PLS HELP 35 POINTS I WILL GIVE BRAINEST

Answer:

producer

Explanation:

The trophic level with the most calorie count is the producer.

A trophic level is a hierarchical level of the food chain with each level consisting of organisms that share the same feeding role in the ecosystem. A typical trophic level consists of the producers which occupy the base level, the primary, secondary, tertiary consumers respectively, and the decomposers.

The highest amount of energy exists at the base of the trophic level and decreases as we move up the trophic level, forming a kind of pyramid at the end. The producers have the highest amount of energy by directly converting energy from the sun to chemical energy. The consumers at subsequent levels are only able to utilize only about 10% of the chemical energy in their own foods.

Answer:

Image result for Where do karst regions occur?

Karsts are found in widely scattered sections of the world, including the Causses of France; the Kwangsi area of China; the Yucatán Peninsula; and the Middle West, Kentucky, and Florida in the United States.

Explanation:

Answer:

Middle West Kentucky.

Explanation:

Karst are found in widely scatter sections of the world.

Answer:

0.014mol

Explanation:

Given parameters:

Mass of Na₂CO₃  = 1.5g

Unknown:

Number of moles  = ?

Solution:

Number of moles of a compound is mathematically expressed as;

  Number of moles  = [tex]\frac{mass}{molar mass}[/tex]  

 Molar mass of  Na₂CO₃  = 2(23) + 12 + 3(16) = 106g/mol

 Number of moles = [tex]\frac{1.5}{106}[/tex]   = 0.014mol

Answer:

NaCl may be i guess so....

Answer:

solubility

Explanation:

Answer:

The usual way of converting black oxide to red oxide involves treating the black oxide with sulphuric acid and then roasting the intermediate product thus formed. lt is known that the amount of acid can be considerably less than the stoichiometric amount needed to convert all the black oxide to a sulphate.

Hope it helps :9

Answer:

Percent yield = 91%

Explanation:

Given data:

Theoretical yield of SF₆ = 124.3 G

Actual yield of SF₆ = 113.7 g

Percent yield of SF₆ = ?

Solution:

Formula:

Percent yield = (actual yield / theoretical yield)× 100

By putting values,

Percent yield = (113.7 g/ 124.3 g) × 100

Percent yield = 0.91 × 100

Percent yield = 91%

Answer:

Approximately 49 minutes.

Explanation:

1 mile = 1.6 km

So 8.0 x 1.6 km

Minutes required: [tex]\frac{10.4 times 60 }{8.0 times 1.6}[/tex]= 48.75 minutes

I hope this helped :)

Answer: d

Explanation:because it makes sence i think

Answer:

Option A. The carbocation accepts a pair of electrons.

Explanation:

A carbocation is defined as a positively charged carbon, which is bound to 3 substituents. Since it has no electrons  nonbonding, it only has six electrons in its valence shell. With only six electrons in its valence shell, a carbocation is a powerful electrophile (and Lewis acid) and can react with any nucleophile that is found.

Carbocations are proposed as intermediates in many  organic reactions. They also work like free radicals, which are electron-deficient species.

Same as free radicals, the carbocations are stabilized by alkyl substituents.

Answer:

Explanation:

The number of S atoms can be found by using the formula

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 0.67 × 6.02 × 10²³

We have the final answer as

Hope this helps you

Answer:

[tex]atoms \ H= 9.767x10^{24}atoms[/tex]

Explanation:

Hello!

In this case, considering that the mass of hydrazine is missing, we can assume it is 130.0 g (a problem found on ethernet). In such a way, since we need a mass-mole-atoms relationship by which we can compute moles of hydrazine given its molar mass (32.06 g/mol), then the moles of hydrogen considering one mole of hydrazine has four moles of hydrogen and one mole of hydrogen has 6.022x10²³ atoms (Avogadro's number); therefore, we proceed as shown below:

[tex]atoms \ H=130.0gN_2H_4*\frac{1molN_2H_4}{32.06gN_2H_4} *\frac{4molH}{1molN_2H_4} *\frac{6.022x10^{23}atoms}{1molH}\\\\atoms \ H= 9.767x10^{24}atoms[/tex]

Notice 130.0 g has four significant figures, therefore the result is displayed with four as well.

Best regards!

Answer: ?L=250 mL × 1L =0.25L 1000 mL

0.150 M = moles of solute moles of solute = 0.038 mol.

Explanation:

Answer:

Both sulphur and oxygen have two unshared pairs of electrons

Explanation:

The compound sulphur monoxide has the formula S=O. It is quite analogous to the diatomic molecules of the group 16 elements.

We must remember that each group element has six electrons in their outermost shell. Two of these are lone pairs leaving only two electrons available for bond formation.

These two electrons are used to form the sigma and pi bonds in S=O, leaving two lone pairs on each of sulphur and oxygen atoms.

Answer:

Their atoms obey the octet rule

Explanation:

Chemical compounds are formed when atoms combine with one another in order to comply with the octet rule. The octet configuration gives an atom stability in electronic structure.

compound is formed when potassium reacts with chlorine, which forms ions with a negative charge. The formula of this compound would therefore be KCl.

The molecular formula if potassium and chlorine reacted to form a neutral compound will be KCI.

To learn about potassium and chlorine reactions, refer to: https://brainly.com/question/20690183

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Answer:

If I remember correctly it should be 10^7 meters.

Explanation:

The power of ten are we able to view the entire Earth in space is 10^8. This is further explained below.

Generally, A telescope is simply defined as a device that magnifies views of faraway things

In conclusion, The power of the telescope will be at 10^8.

Read more about Earth

https://brainly.com/question/24878669

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Answer:

c. SP2

Explanation:

The image in the diagram below shows the structure of  NO₃⁻

Nitrogen is the central atom with the electronic configuration of 1s² 2s² 2p³.

So in its outermost shell, it has 3 electrons and the hybridization is sp²

However,

According to Hund's rule:

The ground state of Nitrogen is;    

1s²    2s²   2p³

↑↓     ↑      ↑  ↑  ↑

At the excited state when it is attached to 3 different oxygen ions, we have:

                1s²     2s²        2p⁵

O⁻ --->     ↑↓      ↑↓     ↑↓    ↑↓   ↑      

                1s²     2s²        2p⁵

O⁻ --->     ↑↓      ↑↓     ↑↓    ↑↓   ↑

                1s²     2s²        2p⁴

O⁻ --->     ↑↓      ↑↓     ↑↓    ↑   ↑

Thus, the 3 sp² orbital lies in a plane and form 3 N - O σ- bond and one π- bond.

Answer:

[tex]1s^2,2s^2,2p^6,3s^2,3p^6,4s^2,3d^5[/tex]

Explanation:

Hello!

In this case, since electron configurations allows to understand how the electrons in an atoms are arranged depending on the energy levels from 1 to 7 and subshells s, p d and f, considering the attached picture, if we want an element for which the last term in its electrons configuration was 3d⁵, we write:

[tex]1s^2,2s^2,2p^6,3s^2,3p^6,4s^2,3d^5[/tex]

It means that the element has 25 electrons, therefore, it should be manganese.

Best regards!

Answer: it's A the same answer as the dude above me not trying to type all that

Explanation: took the test for ap

Answer:

2

Explanation:

C⁴H¹⁰ + 2O² —> 4CH²O + H²

Answer:

The change in entropy of the carbon dioxide is [tex]1.183\times 10^{-3}[/tex] kilojoules per Kelvin.

Explanation:

By assuming that carbon dioxide behaves ideally, the change in entropy ([tex]\Delta S[/tex]), measured in kilojoules per Kelvin, is defined by the following expression:

[tex]\Delta S = m\cdot \bar c_{v}\cdot \ln \frac{T_{f}}{T_{o}}+m\cdot \frac{R_{u}}{M}\cdot \ln \frac{V_{f}}{V_{o}}[/tex] (1)

Where:

[tex]m[/tex] - Mass of the gas, measured in kilograms.

[tex]\bar c_{v}[/tex] - Isochoric specific heat of the gas, measured in kilojoules per kilogram-Kelvin.

[tex]T_{o}[/tex], [tex]T_{f}[/tex] - Initial and final temperatures of the gas, measured in Kelvin.

[tex]V_{o}[/tex], [tex]V_{f}[/tex] - Initial and final volumes of the gas, measured in liters.

[tex]R_{u}[/tex] - Ideal gas constant, measured in kilopascal-cubic meter per kilomole-Kelvin.

[tex]M[/tex] - Molar mass, measured in kilograms per kilomole.

If we know that [tex]T_{o} = T_{f}[/tex], [tex]m = 0.010\,kg[/tex], [tex]R_{u} = 8.315\,\frac{kPa\cdot m^{3}}{kmol\cdot K}[/tex], [tex]M = 44.010\,\frac{kg}{kmol}[/tex], [tex]V_{o} = 6.15\,L[/tex] and [tex]V_{f} = 11.5\,L[/tex], then the change in entropy of the carbon dioxide is:

[tex]\Delta S = \left[\frac{ (0.010\,kg)\cdot \left(8.315\,\frac{kPa\cdot m^{3}}{kmol\cdot K} \right)}{44.010\,\frac{kg}{kmol} } \right]\cdot \ln \left(\frac{11.5\,L}{6.15\,L}\right)[/tex]

[tex]\Delta S = 1.183\times 10^{-3}\,\frac{kJ}{K}[/tex]

The change in entropy of the carbon dioxide is [tex]1.183\times 10^{-3}[/tex] kilojoules per Kelvin.

Answer:

See explanation

Explanation:

According to the Journal of Chemical Education, Volume 80, No.8 (2003); "The first ionization energy of bismuth appears to be  anomalous......It has been claimed that spin– orbit coupling by the Russell–Saunders scheme would lower  the ground state of Bi+ ..."

However, the involvement of  d and f orbitals in Bi and Po implies that the outermost orbitals are poorly screened hence the drop between nitrogen and oxygen is not observed between Bi and Po.

The same argument could be extended to explain the reason why  there not a corresponding drop between Ba and Tl is the sixth period even though they are in the same group as Be and B.

Answer:

The correct option is b

Explanation:

Firstly, the compound is ClF₃ and not ClF₃ClF₃. The name of the compound ClF₃ is chlorine trifluoride. It's electron geometry is trigonal bipyramidal (with the chlorine at the center and the atoms of the fluorine forming a triangular bipyramid around it) with a bond angle of 175° with an hybridization of sp³d.

Answer:

the visual system would be the answer