PLEASE HELP!!

Which is the simplified form of the expression

1 - StartFraction 1 Over q Superscript 30 Baseline EndFraction

2 - q Superscript 30

3 - StartFraction p Superscript 12 Baseline Over q Superscript 60 Baseline EndFraction

4 - p Superscript 12 Baseline q Superscript 60

Answer:

This should help

Step-by-step explanation:

1.05, 1.09 and 1.1 are close to each other so I marked where each one should go

Answer:

1) The mean = 41

The standard deviation = 13.379

2) The mean = 40.67

The standard deviation = 12.365

3) The mean and standard deviation will remain the same

4) The new mean = 44.5  

The new standard deviation = 13.58

5) The mean = 42.25

The standard deviation = 13.83

Step-by-step explanation:

The combines mean is given by the formula;

[tex]\overline {x_{12}} = \dfrac{n_1 \bar x + n_2 \bar x}{n_1 + n_2}[/tex]

The combined standard deviation is given as follows;

[tex]\sigma_{12} = \sqrt{\dfrac{n_1 \times \left (\sigma^2_{1} + d^2_1 \right) + n_2 \times \left (\sigma^2_{2} + d^2_2 \right)}{n_1 + n_2} }[/tex]

d₁ = [tex]\overline{x_{12}}[/tex] - [tex]\overline {x_1}[/tex]

d₂ = [tex]\overline{x_{12}}[/tex] - [tex]\overline {x_2}[/tex]

Substituting the known values, we have;

[tex]\overline {x_{12}} = \dfrac{ 42 + 40}{2}=41[/tex]

d₁ = 41 - 42 = -1

d₂ = 41 - 40 = 1

[tex]\sigma_{12} = \sqrt{\dfrac{ \left (16^2 + 1 \right) + \left (10^2 +1 \right)}{2} } = 13.379[/tex]

2) When n₁ = 1, n₂ = 2, we have;

[tex]\overline {x_{12}} = \dfrac{ 2 \times 42 + 4 \times 40}{6} \approx 40.67[/tex]

d₁ = 40.67 - 42 = -1.33

d₂ = 40.67 - 40 = 0.67

[tex]\sigma_{12} = \sqrt{\dfrac{ 2 \times \left (16^2 + 1.33^2 \right) + 4 \times \left (10^2 +0.67^2 \right)}{6} } \approx 12.365[/tex]

3) The mean and standard deviation will remain the same

4) The new mean = (42 + 47)/2 = 44.5  

The new standard deviation [tex]\sigma_{12} = \sqrt{\dfrac{ \left (16^2 + 2.5^2\right) + \left (10^2 +2.5^2\right)}{2} } \approx 13.58[/tex]

5) [tex]\overline {x_{12}} = \dfrac{ 44.5 + 40}{2}=42.25[/tex]

[tex]\sigma_{12} = \sqrt{\dfrac{ \left (16^2 + 2.5^2\right) + \left (10^2 +4.5^2\right)}{2} } \approx 13.83[/tex]

Answer:

13/16 is the answer. Bad handwriting but try to understand .

Answer:12

Step-by-step explanation:

it’s 12 because 4 x 3 = 12

Answer:

48π units³

Step-by-step explanation:

The volume (V) of a cylinder is calculated as

V = πr²h ( r is the radius of the base and h the height )

Here r = 4 and h = 3 , thus

V = π × 4² × 3

   = π × 16 × 3

    = 48π units³ ← exact answer

Answer: 24

Step-by-step explanation:

i did the problem and got it right

Answer:

sin^2α

Step-by-step explanation:

I will just  pose  x instead  of alpha  here to make things simpler

[tex]\tan ^2\left(x\right)\left(2\cos ^2\left(x\right)+\sin ^2\left(x\right)-1\right)\\\\[/tex]

we know that sin^2x = 1 -  cos^2x so...

[tex]=\left(-1+1-\cos ^2\left(x\right)+2\cos ^2\left(x\right)\right)\tan ^2\left(x\right)[/tex]

[tex]=\cos ^2\left(x\right)\tan ^2\left(x\right)[/tex]

we can rewrite using trigonometric identities (tan = sin/cos)...

[tex]=\left(\frac{\sin \left(x\right)}{\cos \left(x\right)}\right)^2\cos ^2\left(x\right)\\= \sin ^2\left(x\right)[/tex]

Answer:

absolute value of 8.7 is 8.7

Answer:

Company B is offering the lowest price/lb at $12.72/lb.

Step-by-step explanation:

Answer:

let the number be x

thrice of the number=3x

one-half of the number=(1/2)x

so from the expression we:

3x-x/2=2500

(6x-x)/2=2500

6x-x=2*2500

5x=5000

x=5000/5

x=1000

Answer:

Axis is a vertical line at x = 2

Vertex is (2, -1)

y-intercept is (0, 3)

Solutions are x = 1 and x = 3

Step-by-step explanation:

To draw the graph of the quadratic equation you must find at least 5 points lie on the graph by choose values of x and find their values of y

Let us do that

Use x = -1, 0, 1, 2, 3, 4, 5

∵ y = x² - 4x + 3

∵ x = -1

∴ y = (-1)² - 4(-1) + 3 = 1 + 4 + 3 = 8

→ Plot point (-1, 8)

∵ x = 0

∴ y = (0)² - 4(0) + 3 = 0 + 0 + 3 = 3

→ Plot point (0, 3)

∵ x = 1

∴ y = (1)² - 4(1) + 3 = 1 - 4 + 3 = 0

→ Plot point (1, 0)

∵ x = 2

∴ y = (2)² - 4(2) + 3 = 4 - 8 + 3 = -1

→ Plot point (2, -1)

∵ x = 3

∴ y = (3)² - 4(3) + 3 = 9 - 12 + 3 = 0

→ Plot point (3, 0)

∵ x = 4

∴ y = (4)² - 4(4) + 3 = 16 - 16 + 3 = 3

→ Plot point (4, 3)

∵ x = 5

∴ y = (5)² - 4(5) + 3 = 25 - 20 + 3 = 8

→ Plot point (5, 8)

→ Join all the points to form the parabola

From the graph

∵ The axis of symmetry is the vertical line passes through the vertex point

∵ x-coordinate of the vertex point is 2

∴ Axis is a vertical line at x = 2

∵ The coordinates of the vertex point of the parabola are (2, -1)

∴ Vertex is (2, -1)

∵ The parabola intersects the y-axis at point (0, 3)

∴ y-intercept is (0, 3)

∵ x² - 4x + 3 = 0

∵ The solutions of the equation are the values of x at y = 0

→ That means the intersection points of the parabola and the x-axis

∵ The parabola intersects the x-axis at points (1, 0) and (3, 0)

∴ Solutions are x = 1 and x = 3

Answer:

56

Step-by-step explanation:

Answer:

235

Step-by-step explanation:

Answer:

235

20 percent (calculated percentage %) of what number equals 47? Answer: 235.

Step-by-step explanation:

I hope this Helps c:

Answer:

what does lmno means

Step-by-step explanation:

Answer:

Vertex form is y=(x-5)^2-43

Step-by-step explanation:

Given expression: x^2-10x-18

Take half of b:

-10/2=-5

Square the result:

-5^2=25

Add and subtract into original expression:

x^2-10x+25-25-18

Factor and simplify:

(x^2-10x+25)-25-18

(x-5)^2-25-18

(x-5)^2-43

So the vertex form is y=(x-5)^2-43

Answer:

The answer is most likely c.)

Step-by-step explanation:

It says that they sold 40 scarves and hats at the Winter Festival, but it never told us exactly how many hats total and how many scarves total that they sold. So we leave it as "s+h=40" Next we have the price of the scarves and hats, not the numbers sold. Since the scarves cost $18 and the hats cost $14, we know that a certain amount of each equals $700. Since we don't know the exact number of each that were sold, we leave it at "18s+14h=700." Sorry if you got a bit lost.

Answer:

Fourth option is correct. The length of B'C' is 1 unit.

Step-by-step explanation:

The vertices of triangle ABC are A = (2, 2), B = (4, 3), and C = (6, 3).

Distance formula:

The length of BC is 2 units.

It is given that ΔABC is dilated by a scale factor of 0.5 with the origin as the center of dilation, resulting in the image ΔA′B′C′.

It means the ΔABC and ΔA′B′C′ are similar and corresponding sides of ΔA′B′C′ and ΔABC are proportional.

The scale factor is 0.5.

Therefore the length of B'C' is 1 unit and fourth option is correct

Answer:

D= 1 unit

Step-by-step explanation:

Step-by-step explanation:

2 /4

3. 5

doing reciprocal

2× 5

3. 4

= 8×15

12

= 120

12

=10 ans

hope it help u..

Answer:

b = 8.5

Step-by-step explanation:

hope this halps ya!

Answer:

Yes

Step-by-step explanation:

-2(9)+4= -14  and -14 is equal to -14.

Answer:

3.16

Step-by-step explanation:

Hope this helps!

Answer:

After 10 months, both salespersons will sell 160 cars.

Step-by-step explanation:

We are given two different salesperson's statistics of sales. We can use this information to set up a system of equations and solve for our variable.

Let us name the first salesperson Person 1 and the other salesperson Person 2.

Now, for Person 2:

Now, because we have these equations, we can set up a table that will determine the number of months that will elapse before the salespersons will sell the same amount of cars.

For Person 1, the equation will be the increase of the y-value by 13 cars after an initial sale of 30 vehicles. Therefore, we can create a table of values.

[tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & 30 \\ \cline{1-2} 1 & 43 \\ \cline{1-2} 2 & 56 \\ \cline{1-2} 3 & 69 \\ \cline{1-2} 4 & 82 \\ \cline{1-2} 5 & 95 \\ \cline{1-2} 6 & 108 \\ \cline{1-2} 7 & 121 \\ \cline{1-2} 8 & 134 \\ \cline{1-2} 9 & 147 \\ \cline{1-2} 10 & 160 \\ \cline{1-2} \end{array}[/tex]

For Person 2, we can use the same formatting to create a table. However, the rule changes - we must start at 50 cars being sold and increase it by only 11 cars a month.

[tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & 50 \\ \cline{1-2} 1 & 61 \\ \cline{1-2} 2 & 72 \\ \cline{1-2} 3 & 83 \\ \cline{1-2} 4 & 94 \\ \cline{1-2} 5 & 105 \\ \cline{1-2} 6 & 116 \\ \cline{1-2} 7 & 127 \\ \cline{1-2} 8 & 138 \\ \cline{1-2} 9 & 149 \\ \cline{1-2} 10 & 160 \\ \cline{1-2} \end{array}[/tex]

Now, we need to see where the y-values are the same in both tables. We can see that we have a value of (10, 160) in both tables, so after 10 months, the salespersons will sell the same amount of cars.

There is an alternative method of solving the problem that is much quicker and will require much less work.

We are given two equations that are both equal to y. Therefore, we can set them equal to each other (dropping the y) and solving for x.

Our value of x will be the amount of months in which the sales are equal.

[tex]\displaystyle{13x+30=11x+50}\\\\2x + 30 = 50\\\\2x = 20\\\\\boxed{x = 10}[/tex]

Therefore, after 10 months of sales, the salespersons will have sold the same amount of cars. We can plug this information into one of the equations to see how many cars will be sold at that point.

[tex]y = 13(10) + 30\\\\y = 130 + 30 \\\\y = 160[/tex]

In 10 months, 160 cars will be sold. If we set the equations equal to each other and substitute x, we should get a true statement.

[tex]13(10)+30=11(10)+50\\\\130 + 30 = 110 + 50\\\\160 = 160[/tex]

Because we get a true statement, each salesperson will sell 160 cars after 10 months of initial sales.

Answer:

B

Step-by-step explanation:

I am sorry if this is wrong