pls help me thx ......................................................................

The acceleration of the car is 57.04 [tex]m/s^{2}[/tex]

It is given that a sports car accelerates from rest to 103 km/h in 6.5 s.

So, Initial velocity (u) = 0 m/s   { since the car starts from rest }

Final velocity (v) = 103 km/hr = 103 * 18/5 m/s = 370.8 m/s

Now, the time taken (t) = 6.5 seconds.

Acceleration is the measure of how fast the object's velocity changes with respect to time.

Now, Acceleration (a) = Change in velocity/Time taken

So,

[tex]a = \frac{v -u}{t}[/tex]

Putting all the values, we get

[tex]a = \frac{370.8 - 0}{6.5} =\frac{370.8}{6.5} = 57.04[/tex]

Hence, the acceleration of the car is 57.04 [tex]m/s^{2}[/tex]

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The input force on the lever of mechanical advantage 9.5, in order for it to lift a rock of 445 N is 46.84 N.

Force can be defined as the product of mass and acceleration.

To calculate the input force on the lever, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the input force on the lever is 46.84 N.

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Answer:

Explanation:

H = V² / (2·g)

H = 12² / (2·9.8) ≈ 7,3 m

Answer:

By conservation of energy,

Kinetic energy of launched rocket = change in potential energy of rocket at maximum height.

→ Ig h is maximum height reached:

The longer a wire is, the higher the resistance will be.

Neither length (L) nor cross-sectional area (A) influences Rh. It totally depends on the type of material used to make the wire. It is somewhat dependent on temperature variation, but this variation is negligible and is disregarded for most purposes.

Let Resistivity be Rh and Resistance be R.

L for the wire's length and A for its cross-section.

This formula relates to resistance.

R=Rh*L/A

Rh, L, and A are the three parameters that determine resistance.

The resistance increases as the wire lengthen.

Less resistance is there the larger the cross-sectional area. (Put A in the denominator; the numerator is L.)

Only take into account the Length variable. As was previously said, shorter wires have lower resistance and vice versa.

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Answer: The most widely accepted method of determining the posted speed limit is to set the speed limit at what is called the “85th percentile speed”, which is the speed at or below which 85 percent of the traffic is moving.

Explanation:

In respiratory system, Airflow from the lungs becomes obstructed due to chronic inflammatory lung disease called chronic obstructive pulmonary disease (COPD).

Respiratory system :

The network of organs and tissues that aids in breathing is known as the respiratory system.

The most common respiratory diseases are :

Problem causes respiratory system are  :

Precautions of respiratory system diseases :

In respiratory system, Airflow from the lungs becomes obstructed due to chronic inflammatory lung disease called chronic obstructive pulmonary disease (COPD).

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If the absolute temperature of an ideal diatomic gas is quadrupled, then, the average speed of molecules is doubled.

[tex][V_avg=\sqrt(8k *4T)/\pi m],[V_avg=2\sqrt(8kT) \pi m],[V_avg=2v_avg][/tex]

Speed (often abbreviated as "s") is a scalar variable that describes how much an object's location changes over time or how much it changes per unit of time. The average speed of an item in a period of time is the distance traveled by the object divided by the duration of the period.

Time divided by distance are the speed-related metrics.. The meter per second (m/s) is the SI unit of speed, while the kilometer per hour (kph) is the most often used unit of speed in daily life.

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The short summary of the concept of dark matter and dark energy is given here.

An estimated 85% of the universe's mass is assumed to be made up of dark matter, a hypothetical type of stuff.  Because it does not appear to interact with the electromagnetic field—that is, it does not absorb, reflect, or emit electromagnetic radiation—dark matter is referred to as being "dark," making it challenging to detect.

Numerous astrophysical observations support the existence of dark matter, including gravitational effects that cannot be described by the gravity theories currently in use without the presence of more matter than can be observed. Because of this, the majority of scientists believe that dark matter is prevalent in the universe and has significantly influenced both its structure and evolution.

Dark energy is an undiscovered type of energy that has the largest effects on the cosmos according to physical cosmology and astronomy. Supernova observations provided the first direct proof for its existence by demonstrating that the cosmos is expanding faster than ever rather than at a fixed rate. It is necessary to understand the universe's origins and initial elements in order to comprehend its evolution.

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The features of Earth's orbit that concur with and conform to the pattern of Kepler's second law include the fact that Earth feels the largest gravitational pull when it is closest to the Sun.

According to Kepler's second rule, a planet moves in its ellipse so that a line drawn between it and the Sun and focused on it covers the same amount of space in the same amount of time.

The eccentricity of the Earth's orbit around the Sun, which is an ellipse, determines how far from a circle the orbit is (e). The perihelion, or point on the orbit that is closest to the Sun, and the apogee, or point most aphelion of the Sun.

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a) the magnitude of the acceleration of the block is a = 1.633m/s².

b) time to reach the end by the block is t = 1.1867s.

c) mass of mA if the acceleration of the system is 1/100g is mA = 99kg

a) Given,

mA = 15kg

mB = 3kg

The formula for the Tension in the cord, T =mAmBg / (mA + mB)

T = 45*9.8/18

T =24.5N

In the case of mA, we have T = mA*a

acceleration of mA, a = T/mA

a = 24.5 / 15

a = 1.633m/s²

In the case of mB, we have mB*a = mB*g -T

a = (mB*g -T)/mB

a = (3*9.8 - 24.5) /3

a = 1.633m/s²

b) Initial velocity of mA, u = 0

The distance traveled by mA, s = 1.15m

We have,

s = ut + 1/2at²

t = √(2s/a)

t = 1.1867s

c) mB = 1kg

The acceleration of the system, a = g/100

The acceleration of the system is given by the formula, a = mB*g/ (mA + mB)

mA = [mB*g/a] - mB

mA = [1*9.8*100/9.8] -1

mA = 99kg

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Answer:

It could be 45 if the vectors are parallel.

It could be 5 if the vectors are antiparallel.

It could be between 5 and 45 for any other arrangement of these two vectors.

Suppose they are at right angles to another then the sum is

(20^2 + 25^2)^1/2 = 32

Answer:

Prokaryotes such as E. coli, Archaea as well as eukaryotes such as euglena reproduce through binary fission.

Explanation:

Answer:

Prokaryotes such as E. coli, Archaea as well as eukaryotes such as euglena reproduce through binary fission.

Explanation:

Answer:

Checklist 1: What to Bring...Your Rocket Launch Pad & Ignition System Rocket MotorsIgnitersRecovery WaddingAltitude Tracker Your Field Box Also, it would be a good idea for the group to bring A folding card table or picnic table for rocket prep Trash Bags: try to leave your launch field cleaner than you found it. First Aid Kit: be prepared. A fly or tarp set up as a lean-to to protect the rocket prep area from the wind and/or sun. 

So, this is the diagram of the described situation, the strings are attached to a rigid support at their one end and the other end is connected to the particle.

Let, the string making an angle of 45 with the horizontal has a tension of T 1 and

the one making an angle of 30 has a tension of T2.

Now,

what we have done is that we have taken the vertical and

horizontal components of the tension in the two strings.

Now,considering the system to be in equilibrium,

see the diagram,the vertical component of the strings i.e

(T 1 sin 45 & T 2 sin 30) together will act to balance the weight of

the particle(mg)

So,we can say, T 1 sin 45 + T 2 sin 30 = mg. ...(1)

From horizontal equilibrium,we can say, T 1 cos 45 must balance T 2 cos 30 ,

as no other force is present in horizontal direction.

So,T 1 cos 45 = T 2 cos 30. ...(2)

Given,

mg = 10 ⋅ 10 = 100N

So, solving equation 1 & 2 we get,

T 1 = 89.65N and, T 2 = 73.20N

Answer:

hjcyysjjJjxjcmxmmsxjvemmzxjdndmenbxhfnhcjdnuxjd

In this case Behavioral therapy  is being used.

A broad phrase used to describe several forms of therapy used to address mental health conditions is behavioural therapy.

This type of treatment aims to recognize and assist in changing potentially harmful or unhealthy behaviors. It is predicated on the notion that all behaviors are taught and that they are modifiable. Treatment frequently focuses on current issues and solutions.

When staff members at the mental health center do not respond to patients who use threats, but praise patients who are polite, they try to teach politeness and other good behavior by using  Behavioral therapy.

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Answer:

Explanation:

Given:

R = 5 000 km = 5*10⁶ m

g = 6.05 m/s²

G = 6.67·10⁻¹¹ m³/(kg*c²)

______________

M - ?

V - ?

(i)

g = G·M /R²

M = g·R² / G = 6.05·(5·10⁶)² / 6.67·10⁻¹¹ ≈ 2.27·10²⁴ kg·

(ii)

V = √ (g·R) = √ (6.05·5*10⁶) ≈ 5 500 m/s  = 5.5 km/s

Answer:

Explanation:

m₀ = 100 g

m = 6.25 g

T = 33 s

_____________

t - ?

Radioactive decay constant:

λ = ln 2 / T = 0.693 / 33  ≈ 0.021 s⁻¹

Law of radioactive decay:

[tex]m=m_{0} e^{-\lambda t} \\[/tex]

[tex]e^{-\lambda t} = \frac{m}{m_0} \\[/tex]

[tex]ln (e^{-\lambda t}) = ln(\frac{m}{m_0} ) \\[/tex]

[tex]-\lambda t = ln (\frac{m}{m_0})[/tex]

[tex]t = -\frac{ln(\frac{m}{m_0}) }{\lambda}[/tex]

t = - ln (6.25/100) / 0.021 ≈ 132 s

Answer:

120

Explanation:

because it is horizontal

An object of mass 3.0 kg starts from rest and moves along the x-axis. A net horizontal force is applied to the object in the +x direction. The Force-time graph is shown below. The net impulse delivered by the applied force is 102 joule.

A force is an influence that has the power to alter an object's motion. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Force is used to describe a body's tendency to modify or change its state as a result of an external cause. When force is applied, the body can also alter its size, shape, and direction. kicking a ball, pushing and pulling on the door, or kneading dough are a few examples.

We know the Impulse = Area of the Graph

= ( 6 × 4) + 0.5 × 2 × 6

= 30 sec

For First 4 sec

Acceleration = 6 ÷ 3

= 2 m/sec²

S = 0.5 × 2 × 4²

= 16 m

Therefore, work Done = 6 × 16

= 96 J

Then, Average force

= ( 6 - 0 ) ÷ 2

= 3 N

Acceleration = 1 m/sec²

S = 0.5 × 1 × 2²

= 2 m

Work = 3 × 2

= 6 J

Total Work = 96 + 6

= 102 J

Thus, The net impulse delivered by the applied force is 102 joule.

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The current state of research offers some evidence that life events can cause changes in personality traits and that various life events may connect differently to various trait domains.

What is anecdote?

A brief narrative or account abou life events changet a person or event that is typically humorous, instructive, entertaining, or biographical in nature is known as an anecdote.

How do life events change your personality?

These ideas contend that because life events alter, interrupt, or reroute people's habits of thought, feeling, and action, they have long-lasting consequences on personality traits.

Hence is a changes in personality traits a correct answer.

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The answer is 70.6°

Answer:

0 J

Explanation:

KE = .5(m)(v2-v1)

if velocity is constant v2 = v1, then v2 - v1 = 0

therefore if (v2-v1) = 0, then KE must also be equal to 0

Gravitational Potential Energy , Kinetic Energy and velocity of panther just before hitting the ground will be 790.41599 J , 990.41599 J , 5.6523m/s respectively.

Mass is 62 kg with a height 1.3m .

Gravitational Potential Energy means product of mass , gravitational acceleration and height . Mathematically, GPE= mgh

GPE= 62 x 1.3 x 9.8

= 790.41599 J

Energy lost = Final energy- GPE

Final Energy Δ =  790.41599 J + 200 J

=990.41599 J

To find Velocity of panther just before hitting the ground V:-

Δ⇒mV²/2

990.41599 J= 62 V²/2

V²= {990.41599 x 2}/62

= 31.9489029

V=5.6523m/s

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Answer:

0.8m/s²

Explanation:

we know,

v² = u² + 2as

here v is final velocity, u is initial velocity, a is acceleration & s is distance travelled.

8² = 0² + 2*a*40

⇒ 64 = 80a

⇒a = 64/80 = 0.8m/s²

The speed of the water through the pipe is 4.96 m/s

Since a large water tank is completely filled with water. The tank is 3.0 m high and its surface is open. If a small hole is made on one side of the tank at a height of 0.8 m, to find the speed with which the water comes out of the pipe, we use Bernoulli's equation

Bernoulli's equation governs flows through pipes. It is given by

P₁ + ρgh₁ + 1/2ρv₁² = P₂ + ρgh₂ + 1/2ρv₂² where

Given that

So, susbstituting the values of the variables into the equation, we have

P₁ + ρgh₁ + 1/2ρv₁² = P₂ + ρgh₂ + 1/2ρv₂²

1.013 × 10⁵ Pa + 1000 kg/m³ × 9.8 m/s² × 3 m + 1/2 × 1000 kg/m³ × (0 m/s)² = 0 + 1000 kg/m³ × 9.8 m/s² × 0.8 m + 1/2 × 1000 kg/m³ × v₂²

1.013 × 10⁵ Pa + 29400kg/ms² + 0 = 0 Pa + 7840kg/ms² + 5000v²

130700 Pa = 7840kg/ms² + (5000 kg/m³)v²

130700 Pa - 7840 Pa = (5000 kg/m³)v²

122860 Pa = (5000 kg/m³)v²

Making v subject of the formula, we have

v = √(122860 Pa/5000 kg/m³)

= √(130.7/5 Pam³/kg)

= √(24.572 Pam³/kg)

= 4.96 m/s

So, the speed of the water through the pipe is 4.96 m/s

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Mechanical wave is a kind of wave is a wave on the electromagnetic spectrum.

Electromagnetic (EM) waves are cross waves. Their vibrations or oscillations are swapped in electrical and magnetic fields at right angles to the direction of wave travel. The radiation is explained by the amount of energy found in the photons. Radio waves have photons with low energies, and microwave photons ..Electromagnetic waves with smaller wavelengths and higher frequencies include ultraviolet light, X-rays, and gamma rays. Electromagnetic waves with longer kinds of Electromagnetic Waves. Radio Waves have the longest wavelengths of all electromagnetic waves.

So we can conclude that the different types of waves are mechanical and electromagnetic waves. Mechanical waves are divided into transverse and longitudinal waves.

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The buoyant force acts on the cube of wood with a density of 0.780 g/[tex]cm^3[/tex]  And 10.0 cm on each side is 7.644 Newton.

The density is the mass of a material substance per unit volume. d = M/V, where d is density, M is mass, and V is volume, is the formula for density. Grams per cubic centimeter are a typical unit of measurement for density.

As an illustration, the density of Earth is 5.51 grams per cubic centimeter, whereas the density of water is 1 gram per cubic centimeter.

Given:

The density of wood, ρ = 0.780 g/[tex]cm^3[/tex],

The Side of wood, a = 10 cm,

Calculate the buoyant force by the following formula,

F = - ρ * g * V,

Here, F is the buoyant force.

Substitute the values,

F = - 0.780 * 9.8 * [tex]10^3[/tex] * [tex]10^{-3}[/tex]

F = 7.644 Newton

Therefore, the buoyant force acts on the cube of wood with a density of 0.780 g/[tex]cm^3[/tex] is 10.0 cm on each side is 7.644 Newton.

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The magnitude of the gravitational force 0f two solid sphere of radius R is 81F₁ newton.

Gravitational force :

Any two bodies' mutual attraction is directly proportional to the sum of their masses and inversely proportional to the square of their separation.

Force is given as :

F₁ =  (G x m x m )/ (2r)²

To calculate gravitational force :

F₂ = G  x  [27m x 27m]/ [6r]²

F₂ = (G x27)² m² / 36r²

F₂ = (81 G  x m²) / 4r²

F₂ = 81F₁

The magnitude of the gravitational force of two solid sphere of radius R is 81F₁ newton.

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The rubber band travels horizontally 7.0 cm in second time.

Given parameters:

the rubber band is stretched = 2.0 cm.

And, the rubber band travels = 3.5 cm.

Secondly,  the rubber band is stretched = 4.0 cm.

As force is directly proportional with stretching and landing at a horizontal distance,  it travels horizontally in second time

= 4.0 cm x 3.5 cm/ 2.0 cm.

= 7.0 cm.

The vertical movement can't be measured as a new gravitational force comes in play in this case.

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