Plz help plz help me will mark Brainly

Answer:

solubility

Explanation:

The question is incomplete, the complete question is;

The rate of reaction was measured during a chemical reaction. After the first 3 seconds, the rate of reaction was 1.8 x10−6 M/s. Which of the following would you expect after another 3 seconds? a

The rate would be higher, and the concentration of reactants would be lower.

b

The rate would be higher, and the concentration of reactants would be higher.

c

The rate would be lower, and the concentration of reactants would be lower.

d

The rate would be lower, and the concentration of reactants would be higher.

Answer:

The rate would be lower, and the concentration of reactants would be lower.

Explanation:

The rate of reaction refers to how quickly or slowly the reactants disappear or the products appear in a given reaction. The rate of reaction depends on the concentration of the reactants. Thus, as concentration decreases with time, the rate of reaction decreases accordingly.

Therefore, reaction rates tend to decrease with time since the concentration of  the reactants decrease with time as the reactants are being converted into products. Thus after three seconds, the rate would be lower, and the concentration of reactants would be lower. Hence the answer above.

Answer:

The rate would be lower, and the concentration of reactants would be higher.

Explanation:

I took the test and i think i got it right

Answer:

A.

Explanation:

They'd probably want to know the conditions that usually produce fog

Answer:

D Fracture

Explanation:

jus took the test

Answer:

It depends on the country you are coming from. For example, the human trafficking laws in the US are different from UK. If you need an essay on this contact me on (irenedavid at g mail dot com)

Explanation:

Answer:b

Explanation:

Answer:

Water is capable of dissolving a variety of different substances, which is why it is such a good solvent. And, water is called the "universal solvent" because it dissolves more substances than any other liquid. This is important to every living thing on earth.

Answer:

Option 3 and 4

Explanation:

In an endothermic reaction, the potential energy of the system increase. The potential energy of the reactant is less as compared to the potential energy of the products and hence additional energy is required to produce products.

The potential energy of the reactants depend on their chemical state and not the physical state. Hence, option 2 is not correct. Also, the number of reactant do not make any significant impact on the determination of potential energy of reactants. Thus, option 1 is also incorrect

Answer:

B

Explanation:

The appropriate diagram of the question is shown in the first image attached below.

From the diagram, we see the reaction of Cyclopentanol taking place under Tscl pyridine. We are to show the reaction mechanism and determine from the options, which appropriate product fits in.

So, from the reaction, the hydroxyl substituent reacts with Tscl where cl is being lost. This process is followed by an attack of N substituent on the pyridine with the Hydrogen atom and cleaves off for the structure to form a stable structure. The stereochemistry of the compound remains unchanged and it maintains its stick formula.

Thus, X is the appropriate and the correct product.

Solution :

Given :

Hydrogen iodide decomposes to hydrogen and iodine gas

    [tex]$2 HI \ \ \ \Leftrightarrow \ \ \ \ H_2 \ \ \\ + \ \ I_2 $[/tex]

I    0.148            0          0

C     -2a           +a          +a

E  0.148-2a      a            a

We know

[tex]$k_p=\frac{P(H_2)P(I_2)}{P(HI)^2}$[/tex]

[tex]$0.016=\frac{a^2}{(0.148-2a)^2}$[/tex]

[tex]$0.016^{1/2}=\frac{a}{0.148-2a}$[/tex]

[tex]$0.12649=\frac{a}{0.148-2a}$[/tex]

0.0187 = 1.2529 a

a = 0.0149

Therefore

P(HI) = 0.148 - 2a

        = 0.148 - 2(0.0149)

        = 0.1182 atm

P([tex]$H_2$[/tex]) =  a

        = 0.0149 atm

P([tex]$I_2$[/tex]) =  a

        = 0.0149 atm

Answer:

can u explain a little more then i will help like what are the four

Explanation:

Answer:

d) U-238

Explanation:

edg 2021

Answer:

Atoms are kind of like building blocks.

Explanation:

Think of atoms as kind of like a mix between paint pigments and legos. The more legos that you have, the bigger the molecule but keep in mind that there are many different kinds of legos that all can come together to build numerous things. I hope that I answered your question and i apoligize if I didn't.

Explanation: they could be grouped by how they reproduce or they can be grouped by if there hetero or autotrophic

Answer:  pH is 1.6

Explanation: Explanation: HCl is strong acid and it protolyzes totally:

HCl + H2O  ⇒ H3O+ + Cl-

Concentrations are same:  [H3O+] = c(HCl)

pH = - log[H3O+] = - log(0.025) = 1.60

Answer:

K + F2 = KF

Explanation:

Thats the balancee equation for potassium fluoride. The equation is 2K + F2 → 2KF and the balanced equation is K + F2 = KF

Answer:

Explanation:3.2 ft 2 fti2 ft 4 ft ft2

Explanation:

[tex]H _{2}O _{2(aq)} →H _{2}O _{(l)} + O _{2}(g) \\ solution : 2 \: and\: 2[/tex]

Answer:

none of the above

Explanation:

A system is said to have attained dynamic equilibrium when the forward and reverse reactions proceed at the same rate. That is;

Rate of forward reaction = Rate of reverse reaction

The implication of this is that the concentrations of reactants and products remain constant when dynamic equilibrium is attained in a system. This does not mean that the reactant and product concentrations become equal; it rather means that their concentrations do not significantly change once dynamic equilibrium has been attained.

Answer:

the answer is B:

Explanation:

I hope it help.

Answer:d

Explanation:

Answer: The freezing point (in °C) of a 0.743 m aqueous solution of KCI is [tex]2.763^{o}C[/tex].

Explanation:

Given: Molality = 0.743 m

[tex]K_{f}[/tex] for water = [tex]1.86^{o}C/m[/tex]

The equation for dissociation of KCl when dissolved in water is as follows.

[tex]KCl \rightarrow K^{+} + Cl^{-}[/tex]

As it is giving 2 ions. Therefore, Van't Hoff factor for it is equal to 2.

Formula used to calculate the freezing point is as follows.

[tex]\Delta T_{f} = i \times K_{f} \times m[/tex]

where,

i = Van't Hoff factor

[tex]K_{f}[/tex] = molal depression constant

m = molality

Substitute the values into above formula as follows.

[tex]\Delta T_{f} = i \times K_{f} \times m\\= 2 \times 1.86^{o}C/m \times 0.743 m\\= 2.763^{o}C[/tex]

Thus, we can conclude that the freezing point (in °C) of a 0.743 m aqueous solution of KCI is [tex]2.763^{o}C[/tex].

Answer:

Option a (100 kPa) is the appropriate option.

Explanation:

The given value is:

Original pressure,

P₁ = 50 kPa

Let the new pressure be "x".

Now,

⇒  [tex]\frac{P1}{T_1} =\frac{P_2}{T_2}[/tex]

On substituting the values, we get

⇒  [tex]\frac{50}{T_1} =\frac{x}{2T_1}[/tex]

On applying cross-multiplication, we get

⇒  [tex]x = 50\times 2[/tex]

⇒     [tex]=100 \ kPa[/tex]

Thus the answer above is the right one.

Answer:

Ag⁺, Ba²⁺,

Explanation:

We can solve this question using the solubility rules:

When an Halide as Br- is added to a solution, the ions that can be precipitate are Ag⁺, Hg₂²⁺ and Pb²⁺.

That means the first ion present is Ag⁺

When sulfates, SO₄²⁻ are added, the ions that precipitates are: Ag⁺, Ca²⁺, Sr²⁺, Ba²⁺, Hg₂²⁺ and Pb²⁺

The second ion present is Ba²⁺

Hydroxides of Cu²⁺ and Mn²⁺ are insolubles but as no precipitate are formed when the solution is strongly alkaline those ions are not present.

Answer:

[tex]m_{NH_3}=0.0213gNH_3[/tex]

Explanation:

Hello there!

In this case, since it is known that the reaction between ammonia and acetic acid is:

[tex]CH_3COOH+NH_3\rightarrow CH_3COONH_4[/tex]

It is possible for us to realize that the mole ratio of acetic acid (vinegar) to ammonia is 1:1, that is why we can relate the concentrations as follows:

[tex]M_{acid}V_{acid}=M_{base}V_{base}\\\\[/tex]

In such a way, by knowing that the volume of these two are the same, we infer that their concentrations is also de same; and therefore, the mass of ammonia is calculated as:

[tex]m_{NH_3}=0.005L*0.25\frac{molNH_3}{L}*\frac{17.04gNH_3}{1molNH_3}\\\\m_{NH_3}=0.0213gNH_3[/tex]

Regards!

Answer:

you need a theripist or maybe just your girl if this is your question.

Explantion: you are clearly very weird but very cute and ily.

Answer:0.074 L

Explanation:

Answer:

All of the following statements are true regarding wood versus metal except:

c) Under sustained loads wood stops to deform

Explanation:

Wood is known to deform under stress.  It undergoes warping, thereby, losing its original straight shape when its moisture unevenly dries up.  Even concrete deforms under long-time loads.  Similarly, wood, under sustained loads, experiences faster deformation than it ordinarily warps.  To prevent further wood deformation, it must be treated, and its moisture dried up evenly.

Answer:

Maximum safe operating temperature = 450 °C

Explanation:

First, the volume of the cylindrical vessel is determined using the formula:

v = πr²h

Radius, r, of stainless steel vessel = width or diameter / 2

r = 39.0 cm / 2 = 19.5 cm

height of vessel = 46.8 cm

volume of cylinder = 22/7 × 19.5² × 46.8 = 55929.343 cm³ = 0.05593 m³

Using the ideal gas equation to calculate the maximum safe temperature

PV = nRT

pressure, P = 5.30 MPa = 5.30 × 10⁶ Pa

R = 8.314 J/mol.K

n = mass of gas/ molar mass of gas

molar mass of SF₆ = 146 g/mol

mass of Sf₆ = 7.20 kg = 7200 g

n = 7200/146 = 49.315 moles

T = PV/nR

T = (5.30 × 10⁶ × 0.05593) / (49.315 × 8.314)

T = 722.98 K

T in °C = 714.98 - 273.15 = 449.83 °C

Therefore, maximum safe operating temperature = 450 °C

Answer:

P_2 =0.51  atm

Explanation:

Given that:

Volume (V1) = 2.50 L

Temperature (T1) = 298 K

Volume (V2) = 4.50 L

at standard temperature and pressure;

Pressure (P1) = 1 atm

Temperature (T2) = 273 K

Pressure P2 = ??

Using combined gas law:

[tex]\dfrac{P_1V_1}{T_1} = \dfrac{P_2V_2}{T_2} \\ \\ \dfrac{1 *2.5}{298} = \dfrac{P_2*4.5}{273}[/tex]

[tex]0.008389261745 \times 273 = 4.5P_2[/tex]

[tex]P_2 =\dfrac{0.008389261745 \times 273 }{4.5}[/tex]

[tex]P_2 =0.51 \ atm[/tex]