Please Help With This Question?!?

As a cold front moved in the temperature dropped
3 degrees Fahrenheit each hour for 6 hours. What
was the total temperature change after 6 hours? Will your answer be positive or negative?

a) The probability of finding   a meter stick with a length of more than 100.04cm is 0.44013.

b) The probability of finding a group of 42 meter sticks with a mean length of less than 99.82 cm is 0.65866.

c) The probability of finding a group of 50 meter sticks with a mean length of more than 99.87 cm is 0.44013.

d) The probability of finding   a group of 28 meter sticks with a mean length of between 99.82and 99.86 cm is 0.11974.

e) The mean length that would be at the 92nd percentile for a random sample of 32 meter sticks is 99.89714 cm.

a) The probability of finding a meter stick   with a length of more than 100.04cm is

P(X >   100.04 ) =1 - P(X <= 100.04)

= 1- Φ((100.04   - 99.84) / 0.2)

= 1 - Φ(0.12)

= 1 - 0.55987

= 0.44013

b) The probability of finding a group of 42 meter sticks with a mean length of less than 99.82 cm is

P(¯X < 99.82) = 1 - P(X >= 99.82)

= 1 - Φ((99.82 - 99.84) / 0.2 / √42)

= 1 - Φ(-0.1)

= 1 - 0.34134

= 0.65866

c) The probability of finding a group of 50 meter sticks with a mean length of more than 99.87 cm is

P(X > 99.87) = 1 - P(X <= 99.87)

= 1 - Φ((99.87 - 99.84) / 0.2 / √50)

= 1 - Φ(0.15)

= 0.44013

d) The   probability of finding a group of 28 meter sticks with a mean length of between 99.82 and 99.86 cm    is

P(99.82 < X  < 99.86) = Φ  ((99.86 - 99.84)/ 0.2 / √28) - Φ((99.82 - 99.84) / 0.2/ √28)

= Φ(0.15) - Φ(0.12)

= 0.55987 - 0.44013

= 0.11974

e) The mean length that would be at the 92nd percentile for a random sample of 32-meter sticks is

X₉₂ = μ + z₉₂ σ / √n

= 99.84 + z₉₂ (0.2) / √32

= 99.84 + 1.85 (0.2) / √32

= 99.84 + 0.05714

= 99.89714

Therefore, the mean length that would be at the 92nd percentile for a random sample of 32 meter sticks is 99.89714 cm.

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Answer:

31 degrees

Step-by-step explanation:

1. since angle x and angle y are congruent, and segment xw and segment yw are congruent, you can assume that angle xzw and angle wzy are also congruent.

2. set angle xzw and angle wzy equal to each other

8x-1 = 5x+11

3. combine like terms

3x = 12

4. simplify to find the value of x

x = 4

5. plug x into the equation to find the degree of angle wzy

5(4)+11

20+11

=31 degrees

Answer:

The equation of the line that passes through the given points is ;

7y = -x + 12

Step-by-step explanation:

Here, we want to get the equation of the line that passes through the given points

The general equation form

is;

y = mx + b

where m is the slope and b is the y-intercept

Now, let us substitute the x and y coordinate values of each of the points;

for (-2,2); we have

2 = -2m + b

b = 2m + 2 •••••(i)

for F;

1 = 5m + b

b = 1-5m ••••••(ii)

Equate both b

1-5m = 2m + 2

1-2 = 2m + 5m

7m = -1

m = -1/7

Recall;

b = 2m + 2

b = 2(-1/7) + 2

b = -2/7 + 2

b = (-2 + 14)/7 = 12/7

The equation of the line is thus;

y = -1/7x + 12/7

Multiply through by 7

7y = -x + 12

Answer:

1.202

Step-by-step explanation:

Answer:

The difference between the absolute values of these two temperatures is 19°F.

Step-by-step explanation:

|-13| = 13

|6| = 6

13 + 6 = 19°F

Answer:

19

Explanation:

an absolute value is the value of a number without considering its sign.

thus, we can calculate the difference as such:

6 - (- 13) = 6 + 13 = 19

the difference between the absolute values of these two temperatures is 19.

i hope this helps! :D

The proportion of mature pecan trees between 43 and 46 feet tall can be calculated using the normal distribution with a mean of 42 feet and a standard deviation of 7.5 feet.

To find the proportion, we need to calculate the z-scores corresponding to the given heights and then find the area under the normal curve between those z-scores.

First, we calculate the z-score for 43 feet:

z1 = (43 - 42) / 7.5 = 0.1333

Next, we calculate the z-score for 46 feet:

z2 = (46 - 42) / 7.5 = 0.5333

Using a standard normal distribution table or a calculator, we can find the area between these two z-scores. The area corresponds to the proportion of trees between 43 and 46 feet tall.

The explanation would involve using a standard normal distribution table or a calculator to find the area under the normal curve between the z-scores of 0.1333 and 0.5333. This area represents the proportion of mature pecan trees between 43 and 46 feet tall.

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By applying the the FOIL method, which stands for First, Outer, Inner, Last  we obtained the result -84 + 80i for (4 + 10i)^2.

To calculate (4 + 10i)^2, we can:

First, we multiply the first terms of each binomial:

(4 + 10i) * (4 + 10i) = 16 + 40i

Next, we multiply the outer terms of each binomial:

(4 + 10i) * (4 + 10i) = 16 + 40i

Then, we multiply the inner terms of each binomial:

(4 + 10i) * (4 + 10i) = 16 + 40i

Finally, we multiply the last terms of each binomial:

(4 + 10i) * (4 + 10i) = 100i^2

We know that i^2 is equal to -1, so we can substitute that in:

100(-1) = -100

Putting it all together, we get:

(4 + 10i)^2 = 16 + 40i + 40i + (-100)

= -84+80i

Therefore, by applying this method for squaring a complex number, we obtained the result -84 + 80i for (4 + 10i)^2.

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{{{ THE BOLDED CHARACTERS SHOULD BE SMALL. }}}

A sequence can be generated by using an = a(n-1) - 5, where a1 = 100 and n is a whole number greater than 1.

a1 = 100 (given)

a2 = a1 - 5 = 100 - 5 = 95

a3 = a2 - 5 = 95 - 5 = 90

a4 = a3 - 5  = 90 - 5 = 85

a5 = a4 - 5 = 85 - 5 = 80

ANSWER for PART (a): 100, 95, 90, 85, 80

-----------------------------------------------------------------------------

an = a1 + d(n - 1)

an = 100 + -5(n - 1)

an = 100 + -5n + 5

an = 105 - 5n

ANSWER for PART (b): an = 105 - 5n

Answer:

I agree with the person above me and here give him brainliest

Step-by-step explanation:

The volume of the prism with an equilateral triangular base of side S and altitude h is (S * h^2 * sqrt(3))/4.

To find the volume of a prism with an equilateral triangular base using integration, we can divide the prism into infinitesimally small slices parallel to the base and integrate their volumes.

Consider an infinitesimally thin slice located at a distance "y" from the base. The length of this slice is equal to the length of the base, S. The width of the slice at distance "y" can be determined by considering the height of the equilateral triangle at that distance, which is given by h - (h/S) * y.

The volume of this slice is then given by the product of its length, width, and infinitesimal thickness dy, which is S * [h - (h/S) * y] * dy.

To find the total volume, we integrate this expression from y = 0 to y = h:

V = ∫[0,h] S * [h - (h/S) * y] dy.

Evaluating this integral gives us the volume of the prism:

V = S * [h * y - (h/S) * (y^2/2)] evaluated from y = 0 to y = h.

Simplifying this expression yields:

V = (S * h^2 * sqrt(3))/4.

Therefore, the volume of the prism with an equilateral triangular base of side S and altitude h is (S * h^2 * sqrt(3))/4.

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The length M is 12

The measure of the angle BEC is 102

The measure of the arc AB is 128

The length PQ is 18.3

The length M can be calculated using

M² = 8 * (8 + 10)

So, we have

M² = 144

Take the square roots

M = 12

The measure of the angle BEC can be calculated using

BEC = 1/2 * (BC + AD)

So, we have

BEC = 1/2 * (156 + 48)

Evaluate

BEC = 102

The measure of the arc ABcan be calculated using

AB = 180 - 2 * BC

So, we have

AB = 180 - 2 * 26

Evaluate

AB = 128

The length PQ can be calculated using

x² = (12 + 8)² - 8²

So, we have

x² = 336

Take the square roots

x = 18.3

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Answer:

Step-by-step explanation:

lol true

(a) There are 840 distinguishable permutations of the letters in the word "initial." (b) There are 180 distinguishable permutations of the letters in the word "Hawaii." (c) There are 420 distinguishable permutations of the letters in the word "decreed."

(a) For the word "initial," we have a total of 7 letters, with 2 "I"s, and 1 occurrence of each of the remaining letters. Applying the formula, we get:

n! / (3!1!1!1!1!) = 7! / (3!1!1!1!1!) = (7 × 6 × 5 × 4 × 3 × 2 × 1) / (3 × 2 × 1 ×1 × 1 × 1 × 1) = 840

(b) For the word "Hawaii," we have a total of 6 letters, with 1 "H," 2 "A"s, and 2 "I"s. Applying the formula, we get:

n! / (1!2!1!2!) = 6! / (1!2!1!2!) = (6 × 5 × 4 × 3 × 2 × 1) / (1 × 2 × 1 × 2 × 1 × 1) = 180

(c) For the word "decreed," we have a total of 7 letters, with 2 "E"s, 3 "D"s, and 1 occurrence of each of the remaining letters. Applying the formula, we get:

n! / (2!3!1!1!) = 7! / (2!3!1!1!) = (7 × 6 × 5 × 4 × 3 × 2 × 1) / (2 × 1 × 3 × 2 × 1 × 1 × 1) = 420

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To determine the standard error of the estimated slope coefficient and its statistical significance, more information is needed, such as the t-statistic or the p-value associated with the estimated slope coefficient. The options provided do not include the necessary details to make a conclusion.

The standard error of the estimated slope coefficient measures the precision or variability of the estimated coefficient. It provides information about how much the estimated slope coefficient could vary across different samples.

The t-statistic and the p-value, on the other hand, are used to assess the statistical significance of the estimated slope coefficient. The t-statistic measures the number of standard errors the estimated coefficient is away from zero, while the p-value indicates the probability of observing a coefficient as extreme as the estimated one under the null hypothesis that the true coefficient is zero.

Without the t-statistic or p-value, it is not possible to determine the statistical significance of the estimated slope coefficient at the 5% level.

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S is not orientable.

Given a regular surface S in R given by x² + y² = 2022, we need to find out whether S is orientable or not.

The surface is given by, x² + y² = 2022.

Rearranging the terms, we get, y² = 2022 - x²

Let the differentiable function g(x, y) = y, and the set U be the upper hemisphere (upper half) of the surface S.

Then, U = {(x, y, z) : x² + y² = 2022, z ≥ 0}

We know that the partial derivatives of the above function are continuous in U and it follows that U is a regular surface.

We now compute the partial derivatives of g(x, y) :∂g/∂x = 0, and ∂g/∂y = 1

Taking the cross-product of the two partial derivatives, we get : (0i - j + 0k) which is -j.

Now, if we define the positive normal to U to be the upward-pointing unit normal, then we see that (-j) points downward at all points on U.

Thus, U is not orientable.

Therefore, we conclude that the given surface S in R is not orientable.

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Answer:

14

Step-by-step explanation:

separate the figure into two  shapes. On the little one is 2x1 which the answer is 2 then on the larger shape is 6x2 which is 12 then you add 12+2 and then you get your answer

Answer:

2a°+2a°=180°[opposite angle of cyclic quadrilateralis 180°]

4a°=180

a=180°/4

a=45°

4b+2b=180°[similarly]

6b=180°

b=180°/6

b=30

The vector v can be written as the sum of a vector in Span{u} and a vector orthogonal to u as follows: v = (1/5)u + (-4/5)[1 -3].

The main answer can be obtained by decomposing the vector v into two components: one component lies in the span of vector u, and the other component is orthogonal to u. To find the vector in the span of u, we scale the vector u by the scalar (1/5) since v = - [3 1] can be written as (-1/5)[2 1]. This scaled vector lies in the span of u and can be denoted as (1/5)u.

To find the vector orthogonal to u, we subtract the vector in the span of u from v. This can be calculated by multiplying the vector u by the scalar (-4/5) and subtracting the result from v. The orthogonal component is obtained as (-4/5)[1 -3].

Thus, we have successfully decomposed vector v as v = (1/5)u + (-4/5)[1 -3], where (1/5)u lies in the span of u and (-4/5)[1 -3] is orthogonal to u.

In linear algebra, vector decomposition is a fundamental concept that allows us to express a given vector as a sum of vectors that have specific properties. The decomposition involves finding a vector in the span of a given vector and another vector that is orthogonal to it. This process enables us to analyze the behavior and properties of vectors more effectively.

In the context of this problem, the vector v is decomposed into two components. The first component, (1/5)u, lies in the span of the vector u. The span of a vector u is the set of all vectors that can be obtained by scaling u by any scalar value. Therefore, (1/5)u represents the part of v that can be expressed as a linear combination of u.

The second component, (-4/5)[1 -3], is orthogonal to u. Two vectors are orthogonal if their dot product is zero. In this case, we subtract the vector in the span of u from v to obtain the orthogonal component. By choosing the scalar (-4/5), we ensure that the resulting vector is orthogonal to u.

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Answer:

450 cm ^3

Step-by-step explanation:

The length function f(w) of a string w = w₁w₂...W), where n ∈ N and Vi ∈ W: € 9, is equal to n.

The length function f(w) is defined recursively based on the structure of the string w. In the base case, if w is an empty string (ε), the length is defined as 0. In the recursive case, if w can be written as au, where a is a character from the alphabet and u is a string over the alphabet Σ, then the length is defined as 1 plus the length of u.

To prove that for any string w =w₁w₂...wy, where n ∈ N and Vi ∈ W: € 9, the length function f(w) is equal to n, we will use a proof by induction.

For w = ε (an empty string), we have f(ε) = 0, which satisfies the condition when n = 0.

Assume that for any string w = w₁w₂...wn, where n ∈ N and Vi ∈ W: € 9, the length function f(w) = n.

Now, consider a string w' = w₁w₂...wn+1. By the recursive definition, we can write w' as au, where a is the last character wn+1 and u is the string w₁w₂...wn. From our assumption, we know that f(u) = n.

Therefore, f(w') = 1 + f(u) = 1 + n = n + 1.

Since we have established that for any string w = w₁w₂...wy, where n ∈ N and Vi ∈ W: € 9, the length function f(w) = n, we can conclude that f(w) = n.

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To verify that a matrix A satisfies the conditions A € M2x2(R), A = [a b; c d], and det(A) = 0, we can use the formula for the determinant of a 2x2 matrix:

det(A) = ad - bc

In this case, since det(A) = 0, we have:

ad - bc = 0

This formula allows us to check whether a given matrix satisfies the given conditions.

To find three matrices A when a = 5 and det(A) = 27, we can use the formula:

ad - bc = 27

Let's assume b = 1, c = 0, and d = 27/a.

Substituting these values into the formula, we get:

5 * (27/a) - 1 * 0 = 27

135/a = 27

a = 135/27

a = 5

Therefore, one possible matrix A that satisfies the conditions is:

A = [5 1; 0 27/5]

Similarly, we can find two more matrices by choosing different values for b, c, and d, as long as the determinant condition is satisfied.

Now, let's suppose B is a matrix such that det(B) = det(A):

B = [p q; r s]

To show that det(B) = det(A), we can equate their determinants:

det(B) = det(A)

ps - qr = ad - bc

Since we already know that ad - bc = 0, we can conclude that:

ps - qr = 0

This equation shows that the determinant of B is also zero, satisfying the condition det(B) = 0.

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Answer:

x = 27.2 or 27 1/5

Step-by-step explanation:

cos 54° = 16/x

x = 27.2 or 27 1/5

Answer:

13

Step-by-step explanation:

Answer:

13

Step-by-step explanation:

Hello There!

We can calculate the distance between two points using the distance formula

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

where the x and y values are derived from the coordinates in which you are trying to find the distance between

The points we need to find the distance between is (3,-8) and (8,4)

So we plug the x values and y values into the formula

[tex]d=\sqrt{(8-3)^2+(4-(-8)^2} \\8-3=5\\4-(-8)=12\\d=\sqrt{5^2+12^2} \\5^2=25\\12^2=144\\144+25=169\\\sqrt{169} =13[/tex]

so we can conclude that the distance between the two points is 13 units

Answer: 12.5

Step-by-step explanation:

Answer:

20.25

Step-by-step explanation:

Just multiply the base and height then divide the results in half.

Hope this helps!

Answer:

$2,725

Step-by-step explanation:

The maximum number of days is 7.

The cost per days is $375.

The cost for 7 days is 7 * $375 = $2,625.

The owner applies a $100 fee for cleaning which must be added to the cost of the days.

$2,625 + $100 = $2,725

The greatest value for the range is the greatest cost there can be which is $2,725.

a) The proportion of male Internet users who use social networking is approximately 0.6747, and the proportion of female Internet users who use social networking is approximately 0.7358.

b) The difference in proportions is approximately -0.0611.

c) The standard error of the difference is approximately 0.0181.

d) The 95% confidence interval for the difference between these proportions is (-0.096, -0.026).

To calculate the standard error of the difference and find a 95% confidence interval for the difference between the proportions, we can use the formulas for proportions and their differences.

Let [tex]p_1[/tex] be the proportion of male Internet users who use social networking, and [tex]p_2[/tex] be the proportion of female Internet users who use social networking.

a) Proportion for male Internet users: [tex]p_1[/tex] = 517/766 = 0.6747

Proportion for female Internet users: [tex]p_2[/tex] = 692/941 = 0.7358

b) Difference in proportions: [tex]p_1 - p_2[/tex] = 0.6747 - 0.7358 = -0.0611

c) The standard error of the difference (SE) can be calculated using the formula:

[tex]SE = \sqrt{(p_1(1-p_1)/n_1) + (p_2(1-p_2)/n_2)}[/tex]

Where [tex]n_1[/tex] and [tex]n_2[/tex] are the sample sizes for male and female Internet users, respectively.

For male Internet users: [tex]n_1[/tex] = 766

For female Internet users: [tex]n_2[/tex] = 941

Plugging in the values, we have:

[tex]SE = \sqrt{(0.6747(1-0.6747)/766) + (0.7358(1-0.7358)/941)}[/tex]

d) To find the 95% confidence interval for the difference between these proportions, we can use the formula:

[tex]CI = (p_1 - p_2) \± (Z * SE)[/tex]

Where Z is the critical value corresponding to a 95% confidence level. For a large sample size, Z is approximately 1.96.

CI = (-0.0611) ± (1.96 * SE)

CI = -0.0611 ± 0.0355

CI = (-0.096, -0.026)

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B. 0.14 mg will be present after 9 hours.

The given function is D(h) = 5e^(-0.4h), which can be used to determine the milligrams D of a certain drug in a patient's bloodstream h hours after the drug has been given.

To find the milligrams after 9 hours, we need to plug in h = 9 in the function D(h) = 5e^(-0.4h).

D(h) = 5e^(-0.4h)

D(9) = 5e^(-0.4(9))

D(9) = 5e^(-3.6)

D(9) = 5 × 0.024419

D(9) = 0.1220 ≈ 0.12 mg

Hence, the answer is option (c) 1.22 mg.

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Answer:

Circumference = 2(pi)r

C = 2*3.14*4.0= 25.12 round 25.10 m

Step-by-step explanation: