Answer:
D or answer choice 4
Step-by-step explanation:
find the equation of a line in slope-intercept form, containing the points (9,2.6) and (8,2.2).
Six less than the product of 8 and a number equals 2
Answer:
unknown number = 1
Step-by-step explanation:
Let the unknown number be x.
(8×x)-6=2
8x-6=2
8x=2+6
=8
x=8÷8
=1
Hence, unknown number = 1.
Find the equation of the line where m = 1 and b = 8.
y = 8 - x
y = 8
y = 8x + 1
y = x + 8
Answer:
Y=x+8
Step-by-step explanation:
ABC ≃DEF. Find the lengths of the given sides
Answer:
BC = 8 and EF = 8.
Step-by-step explanation:
Since triangle ABC and DEF are congruent to each other, BC corresponds with EF (as determined by the triangle names).
Set BC and EF equal to each other.
x + 6 = 3x + 2
Subtract x from both sides.
6 = 2x + 2
Subtract 2 from both sides.
4 = 2x.
Divide 2 on both sides.
x = 2.
Substitute 2 for x.
BC = 2 + 6
BC = 8
Since we already know that EF is congruent to BC, EF is also 8.
EC = 3(2) + 2
EC = 6 + 2
EC = 8
A car is being compacted into a rectangular solid. The volume is decreasing at a rate of 2 m3/sec. The length and width of the compactor are square, but the height is not the same length as the length and width. If the length and width walls move toward each other at a rate of 0.25 m/ sec, find the rate at which the height is changing when the length and width are 2 m and the height is 1.5 m.
Using implicit differentiation, it is found that the height is changing at a rate of -0.875 m/sec.
The volume of a rectangular solid of length l, width w and height h is given by:
[tex]V = lwh[/tex]
Applying implicit differentiation, the rate of change of the volume is given by:
[tex]\frac{dV}{dt} = wh\frac{dl}{dt} + lh\frac{dw}{dt} + lw\frac{dh}{dt}[/tex]
In this problem:
Volume is decreasing at a rate of 2 m3/sec, hence [tex]\frac{dV}{dt} = -2[/tex]The length and width walls move toward each other at a rate of 0.25 m/ sec, hence [tex]\frac{dl}{dt} = \frac{dw}{dt} = 0.25[/tex]Length and width are 2 m and the height is 1.5 m, hence [tex]l = w = 2, h = 1.5[/tex]Then:
[tex]\frac{dV}{dt} = wh\frac{dl}{dt} + lh\frac{dw}{dt} + lw\frac{dh}{dt}[/tex]
[tex]-2 = 2(1.5)(0.25) + 2(1.5)(0.25) + 2(2)\frac{dh}{dt}[/tex]
[tex]4\frac{dh}{dt} = -3.5[/tex]
[tex]\frac{dh}{dt} = -\frac{3.5}{4}[/tex]
[tex]\frac{dh}{dt} = -0.875[/tex]
The height is changing at a rate of -0.875 m/sec.
A similar problem is given at https://brainly.com/question/9543179
Help me plz I really need help
Answer:
it won't let me message back.
Step-by-step explanation:
Evaluate 12.3v+11.9w when v=7 and w=8.
please
Answer:
181.3
Step-by-step explanation:
I hope this helps!
3. Sarah has a goal to save $81.84 for a new gan
If she has 12 weeks to save the money, how much does she need
to save each week?
Answer:
Hi!
12x = 81.84
x = 6.82
6.82 dollars every week
Determine the value of x. Question 4 options: A) 10 B) 5 C) 10 D) 5
what is 351.86 in terms of pi?
Answer:
It can either be 17593pi/9000 rad or if youre looking for a decimal answer is it 1.95pi and rad=6.14
Step-by-step explanation:
Solve.
w−(−1/6)=1.08
Enter your answer as a fraction in simplest form in the box.
Answer:
137/150
Step-by-step explanation:
We can solve for w by adding -1/6 to both sides of the equation.
w -(-1/6) = 1.08
w = 1.08 +(-1/6) = 108/100 -1/6
w = 54/50 =1/6 = 162/150 -25/150
w = 137/150
A bakery sells 1/2 dozen cookies for $6.48. At this rate, how much would it cost for 3 dozen cookies?
Simplify the following expression.
(42x + 59y) + (-14x + 35y)
A.
28x + 94y
B.
56x + 94y
C.
56x + 24y
D.
28x + 24y
Answer:
A. 28x + 94y
Step-by-step explanation:
First, line up the like terms as if you were adding vertically, and combine them.
(42x + 59y)
+ (-14x + 35y)
(28x + 94y)
Hope this helps :)
A 11 foot ladder is placed against a building. If the base of the ladder is 7 feet away from the building, how far up the building will the ladder reach? Round the answer to the nearest tenth.
Check the picture below.
solve please: 1/4x-5+1.2x
Answer:
29x/20 - 5
Step-by-step explanation:
1/4x - 5 + 1.2x
=> 0.25x - 5 + 1.2x
=> 1.45x - 5
=> 29x/20 - 5
Therefore, this is the simplified form: 29x/20 - 5
A table is on sale for 32% off. The sale price is $459.
What is the regular price?
the regular price is "x", which of course is the 100%, but we also know that $459 is 32% off that, hmmmmm well 100% - 32% = 68%, so $459 is really 68% of "x", because $459 is whatever "x" is minus 32%.
[tex]\begin{array}{ccll} amount&\%\\ \cline{1-2} x&100\\ 459&68 \end{array}\implies \cfrac{x}{459}=\cfrac{100}{68}\implies \cfrac{x}{459}=\cfrac{25}{17} \\\\\\ 17x = 11475\implies x = \cfrac{11475}{17}\implies x = 675[/tex]
Given: measure 1, measure 2, measure 3, and measure 4 formed by two intersecting segments Prove: measure 1 and measure 3 are congruent. NEED HELP ASAP!!
Step-by-step explanation:
Note:The text below that are formatted in bold and underlined font are the solutions to the missing boxes in your given problem.
Explanation:Given that ∠1, ∠2, ∠3, and ∠4 are formed by two intersecting segments, and that:
∠1 and ∠2 form a linear pair
∠2 and ∠3 form a linear pair
These linear pair relationships suggest that by the Linear Pair Postulate:
∠1 and ∠2 are supplementary. ⇒ Linear Pair Postulate
∠2 and ∠3 are supplementary. ⇒ Linear Pair Postulate
m∠2 + m∠ 3 = 180° ⇒ Definition of supplementary angles.
m∠1 + m∠3 = m∠2 + m∠ 3 ⇒ Substitution Property of Equality.
m∠1 = m∠3 ⇒ Subtraction Property of Equality.
-1/3 + (-7/4)
Ill give this cookie to who solves it
Answer:
-25/12
Step-by-step explanation:
first, you need a common denominator. in this case, it's 12.
-1/3=-4/12
-7/4=-21/12
and then you add
-4+-21=-25
so -25/12 is your answer
......................................
Please take a look at the picture
Answer:
x=-22.42
Step-by-step explanation:
-18.43=3.99+x
Move the variable to the left-hand side and move the constant to the right. Change their signs.
-x=3.99+18.43
Add.
-x=22.42
Change the signs on both sides of the equation.
x=-22.42
Hope this helps :)
2x - 5y = 6 and -2x + 7y = 14
*Using elimination*
The original price of a dress is 95.00. A discount of 10% is offered for cash payment. How much does one save by paying cash for the dress?
Answer:
10% of 95 is 9.5
So 95 - 9.5 = 85.5
two numbers are in the ratio 7:9. The smaller number is 42. what is the number?
42 = 7*6
so,
7:9 = 7*6 : 9*6 = 42:54
find the area of a circle when the radius is 10cm. Take the value of pi as 3.14
Answer:
314.16 cm squared
Step-by-step explanation:
The price of a gallon of milk increased from $5.50 to $7.50. Describe the price increase as a percent.
Step-by-step explanation:
7.50= (1 + x/100 ) × 5.50
7.50/ 5.50 = 1+x/100
x/100 = 0.36
x= 36.36%
A motorboat is capable of traveling at a speed of 14 miles per hour in still water. On a particular day, it took 15 minutes longer to travel a distance of 12 miles
upstream than it took to travel the same distance downstream. What was the rate of current in the stream on that day?
By solving a system of equations we will find that the rate of current in the stream is S = 2 mi/h.
When the motorboat travels downstream, the total velocity will be the velocity of the motorboat in still water plus the velocity of the stream, while if the motorboat travels upstream, we have the velocity of the stream subtracted.
So upstream the speed is:
(14 mi/h - S)
Downstream the speed is:
(14 mi/h + S)
Where S is the rate of current in the stream.
We know that downstream it takes 15 minutes more to travel 12 miles, then we can write the system of equations:
(14 mi/h + S)*T = 12 mi
(14 mi/h - S)*(T - 15 min) = 12 mi
To solve this, we need to isolate one of the variables in one of the equations, I will isolate T in the first one:
T = (12 mi)/(14 mi/h + S)
Replacing that in the other equation we will get:
(14 mi/h - S)*((12 mi)/(14 mi/h + S) - 15 min) = 12 mi
Now we can solve this for S. Now we can multiply both sides by (14 mi/h + S).
(14 mi/h - S)*12 mi - (14 mi/h + S)*(14 mi/h - S)*(- 15 min) = 12 mi*(14 mi/h + S)
Also notice that the speeds are in hours, so we can rewrite:
- 15 min = -0.25 h
(14 mi/h - S)*12 mi - (14 mi/h + S)*(14 mi/h - S)*(- 0.25 h) = 12 mi*(14 mi/h + S)
168 mi^2/h - 12mi*S + 49mi^2/h + 0.25h*S^2 = 168mi^2/h + 12mi*S
- 12mi*S + 49mi^2/h - 0.25h*S^2 = 12mi*S
-24mi*S - 0.25h*S^2 + 49mi^2/h = 0
This is a quadratic equation, the solutions are:
[tex]S = \frac{24mi \pm \sqrt{(-24mi)^2 - 4*(49mi^2/h)*(-0.25h)} }{2*-0.25h} \\\\S = \frac{24mi \pm 25 mi }{-0.5h}[/tex]
We only take the positive solution, so we get:
S = (24 mi - 25 mi)/(-0.5 mi) = 2 mi/h
The rate of current in the stream is 2 mi/h.
If you want to learn more, you can read:
https://brainly.com/question/24345308
What is the coefficient of x in expression of 5mx
⇒
Coefficient of this expression is 5 only.
- BRAINLIEST answerer
You are given the first four terms of an arithmetic sequence. Under what
conditions might a recursive formula be preferred over the explicit formula?
Under what conditions might an explicit formula be preferred over the
recursive formula?
Let
f
and
g
be defined by
f
:
x
→
3
x
−
1
)
a
n
d
\(
g
:
x
→
2
−
5
x
. Find
f
o
g
(
2
)
Answer:
Solution
verified
Verified by Toppr
f,g:R→R is defined as
f(x)=x+1
g(x)=2x−3
Now, (f+g)(x)=f(x)+g(x)=(x+1)+(2x−3)=3x−2
∴(f+g)(x)=3x−2
Now, (f−g)(x)=f(x)−g(x)=(x+1)−(2x−3)=x+1−2x+3=−x+4
∴(f−g)(x)=−x+4
(
g
f
)(x)=
g(x)
f(x)
,g(x)
=0,x∈R
∴(
g
f
)(x)=
2x−3
x+1
,2x−3
=0 or 2x
=3
∴(
g
f
)(x)=
2x−3
x+1
,x
=
2
3
find the amount accumulated in an account after $9000 is invested for 8 years at a 4% coumpounded monthly
Step-by-step explanation:
9000(1+0.04/12)^(8*12)
9000(1.0033333)^96
9000(1.3763)
A=12,387.56
Find X for brainiest
Answer:
136°
Step-by-step explanation:
Look at the attached paper for the steps.
Answer:
136°
Step-by-step explanation:
In quadrilateral ABCD,
[tex]m\angle A = 180\degree - 107\degree = 73\degree[/tex](Angles in linear pair)
[tex]m\angle B = 61\degree [/tex](Vertical Angles)
[tex]m\angle C= 90\degree [/tex](Given)
[tex]m\angle A +m\angle B+m\angle C+m\angle D= 360\degree[/tex](Interior angle sum postulate of a quadrilateral)
[tex]73\degree +61\degree+90\degree+x= 360\degree[/tex]
[tex]224\degree+x= 360\degree[/tex]
[tex]x= 360\degree-224\degree[/tex]
[tex]x= 136\degree[/tex]