Pleaseee help

Lisa has collected data to find that the number of pages per book on a book shelf has a normal distribution. What is the probability that a randomly selected book has fewer than 170 pages if the mean (k) is 195 pages and the standard deviation (o) is 25 pages? Use the empirical rule. Enter your answer as a percent rounded to two decimal places if necessary.

Answer:

The equation of a circle with center (a,b) and radius r is given by:

(x - a)² + (y - b)² = r²

Comparing this with the given equation x² + y² = 196, we can see that a = 0, b = 0, and r² = 196. Therefore, the radius of the circle is:

r = sqrt(196) = 14

Hence, the radius of the circle is 14 units.

The value returned by the call binary Search(values, target) is 5.

Let's perform a binary search on the given array:

The code segment provided is: int[] values = {1, 2, 3, 4, 5, 8, 8, 8}; int target = 8;

1. Initialize variables: low = 0, high = 7 (length of array - 1)
2. Calculate mid: mid = (low + high) / 2 = (0 + 7) / 2 = 3
3. Check if the target is equal to the middle element: values[3] = 4, which is not equal to 8
4. Since the target (8) is greater than the middle element (4), update low: low = mid + 1 = 3 + 1 = 4
5. Calculate mid again: mid = (low + high) / 2 = (4 + 7) / 2 = 5
6. Check if the target is equal to the middle element: values[5] = 8, which is equal to the target

As a result, the binary search function returns the index of the target, which is 5.

Therefore, the value returned by the call binary Search(values, target) is 5.

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Therefore, the area of the region inside the circle and outside the cardioid is. [tex]2\sqrt(3)[/tex].

To find the area of the region inside the circle and outside the cardioid, we need to integrate the difference between the areas of the circle and the cardioid over the interval where they intersect. The points of intersection are at theta = pi/6 and theta = 5pi/6, as given in the problem.

First, let's find the equation of the cardioid in Cartesian coordinates. We have r = 3 + 3sin(θ), so in Cartesian coordinates, this is:

[tex]x^2 + y^2[/tex]= [tex](3 + 3sin(θ)) ^2[/tex]

[tex]x^2 + y^2[/tex]= [tex]9 + 18sin(θ) + 9sin^2(θ)[/tex]

[tex](x^2 + y^2 - 9)[/tex] = [tex]18sin(θ) + 9sin^2(θ)[/tex]

Using the equation of the circle, r = 9sin(theta), we can rewrite sin(theta) as r/9:

([tex]x^2 + y^2 - 9) = 18(r/9) + 9(r/9)^2[/tex]

[tex]x^2 + y^2 = 3r + r^2/3[/tex]

Now we can set up the integral to find the area:

A = 1/2 ∫[tex](pi/6) ^{(5\pi/6)} [81sin^2(θ) - 9 - 18sin(θ) - 9sin^2(θ)] dθ[/tex]

[tex]A = 1/2 ∫(pi/6)^(5pi/6) [72sin^2(θ) - 9 - 18sin(θ)] dθ[/tex]

Since the region is symmetric about the vertical axis theta = pi/2, we can double this integral:

A = ∫[tex](pi/6)^(pi/2) [72sin^2(θ) - 9 - 18sin(θ)] dθ[/tex]

Now we can use the identity sin^2(θ) = 1/2(1 - cos(2θ)) to simplify the integral:

A = ∫[tex](\pi/6) ^(pi/2) [36(1-cos(2θ)) - 9 - 18sin(θ)] dθ[/tex]

A = ∫[tex](pi/6) ^(\pi/2) [-36cos(2θ) - sin(θ)] dθ[/tex]

Integrating, we get:

A = [-[tex]18sin(2θ) - cos(θ)] |_\pi/6^\pi/2[/tex]

[tex]A = [-18sin(2(\pi/2) - 2(\pi/6)) - cos(\pi/2) + cos(\pi/6)] - [-18sin(2(\pi/6)) - cos(\pi/6)][/tex]

[tex]A = [-18sin(\pi /3) - 0.5] - [-9\sqrt(3)/2 - sqrt(3)/2][/tex]

[tex]A = -18\sqrt(3)/2 + 4.5 + 9\sqrt(3)/2 - \sqrt(3)/2[/tex]

[tex]A = 4\sqrt(3)/2[/tex]

[tex]A = 2\sqrt(3)[/tex]

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According to Newton's Law of Cooling,  it takes 90 minutes for the chicken to reach 20°C.

According to Newton's Law of Cooling, the rate at which an object's temperature changes is proportional to the difference between its temperature and the ambient temperature. The formula for Newton's Law of Cooling is:

ΔT/Δt = k(T - Ta)

Where ΔT is the change in temperature, Δt is the change in time, k is a constant, T is the object's temperature, and Ta is the ambient temperature.

From the given information, we have:

ΔT1 = 10C - 0C = 10°C
Δt1 = 45 minutes
Ta = 23°C

Now, we want to find the time it takes for the chicken to reach 20°C:

ΔT2 = 20C - 0C = 20°C

Using the formula and the fact that k and Ta are constants, we can set up the following proportion:

(ΔT1/Δt1) / (ΔT2/Δt2) = 1

Solving for Δt2:

(10/45) / (20/Δt2) = 1

Cross-multiplying and solving for Δt2, we get:

Δt2 = 90 minutes

So, it takes 90 minutes for the chicken to reach 20°C.

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The iterated integral evaluates to approximately 37.45.

To evaluate the iterated integral ∫(from 0 to 3) ∫(from 0 to 9) y*cos(x) dy dx:

1. Start with the inner integral, which is with respect to y: ∫(from 0 to 9) y*cos(x) dy. Integrate y, giving (1/2)y^2*cos(x). Evaluate this from y=0 to y=9, resulting in (1/2)*81*cos(x).

2. Now, move to the outer integral, which is with respect to x: ∫(from 0 to 3) (1/2)*81*cos(x) dx. Integrate cos(x), giving 40.5*sin(x). Evaluate this from x=0 to x=3, resulting in 40.5*(sin(3) - sin(0)).

3. Finally, calculate the value: 40.5*(sin(3) - 0) ≈ 37.45.

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Values the constant c are;

a) c = 2.16.

b) c = 0.57.

c) c = -1.17.

a) We need to find the value of c such that Φ(c) = 0.9838. Using a standard normal table or a calculator, we find that the z-score corresponding to a cumulative probability of 0.9838 is approximately 2.16. Therefore, c = 2.16.

b) We need to find the value of c such that P(0 ≤ Z ≤ c) = 0.291. Using a standard normal table or a calculator, we find that the z-score corresponding to a cumulative probability of 0.291 is approximately 0.57. Therefore, c = 0.57.

c) We need to find the value of c such that P(c ≤ Z) = 0.121. Using a standard normal table or a calculator, we find that the z-score corresponding to a cumulative probability of 0.121 is approximately -1.17. Therefore, c = -1.17.

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The correct pair of constraints to add is option d: P24 - P25 <= 80; P25 - P24 <= 80

To specify that production of product 2 in period 4 and in period 5 differs by no more than 80 units, the correct pair of constraints to add is option d: P24 - P25 <= 80; P25 - P24 <= 80.

The constraint P24 - P25 <= 80 ensures that the production of product 2 in period 4 (P24) does not exceed the production in period 5 (P25) by more than 80 units.

The constraint P25 - P24 <= 80 ensures that the production in period 5 (P25) does not exceed the production in period 4 (P24) by more than 80 units.

These two constraints together ensure that the production of product 2 in period 4 and period 5 differs by no more than 80 units in either direction, as both P24 - P25 and P25 - P24 are limited to be less than or equal to 80.

Therefore, the correct pair of constraints to add is option d: P24 - P25 <= 80; P25 - P24 <= 80

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Answer:

-31 c + 13

Step-by-step explanation:

-13c+8-18c+5

combine like terms

-18c and -13c combined is -31c

8 + 5 = 13

-31 c + 13

Answer

-31c+13 is your answer (see explanation below!)

Step-by-step explanation:

1) Add the numbers:

[tex]-13c + 8 - 18c + 5\\-13c + 13 -18c\\[/tex]

2) Combine like terms:

[tex]-13c+13-18c\\-31c+13\\[/tex]

[tex]A: -31c+13[/tex]

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The solution y(t) is a piecewise defined function given by: [tex]y(t) = (e^(-t/2) \times sin((t - \pi)/2))/2 + (e^(-t/2)\times sin((t - \pi)/2 + \pi))/2 for \pi \leq t \leq < 2\pi[/tex]

y(t) = 0 for t < π and t ≥ 2π

To solve the given initial value problem using Laplace transform, we apply the Laplace transform to both sides of the differential equation:

L{y''} + 2L{y'} + 2L{y} = L{g(t)}

Using the standard Laplace transform formulas for derivatives and unit step function, we get:

[tex]s^2[/tex] Y(s) - s y(0) - y'(0) + 2s Y(s) - 2y(0) + 2Y(s) = 1/(s[tex]e^(\pi)[/tex] - s e^(2π))

Substituting y(0) = 0 and y'(0) = 1, and simplifying, we get:

Y(s) = (1 - s)/([tex]s^2[/tex] + 2s + 2) [tex]\times[/tex] 1/(s [tex]e^\pi[/tex] - s [tex]e^(2\pi)[/tex])

To express y(t) as a piecewise defined function, we need to invert this Laplace transform using partial fraction decomposition and inverse Laplace transform. The roots of the denominator s^2 + 2s + 2 are complex conjugates given by:

s = -1 + i and s = -1 - i

Therefore, we can write the partial fraction decomposition as:

(1 - s)/([tex]s^2[/tex] + 2s + 2) = A/(s + 1 - i) + B/(s + 1 + i)

Multiplying both sides by the denominator and substituting s = -1 + i and s = -1 - i, we get:

A = (-1 + i)/4 and B = (-1 - i)/4

Substituting these values, we get:

Y(s) = (-1 + i)/(4(s + 1 - i)) + (-1 - i)/(4(s + 1 + i))

Taking the inverse Laplace transform of each term using the table of Laplace transforms, we get:

y(t) = ([tex]e^{(-t/2)[/tex] [tex]\times[/tex]sin((t - π)/2))/2 + ([tex]e^{(-t/2)[/tex][tex]\times[/tex]sin((t - π)/2 + π))/2 for π ≤ t < 2π

and y(t) = 0 for t < π and t ≥ 2π

Therefore, the solution y(t) is a piecewise defined function given by:

y(t) = ([tex]e^{(-t/2)[/tex] [tex]\times[/tex] sin((t - π)/2))/2 + ([tex]e^{(-t/2)[/tex][tex]\times[/tex] sin((t - π)/2 + π))/2 for π ≤ t < 2π

y(t) = 0 for t < π and t ≥ 2π

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The solution y(t) is a piecewise defined function given by: [tex]y(t) = (e^(-t/2) \times sin((t - \pi)/2))/2 + (e^(-t/2)\times sin((t - \pi)/2 + \pi))/2 for \pi \leq t \leq < 2\pi[/tex]

y(t) = 0 for t < π and t ≥ 2π

To solve the given initial value problem using Laplace transform, we apply the Laplace transform to both sides of the differential equation:

L{y''} + 2L{y'} + 2L{y} = L{g(t)}

Using the standard Laplace transform formulas for derivatives and unit step function, we get:

[tex]s^2[/tex] Y(s) - s y(0) - y'(0) + 2s Y(s) - 2y(0) + 2Y(s) = 1/(s[tex]e^(\pi)[/tex] - s e^(2π))

Substituting y(0) = 0 and y'(0) = 1, and simplifying, we get:

Y(s) = (1 - s)/([tex]s^2[/tex] + 2s + 2) [tex]\times[/tex] 1/(s [tex]e^\pi[/tex] - s [tex]e^(2\pi)[/tex])

To express y(t) as a piecewise defined function, we need to invert this Laplace transform using partial fraction decomposition and inverse Laplace transform. The roots of the denominator s^2 + 2s + 2 are complex conjugates given by:

s = -1 + i and s = -1 - i

Therefore, we can write the partial fraction decomposition as:

(1 - s)/([tex]s^2[/tex] + 2s + 2) = A/(s + 1 - i) + B/(s + 1 + i)

Multiplying both sides by the denominator and substituting s = -1 + i and s = -1 - i, we get:

A = (-1 + i)/4 and B = (-1 - i)/4

Substituting these values, we get:

Y(s) = (-1 + i)/(4(s + 1 - i)) + (-1 - i)/(4(s + 1 + i))

Taking the inverse Laplace transform of each term using the table of Laplace transforms, we get:

y(t) = ([tex]e^{(-t/2)[/tex] [tex]\times[/tex]sin((t - π)/2))/2 + ([tex]e^{(-t/2)[/tex][tex]\times[/tex]sin((t - π)/2 + π))/2 for π ≤ t < 2π

and y(t) = 0 for t < π and t ≥ 2π

Therefore, the solution y(t) is a piecewise defined function given by:

y(t) = ([tex]e^{(-t/2)[/tex] [tex]\times[/tex] sin((t - π)/2))/2 + ([tex]e^{(-t/2)[/tex][tex]\times[/tex] sin((t - π)/2 + π))/2 for π ≤ t < 2π

y(t) = 0 for t < π and t ≥ 2π

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Answer: £46.36.

Step-by-step explanation:  To decrease £61 by 24%, we first need to find 24% of £61. We can do this by multiplying £61 by 0.24: £61 * 0.24 = £14.64. Now, to decrease £61 by 24%, we subtract £14.64 from £61: £61 - £14.64 = £46.36.

So, if you decrease £61 by 24%, the result is £46.36.

Answer:

B

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Considering the differential equation 2x²y" + 3xy' + (2x - 1)y = 0. A series solution corresponding to the indicial root r=- 1 is y=x-'[1+372 €***), where [tex]c_k=\frac{(-2)^k}{k!(-1)*(2k-3)!}[/tex].

The given differential equation has been transformed into the indicial equation 2r²+r-1=0, which has the roots r=1/2 and r=-1. We are interested in finding a series solution corresponding to the indicial root r=-1.
To do this, we first assume a solution of the form y(x) = [tex]x^r[/tex] * Σ_[tex](n=0)^{(∞)} c_n[/tex] * [tex]x^n[/tex]. Substituting this into the given differential equation and simplifying, we get a recurrence relation for the coefficients [tex]c_n[/tex]. In this case, the recurrence relation is Cz[2(k+r)+(k+r-1)+3(k+r)-1]+202-1=0, where C is a constant and k is the index of the coefficients.
Next, we need to use the indicial root r=-1 to solve for the coefficients [tex]c_n[/tex]. Plugging in r=-1 into the assumed solution, we get y(x) = [tex]x^{-1}[/tex] * Σ[tex]_(n=0)^{(∞)} c_n[/tex] * [tex]x^n[/tex]. We can simplify this to y(x) = Σ_[tex](n=0)^{(∞)}[/tex] c_n * [tex]x^{(n-1)}[/tex]. Then, we can use the recurrence relation to solve for the coefficients.
In this case, the correct answer is [tex]c_k=\frac{(-2)^k}{k!(-1)*(2k-3)!}[/tex].

The complete question is:-

Consider the differential equation 2x²y" + 3xy' + (2x - 1)y = 0. The indicial equation is [tex]2r^2[/tex]+r-1=0. The recurrence relation is [tex]c_k{2(k+r)+(k+r-1)+3(k+r)-1]+2c_{k-1}=0[/tex].

A series solution corresponding to the indicial root r=- 1 is y=x-'[1+372 €***), where

Select the correct answer.

a. [tex]c_k=\frac{(-2)^k}{k!(-1).1.3...(2k-3)}[/tex]

b. [tex]c_k=\frac{-2^k}{k!.1.3...(2k-3)}[/tex]

c. [tex]c_k=\frac{(-2)^k}{k!(-1).1.3...(2k-1)}[/tex]

d. [tex]c_k=\frac{(-2)^k}{k!(-1)*(2k-3)!}[/tex]

e. [tex]c_k=\frac{(-2)^k}{k!(-1).1.3...(2k-5)}[/tex]

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The interval the value of the function (f - g)(x) is negative is (-∞, 2]

A function is a rule or definition that maps an input variable unto an output such that each input has exactly one output.

The equations on the possible graphs in the question, obtained from a similar question posted online are;

f(x) = x - 3

g(x) = -0.5·x

(f - g)(x) = x - 3 - (-0.5·x) = 1.5·x - 3

(f - g)(x) = 1.5·x - 3

Therefore; The x-intercept of the function (f - g)(x) = 1.5·x - 3 is; (f - g)(x) = 0 1.5·x - 3

1.5·x - 3 = 0

1.5·x = 3

x = 3/1.5 = 2

x = 2

The y-intercept is the point where, x = 0, therefore;

(f - g)(0) = 1.5×0 - 3 = -3

The interval the function is negative is therefore;

The equations of the possible graphs of the function, obtained from a question posted online are;

f(x) = x - 3, g(x) = -0.5·x

The interval the function (f - g)(x) is negative is required

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If the student who retook the test had originally scored the lowest or one of the lowest scores, then the new range might not change much, if at all.

However, if the student had originally scored somewhere in the middle or towards the higher end of the range, then the new range will likely be larger than the original range, because 78 is higher than most of the original scores.

The mean (average) of a set of numbers is calculated by adding up all the numbers and dividing the sum by the total number of numbers.

mean = S/n

Therefore, the new mean score will be:

new mean = (S + 23)/n

The range of a set of numbers is the difference between the highest and lowest numbers in the set.

Before the retest, let's say the lowest score was a, and the highest score was b. Then, the range was:

range = b - a

After the retest, the lowest score will still be a, but the highest score will be either b or 78, whichever is higher. Therefore, the new range will be:

new range = max(b, 78) - a

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Answer: 2 red balloons and 4 white balloons in each bunch

Step-by-step explanation:

divide 16/8 = 2 balloons in each bunch

divide 32/8 = 4 balloons in each bunch

Every minute, the number of bacteria decays by a factor of 16^(-60).

An exponential function has the definition presented as follows:

y = ab^x.

In which the parameters are given as follows:

The decay factor k of the exponential function is obtained as follows:

b = 1 - k

k = 1 - b.

The parameter b for the function in this problem is given as follows:

b = 15/16.

Hence the decay factor each second is obtained as follows:

k = 1 - 15/16

k = 16/16 - 15/16

k = 1/16.

Then the decay factor each minute is given as follows:

k = (1/16)^60

k = 16^(-60).

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Answer:

3(x - 1)

Step-by-step explanation:

Let x be the number.

3(x - 1)

Answer:

y= what u get after calculation

x = number that u think

so

y=3(x-1)

The polynomials are

In order to find the factored form of a polynomial with x-intercepts at (-3, 0), (2, 0), and (4, 0), we must write out the equation as:

f(x) = a * (x + 3) * (x - 2) * (x - 4)

Knowing that a = 1, we simplify the equation to obtain the final form:

f(x) = (x + 3) * (x - 2) * (x - 4)

If the given curve has a bounce at the point (2,0) and a bend at (8,0), then its factored form would be:

f(x) = a * (x - 2)^2 * (x - 8)

Given that a = 1, the simplified version is written as follows:

f(x) = (x - 2)^2 * (x - 8)

Using (3, -6),

y = a * x^2 * (x + 1)

solving for a as follows:

-6 = a * 3^2 * (3 + 1)

-6 = a * 9 * 4

a = -6 / 36

f(x) = (-1/6) * x^2 * (x + 1).

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2,186 ways

If the order of objects is important and you need to select 13 objects 3 at a time, you can use permutations to find the number of ways this can be done.

Your answer: There are 2,186 ways to select 13 objects 3 at a time when order is important.

Step-by-step explanation:

1. Use the formula for permutations: P(n, r) = n! / (n - r)!, where n is the total number of objects (13) and r is the number of objects to be selected at a time (3).

2. Calculate the factorials: 13! = 6,227,020,800 and 10! = 3,628,800.

3. Divide the two factorials: 6,227,020,800 / 3,628,800 = 2,186.

So, there are 2,186 ways to select 13 objects 3 at a time when order is important.

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The correct answer is (b) Analysis of variance.

The most appropriate test to determine if there is a difference in fatigue between three groups of subjects is the analysis of variance (ANOVA) test. ANOVA is a statistical method used to compare the means of three or more groups to determine if there are significant differences between them.

In this case, the three groups of subjects represent different levels of the independent variable (such as different treatments or conditions), and the dependent variable is fatigue. By performing an ANOVA test, we can determine if there is a significant difference in the mean fatigue scores between the three groups. If the ANOVA test shows that there is a significant difference, further post-hoc tests can be performed to determine which groups differ significantly from each other.

Therefore, the correct answer is (b) Analysis of variance.

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Answer:

8x^(3/2)

Step-by-step explanation:

We can simplify the expression first:

2sqrt(x)4x^(-5/2)=8x^(-3/2)

Now we can rewrite this in the form kx^2:

8x^(=3/2)=8(x^(-3/2))(x^(5/2))/x^2

=8(x^2/x^3)(x^(1/2))/x^2

=8x^(-1/2)

therefore, 2sqrt(x)4x^(-5/2) is equivalent to 8x^(-1/2), which can be written in the form kx^2 as 8x^(3/2)

I hope this helps!

1. The probability of gaining no more than 2 clients is 0.28. 2. For atleast 4 new clients: 0.37. 3. The expected value is 3.17.

The study of arbitrary events or experiments falls under the purview of probability, a subfield of mathematics. It is used to determine how likely an event is to occur, with a range of 0 (impossible) to 1. (certain). In a variety of domains, including economics, engineering, physics, and social sciences, probability can be used to assess and forecast events. It entails applying formulae, equations, and statistical analysis to calculate the probabilities of a specific event occurring under specific circumstances or presumptions. Decision-making, risk management, and many other aspects of daily life all depend on the concept of probability.

1. The probability of gaining no more than 2 clients is given as:

P(X ≤ 2) = P(X = 0) + P(X = 1) + P(X = 2)

Substituting the value of probabilities from the table we have;

P(X ≤ 2) = 0.03 + 0.10 + 0.15 = 0.28

2. For atleast 4 new clients we have:

P(X ≥ 4) = P(X = 4) + P(X = 5) + P(X = 6) = 0.20 + 0.10 + 0.07 = 0.37

3. The expected value is given as:

E(X) = 0(0.03) + 1(0.10) + 2(0.15) + 3(0.35) + 4(0.20) + 5(0.10) + 6(0.07) = 3.17

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The complete question is:

New clients, X : 0 1 2 3 4 5 6

P(X): 0.03 0.10 0.15 0.35 0.20 0.10 0.07

1. The probability of gaining no more than 2 clients is 0.28. 2. For atleast 4 new clients: 0.37. 3. The expected value is 3.17.

The study of arbitrary events or experiments falls under the purview of probability, a subfield of mathematics. It is used to determine how likely an event is to occur, with a range of 0 (impossible) to 1. (certain). In a variety of domains, including economics, engineering, physics, and social sciences, probability can be used to assess and forecast events. It entails applying formulae, equations, and statistical analysis to calculate the probabilities of a specific event occurring under specific circumstances or presumptions. Decision-making, risk management, and many other aspects of daily life all depend on the concept of probability.

1. The probability of gaining no more than 2 clients is given as:

P(X ≤ 2) = P(X = 0) + P(X = 1) + P(X = 2)

Substituting the value of probabilities from the table we have;

P(X ≤ 2) = 0.03 + 0.10 + 0.15 = 0.28

2. For atleast 4 new clients we have:

P(X ≥ 4) = P(X = 4) + P(X = 5) + P(X = 6) = 0.20 + 0.10 + 0.07 = 0.37

3. The expected value is given as:

E(X) = 0(0.03) + 1(0.10) + 2(0.15) + 3(0.35) + 4(0.20) + 5(0.10) + 6(0.07) = 3.17

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The complete question is:

New clients, X : 0 1 2 3 4 5 6

P(X): 0.03 0.10 0.15 0.35 0.20 0.10 0.07

The single summation expression in terms of k is:

\sum_[tex]{i=1}^{{m}}[/tex]i(i+1)(i+2) = 2k + 10

What is algebra?

Algebra is a branch of mathematics that deals with mathematical operations and symbols used to represent numbers and quantities in equations and formulas.

We can approach this problem by first expanding the summation expressions on both sides of the equation:

On the left-hand side:

m k Σ m + 1 Σ = ∑[tex]{i=1}^{{m}}[/tex]i{m} i ∑{j=1}^{i+1} j

On the right-hand side:

k + 5 k = 6k

Now, we can combine the two summations on the left-hand side by first fixing the value of i in the inner summation and then summing over all possible values of i:

m k Σ m + 1 Σ = ∑[tex]{i=1}^{{m}}[/tex]i i ∑{j=1}^{i+1} j = ∑_[tex]{i=1}^{{m}}[/tex]i i \left(\frac{(i+1)(i+2)}{2}\right)

Simplifying this expression, we get:

m k Σ m + 1 Σ = \frac{1}{2} \sum_[tex]{i=1}^{{m}}[/tex]ii(i+1)(i+2)

Now, we can express the right-hand side of the equation as a summation in terms of k:

k + 5 k = 6k = \sum_{i=1}^{k+5} 1

Therefore, the original equation can be written as:

\frac{1}{2} \sum_[tex]{i=1}^{{m}}[/tex] i(i+1)(i+2) = \sum_{i=1}^{k+5} 1

Simplifying further, we get:

\frac{1}{2} \sum_[tex]{i=1}^{{m}}[/tex] i(i+1)(i+2) = k + 5

Therefore, the single summation expression in terms of k is:

\sum_[tex]{i=1}^{{m}}[/tex]i(i+1)(i+2) = 2k + 10.

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In a circle with center O, chord KL is perpendicular to diameter GH. If KP=PL=18 and GH=36, what is the measure of arc GM?

Based on the mentioned informations and provided valus, the measure of arc of the circle GM is calculated out to be 18π.

Since KL is perpendicular to GH and GH is a diameter, KL is a chord that bisects the circle into two equal halves. Therefore, the arc GM is half the measure of the circle.

The measure of the circle can be found using the diameter GH, which is equal to 36. The formula for the circumference of a circle is C = πd, where d is the diameter. Therefore, the circumference of this circle is C = π(36) = 36π.

Since arc GM is half the measure of the circle, its measure can be found by dividing the circumference by 2.

arc GM = (1/2)C = (1/2)(36π) = 18π

Therefore, the measure of arc GM is 18π.

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c1 and c2 are arbitrary constants, and x is the independent variable.

We first need to find the characteristic equation:

r² + 10r + 41 = 0

Now, we need to find the roots of this quadratic equation. Using the quadratic formula:

r = (-b ± √(b² - 4ac)) / 2a

Here, a = 1, b = 10, and c = 41. Plugging in these values:

r = (-10 ± √(10² - 4(1)(41))) / 2(1)

r = (-10 ± √(100 - 164)) / 2

Since the discriminant (b² - 4ac) is negative, the roots will be complex:

r = (-10 ± √(-64)) / 2

r = -5 ± 4i

Now that we have the complex roots, we can write the general solution as:

y(x) = c1 * e^(-5x) * cos(4x) + c2 * e^(-5x) * sin(4x)

Here, c1 and c2 are arbitrary constants, and x is the independent variable.

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Answer:

14.1mm² (to 1 d.p)

Step-by-step explanation:

area of a circle = πr²

so therefore the area of a semicircle is πr²/2 (because a semicircle is half of a circle)

radius = 3mm

area = π×3²/2

=9/2π

=14.13716....

=14.1mm² (to 1 d.p)

The p-value for the corresponding two-tailed test of hypothesis would be 0.026, obtained by doubling the p-value for the one-sided test.

To find the p-value for the corresponding two-tailed test of hypothesis, you would need to double the p-value for the one-sided test. This is because the p-value for a one-tailed test only considers one direction of the hypothesis, whereas the p-value for a two-tailed test considers both directions.

So, if the p-value for a one-sided test of hypothesis is p = 0.013, then the p-value for the corresponding two-tailed test of hypothesis would be

p-value = 2 × 0.013

Multiply the numbers

= 0.026

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The value of the definite integral ∫(4 - 4√(16 - x^2)) dx, as determined by the area under the graph of the integral from x = -4 to x = 4, is 8π.

To evaluate the definite integral ∫(4 - 4√(16 - x^2)) dx:

We will first graph the integrand and then find the area under the curve.

Step 1: Graph the integrand
The integrand function is f(x) = 4 - 4√(16 - x^2).

This represents a semicircle with a radius of 4 and centered at the origin (0, 4).

The function is transformed from the standard semicircle equation by subtracting 4 from the square root term.

Step 2: Determine the limits of integration
The given integral is a definite integral with limits -4 to 4.

This means that we will find the area under the curve of the function f(x) from x = -4 to x = 4.

Step 3: Calculate the area under the curve
Since the function represents a semicircle, we can find the area of the whole circle and then divide by 2.

The area of a circle is given by A = πr^2, where r is the radius. In our case, r = 4.

A = π(4^2) = 16π

Now, we'll divide the area by 2 to get the area of the semicircle.

Area of semicircle = (1/2) * 16π = 8π

Step 4: Determine the value of the definite integral
The value of the definite integral ∫(4 - 4√(16 - x^2)) dx, as determined by the area under the graph of the integral from x = -4 to x = 4, is 8π.

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