please help!
PQRS is a kite. Enter coordinates
for point S.
P(0, b)
S
Q(a, 0)
R(0, -c)
S([ ? ] ,[ ? ])

During an experiment of acceleration changes, the value that must stay constant during these trials is d. Mass

Inertia, a basic characteristic of all matter, may be measured quantitatively using mass. When a force is applied, an item effectively provides resistance to changes in velocity or position. The change brought about by an applied force is less the more mass an item has. According to Newton's second law of motion an object's acceleration is inversely proportional to its mass and directly proportional to the net force that has been applied to it. It may be expressed mathematically as F = ma.

The goal of this experiment is to see how variations in force impact acceleration. It is crucial to maintain the mass constant throughout the trials in order to isolate the impact of force on acceleration. Any observable variations in acceleration may be entirely attributable to variations in the applied force by maintaining the mass constant.

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A subspace must satisfy three conditions: closure under addition, closure under scalar multiplication, and containing the zero vector. Therefore, the correct statement is B. W is a subspace of P2.

In order to determine whether statement A or B is true, we need to check the subspace criteria.

Let's analyze the statements:

A. W is not a subspace of P2 because 0 € W.

If 0 € W, then W does not contain the zero vector. However, the zero vector is the polynomial 0 + 2(0)x + (0)x^2 = 0, which is an element of W. Thus, statement A is false.

B. W is a subspace of P2.

For W to be a subspace, it needs to satisfy all three subspace criteria. Let's check each criterion:

Since W satisfies all three subspace criteria, statement B is true.

Therefore, the correct statement is B. W is a subspace of P2.

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Answer:

2 km < 4,000 m

Step-by-step explanation:

2 km = 2,000 m

Therefore, 2,000 m is less than 4,000 m.

Answer:

the answer is 14 I pinkie promise!

sec 290° = 1/cos 110°= -2.9238.

To find the value of sec 290° using a reference angle, we first need to determine the reference angle for 290°.

The reference angle is the acute angle formed between the terminal side of the given angle (290°) and the x-axis. To find the reference angle, we subtract the nearest multiple of 180° from the given angle:

Reference angle = 290° - 180° = 110°

Now, we can express sec 290° in terms of the secant of the reference angle (110°). The secant function is defined as the reciprocal of the cosine function:

sec(x) = 1/cos(x)

Therefore, sec 290° can be written as:

sec 290° = 1/cos 110° = -2.9238.

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The correct statement regarding the residual plot in this problem, and whether the line of best fit is a good fit, is given as follows:

Yes, the points have no pattern.

For a data-set, the definition of a residual is that it is the difference of the actual output value by the predicted output value, hence it is defined by the subtraction operation as follows:

Residual = Observed - Predicted.

Hence the graph of the line of best fit should have the smallest possible residual values, and no pattern between the residuals.

As there is no pattern between the residuals in this problem, the line is in fact a good fit and the first option is the correct option.

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The maximum possible cost in dollars is $226.76 (approx).

Standard deviation = $88

Let X be the cost of the automobile repair, then X ~ N(367, 88^2) (normal distribution)

Now, we need to find the following probabilities:

(a) P(X > 480)(b) P(X < 240)(c) P(240 < X < 480)(d)

Find X such that P(X < X1) = 0.05, where X1 is the lower 5% point of X(a) P(X > 480)

We need to find P(X > 480)P(X > 480) = P(Z > (480 - 367)/88) [Standardizing the random variable X]P(X > 480) = P(Z > 1.2955)

Using the standard normal table, the value of P(Z > 1.2955) = 0.0983 (approx)

Hence, the required probability is 0.0983 (approx)(b) P(X < 240)

We need to find P(X < 240)P(X < 240) = P(Z < (240 - 367)/88) [Standardizing the random variable X]P(X < 240) = P(Z < -1.4432)

Using the standard normal table, the value of P(Z < -1.4432) = 0.0749 (approx)

Hence, the required probability is 0.0749 (approx)(c) P(240 < X < 480)

We need to find P(240 < X < 480)P(240 < X < 480) = P(Z < (480 - 367)/88) - P(Z < (240 - 367)/88) [Standardizing the random variable X]P(240 < X < 480) = P(Z < 1.2955) - P(Z < -1.4432)

Using the standard normal table, the value of P(Z < 1.2955) = 0.9017 (approx)and the value of P(Z < -1.4432) = 0.0749 (approx)

Hence, the required probability is 0.9017 - 0.0749 = 0.8268 (approx)(d)

Find the maximum possible cost in dollars, if the cost for your car repair is in the lower 5% of automobile repair charges.

This is nothing but finding the lower 5% point of X.We need to find X1 such that P(X < X1) = 0.05.P(X < X1) = P(Z < (X1 - 367)/88) [Standardizing the random variable X]0.05 = P(Z < (X1 - 367)/88)

Using the standard normal table, the value of Z such that P(Z < Z0) = 0.05 is -1.645 (approx)

Hence, we get,-1.645 = (X1 - 367)/88

Solving for X1, we get: X1 = 88*(-1.645) + 367 = $226.76 (approx)

Therefore, the maximum possible cost in dollars is $226.76 (approx).

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a) The volume of the solid E in rectangular coordinate system is given by: [tex]$$\iiint_{E}[/tex] dx dy dz = [tex]\int_{-2}^{2} \int_{0}^{\sqrt{z^2}} \int_{-\sqrt{z^2 - y^2}}^{\sqrt{z^2 - y^2}} dx dy dz$$[/tex]

b) The volume of the solid E in cylindrical coordinate system is given by:  [tex]$$\iiint_{E} \rho d\rho d\theta dz = \int_{0}^{2} \int_{0}^{\frac{\pi}{2}} \int_{0}^{\sqrt{4 - z^2}} \rho d\rho d\theta dz$$[/tex]

c) The volume of the solid E is 11π/3.

a) The solid E that lies between the cone z² = x² + y² and the sphere x² + y² + (z + 2)² = 2.

Let the limits of x, y, z be X, Y, Z respectively.

The limits of X:

From the equation, z² = x² + y²

Z² = X² + Y²

X² = Z² - Y²

Let Z = 0, then X² = - Y² which is impossible. Therefore, Y can take any value such that Y < Z.

The limits of Y:

From the equation, z² = x² + y²

Z² = X² + Y²

Y² = Z² - X²

Let Z = 0, then Y² = - X² which is impossible. Therefore, X can take any value such that X < Z.

Limits of Z:

From the equation x² + y² + (z + 2)² = 2z² + 4z + 8 = 2(Z + 1)² + 6

The limits of z are Z < 2 and Z > - 2.

Volume in rectangular coordinate system:

[tex]$$\iiint_{E}[/tex] dx dy dz = [tex]\int_{-2}^{2} \int_{0}^{\sqrt{z^2}} \int_{-\sqrt{z^2 - y^2}}^{\sqrt{z^2 - y^2}} dx dy dz$$[/tex]

b) Volume of solid E in cylindrical coordinate system

Let the limits of ρ, θ, z be R, Θ, Z respectively.

The limits of R:

From the equation, z² = ρ² cos²θ + ρ² sin²θ

Z² = ρ²

Rho² = Z²/ cos²θ + sin²θ

Rho = Z/ cosθ

Let Z = 0, then Rho = 0. Therefore, R can take any value such that 0 ≤ R < 2.

Limits of Θ:

From the equation, z² = ρ² cos²θ + ρ² sin²θ

Z² = ρ² sin²θ

Theta² = tan⁻²(Z²/ ρ²)

Let Z = 0, then Θ = 0. Therefore, Θ can take any value such that 0 ≤ Θ ≤ π/2.

Limits of Z:

From the equation x² + y² + (z + 2)² = 2z² + 4z + 8 = 2(Z + 1)² + 6

The limits of Z are -2 ≤ Z < 2.

Volume in cylindrical coordinate system:

[tex]$$\iiint_{E} \rho d\rho d\theta dz = \int_{0}^{2} \int_{0}^{\frac{\pi}{2}} \int_{0}^{\sqrt{4 - z^2}} \rho d\rho d\theta dz$$[/tex]

c) Evaluation of the volume of solid E:

Using rectangular coordinate system, the volume of solid E is

[tex]$$\iiint_{E} dx dy dz[/tex] = [tex]\int_{-2}^{2} \int_{0}^{\sqrt{z^2}} \int_{-\sqrt{z^2 - y^2}}^{\sqrt{z^2 - y^2}} dx dy dz$$$$[/tex]

[tex]=\int_{-2}^{2} \int_{0}^{\sqrt{z^2}} [x]_{-\sqrt{z^2 - y^2}}^{\sqrt{z^2 - y^2}} dy dz$$$$=\int_{-2}^{2} \int_{0}^{\sqrt{z^2}} 2\sqrt{z^2 - y^2} dy dz$$$$=\int_{-2}^{2} \left[-\frac{1}{2}(z^2 - y^2)^{3/2}\right]_{y=0}^{y=\sqrt{z^2}} dz$$$$=\int_{-2}^{2} \frac{1}{2}z^3 dz = 0$$[/tex]

Therefore, the volume of solid E using rectangular coordinate system is 0.

Using cylindrical coordinate system, the volume of solid E is

[tex]$$\iiint_{E} \rho d\rho d\theta dz = \int_{0}^{2} \int_{0}^{\frac{\pi}{2}} \int_{0}^{\sqrt{4 - z^2}} \rho d\rho d\theta dz$$$$=\int_{0}^{2} \int_{0}^{\frac{\pi}{2}} \left[\frac{\rho^2}{2}\right]_{0}^{\sqrt{4 - z^2}} d\theta dz$$$$=\int_{0}^{2} \int_{0}^{\frac{\pi}{2}} 2 - \frac{z^2}{2} d\theta dz$$$$=\int_{0}^{2} \left[2\theta - \frac{\theta z^2}{2}\right]_{\theta = 0}^{\theta = \frac{\pi}{2}} dz$$$$=\int_{0}^{2} \pi - \frac{\pi z^2}{4} dz = \frac{11\pi}{3}$$[/tex]

Therefore, the volume of solid E using cylindrical coordinate system is 11π/3.

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Answer:

x=-6, y=-7

Step-by-step explanation:

Answer:

x = -6, y = -7

Step-by-step explanation:

One way to solve for x and y is using the substitution method

(1) 3x + 4y = -46

(2) 6x + y = -43

Solve for y in equation (2)

6x + y =-43, so y = -43 - 6x

Substitute y = -43 -6x into equation (1)

3x + 4(-43 -6x) = -46

3x -172 -24x = -46

-21x -172 = -46

-21x = 126

x = -6

Find y by substituting x = -6 into equation (2)

6(-6) + y = -43

-36 + y = -43

y = -7

Answer:

0.0129449838188

Answer:

D 19,905

Step-by-step explanation:

19,905.22×25%=4976.31

19905.22-4976.31=14,928.91

14928.91×8%=1194.31

14928.91-1194.31=13734.6

Answer:

Your answer would be D. I know this is kind of late, but maybe other people that come up here could get some help

Step-by-step explanation:

Answer:

100-47=53 so 53$ profit

Step-by-step explanation:

Answer:

Observation : No two such factors can be found !! Conclusion : Trinomial can not be factored. Equation at the end of step 2 : 2n2 - 7n - 5 = 0. Step 3 : Parabola ...

Step-by-step explanation:

Answer:

Step-by-step explanation:

Based on the sample data, we can construct a 99% confidence interval estimate for the percentage of girls born as approximately 85.1% to 94.9%.

To construct a confidence interval estimate for the percentage of girls born, we can use the formula for estimating a proportion.

First, we calculate the sample proportion, which is the number of successes (girls) divided by the total number of trials (babies born):

Sample proportion (p-hat) = Number of girls / Total number of babies born

= 288 / 320

= 0.9

Next, we can construct the confidence interval using the sample proportion. Since we want a 99% confidence interval, we need to find the critical value corresponding to that level of confidence. For a two-tailed test, the critical value is obtained from the standard normal distribution (Z-distribution).

Using a Z-table or calculator, the critical value for a 99% confidence level is approximately 2.576.

The margin of error (E) can be calculated as:

Margin of error (E) = Critical value * Standard error

The standard error (SE) for estimating a proportion is given by:

Standard error (SE) = [tex]\sqrt {(p-hat * (1 - p-hat)) / n}[/tex]

where p-hat is the sample proportion and n is the sample size.

Using these values, we can calculate the margin of error:

Standard error (SE) = [tex]\sqrt {(0.9 * (1 - 0.9)) / 320}[/tex]

≈ 0.019

Margin of error (E) = 2.576 * 0.019

≈ 0.049

Finally, we can construct the confidence interval:

Confidence interval = Sample proportion ± Margin of error

= 0.9 ± 0.049

≈ (0.851, 0.949)

Therefore, based on the sample data, we can construct a 99% confidence interval estimate for the percentage of girls born as approximately 85.1% to 94.9%.

Since the interval includes the value of 0.5 (50%), which represents an equal chance of having a girl or a boy, it suggests that the method used in the clinical trial does not significantly increase the probability of conceiving a girl.

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Answer:

Therefore, after 12 years the car will value $6,765.35.

Step-by-step explanation:

In the context of analyzing the relationship between studying time and test grades, the domain of the scatterplot would be the number of minutes the students studied (option D).

The domain refers to the set of possible inputs or variables in a given context. In this case, the scatterplot is being created based on the relationship between the time students spent studying and their corresponding test grades. Therefore, the domain in this context would be the number of minutes the students studied (option D).

The domain represents the independent variable, which is the variable that is controlled or manipulated in the analysis. In this scenario, the math teacher wants to analyze the relationship between studying time and test grades, so the number of minutes studied would be the independent variable. The teacher surveys the students to collect data on the time spent studying, and this variable becomes the domain of the scatterplot.

The range, on the other hand, represents the dependent variable, which is the variable that is measured or observed as an outcome or response. In this case, the dependent variable would be the students' test grades. The scatterplot will show how the test grades correspond to the amount of time students studied.

To summarize, in the context of analyzing the relationship between studying time and test grades, the domain of the scatterplot would be the number of minutes the students studied (option D).

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Answer:

A is the answer

Step-by-step explanation:

All you have to do is follow the order pair such as 2, 100 and see if that is a correct pair.

Hope that helps

Answer: A. (2, 100)

Step-by-step explanation:

Answer:

n=2

Step-by-step explanation:

[tex]\frac{3.3.3.3.3.3}{3.3.3.3} = 3^{n}[/tex]

[tex]3^{2}[/tex]= [tex]3^{n}[/tex]

n=2

Answer:

[tex]3^1[/tex]

Step-by-step explanation:

[tex]\frac{3*3*3*3*3}{3*3*3*3} =3^1[/tex]

Answer:

Step-by-step explanation:

Look at the graph, look at homework and then look at the number right outside of it.

Answer:

4[tex]\sqrt{3}[/tex]

Step-by-step explanation:

Using the rule of radicals

[tex]\sqrt{a}[/tex] × [tex]\sqrt{b}[/tex] ⇔ [tex]\sqrt{ab}[/tex] , then

[tex]\sqrt{48}[/tex]

= [tex]\sqrt{16(3)}[/tex]

= [tex]\sqrt{16}[/tex] × [tex]\sqrt{3}[/tex]

= 4[tex]\sqrt{3}[/tex]

Answer:

the first plotting was correct.

Step-by-step explanation:

the values will be arranged in an ascending order from their roots which are the first digit

Answer:

8/7

Step-by-step explanation:

12*2=24.

7*3=21

24/21 is divisible by 3

=8/7

Answer:

2cm

Step-by-step explanation:

Given data

Capacity/volume of liquid held=  6π cm^3

Height= 6cm

Required

The diameter d of the tube

let us apply the expression for the volume of cylinder

V=πr^2h

6π=πr^2*6

6=r^2*6

r^2= 6/6

r^2=1

r= √1

r=1cm

Hence the diameter d = 2r= 2*1= 2cm