pls help its an image scroll down

Step-by-step explanation:

8.a.

a function is something that looks like

y = ax + b or similar.

it describes the way to calculate the result for whatever input value you can come up with.

so,

C = 12×d + 8

you could also say

C(d) = 12×d + 8

as, when you rent, you have to pay these $8 in any case, no matter how long you stay, and you need to pay $12 per day you stay.

funny thing is : you understood this perfectly well when doing b.

c.

the constant rate of change is always the factor of the input variable. here : 12

it is the ratio of (y change) / (x change)

or here (C change / d change).

it indicates that for any increase of d by 1 (staying one day longer) the charges C increase by 12.

9.a.

remember, what we just said about the rate of change ?

it is (result change) / (input change).

between 2010 and 2015

the input changed by +5 (from 2010 to 2015).

the result changed by +6.25 (from 37 to 43.25).

the rate of change is therefore

6.25/5 = 1.25 = 1 1/4 = 5/4

the function is therefore

population in millions = (years since 2010)×5/4 + 37

p = y×5/4 + 37

b.

now we want to find the number of years (y) so that the result of that equation is 50.

50 = y×5/4 + 37

13 = y×5/4

52 = 5y

y = 52/5 = 10.4

so, this will be during the 11th year after 2010 = 2021.

10.

be careful and concentrate.

you see that the sequence goes up 20, when n goes up 5 (and not just 1) ? there was your initial mistake.

a.

again, remember the change rate : it is result change / input change.

so, we have here 20/5 = 4.

so,

C(n) = 4×n + 50

b.

n = 12

C(12) = 4×12 + 50 = 98

c.

now we have C(n), and want to find for which n this is true.

C(n) = 78

78 = 4×n + 50

28 = 4×n

n = 7

after 7 visits the costs are 78.

there are the basic costs of 50 (for n = 0 or 0 visits) and then extra 4 for every visit.

d.

the x-axis is for the number of visits, the y-axis for the costs.

so, the line starts at the point (0, 50), and then passes through the points of the original table (5, 70), (10, 90), (15, 110). and if you want you can calculate the points for higher x (or number of visits).

Answer:

x-20

Step-by-step explanation:

check a math app if u want to see

Answer: A) y = x + 3

Step-by-step explanation:

Use two points given in the table and plug them into slope-intercept form y = mx + b.

In order to solve for m, the slope, by plugging them into  [tex]\frac{y_{2} -y_{1} }{x_{2} -x_{1} }[/tex].

(0, 3) (2, 5)

[tex]\frac{5-3}{2-0}[/tex] = [tex]\frac{2}{2}[/tex] = 1

Use one of the points and plug it into the slope-intercept form y = mx + b.

3 = 1(0) + b

3 = 0 + b

3 = b

The linear equation to the table would be y = x + 3.

Answer:

  7.1 cm

Step-by-step explanation:

You want the height of a cylinder of radius 8.2 cm and volume 1500 cm³.

  V = πr²h . . . . . formula for the volume of a cylinder

  h = V/(πr²) . . . formula solved to give h

  h = (1500 cm³)/(π·(8.2 cm)²) ≈ 7.1 cm

The depth of the water is about 7.1 cm.

Answer:

(5π/8, 0)

Step-by-step explanation:

x intercept occurs when y = 0

0 = tan(x - 5π/8)

as tan0 = 0

x - 5π/8 = 0

x = 5π/8

Answer:

B. The x-coordinate is positive, and the y-coordinate is negative

Step-by-step explanation:

Counting for the quadrants starts and the positive x-axis and then moves counterclockwise. This means that the IV quadrant will be the bottom right quadrant. The right axis is the positive x-axis and the bottom axis is the negative y-axis. This means that the coordinate for the IV quadrant must look like (x,-y).

Answer:

false i think

Step-by-step explanation:

16+1=17-1=16-2=14

I assume the integral is supposed to be

[tex]\displaystyle \int_C z^2\,dx + x^2\,dy + y^2\,dz[/tex]

Parameterize C by

[tex](x(t),y(t),z(t)) = (1-t)(1,0,0) + t(5,1,2) = (1+4t, t, 2t)[/tex]

with 0 ≤ t ≤ 1, and dx = 4 dt, dy = dt, and dz = 2 dt. Then the line integral is

[tex]\displaystyle \int_C z^2\,dx + x^2\,dy + y^2\,dz = \int_0^1 (2t)^2(4\,dt) + (1+4t)^2\,dt + t^2(2\,dt)[/tex]

[tex]\displaystyle \int_C z^2\,dx + x^2\,dy + y^2\,dz = \int_0^1(1+8t+34t^2)\,dt[/tex]

[tex]\displaystyle \int_C z^2\,dx + x^2\,dy + y^2\,dz = 1+4+\frac{34}3 = \boxed{\frac{49}3}[/tex]

Answer:

78 buttons left

Step-by-step explanation:

I multiplied 24 children by 3 buttons because each child took 3 buttons and I got 72 buttons taken.

Then I subtracted 150 buttons which is the starting number by 72 buttons (the amount taken by the child's) to get 78 buttons left in the box. ( I just separated negative 72 buttons into -50 and -22 to make it easier)

Answer: Yes

Step-by-step explanation: They are similar because it the same kind of triangle just ones smaller and the other is bigger.

[tex]\huge\green{\tt MathSolution:}[/tex]

C. y < × y < 4

Answer:

I am pretty sure the answer is 27.02.

Step-by-step explanation:

Hope this helps!

Answer:

Add 6 to both sides

Step-by-step explanation:

The (usual) first thing to do when solving any equation is to simplify both sides of the equation. However, since we have nothing to simplify, we move onto the next step that'll be the first step: isolating the variable, x. To do so, we must do the inverse of subtracting 6 (which is adding 6).

Answer:

[tex]2\frac{1}{3}[/tex]

Step-by-step explanation:

Alrighty, when dividing fractions there is a trick called "keep, change, flip".

Step 1: Keep- Keep the first fraction the same

[tex]\frac{7}{9}[/tex]

Step 2: Change- Change the division sign to a multiplication sign

[tex]\frac{7}{9} *[/tex]

Step 3: Flip- Flip the second fraction (the reciprocal)

[tex]\frac{1}{3} --->\frac{3}{1}[/tex]              [tex]\frac{7}{9} * \frac{3}{1}[/tex]

Then, you multiply straight across

[tex]\frac{7}{9} * \frac{3}{1} = \frac{21}{9}[/tex]

Now, we simplify

[tex]\frac{21}{9} = \frac{7}{3} = 2\frac{1}{3}[/tex]

Answer:

  145. YZ = 48 in

  147. XY = 6 ft

  148: XY = 3 in

Step-by-step explanation:

In each case, multiply the given proportion by a value that makes it match the given information about the segments.

XY is 24in, lines XY:YZ = 1:2. What is the length of line YZ?

Multiply the proportion by 24 in:

  XY : YZ = (24 in)(1) : (24 in)(2) = 24 in : 48 in

  YZ = 48 in . . . (C)

__

YZ is 9ft, lines XY:YZ= 2:3. What is the length of line XY?

Multiply the proportion by 3 ft:

  XY : YZ = (3 ft)(2) : (3 ft)(3) = 6 ft : 9 ft

  XY = 6 ft . . . (B)

__

YZ is 1ft, line XY:YZ = 1:4. What is the length of line XY?

Multiply the proportion by 3 in:

  XY : YZ = (3 in)(1) : (3 in)(4) = 3 in : 12 in = 3 in : 1 ft

  XY = 3 in . . . (A)

Answer:  C.  (-1, 2)

Explanation: The two lines intersect at this point. This point satisfies both equations at the same time.

Answer:

wth that's hard I can't answer that

Answer:

Step-by-step explanation:

let the side of triangle=x

hypotenuse=x+4

(x+4)^2=x^2+x^2

x^2+8x+16=2x^2

x^2-8x-16=0

x²-8x=16

x²-8x+16=16+16=32

(x-4)²=16×2=(4√2)²

x-4=±4√2

x=4±4√2

either x=4+4√2=4(1+√2)

or x=4-4√2=-4(√2-1)<0 (rejected)

leg x=4(1+√2)≈4(1+1.414)≈4×2.414≈8.828≈8.83 cm

hypotenuse≈8.83+4=12.83 cm

Answer:

The Awnser is 27 for both I did that I-ready before

Step-by-step explanation:

Answer:

27 for both blanks

Step-by-step explanation:

I just did it on iready and I got it correct

Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

49. [tex]x = \dfrac{1}{a}[/tex] and [tex]y = 3[/tex]

50. [tex]x = \dfrac{1}{2a}[/tex] and [tex]y = \dfrac{1}{b}[/tex]

Step-by-step explanation:

We are going to solve these systems of equations using the elimination method.

49. Given:

[tex]5ax + 4y = 17[/tex] (1)

[tex]\:\:ax + 7y = 22[/tex] (2)

Multiply Eqn(1) by 7 and multiply Eqn(2) by -4 to get

[tex]\:\:35ax + 28y = 119[/tex]

[tex]-4ax - 28y = -88[/tex]

Adding the two equations above, we get

[tex]31ax = 31 \Rightarrow x = \dfrac{1}{a}[/tex]

Substituting this value for a into Eqn(2), we get

[tex]y = 3[/tex]

50. Given:

[tex]4ax + \:\:by = 3[/tex] (3)

[tex]6ax + 5by = 8[/tex] (4)

Multiplying Eqn(3) by -5, we get

[tex]-20ax - 5by = -15[/tex]

[tex]\:\:\:\:\:\:6ax + 5by = \:\:8[/tex]

Adding the two equations above, we get

[tex]-14ax = -7 \Rightarrow x = \dfrac{1}{2a}[/tex]

Plugging in the value of x into Eqn(3), we get the value for y as

[tex]4a(\frac{1}{2a}) + by = 3[/tex]

or

[tex]2 + by = 3 \Rightarrow y = \dfrac{1}{b}[/tex]

false for 4.

ture for the 1st one

brianliest me

Answer:

1 True. 2. True

Answer:

(6, 10)

Step-by-step explanation:

You found (6, 4)

The second would be

(6, 10) making BD || to CA