my test tomorrow and I need help!

Please Help These Are Just Practice Problems Before My Test Tomorrow And I Need Help!

Answers

Answer 1

Answer:

x²=20² -14²

x²=400-196

x²=204

x=√204


Related Questions

Solve the equation.
[tex] {3}^{4(m + 1)} + {3}^{4m} - 246 = 0 \\ [/tex]

Answers

[tex]3^{4m+4}+3^{4m}=246\\ (3^{4}+1)*3^{4m}=246\\82*3^{4m}=246\\3^{4m}=3\\m=\frac{1}{4}[/tex]

You group them since they have the same base (3). (3^4+1)*3^4m since they have almost the similar characters (ex. 3^4(m+1) is 3^4m+4). In the brackets we get (81+1) since 3^4 is 81, then we do the sum in the brackets (81+1) is 82 multiplied by 3^4m. Then we divide both sides with /82. 82/82 is one, 256/82 is 3. Since 3^4m and 3^1 have the same bases we just use 4m=1 where we get that m is 1/4.

help me please ...........with this work
I'm trying my best to figure out how to do this so if someone can help me with the right answer please help me

Rewrite y = x2 + 2x - 1 into vertex form.
y=(x+1)2−2 Use x = - b\2a to find the vertex (h, k).

Substitute a, h, and k into y = a(x - h)2 + k:
2a(x-h)+k 2ax-2ah+k

Answers

Answer:

Vertex form is: y = ( x + 1 )^2 − 2

Step-by-step explanation:

I'm not sure about the substitution part.

Write a linear function f with given values. F(3)=-4, f(5)= -4

Answers

Answer:

y = -4

Step-by-step explanation:

dy/dx gives you slope

(-4)-(-4)/5-3 = 0/2  ----> slope = 0

y = mx+b

m = 0

y = 0x+b

y = b

as it says F(3) and F(5) = -4 b must be -4

so you end up with y = -4

If a graphed line passes through ordered pair
points (-6, 2) and (5, 4), what is the slope of
the line?

Answers

Answer:

I think it would be 2/11 . hope it helps u ^.^

consider a population proportion p = 0.68. a-1. calculate the expected value and the standard error of p− with n = 30

Answers

If a population proportion p = 0.68, the expected value and the standard error of p' with n = 30 is 0.68 and 0.090 respectively.

To calculate the expected value and standard error of the sample proportion p' with a known population proportion p = 0.68 and a sample size n = 30, we use the formulas:

Expected value of p' (E[p']) = p

Standard error of p' (SE[p']) = √((p * (1 - p)) / n)

Given that the population proportion p = 0.68 and the sample size n = 30, we can substitute these values into the formulas:

E[p'] = p = 0.68

SE[p'] = √((p * (1 - p)) / n) = √((0.68 * (1 - 0.68)) / 30) = √(0.2176 / 30) ≈ 0.090

Therefore, the expected value of the sample proportion p' is 0.68, indicating that, on average, we expect the sample proportion to be equal to the population proportion.

The standard error of the sample proportion is approximately 0.090, representing the estimated standard deviation of the sampling distribution of p' and indicating the variability in the estimates of p'.

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Write an equivalent expression for 5+2+2x+2
please help me ​

Answers

Answer:

2x+9

Step-by-step explanation:

You have to combine like terms. 2x stays the same because there are no other like terms, but 5, 2, and 2 can be added together to make 9

9)
Consider
-196/14
Which THREE statements are correct?
A)
The quotient is 14.
B)
The quotient is -14.
The quotient is -
D)
- 196
is equivalent to the expression.
14
E)
196
-14
is equivalent to the expression.

Answers

Maybe B (not sure).................

Lacey opened a savings account and deposited $100.00. The
account earns 6% interest, compounded monthly. If she wants
to use the money to buy a new bicycle in 2 years, how much
will she be able to spend on the bike?
Round your answer to the nearest cent.

Answers

Answer:

$244.00

Step-by-step explanation:

- gave bank $100

- +6% of $100 per month

- 6% of $100 = $6 (earns $6 per month)

- twelve months in a year, so 12 x $6 = $72 per year

- $100 + $72 + $72 = $244

If Lacey wants to utilize her money to purchase a new bicycle in two years, she will spend $244 on the bike.

Adjust the equation so the line passes through the points.

Answers

Put a negative sign in front of the 3/2

Help yalll please

Find the vale of X

Answers

Answer:

45°

Step-by-step explanation:

x should be the equivalent angle as the 45° given, as this is a perfect circle, so the distance from the center shouldn't affect the angle

Let z = (a + ai)(b + b/3i) where a and b are positive real numbers. Without using a calculator, determine arg z.

Answers

The argument (arg) of the complex number z = (a + ai)(b + b/3i), where a and b are positive real numbers, is π/6 radians or 30 degrees.

To determine the argument (arg) of the complex number z = (a + ai)(b + b/3i), where a and b are positive real numbers, we can simplify the expression and find the argument without using a calculator.

First, expand the product (a + ai)(b + b/3i):

z = (a + ai)(b + b/3i)

 = ab + ab/3i + abi - ab/3

Combining like terms, we get:

z = (ab - ab/3) + (ab/3 + ab)i

 = (2ab/3) + (ab/3)i

Now, we have the complex number z in the form z = x + yi, where x = 2ab/3 and y = ab/3.

To compute the argument (arg) of z, we can use the definition of the argument as the angle θ between the positive real axis and the line connecting the origin to the complex number z in the complex plane.

Since a and b are positive real numbers, both x and y are positive.

The argument (arg) of z can be determined as:

arg z = arctan(y/x)

      = arctan((ab/3) / (2ab/3))

      = arctan(1/2)

      = π/6

Therefore, without using a calculator, the argument (arg) of the complex number z = (a + ai)(b + b/3i) is π/6 radians or 30 degrees.

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a company staff consists of 20 accountants, 12 economists and 4 secretaries. a staff is chosen at random. Find the probability that the staff is an accountant. With solution.​

Answers

Answer:

5/9

Step-by-step explanation:

Number of accountants = 20

Number of economists = 12

Number of secretaries = 4

Total number of Staffs = 20 + 12 + 4 = 36 staffs

Probability = required outcome / Total possible outcomes

Required outcome = number of accountants

Total possible outcomes = total number of staffs

P(selecting an economist) = 20 / 36 = 5 / 9

The probability that the staff is an accountant is 5/9.

Given

A company staff consists of 20 accountants, 12 economists and 4 secretaries. a staff is chosen at random.

Probability;

Probability is defined as the number of observations and total number of observation.

Total number of Staffs = 20 + 12 + 4 = 36 staffs.

The following formula is used to determine the probability;

[tex]\rm Probability=\dfrac{Accountant \ staff}{Total \ number \ of \ staff}[/tex]

Substitute all the values in the formula;

[tex]\rm Probability=\dfrac{Accountant \ staff}{Total \ number \ of \ staff}\\\\\rm Probability=\dfrac{20}{36}\\\\\rm Probability=\dfrac{5}{9}[/tex]

Hence, the probability that the staff is an accountant is 5/9.

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(5)
A plane contains the points A(1, 2, 8), B(-2, 3, 6), and C(5,-1, 4).
(a) Determine 2 vectors parallel to the plane.
(b) Determine 2 vectors perpendicular to the plane.
(C) Write a vector equation of the plane.
(d) Write a scalar equation of the plane.
(e) Determine if the point D(-7, 4, 0) is contained in the plane.
(f) Write an equation of the line through the y and z intercepts of the plane.

Answers

Answer:

7

Step-by-step explanation:


pleaae help explain and write clearly thank you
you need to write a post describing either the column space or the null space of a matrix.

Answers

The null space of a matrix is the set of all vectors that satisfy the equation Ax = 0.

The null space of a matrix is the set of all vectors that satisfy the equation Ax = 0. In other words, the null space of a matrix A is the set of all solutions x to the equation Ax = 0. The null space of a matrix is also known as the kernel of a matrix. It is a subspace of the vector space R^n. The null space of a matrix can be used to determine if a system of linear equations has a unique solution, no solution, or infinitely many solutions. If the null space of a matrix is the zero vector, then the system has a unique solution. If the null space of a matrix is non-empty, then the system has infinitely many solutions. A matrix is an array of numbers that has been set up in rows and columns to make a rectangular shape. The elements, or entries, of the matrix are the integers. In addition to numerous mathematical disciplines, matrices find extensive use in the fields of engineering, physics, economics, and statistics. In computer graphics, where they have been used to describe picture rotations and other transformations, matrices have vital applications as well.

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Calculate the mean, median, and range of the data in the dot plot.

Answers

Answer:

median = 5

range = 2

mean = 11

Step-by-step explanation:

Draw the graph of y = log, (z) - 4

Answers

The graph of y = log(z) - 4 is a downward shifted logarithmic function with a vertical asymptote at z = 0.

The equation y = log(z) - 4 represents a logarithmic function. The graph of a logarithmic function typically consists of a vertical asymptote, which is a vertical line that the graph approaches but never crosses. In this case, the vertical asymptote occurs at z = 0, as the logarithm of a negative number is undefined.

The graph is vertically shifted downward by 4 units, which means that the entire graph is shifted downward by 4 units compared to the standard logarithmic function. This shift moves the graph downward parallel to the y-axis.

The domain of the function is the set of positive real numbers (z > 0), as the logarithm is defined only for positive values. The range of the function is all real numbers, as the graph extends infinitely in both the positive and negative y-directions.

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A rooted tree where every other vertex is connected to the root by an edge is called a bonsai tree. (This includes the case where the tree is a seed, with no other vertices besides the root.) A collection of bonsai trees is called a bonsai forest. If n and k are positive integers, explain why the number of labeled bonsai forests with n vertices and k trees is (3) kn-k.

Answers

The number of labeled bonsai forests with n vertices and k trees is given by (3)^(kn-k).

The number of labeled bonsai forests with n vertices and k trees is (3)^(kn-k).

To understand why this is the case, let's break it down step by step.

First, let's consider a single bonsai tree with a root and n-1 other vertices connected to the root.

Each of these n-1 vertices can have one of three choices: either it is connected to the root, it is not connected to the root, or it is the root itself. Therefore, for a single bonsai tree, we have 3^(n-1) possibilities.

Now, if we have k bonsai trees, we can treat each tree as an independent entity. Therefore, the total number of labeled bonsai forests with k trees would be the product of the number of possibilities for each individual tree.

Hence, the total number of labeled bonsai forests with n vertices and k trees is (3)^(n-1) * (3)^(n-1) * ... * (3)^(n-1) (k times), which can be written as (3)^(kn-k).

In simpler terms, for each vertex in the bonsai forest, there are three possible choices: being connected to the root, not connected to the root, or being the root itself. As each vertex is independent and has the same three choices, the total number of possibilities for the entire forest is calculated by multiplying the number of possibilities for each vertex (3) by itself (n-1) times, for a total of kn-k times.

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Fill in the blanks:- If y = 2 - x + x2 + 8ex is a solution of a homogeneous fourth-order linear differential equation with constant coefficients, then the roots of the auxiliary equation are_________ .

Answers

The roots of the auxiliary equation for a homogeneous fourth-order linear differential equation with constant coefficients, given that the solution is y = 2 - x + x^2 + 8e^x, are -1, -1, -2, and -2.

For a homogeneous linear differential equation with constant coefficients, the auxiliary equation is obtained by replacing the derivatives of y with powers of the variable. In this case, since the given solution is y = 2 - x + x^2 + 8e^x, we differentiate y with respect to x to obtain the derivatives.

The fourth-order linear differential equation corresponds to the fourth power of the variable, which is x. Therefore, the auxiliary equation is a polynomial equation of degree four. To find the roots of the auxiliary equation, we set the polynomial equal to zero and solve for x.

The roots of the auxiliary equation for this particular solution, after solving the polynomial equation, are -1, -1, -2, and -2. These values represent the roots of the characteristic equation and are crucial in determining the form of the general solution of the differential equation.

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Favorite Songs? I need to update my playlist!

Answers

Step-by-step explanation:

megan thee stallion songs

cardi b's songs

space cadet-gunna

astronaut in the ocean

Flo milli

and my personal favorite

knock knock- sofaygo

solve the following question

Answers

Answer:

g) [tex]u^{4}\cdot v^{-1}\cdot z^{3}[/tex], h) [tex]\frac{(x+4)\cdot (x+2)}{3\cdot (x-5)}[/tex]

Step-by-step explanation:

We proceed to solve each equation by algebraic means:

g) [tex]\frac{u^{5}\cdot v}{z}\div \frac{u\cdot v^{2}}{z^{4}}[/tex]

1) [tex]\frac{u^{5}\cdot v}{z}\div \frac{u\cdot v^{2}}{z^{4}}[/tex] Given

2) [tex]\frac{\frac{u^{5}\cdot v}{z} }{\frac{u\cdot v^{2}}{z^{4}} }[/tex] Definition of division

3) [tex]\frac{u^{5}\cdot v\cdot z^{4}}{u\cdot v^{2}\cdot z}[/tex]   [tex]\frac{\frac{a}{b} }{\frac{c}{d} } = \frac{a\cdot d}{b\cdot c}[/tex]

4) [tex]\left(\frac{u^{5}}{u} \right)\cdot \left(\frac{v}{v^{2}} \right)\cdot \left(\frac{z^{4}}{z} \right)[/tex]  Associative property

5) [tex]u^{4}\cdot v^{-1}\cdot z^{3}[/tex]   [tex]\frac{a^{m}}{a^{n}} = a^{m-n}[/tex]/Result

h) [tex]\frac{x^{2}-16}{x^{2}-10\cdot x + 25} \div \frac{3\cdot x - 12}{x^{2}-3\cdot x -10}[/tex]

1) [tex]\frac{x^{2}-16}{x^{2}-10\cdot x + 25} \div \frac{3\cdot x - 12}{x^{2}-3\cdot x -10}[/tex] Given

2) [tex]\frac{\frac{x^{2}-16}{x^{2}-10\cdot x+25} }{\frac{3\cdot x - 12}{x^{2}-3\cdot x - 10} }[/tex] Definition of division

3) [tex]\frac{(x^{2}-16)\cdot (x^{2}-3\cdot x -10)}{(x^{2}-10\cdot x + 25)\cdot (3\cdot x - 12)}[/tex]  [tex]\frac{\frac{a}{b} }{\frac{c}{d} } = \frac{a\cdot d}{b\cdot c}[/tex]

4) [tex]\frac{(x+4)\cdot (x-4)\cdot (x-5)\cdot (x+2)}{3\cdot (x-5)^{2}\cdot (x-4) }[/tex] Factorization/Distributive property

5) [tex]\left(\frac{1}{3} \right)\cdot (x+4)\cdot (x+2)\cdot \left(\frac{x-4}{x-4} \right)\cdot \left[\frac{x-5}{(x-5)^{2}} \right][/tex] Modulative and commutative properties/Associative property

6) [tex]\frac{(x+4)\cdot (x+2)}{3\cdot (x-5)}[/tex]  [tex]\frac{a^{m}}{a^{n}} = a^{m-n}[/tex]/[tex]\frac{a}{b}\times \frac{c}{d} = \frac{a\cdot c}{b\cdot d}[/tex]/Definition of division/Result

Martin is considering the expression 1/2(7x+48)and -(1/2x-3)+4(x+5)​

Answers

Step-by-step explanation:

1/2(7x+48) = 7x ÷2 +48÷2 = 7x÷2 + 24

and

-(1/2x-3)+4(x+5) = 7x ÷2 + 46÷2 = 7x÷2 +23

What is the median amount of water (in ounces) that Mindy drank per day

Answers

Answer:

i need the rest of the problem to figure it out sorry

Step-by-step explanation:

Answer:

60 ounces

Step-by-step explanation:

got i t on edmentum

Please help me!! No files allowed. I need the answer and an explanation!

Answers

Answer:

27/86

Step-by-step explanation:

the difference is multiplying by 3. next number is

27/86

please tell me where to plot the points and what the solution will be.

Answers

The graph would look like this...

The population P (in thousands) of Austin, Texas, during a recent decade can be approximated by

y=494.29(1.03)t,
y=494.29(1.03)t,

where t is the number of years since the beginning of the decade. a. Tell whether the model represents exponential growth or exponential decay. Identify the annual percent increase or decrease in population. c. Estimate when the population was about 590,000.

Answers

The given model represents exponential growth as the base is greater than 1. Hence, the population will increase every year.

When a quantity grows or increases at a constant rate per unit of time, it is called exponential growth.Exponential decay: When a quantity decreases at a constant rate per unit of time, it is called exponential decay.The given model for population growth isy = 494.29(1.03)t, where t is the number of years since the beginning of the decade. Here, the base of the exponential is 1.03, which is greater than 1. So, the given model represents exponential growth.The annual percent increase in population is 3% (as 1.03 is a 3% increase in each year).c. We need to estimate when the population was about 590,000. To do this, we need to substitute y = 590 in the given equation and solve for t.494.29(1.03)t = 5904.31t = log(590/494.29) / log(1.03) = 12.91 years approximatelyTherefore, the population was about 590,000 in the 13th year, i.e., after 12 years (as it is given that t is the number of years since the beginning of the decade).

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What is the midpoint of line segment QU given Q(6, 3) and P(-6, -1).

Answers

Answer: Use cylindrical coordinates. Evaluate z dv, where E is enclosed by ... A: Solution:Given∫c3y sinx dx+5xdyFormula:∫cPdx+Qdy=∬ ∂Q∂x-∂P∂y dA ... z) if the midpoint of the line segment joining the two points (x, y, z) and (-6, -5, -4). ... A: A cone is a 3-D shape with a circular base and tapers smoothly over to an

Step-by-step explanation:

BRAINLIESTTTTT PLZZZZ

Answers

Answer:

Slope is -5/3

Step-by-step explanation: when you look at the graph, the line is descending meaning it will be a negative, so we can eliminate the answers that are positive leaving us with 2 options. Then we have to do rise/run, you figure that out by counting how many points the line goes up and to the right or left, and intersects with the line

10. Use the two given poInts and calculate the slope.
(7,2), (6,1)

Answers

Answer:

The answer is m=1 , the slope is 1

Step-by-step explanation:

Joe plays basketball for the Wildcats and missed some of the season due to an injury. He did soune calculations that showed the mean number of points scored by his team was greater when he played than when he did not play. Here we test whether or not the mean was significantly greater The table summarizes this data where the i's are actually population means but we treat them like sample means. The degrees of freedom (d.f.) is given to save calculation time if you are not using software The Test: Test the claim that the mean points scored by the team was significantly greater when Joe played. Use a 0.05 significance level With Joe () 12 74.1 12.5 6.52 Without Joe (865.7 38.2 6.18 d.. 16 1 • Example 1: Using the given data, test the claim that the mean cholesterol level for all men who is the drug is less than the mean for those who do not use the drug. Assume both populations are normally distributed and use a 0.05 significance level. men Cholesterol Levels in mg/dL. No Drug (13) 237 289 257 228 303 275 262 304 214 233 263.2 811.1 28.6 Drug (12) 194 210 230 186 266 222 242 281 240 212 231.2 864.0 29.4 1. Here we are claiming that which means > Or-2 > 0.

Answers

The t-test allows us to evaluate whether the mean points scored by the team were significantly different between the scenarios with and without Joe.

To test the claim that the mean points scored by the team were significantly greater when Joe played, we can perform a t-test for independent samples.

Let's denote the mean number of points scored by the team when Joe played as mu1 and the mean number of points scored when Joe did not play as  mu2. The null hypothesis (H0) is that μ1 is not significantly greater than mu2, and the alternative hypothesis (H1) is that μ1 is significantly greater than mu2.

To perform the t-test, we need the sample means, standard deviations, and sample sizes for both scenarios (with Joe and without Joe). From the given data, we have the following:

With Joe:

Sample mean (x1) = 74.1

Sample standard deviation (s1) = 12.5

Sample size (n1) = 12

Without Joe:

Sample mean (x2) = 65.7

Sample standard deviation (s2) = 38.2

Sample size (n2) = 16

Now we can calculate the test statistic using the formula:

t = (x1 - x2) / sqrt((s1^2 / n1) + (s2^2 / n2))

Plugging in the values, we get:

t = (74.1 - 65.7) / sqrt((12.5^2 / 12) + (38.2^2 / 16))

Next, we determine the degrees of freedom (df) for the t-distribution. Since the sample sizes are different for the two scenarios, we use the approximate formula:

df = ((s1^2 / n1 + s2^2 / n2)^2) / ((s1^2 / n1)^2 / (n1 - 1) + (s2^2 / n2)^2 / (n2 - 1))

Plugging in the values, we get:

df = ((12.5^2 / 12 + 38.22 / 16)^2) / ((12.5^2 / 12)^2 / (12 - 1) + (38.2^2 / 16)^2 / (16 - 1))

After calculating the t-value and degrees of freedom, we can compare the t-value to the critical value from the t-distribution at the desired significance level (0.05). If the t-value is greater than the critical value,  and reject the null hypothesis and conclude that the mean points scored by the team were significantly greater when Joe played.

The specific calculations will depend on the actual data provided, but this explanation provides a general framework for performing the test.

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Consider the following quadratic models: (1) y = 1 – 2x + x2 (2) y = 1 + 2x + x2 (3) y = 1 + x2 (4) y = 1 - 42 (5) y = 1 + 372 y a. Graph each of the quadratic models, side by side, on the same sheet of graph paper

Answers

All the graph of equations are shown in figure.

We have to given that,

All the quadratic equations are,

1) y = 1 - 2x + x²

2) y = 1 + 2x + x²

3) y = 1 + x²

4) y = 1 - x²

5) y = 1 + 3x²

We can see that,

All the equation form a quadratic equation.

Hence, Each graph shows a parabola.

Therefore, All the graph of equations,

1) y = 1 - 2x + x²

2) y = 1 + 2x + x²

3) y = 1 + x²

4) y = 1 - x²

5) y = 1 + 3x²

are shown in figure.

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